PDO prepeared statements PHP Call to undefined method PDO::execute() [duplicate] - php

This question already has an answer here:
Call to undefined method PDO::execute()
(1 answer)
Closed 5 years ago.
I am new to php mysqli ect and i have done my best to arrange a prepeared statement function to no avail. All i get is the following Error.
Call to undefined method PDO::execute()
I donnot understand why this is happening.
The values are being passed and echo'd but i still get this error.
It does not retrieve data from database either as error is called before doing so.
Can anybody see from the code what the problem is.. iv searched about on the net ect. and the closest i got what about checking the Isset of the inputs, but i had allready done this so thats not the issue.
im baffled.
Thanks for any advice... Its probly really simple. But so am i.
<?php
//include('conect.php')
$dbh = new PDO("mysql:host=localhost;dbname=classifieds", 'root', '');
$type=$_POST['type'];
$price=$_POST['price'];
if (isset($type) && isset($price)) {
echo $type;
echo $price;
$dbh->prepare('SELECT * FROM testdata WHERE type=? AND price=?');
$stm = $dbh->execute(array($type, $price));
if(($row = $stm->fetchObject())) {
$type=$row['type'];
$price=$row['price'];
echo $type;
echo $price;
} else
{ echo "none recieved"; }
} else
{echo "invalid"; }
?>

You have to assign $dbh->prepare('SELECT * FROM testdata WHERE type=? AND price=?'); to a variable and then call execute() method on it.
Example:
$smth = $dbh->prepare('SELECT * FROM testdata WHERE type=? AND price=?');
$result = $smth->execute(array($type, $price));
That's because PDO doesn't have execute method but PDOStatement object resolved from prepare method does.

Related

Unable to run query using prepared statement in MySQLi [duplicate]

This question already has an answer here:
What to do with mysqli problems? Errors like mysqli_fetch_array(): Argument #1 must be of type mysqli_result and such
(1 answer)
Closed 5 years ago.
I am working on the below code. Why am I not able to run the query properly? I already check the database connection and it is fine
<?php
$sql = "SELECT dt, events, eventtype FROM events";
$stmt = $mysqli->prepare($sql);
$stmt->execute();
$stmt->bind_result($dt,$events,$eventtype);
$stmt->store_result();
if($stmt->num_rows >0) {
$stmt->fetch();
}
else {
echo "Cant Find The data!";
}
$stmt->close();
$mysqli->close();
echo $dt;
echo $events;
echo $eventtype;
?>
getting this error
Fatal error : Call to a member function execute() on boolean in
/srv/disk1/2555378/www/domain.net/index.php on line 113
This means that the variable $mysqli contains a boolean value, probably false.
According to the php docs, http://php.net/manual/en/mysqli.prepare.php, the function mysqli::prepare will return false in case of an error.
You should use the error variable to get more information, like here: http://php.net/manual/en/mysqli.error.php

PDO prepared statement for update doesn't work properly [duplicate]

This question already has answers here:
What is the difference between bindParam and bindValue?
(7 answers)
Closed 7 years ago.
This is my php code:
public function update($table,$fields_and_values,$condition_field,$condition_field_value)
{
$query="UPDATE $table SET ";
foreach($fields_and_values as $field=>$value) $query.=($field."=:".$field." ,");
$query.=" ";
$query=str_replace(", "," WHERE ",$query);
$query.=($condition_field."='".$condition_field_value."'");
echo $query;
$stmt=$this->conn->prepare($query);
foreach($fields_and_values as $field=>$value) $stmt->bindParam(":".$field,$value);
$stmt->execute();
}
and this is how i call the function in my class:
$db=new db_connection('localhost','root','','maps');
$db->connect();
$arr=array('username'=>'testfromnewclass3','password'=>'123456');
$db->update('users',$arr,'username','term');
$db->disconnect();
It doesn't matter what the other functions like disconnect do! They work correctly.
My problem is that when this command executes, both username and password become 123456 !
And this is what i get from that echo $query:
UPDATE users SET username=:username ,password=:password WHERE username='term'
Is something wrong with my function? and if so how can i fix it?
Use $stmt->bindValue($field, $value);
instead of $stmt->bindParam(":".$field,$value);
Check this to understand difference between PDOStatement::bindParam() and PDOStatement::bindValue()

Object can't be converted to a string in MySQLi PHP [duplicate]

