Still a newb to coding . have almost no idea what im doing . i tried to make a php page which would let me upload and view an image . do not know what is wrong . i tried to do it as correctly as possible . could someone please help me out ?
<!doctype html>
<html>
<head>
</head>
<body>
<form method="post">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
<?php
if(isset($_POST['submit']))
echo "button has been clicked";
$con = mysqli_connect("127.0.0.1","root","","demo");
if(!$con)
echo "didnt connect to database ";
else echo "connected ";
$imagename= mysqli_real_escape_string($_FILES['image'] ['name']);
$imagefile =mysqli_real_escape_string(file_get_contents($_FILES['image']['tmp_name']));
$qry = "INSERT INTO image (name,file) VALUES ('$imagename','$imagefile')";
$result = mysqli_query($con,$qry);
if($result)
echo "image has been uploaded";
viewimage();
function viewimage()
{$recon = mysqli_connect("127.0.0.1","root","","demo");
$view = "SELECT * FROM image ";
$data =mysqli_query($recon,$view);
$res2 =mysqli_fetch_assoc($data);
$currimage =$res2['file'];
echo "$currimage <br/>";
}
?>
</body>
</html>
To be able to catch a post variable, you need to submit the form and handle the action. The first problem with your code is that your form is not complete - it's missing a closing tag. Second thing, to be able to send a file through the post, you'll need multipart form. You should add enctype="multipart/form-data" as an attribute of the form.
So, instead of
<form method="post">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
You'll need
<form method="post" enctype="multipart/form-data">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
</form>
you must move the uploaded image to server
try this code -- create directory /uploads/
<!doctype html>
<html>
<head>
</head>
<body>
<form method="post" enctype="multipart/form-data">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
<?php
if(isset($_POST['submit']))
echo "button has been clicked";
$con = mysqli_connect("127.0.0.1","root","","demo");
if(!$con)
echo "didnt connect to database ";
else echo "connected";
$uploads_dir = '/uploads';
$tmp_name = $_FILES["image"]["tmp_name"];
$name = $_FILES["image"]["name"];
move_uploaded_file($tmp_name, "$uploads_dir/$name");
$qry = "INSERT INTO image (name,file) VALUES ('$name','$tmp_name')";
$result = mysqli_query($con,$qry);
if($result)
echo "image has been uploaded";
viewimage();
function viewimage()
{$recon = mysqli_connect("127.0.0.1","root","","demo");
$view = "SELECT * FROM image ";
$data =mysqli_query($recon,$view);
$res2 =mysqli_fetch_assoc($data);
$currimage =$res2['file'];
echo '<img src="'.$currimage.'" /> <br/>';
}
?>
</body>
</html>
Related
I am trying to create a folder with user given name and to upload the selected files into that folder, but I am only able to create the folder and not able to move the uploaded files into that folder. Please help me.
<html>
<head>
<title>File upload</title>
</head>
<body>
<form action="#" method="post" enctype="multipart/form-data">
<input type="file" name="file">
<br>
<label>Enter the folder name:</label>
<input type="text" name="foldername">
<br>
<input type="submit" name="submit" value="Upload">
</form>
</body>
</html>
<?php
if(isset($_POST['submit']))
{
$foldername=$_POST['foldername'];
$filename=$_FILES['file']['name'];
$tmpname=$_FILES['file']['tmp_name'];
$result=mkdir($foldername);
if($result)
{
echo "created folder";
}
else
{
echo "not created folder";
}
$row=move_uploaded_file($tmpname,"$result/$filename");
if($row)
{
echo "succesffully uploaded";
}
else
{
echo "failed to upload";
}
}
?>
You have this:
$result = mkdir($foldername);
And when you try to move the files you do this:
$row = move_uploaded_file($tmpname,"$result/$filename");
$result will be a boolean based on the success or failure of mkdir. I think what you need is this:
$row = move_uploaded_file($tmpname, "$foldername/$filename");
Just made few changes to your code. mkdir() needs the foldername and permission to create. Then in the move_uploaded_file function i changed your $ result to $foldername i.e the created folder
<html>
<head>
<title>File upload</title>
</head>
<body>
<form action="#" method="post" enctype="multipart/form-data">
<input type="file" name="file">
<br>
<label>Enter the folder name:</label>
<input type="text" name="foldername">
<br>
<input type="submit" name="submit" value="Upload">
</form>
</body>
</html>
<?php
if(isset($_POST['submit']))
{
$foldername=$_POST['foldername'];
$filename=$_FILES['file']['name'];
$tmpname=$_FILES['file']['tmp_name'];
$result = mkdir($foldername,0777);
if($result)
{
echo "created folder";
}
else
{
echo "not created folder";
}
$row=move_uploaded_file($tmpname,"$foldername/$filename");
if($row)
{
echo "succesffully uploaded";
}
else
{
echo "failed to upload";
}
}
?>
I try upload image to mysql database and display it along with the description of image using php. After i upload the image and display it , a broken image was displayed but the description of the image was displayed without any error. How can I solve this problem ? Appreciate your help
<?php
$msg = "";
//if upload button is pressed
if(isset($_POST['upload']))
{
// the path to store the uploaded image
$target = "images/".basename($_FILES['image']['name']);
// connect to database
$db = mysqli_connect("localhost","root","","product");
// Get all the submitted data from the form
$image = $_FILES['image']['name'];
$text = $_POST['text'];
