I try upload image to mysql database and display it along with the description of image using php. After i upload the image and display it , a broken image was displayed but the description of the image was displayed without any error. How can I solve this problem ? Appreciate your help
<?php
$msg = "";
//if upload button is pressed
if(isset($_POST['upload']))
{
// the path to store the uploaded image
$target = "images/".basename($_FILES['image']['name']);
// connect to database
$db = mysqli_connect("localhost","root","","product");
// Get all the submitted data from the form
$image = $_FILES['image']['name'];
$text = $_POST['text'];
$sql = "INSERT INTO product_list (image, text) VALUES ('$image','$text')";
mysqli_query($db,$sql); // stores the submitted data into the database table : product_list
// move uploaded image to the folder : image
if (move_uploaded_file($_FILES['image']['tmp_name'],$target))
{
$msg = "Image and text uploaded successfully";
}else
{
$msg = "There was a problem uploading image";
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Image Upload With Description</title>
<link rel="stylesheet" type="text/css" href="formstyle.css">
</head>
<body>
<div id="content">
<?php
$db = mysqli_connect("localhost","root","","product");
$sql = "SELECT * FROM product_list";
$result = mysqli_query($db, $sql);
while ($row = mysqli_fetch_array($result))
{
echo "<div id='img_div'>";
echo "<img src='".$row['image']."'>";
echo "<p>".$row['text']."</p>";
echo "</div>";
}
?>
<form method="post" action="try.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="1000000">
<div>
<input type="file" name="image">
</div>
<div>
<textarea name="text" cols="40" rows="4" placeholder="Details of product"></textarea>
</div>
<div>
<input type="submit" name="upload" value="Upload Image">
</div>
</form>
</div>
</body>
</html>
This is my result :
You are storing it in the DB without the images directory. You either need to store it with that, or always remember to call it that way in your image calls.
echo "<img src='images/".$row['image']."'>";
or make your the record you are writing the same as the filesystem location.
$image = 'images/' . $_FILES['image']['name'];
Note you are open to SQL injections and file inclusion injections with this code.
try this
<?php
$msg = "";
//if upload button is pressed
if(isset($_POST['upload']))
{
// the path to store the uploaded image
$destination_path = getcwd().DIRECTORY_SEPARATOR;
$target_path = $destination_path . basename( $_FILES["image"]["name"]);
// connect to database
$db = mysqli_connect("localhost","root","","product");
// Get all the submitted data from the form
$image = $_FILES['image']['name'];
$text = $_POST['text'];
$sql = "INSERT INTO product_list (image, text) VALUES ('$image','$text')";
mysqli_query($db,$sql); // stores the submitted data into the database table : product_list
//#move_uploaded_file($_FILES['image']['tmp_name'], $target_path)
// move uploaded image to the folder : image
if (move_uploaded_file($_FILES['image']['tmp_name'],$target_path))
{
$msg = "Image and text uploaded successfully";
}else
{
$msg = "There was a problem uploading image";
}
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Image Upload With Description</title>
<link rel="stylesheet" type="text/css" href="formstyle.css">
</head>
<body>
<div id="content">
<?php
$db = mysqli_connect("localhost","root","","product");
$sql = "SELECT * FROM product_list";
$result = mysqli_query($db, $sql);
while ($row = mysqli_fetch_array($result))
{
echo "<div id='img_div'>";
echo "<img src='".$row['image']."'>";
echo "<p>".$row['text']."</p>";
echo "</div>";
}
?>
<form method="post" action="index.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="1000000">
<div>
<input type="file" name="image">
</div>
<div>
<textarea name="text" cols="40" rows="4" placeholder="Details of product"></textarea>
</div>
<div>
<input type="submit" name="upload" value="Upload Image">
</div>
</form>
</div>
</body>
</html>
Related
Im currently in the process of creating a simple PHP website which can display a list of NBA teams and the respective players. One of the things I'm currently working on right now is adding the ability to upload images from the page itself instead of going to PHPMyAdmin.
Here's what the page looks like right now:
I'm trying to figure out how to add the team logo the same way I can add a new team name. As you can see in the bottom part there is an Add Team option which allows the user to add a new team and that team will be registered in the database.