This question already has answers here:
Object of class mysqli_result could not be converted to string
(5 answers)
Closed 1 year ago.
Catchable fatal error: Object of class mysqli_result could not be converted to string in C:\xampp\htdocs\xxx\dash.php on line 20
I am quite fairly new, and being a old-school coder, simply using mysql_result to grab such data, I am unaware of how to go about this. I have a class->function setup.
Line 20 of dash.php contains:
echo $user->GetVar('rank', 'Liam', $mysqli);
While, the function is:
function GetVar($var, $username, $mysqli)
{
$result = $mysqli->query("SELECT " . $var . " FROM users WHERE username = '" . $username . "' LIMIT 1");
return $result;
$result->close();
}
Now, to my understanding, I am meant to convert $result into a string, but I am not fully aware of how to do so. I've tried using a few methods, but to no avail. So I've come to the community to hopefully get a answer, I've also looked around but noticed that all other threads are asking for num_rows, while I just want to grab the string from the query select.
You have to fetch it first before echoing the results. Rough Example:
function GetVar($var, $username, $mysqli) {
// make the query
$query = $mysqli->query("SELECT ".$var." FROM users WHERE username = '".$username."' LIMIT 1");
$result = $query->fetch_assoc(); // fetch it first
return $result[$var];
}
Then use your function:
echo $user->GetVar('rank', 'Liam', $mysqli);
Important Note: Since you're starting out, kindly check about prepared statements. Don't directly append user input on your query.
if ($result = $mysqli->query($query)) {
while($row = $result->fetch_object()) {
echo row['column_name'];
}
}
$result->close();
where you see 'column_name put the name of the column you want to get the string from.

mysqli_result is not working properly? [duplicate]

This question already has answers here:
Fatal error: Call to undefined function mysqli_result()
(2 answers)
Closed 8 years ago.
There is a table 'hit_count' containing only one column 'count' in database in which I am trying to count the hits by user. problem is whenever I am running this code it shows an error message "Fatal error: Call to undefined function mysqli_result()". Please help!!
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
require 'connect.inc.php';
function update_count()
{
global $link;
$query = "SELECT `count` FROM `hit_count`";
if($query_run = mysqli_query($link,$query) || die(mysqli_error($link)))
{
echo 'checking control';
$count = mysqli_result($query_run,0,'count');
echo $count;
}
else
{
echo 'Problem Occured!!';
}
}
update_count();
?>
There isn't a mysqli_result function (not that you can't define it, but what for?). There is a mysqli_result Class, and it has static methods that you can call, of course. But I believe you're doing this wrong.
The correct way would be something like
$count=array();
if($query_run = mysqli_query($link,$query) || die(mysqli_error($link))) {
while ($row = $query_run->fetch_array(MYSQLI_ASSOC)) {
$count[]=$row["count"];
}
}
remember that the outcom of mysqli_query will be an iterable object. Don't expect it to return an aggregate value by default.
PD: if you name your columns with reserved words like count, you're gonna have a bad time.

mysqli_stmt_bind_result() number of variables doesnt match? help me how to count [duplicate]

This question already has an answer here:
PHP mysqli prepare statement not working
(1 answer)
Closed 1 year ago.
I simply want to select a bunch of fields from a data base - as I have done it a lot of times before... But somehow I get this error:
Warning: mysqli_stmt_bind_result(): Number of bind variables doesn't match number of fields in prepared statement
But I count exactly 14 columns, so why when I add 14 variables does it throw this error?
public function get_invitation_fields()
{
$this->fields_db = array();
include('system/mysqli_db.php'); //db connection opens here
$statement="SELECT
invitation_ID,
recipient,
text,
name,
usr_ID,
deleted,
send_date,
resend_date,
last_date,
status,
register_date,
verify_date,
redeem_date
trans_ID
FROM invitations WHERE email=?";
if ($stmt = mysqli_prepare($db, $statement))
{
mysqli_stmt_bind_param($stmt, "s", $this->email);
if(!mysqli_stmt_execute($stmt))
{echo mysqli_stmt_error($stmt); echo mysqli_error($db); }
mysqli_stmt_bind_result($stmt,
$this->fields_db['invitation_ID'],
$this->fields_db['recipient'],
$this->fields_db['text'],
$this->fields_db['name'],
$this->fields_db['usr_ID'],
$this->fields_db['deleted'],
$this->fields_db['send_date'],
$this->fields_db['resend_date'],
$this->fields_db['last_date'],
$this->fields_db['status'],
$this->fields_db['register_date'],
$this->fields_db['verify_date'],
$this->fields_db['redeem_date'],
$this->fields_db['trans_ID']
); //PHP points the error to this line.
mysqli_stmt_fetch($stmt);
$this->invite_fields_db = $this->fields_db;
mysqli_stmt_close($stmt);
}
else
{
echo mysqli_stmt_error($stmt);
echo mysqli_error($db);
}
mysqli_close($db);
}
Can anyone see what's wrong?
Just don't use mysqli with it's bind_result, which indeed makes you ask other people to count your variables.
Either use PDO, which will make your code as short as
public function get_invitation_fields($email)
{
global $pdo; // connection should be opened ONCE at the beginning of the whole app
$sql = "SELECT * FROM invitations WHERE email=?";
$stm = $pdo->prepare($sql);
$stm->execute(array($email));
return $stm->fetch(); // values have to be RETURNED, not assigned
}
or at least use get_result() to get a familiar array from the query, without need of binding every variable manually, though it's not guaranteed to work.

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