$sql = "INSERT INTO product_list (image, text) VALUES ('$image','$text')";
mysqli_query($db,$sql); // stores the submitted data into the database table : product_list
// move uploaded image to the folder : image
if (move_uploaded_file($_FILES['image']['tmp_name'],$target))
{
$msg = "Image and text uploaded successfully";
}else
{
$msg = "There was a problem uploading image";
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Image Upload With Description</title>
<link rel="stylesheet" type="text/css" href="formstyle.css">
</head>
<body>
<div id="content">
<?php
$db = mysqli_connect("localhost","root","","product");
$sql = "SELECT * FROM product_list";
$result = mysqli_query($db, $sql);
while ($row = mysqli_fetch_array($result))
{
echo "<div id='img_div'>";
echo "<img src='".$row['image']."'>";
echo "<p>".$row['text']."</p>";
echo "</div>";
}
?>
<form method="post" action="try.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="1000000">
<div>
<input type="file" name="image">
</div>
<div>
<textarea name="text" cols="40" rows="4" placeholder="Details of product"></textarea>
</div>
<div>
<input type="submit" name="upload" value="Upload Image">
</div>
</form>
</div>
</body>
</html>
This is my result :
You are storing it in the DB without the images directory. You either need to store it with that, or always remember to call it that way in your image calls.
echo "<img src='images/".$row['image']."'>";
or make your the record you are writing the same as the filesystem location.
$image = 'images/' . $_FILES['image']['name'];
Note you are open to SQL injections and file inclusion injections with this code.
try this
<?php
$msg = "";
//if upload button is pressed
if(isset($_POST['upload']))
{
// the path to store the uploaded image
$destination_path = getcwd().DIRECTORY_SEPARATOR;
$target_path = $destination_path . basename( $_FILES["image"]["name"]);
// connect to database
$db = mysqli_connect("localhost","root","","product");
// Get all the submitted data from the form
$image = $_FILES['image']['name'];
$text = $_POST['text'];
$sql = "INSERT INTO product_list (image, text) VALUES ('$image','$text')";
mysqli_query($db,$sql); // stores the submitted data into the database table : product_list
//#move_uploaded_file($_FILES['image']['tmp_name'], $target_path)
// move uploaded image to the folder : image
if (move_uploaded_file($_FILES['image']['tmp_name'],$target_path))
{
$msg = "Image and text uploaded successfully";
}else
{
$msg = "There was a problem uploading image";
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Image Upload With Description</title>
<link rel="stylesheet" type="text/css" href="formstyle.css">
</head>
<body>
<div id="content">
<?php
$db = mysqli_connect("localhost","root","","product");
$sql = "SELECT * FROM product_list";
$result = mysqli_query($db, $sql);
while ($row = mysqli_fetch_array($result))
{
echo "<div id='img_div'>";
echo "<img src='".$row['image']."'>";
echo "<p>".$row['text']."</p>";
echo "</div>";
}
?>
<form method="post" action="index.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="1000000">
<div>
<input type="file" name="image">
</div>
<div>
<textarea name="text" cols="40" rows="4" placeholder="Details of product"></textarea>
</div>
<div>
<input type="submit" name="upload" value="Upload Image">
</div>
</form>
</div>
</body>
</html>
I'm trying to upload a file in php and unable to do it. The file I'm trying to upload is a csv file, but it should not be a concern. I'm using php to upload my file. I'm also trying to process the form in the same page. Below is my code for file upload and it is not working...
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])) {
if(isset($_POST['csv_file'])) {
echo "<p>".$_POST['csv_file']." => file input successfull</p>";
fileUpload();
}
}
function fileUpload () {
$target_dir = "var/import/";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir.$file_name)) {
echo "<h1>File Upload Success</h1>";
}
else {
echo "<h1>File Upload not successfull</h1>";
}
}
?>
update your form code with enctype attribute
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype = "multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
use enctype="multipart/form-data"
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
I have try below code and it's work perfect.
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if (isset($_POST['submit'])) {
echo "<p>" . $_POST['csv_file'] . " => file input successfull</p>";
$target_dir = "images ";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir . $file_name)) {
echo "<h1>File Upload Success</h1>";
} else {
echo "<h1>File Upload not successfull</h1>";
}
}
?>
</body>
</html>
It should be something like this
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])) {
if ($_FILES['csv_file']['size'] > 0)
{
echo "<p>".$_FILES['csv_file']['name']." => file input successfull</p>";
fileUpload();
}
}
function fileUpload () {
$target_dir = "var/import/";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir.$file_name)) {
echo "<h1>File Upload Success</h1>";
}
else {
echo "<h1>File Upload not successfull</h1>";
}
}
?>
</body>
Below are the changes you need to make
Add enctype = "multipart/form-data" in form tag as new attribute
Change from this if(isset($_POST['csv_file'])) { to this if($_FILES['csv_file']['size'] > 0) { as you need to check size
whether its uploaded or not
Change from this echo "<p>".$_POST['csv_file']." => file input
successfull</p>"; to this echo "<p>".$_FILES['csv_file']['name']."