I've tried to write some PHP code which enables the process of uploading images but have failed to do so.
team_list.php
<?php
error_reporting(0);
require_once('../Model/database.php');
// Get all categories
$query = 'SELECT * FROM categories
ORDER BY categoryID';
$statement = $db->prepare($query);
$statement->execute();
$teams = $statement->fetchAll();
$statement->closeCursor();
// Initialize message variable
$msg = "";
// If upload button is clicked ...
if (isset($_POST['upload'])) {
// Get image name
$image = $_FILES['image'];
// image file directory
$target = "images/".basename($image);
$sql = "INSERT INTO categories (img) VALUES ('$image')";
// execute query
mysqli_query($db, $sql);
if (move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
$msg = "Image uploaded successfully";
}else{
$msg = "Failed to upload image";
}
}
$result = mysqli_query($db, "SELECT * FROM categories");
?>
<!DOCTYPE html>
<html>
<!-- the head section -->
<head>
<title>NBA</title>
<link rel="stylesheet" type="text/css" href="../css/index.css">
<link rel="shortcut icon" type="image/png" href="images/favicon.ico"/>
</head>
<!-- the body section -->
<body>
<main>
<h1 id="addCategoryh1">Teams</h1>
<table id="categoryListTable">
<tr>
<th>Name</th>
<th> </th>
</tr>
<?php foreach ($teams as $team) : ?>
<tr>
<td><?php echo $team['categoryName']; ?></td>
<td>
<form action="delete_team.php" method="post"
id="delete_product_form">
<input type="hidden" name="team_id"
value="<?php echo $team['categoryID']; ?>">
<input id="deleteCategoryList" type="submit" value="Delete">
</form>
</td>
</tr>
<?php endforeach; ?>
</table>
<br>
<?php
while ($row = mysqli_fetch_array($result)) {
echo "<div id='img_div'>";
echo "<img src='images/".$row['image']."' >";
echo "<p>".$row['image_text']."</p>";
echo "</div>";
}
?>
<h2 id="add_category_h2">Add Team</h2>
<form action="add_team.php" method="post"
id="add_category_form">
<label>Name:</label>
<input type="input" name="name">
<input id="add_category_button" type="submit" value="Add">
</form>
<form method="POST" action="team_list.php" enctype="multipart/form-data">
<input type="hidden" name="size" value="1000000">
<div>
<input type="file" name="image">
</div>
<div>
<button type="submit" name="upload">POST</button>
</div>
</form>
<br>
<p>View Team List</p>
</main>
<footer id="categoryListFooter">
<p>© <?php echo date("Y"); ?> NBA</p>
</footer>
</body>
</html>
And this is the add_team.php file, which gets the data from database
<?php
// Get the team data
$name = filter_input(INPUT_POST, 'name');
// Validate inputs
if ($name == null) {
$error = "Invalid team data. Check all fields and try again.";
include('../Error/error.php');
} else {
require_once('../Model/database.php');
// Add the product to the database
$query = 'INSERT INTO categories (categoryName)
VALUES (:team_name)';
$query = "INSERT INTO categories (image) VALUES ('$fileName', '$content')";
$statement = $db->prepare($query);
$statement->bindValue(':team_name', $name);
$statement->execute();
$statement->closeCursor();
// Display the team List page
include('team_list.php');
}
?>
This is how the standing.php page looks like
updated add_team.php
// Get the team data
$name = filter_input(INPUT_POST, 'name');
// Validate inputs
if ($name == null) {
$error = "Invalid team data. Check all fields and try again.";
include('../Error/error.php');
} else {
require_once('../Model/database.php');
// Add the product to the database
$query = 'INSERT INTO categories (categoryName)
VALUES (:team_name)';
$query = "INSERT INTO categories (image) VALUES ('$fileName', '$content')";
$statement = $db->prepare($query);
$statement->bindValue(':team_name', $name);
$statement->execute();
$statement->closeCursor();
// Display the team List page
include('team_list.php');
// This is the directory where images will be saved
$target = "../images/";
$target = $target . basename( $_FILES['image']['name']);
// This gets all the other information from the form
$filename = basename( $_FILES['image']['name']);
$team_name = $_POST['team_name'];
// Write the file name to the server
if(move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
//Tells you if its all ok
echo "The file ". basename( $_FILES['image']['name']). " has been uploaded, and your information has been added to the directory";
// Connects to your Database
mysql_connect("renwid", "password") or die(mysql_error()) ;
mysql_select_db("nba") or die(mysql_error()) ;
