PHP - prepared statements result as an object [duplicate] - php

Question

This question already has answers here:
Is it possible to use mysqli_fetch_object with a prepared statement
(3 answers)
Closed 6 years ago.
So, I have the following function:
private function getUserData($user_nickname)
{
if ($this->databaseConnection()) {
$stmt1=$this->dbh->prepare('SELECT * FROM users WHERE nickname = ?');
$stmt1->bind_param('s', $user_nickname);
$stmt1->execute();
return $stmt1->fetch_object();
}
else {
return false;
}
}
And I get the following error: Fatal error: Uncaught Error: Call to undefined method mysqli_stmt::fetch_object()
I did a little research and I didn't find any fetch object in mysqli_stmt
http://php.net/manual/en/class.mysqli-stmt.php
Does it means that if I use prepared statements, I can't use result as an object? I really want it to work as an object.
P.S. I use mysqli.

Answer 1

Mysqli is not a very usable API.
You can try to use get_result() but it could be unavailable on your system.
Let me suggest you to use PDO instead of mysqli:
private function getUserData($user_nickname)
{
$stmt = $this->dbh->prepare('SELECT * FROM users WHERE nickname = ?');
$stmt->execute([$user_nickname]);
return $stmt->fetch(PDO::FETCH_OBJ);
}
Among other benefits over mysqli, PDO can return not only an anonymous stdObject but can create an instance of an existing class, passing parameters to constructor. Say, if you have a User class, you may write
private function getUserData($user_nickname)
{
$stmt = $this->dbh->prepare('SELECT * FROM users WHERE nickname = ?');
$stmt->execute([$user_nickname]);
return $stmt->fetchObject('User');
}