=> file input successfull</p>"; as you need to use $_FILES to get file name instead of $_POST
Last but not the least, complete </body> tag if you have not yet.
Upload code in PHP[without checking its extension]
<?php
if(isset($_POST['save'])){
$path="var/import/";
$name = $_FILES['csv_file']['name'];//Name of the File
$temp = $_FILES['csv_file']['tmp_name'];
if(move_uploaded_file($temp, $path . $name)){
echo "success";
}else{
echo "failed";
}
}
?>
<form method="post" action="" enctype="multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="save" value="submit">
</form>
First Give permission to folder where you going to upload Ex: "var/import/" folder.
<!DOCTYPE html>
<html>
<head>
<title>File Upload</title>
</head>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST" enctype= "multipart/form-data">
<input type="file" name="csv_file">
<input type="submit" name="submit">
</form>
<?php
if(isset($_POST['submit'])) {
if(isset($_FILES['csv_file']) && $_FILES['csv_file']['size'] > 0) {
echo "<p>".$_FILES['csv_file']['name']." => file input successfull</p>";
fileUpload();
}
}
function fileUpload () {
$target_dir = "var/import/";
$file_name = $_FILES['csv_file']['name'];
$file_tmp = $_FILES['csv_file']['tmp_name'];
if (move_uploaded_file($file_tmp, $target_dir.$file_name)) {
echo "<h1>File Upload Success</h1>";
}
else {
echo "<h1>File Upload not successfull</h1>";
}
}
for uploading files, the trick is enctype="multipart/form-data"
use this form definition
I have checked out other questions of same topic on this site and tried to find the solution but unsuccessful. Images are stored in database and loaded in folder successfully but are not displayed
Here is my code:
<html>
<body>
<form action="image.php" method="post" enctype="multipart/form-data">
<input type="text" name="image_description" placeholder="Enter name" required>
<input type="file" name="myfile">
<input type="submit" name="upload" value="upload">
</form>
</body>
</html>
<?php
include("db.php");
if(isset($_POST['upload'])) {
$image_description = $_POST['image_description'];
$name = $_FILES["myfile"]["name"];
$type = $_FILES["myfile"]["type"];
$size = $_FILES["myfile"]["size"];
$temp = $_FILES["myfile"]["tmp_name"];
$error = $_FILES["myfile"]["error"];
$upload=move_uploaded_file($temp, "uploaded/" . $name);
$query= "INSERT INTO image(image_description,image_name,image_type,image_size) VALUES ('$image_description','$name','$type','$size')";
if(mysqli_query($conn,$query) && $upload) {
echo "successfully uploaded";
}
else
die(mysqli_error($conn));
}
$query = mysqli_query($conn,"SELECT * FROM image");
while($row = mysqli_fetch_array($query))
{?>
<img style="width: 200px;height: 200px;" src="<?php echo 'uploaded/' .$row['image_name'] ?>">
<?php
echo $row['image_description'] . "<br>";
}?>
Images are displayed as in picture
This is database table
The URL of your page is index.php/; notice the trailing slash.
A relative URL (e.g. src="uploaded/..") will resolve to index.php/uploaded/...
That folder obviously does not exist on your disk.
Use root-relative URLs: src="/uploaded/.."
or use relative URLs but go to the right folder: src="../uploaded/.."
or fix your weird URL and make it index.php, from which even relative URLs will resolve correctly.
I'm stuck with a simple php code, which must move a uploaded file from tmp to a desired location. Please find my code below. I'm not sure where i'm going wrong.
Any help is appreciated.
php code:
<?php
define("UPLOAD_DIR", "/srv/www/wordpress/mywebpage/uploads/");
$scr = $_FILES["jb_cv"]["tmp_name"];
$desttmp = $_FILES["jb_cv"]["name"];
$dest = UPLOAD_DIR .$desttmp;
echo " source file : ";
echo $scr."\t";
echo " destination file : ";
echo $dest;
$success = move_uploaded_file($scr,$dest);
if (!$success) {
echo "<p>Unable to save file.</p>";
exit;
}
?>
HTML code:
<html>
<head>
<title>Form</title>
</head>
<body>
<h1>Enter your name</h1>
<form method="post" action="move.php" id="contactform" name="contactform" enctype="multipart/form-data">
<label> Upload your CV</label> <input name="jb_cv" type="file" />
<input type="submit" value="SUBMIT" />
</form>
</body>
</html