//Writes the information to the database
mysql_query("INSERT INTO categories (img, team_name)
VALUES ('$filename', '$team_name')") ;
} else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
}
?>
You have to first upload successfully to the folder then you can add record in to your database
<?php
if(isset($_POST['submit'])) {
// This is the directory where images will be saved
$target = "images/";
$target = $target . basename( $_FILES['image']['name']);
// This gets all the other information from the form
$filename = basename( $_FILES['image']['name']);
$team_name = $_POST['team_name'];
// Write the file name to the server
if(move_uploaded_file($_FILES['image']['tmp_name'], $target)) {
//Tells you if its all ok
echo "The file ". basename( $_FILES['image']['name']). " has been uploaded, and your information has been added to the directory";
// Connects to your Database
// mysql_connect("localhost", "root", "") or die(mysql_error()) ;
// mysql_select_db("your_db") or die(mysql_error()) ;
//Writes the information to the database
// mysql_query("INSERT INTO picture (image, team_name)
// VALUES ('$filename', '$team_name')") ;
} else {
//Gives and error if its not
echo "Sorry, there was a problem uploading your file.";
}
}
?>
Your HTML should be
<form action="" method="post" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="image" id="image">
<input type="text" name="team_name" id="team_name">
<input type="submit" value="Submit" name="submit">
</form>
Refer https://github.com/aslamanver/nbaTest
You should create a uniqid when uploading the image, this way depending on how many people will upload images, if one were to upload the same image as another, it wouldn't be overwritten in the database
You can do this by using the explode and end function in PHP, also look into prepared statements when using SQL statements, this is to protect your DB against SQL injections, here's a good link:
https://www.w3schools.com/php/php_mysql_prepared_statements.asp
The $_FILES has a few attributes including $_FILES["name"]["error"] which checks for errors, ideally you would make an if statement in which you specify the error condition for the file to uploaded to your DB. Also remember that you must first specify the directory before inserting it into your DB and if the file containing the code is in another folder, you use ../ to go back a directory.
When you display the image on your site you use this:
<img src="directory/<?php echo $row["row"]; ?>">
I am trying to upload a pdf file and an image in php mysql but it seems that the move_uploaded_file function can only work with one file. I have tried to make it work with both files but it doesn't seem to me working. It moves just the images to the target folder and adds both image name and pdf name to the database but it doesn't move the pdf to target folder. This is the code. pls help
<?php
session_start();
require_once("includedfunctions.php");
include 'dbh.php';
if (isset($_POST['submit'])){
$title=$_POST['title'];
$author=$_POST['author'];
$target = "img/pic_book/";
$target2 = "img/pdf/";
$imgname = basename($_FILES["cphoto"]["name"]);
$bookname = basename($_FILES["book"]["name"]);
$newname = $target.basename($_FILES["cphoto"]["name"]);
$newname2 = $target2.basename($_FILES["book"]["name"]);
$img_type = pathinfo($newname,PATHINFO_EXTENSION);
$book_type = pathinfo($newname2,PATHINFO_EXTENSION);
if($img_type!='jpg' && $img_type!='JPG' && $img_type!='png' && $img_type!='PNG'){
$message="Please ensure you are entering an image";
}else{
if($book_type != 'pdf'){
$message="books must be uploaded in pdf format";
}else{
if(!preg_match("/^[a-zA-Z'-]+$/",$author)){
$message = "<p style='color:red'>Please enter the real name of the author; not a nickname.</p>";
}else{
if (move_uploaded_file($_FILES["cphoto"]["tmp_name"], $newname)) {
if(move_uploaded_file($_FILES["book"]["tmp_name"], $newname2));{
$sql = "INSERT INTO books (Title, Author, pathtopdf, pathtoimage) VALUES ('$title', '$author', '$bookname', '$imgname')";
$result = mysqli_query($conn, $sql);
if($result){
$message = "upload successful";
}else{
$message = "upload failed1";
}
}
}else{
$message = "upload failed";
}
}
}
}
}
else{
$message="";
$title="";
}
?>
<html>
<head>
<title>Libraria</title>
<link href="css/bootstrap.min.css" rel="stylesheet">
<link href="css/contactcss.css" rel="stylesheet">
<script src="js/respond.js"></script>
</head>
<body>
<br><br><br><br><br>
<!-- content -->
<div class="container">
<?php
echo '<p>Welcome ' . $_SESSION['name']. '</p><br>';
echo '<p>' . $message. ' </p>';
?>
<br><br>
<!--form-->
<div class="row">
<form action="admin2.php" method = "post" enctype="multipart/form-data">
<label for="Title">Title</label><br>
<input type="text" id="fname" value ="<?php echo $title; ?>" name="title" placeholder="Title of the book" required><br>
<label for="author">Author</label><br>
<input type="text" id="lname" name="author" placeholder="Author of the book" required><br>
<label for="Cover photo">Cover photo</label><br>
<input type="file" id="cphoto" name="cphoto" required><br>
<label for="book">Book</label>
<input type="file" id="book" name="book" required><br>
<button class="submit" type="submit" name="submit"><b>Upload</b></button>
</form>
</div>
</div>
</body>
</html>
Code is all correct. just check pdf size. if size is more than 4MB than it will not allowed to upload. you need to increase upload file size in php.ini file or apache config settting file.
Have a great day :)
application/pdf is the mime type for pdf not just pdf.
Still a newb to coding . have almost no idea what im doing . i tried to make a php page which would let me upload and view an image . do not know what is wrong . i tried to do it as correctly as possible . could someone please help me out ?
<!doctype html>
<html>
<head>
</head>
<body>
<form method="post">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
<?php
if(isset($_POST['submit']))
echo "button has been clicked";
$con = mysqli_connect("127.0.0.1","root","","demo");
if(!$con)
echo "didnt connect to database ";
else echo "connected ";
$imagename= mysqli_real_escape_string($_FILES['image'] ['name']);
$imagefile =mysqli_real_escape_string(file_get_contents($_FILES['image']['tmp_name']));
$qry = "INSERT INTO image (name,file) VALUES ('$imagename','$imagefile')";
$result = mysqli_query($con,$qry);
if($result)
echo "image has been uploaded";
viewimage();
function viewimage()
{$recon = mysqli_connect("127.0.0.1","root","","demo");
$view = "SELECT * FROM image ";
$data =mysqli_query($recon,$view);
$res2 =mysqli_fetch_assoc($data);
$currimage =$res2['file'];
echo "$currimage <br/>";
}
?>
</body>
</html>
To be able to catch a post variable, you need to submit the form and handle the action. The first problem with your code is that your form is not complete - it's missing a closing tag. Second thing, to be able to send a file through the post, you'll need multipart form. You should add enctype="multipart/form-data" as an attribute of the form.
So, instead of
<form method="post">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
You'll need
<form method="post" enctype="multipart/form-data">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
</form>
you must move the uploaded image to server
try this code -- create directory /uploads/
<!doctype html>
<html>
<head>
</head>
<body>
<form method="post" enctype="multipart/form-data">
<input type="file" name="image"></input>
<input type="submit" name="submit" value="upload"></input>
<?php
if(isset($_POST['submit']))
echo "button has been clicked";
$con = mysqli_connect("127.0.0.1","root","","demo");
if(!$con)
echo "didnt connect to database ";
else echo "connected";
$uploads_dir = '/uploads';
$tmp_name = $_FILES["image"]["tmp_name"];
$name = $_FILES["image"]["name"];
move_uploaded_file($tmp_name, "$uploads_dir/$name");
$qry = "INSERT INTO image (name,file) VALUES ('$name','$tmp_name')";
$result = mysqli_query($con,$qry);
if($result)
echo "image has been uploaded";
viewimage();
function viewimage()
{$recon = mysqli_connect("127.0.0.1","root","","demo");
$view = "SELECT * FROM image ";
$data =mysqli_query($recon,$view);
$res2 =mysqli_fetch_assoc($data);
$currimage =$res2['file'];
echo '<img src="'.$currimage.'" /> <br/>';
}
?>
</body>
</html>
I am making a gallery that uses a MySQL database (yeah I know it's a bad practice but it's the requirement for the moment.) I can upload multiple images but I'm having trouble displaying all images stored inside the database. The FORM allows five images to be uploaded. Then the user must proceed to another page where all the images in database (including the ones uploaded recently) will be displayed together with the description of the images. I have code already but the one that will work on the display is not working or I think is wrong.
Here is the form code:
<html>
<head>
<title> Upload image</title>
</head>
<body>
<div align="center">
<form action="fUpload.php" method="POST" enctype="multipart/form-data">
All forms must be filled. <br />
File: <br />
<input type="file" name="image[]"/> <input type="text" name="imageDescription[]" size="30" /> <br />
<input type="file" name="image[]"/> <input type="text" name="imageDescription[]" size="30" /> <br />
<input type="file" name="image[]"/> <input type="text" name="imageDescription[]" size="30" /> <br />
<input type="file" name="image[]"/> <input type="text" name="imageDescription[]" size="30" /> <br />
<input type="file" name="image[]"/> <input type="text" name="imageDescription[]" size="30" /> <br />
<input type="submit" value="Upload image" />
</form>
</div>
</body>
</html>
Here is the script that would upload:
<?php
//connect to the database//
$con = mysql_connect("localhost","root", "");
if(!$con)
{
die('Could not connect to the database:' . mysql_error());
echo "ERROR IN CONNECTION";
}
$sel = mysql_select_db("imagedatabase");
if(!$sel)
{
die('Could not connect to the database:' . mysql_error());
echo "ERROR IN CONNECTION";
}
//file properties//
$file = $_FILES['image']['tmp_name'];
echo '<br />';
/*if(!isset($file))
echo "Please select your images";
else
{
*/for($count = 0; $count < count($_FILES['image']); $count++)
{
//$image = file_get_contents($_FILES['image']['tmp_name']);
$image_desc[$count] = addslashes($_POST['imageDescription'][$count]);
$image_name[$count] = addslashes($_FILES['image]']['name'][$count]); echo '<br \>';
$image_size[$count] = #getimagesize($_FILES['image']['tmp_name'][$count]);
$error[$count] = $_FILES['image']['error'][$count];
if($image_size[$count] === FALSE || ($image_size[$count]) == 0)
echo "That's not an image";
else
{
// Temporary file name stored on the server
$tmpName[$count] = $_FILES['image']['tmp_name'][$count];
// Read the file
$fp[$count] = fopen($tmpName[$count], 'r');
$data[$count] = fread($fp[$count], filesize($tmpName[$count]));
$data[$count] = addslashes($data[$count]);
fclose($fp[$count]);
// Create the query and insert
// into our database.
$results = mysql_query("INSERT INTO images( description, image) VALUES ('$image_desc[$count]','$data[$count]')", $con);
if(!$results)
echo "Problem uploding the image. Please check your database";
//else
//{
echo "";
//$last_id = mysql_insert_id();
//echo "Image Uploaded. <p /> <p /><img src=display.php? id=$last_id>";
//header('Lcation: display2.php?id=$last_id');
}
//}
}
mysql_close($con);
header('Location: fGallery.php');
?>
And finally the one that should display:
<html>
<body>
</body>
<?php
//connect to the database//
mysql_connect("localhost","root", "") or die(mysql_error());
mysql_select_db("imagedatabase") or die(mysql_error());
//requesting image id
$id = addslashes($_REQUEST['id']);
$image = mysql_query("SELECT * FROM images WHERE id = $id");
while($datum = mysql_fetch_array($image, MYSQL_ASSOC))
{
printf("Description %s $image = $image['image'];
header("Content-type: image/jpeg");
}
mysql_close();
?>
Your help is much appreciated. I need it badly to move on.
From what i understand from your post is that uploading and storing isn't a problem, but showing the images is. That's probably because you're using vars that are not set, so no results kan be found in the database. If i misunderstood let me know.
<?php
// No ID
$image = mysql_query("SELECT * FROM images ORDER BY id DESC");
?>
Also look at what Prof83 says. Ignore my post if your script works with just one image.
Last but not least, if you're using different filetypes, also echo the correct MIME format in the header.
Update
I combined both answers.
Edit your loop:
<?php
while($row = mysql_fetch_assoc($image))
{
echo '<img src="img.php?id='.$row["id"].'">';
}
?>
Create a page name img.php
<?php
$query = mysql_query("SELECT image FROM images WHERE id = ".$_GET['id']);
$row = mysql_fetch_assoc($query);
header("Content-type: image/jpeg");
echo $row['image'];
?>
Ok you can't display multiple images within a image/jpeg page...
You're telling the browser that the page is image/jpeg (in other words, the page is AN IMAGE) but you're echoing out multiple image data
You should rather use the gallery page to show all images like this:
<?php
// $images = result from database of all image rows
foreach ($images as $img) echo '<img src="img.php?id='.$img["id"].'">';
?>
and in img.php:
// Load the image data for id in $_GET['id'];
header("Content-type: image/jpeg");
echo $data;
i have this page for upload:
<?php
require ('incs/db.php');
require_once ('incs/funcs.php');
?>
<?php
if (array_key_exists('upload', $_POST)) {
$directory = str_replace(basename($_SERVER['PHP_SELF']),'',$_SERVER['PHP_SELF']);
$uploadHandler = $_SERVER['DOCUMENT_ROOT']. $directory . 'images/';
// $uploadHandler = "echtitipi".$_SERVER['HTTP_HOST']. '/images/';
$max_file_size = 30000;
define('UPLOAD_DIR', $uploadHandler);
$ext= end(explode(".", $_FILES['image']['name']));
$name = rand(1111111,9999999).'.'.$ext;
if (move_uploaded_file($_FILES['image']['tmp_name'], $uploadHandler. $name))
{
$upload = true;
$title = $_POST ['title'];
$sql = "INSERT INTO photo (id, keyword, photoName)
VALUES ('','$title','$name')
";
$result = mysql_query ( $sql, $con );
}
else
{
$upload = false;
$msg = 'Cant Upload!';
}
}
?>
<?php
include ('incs/header.php');
?>
<?php
getUrlQuery();
?>
<script language="javascript">
<!--
function pick(symbol, path) {
if (window.opener && !window.opener.closed)
window.opener.document.form.img.value = symbol;
window.opener.document.form.imgbox.src = path;
window.close();
}
// -->
</script>
<form action="upload.php" method="post" enctype="multipart/form-data" name="uploadImage" id="uploadImage">
<p>
<label for="image">
Tanım:
</label>
<input type="text" name="title" id="title" />
<label for="image">
Upload image:
</label>
<input type="file" name="image" id="image" />
</p>
<p>
<input type="submit" name="upload" id="upload" value="Upload" />
</p>
</form>
<?php
if($upload == true)
{
echo "<a hrf(because spam!)=\"javascript:pick('$name','images/$name')\"><im(g) src=\"images/$name\" border=\"0\" alt=\"use\"></a>";
}
?>
<?php
include ('incs/footer.php');
?>
`
this upload image to curretnt root's images folder. My current folder is admin:
root/admin/images
root/images
when i use
$uploadHandler = "http://".$_SERVER['HTTP_HOST']. '/images/';
script doesnot work.
<?php
if($upload == true)
{
echo "<a hrf=\"javascriptick('$name','{$uploadHandler}$name')\"><im(g) src=\"{$uploadHandler}$name\" border=\"0\" alt=\"use\"></a>";
}
?>
the image couldnot add to editor. I guess There is a problem with javascript.
what is wrong in script
echo "<a hrf=\"javascriptick('$name','{$uploadHandler}$name')\"><im(g) src=\"{$uploadHandler}$name\" border=\"0\" alt=\"use\"></a>";
change into
echo "<img src=\"{$uploadHandler}$name\" border=\"0\" alt=\"use\">";
I guess this will help...
Im sorry for bad dictation because i cant write the right script because sending errors(link and images)
above code uploaded code to
/www/admin/images
and save information to database and add image to tinymce editor. But I want to upload code to:
www/images
when I use :
$uploadHandler = $_SERVER['DOCUMENT_ROOT'].'/images/';
and
"<img src=\"images/$name\" border=\"0\" alt=\"use\">"
the image couldnot add to editor. This is my problem.