Replace occurrence of string with image in PHP+SQL loop? - php

Question

This PHP code takes records from my database and displays them. Basically, I want every occurrence of the string "cross" (lowercase only) to be changed to an image that is on my web server.
Records currently look like: crossJohn Doe. So when it appears on the page, it should replace cross with the img and keep the rest.
The code:
$sql = "SELECT DisplayName, LastName, FirstName FROM donor WHERE DonationAmount = 1000 ORDER BY LastName ASC LIMIT 154";
$result = mysqli_query($conn, $sql); // query
if (mysqli_num_rows($result) > 0) { // as long as the query returns something, do the calcs.
$array = array(); // create a variable to hold the information
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){ // whule there are results, put them in the array
$array[] = $row; // add the row in to the results (data) array
}
$counter = (count($array)); // find the amount of items in the array
$divisorCount = ceil($counter/2); // column count
$forEachCount = 1;
//loop while there are items in the array
foreach ($array as $row){
$forEachCount++; //increment counter
// naming logic
if (empty($row['DisplayName'])) { // if there is no DisplayName
if (empty($row['FirstName'])) { // show lastname
$block[] = "<div class='block'>".$row['LastName']."</div>\n";
}
else { //show first + last if no display name
$block[] = "<div class='block'>".$row['FirstName']." ".$row['LastName']."</div>\n";
}
} else { // show display name
$block[] = "<div class='block'>".$row['DisplayName']."</div>\n";
}
if($forEachCount > $divisorCount){ //insert each record into a "block"
$forEachCount = 0;
end($block);
$key = key($block);
$block[$key] .= "</div><div class='column'>"; // insert all "blocks" into a css div
}
}
unset($row,$key,$forEachCount,$divisorCount); //cleanup
//insert the div and populate it with the blocks
$output = "<div class='tableContainer'>
<div class='column'>".implode($block)."</div>
</div>";
print_r($output); // display all of it!
unset($array,$block);
}else{echo "<p>There are no donors in this category.</p>";}

Answer 1

using the REPLACE mysql string function might be enough
$sql = "SELECT REPLACE(DisplayName,'cross','<img src=\"path/to/image\" />') AS `DisplayName`, REPLACE(LastName,'cross','<img src=\"path/to/image\" />') AS `LastName`, REPLACE(FirstName,'cross','<img src=\"path/to/image\" />') AS `FirstName` FROM donor WHERE DonationAmount = 1000 ORDER BY LastName ASC LIMIT 154";
-- http://dev.mysql.com/doc/refman/5.7/en/string-functions.html#function_replace

Answer 2

you can use mysqli_fetch_assoc instead of using mysqli_fetch_array and adding another argument to get only the associative one
while ($row = mysqli_fetch_assoc($result)) {
if (stripos('cross',$row['keyname']) !== false)
$row['keyname'] = str_replace('cross','<img src="path/to/image"/>',$row['keyname']);
$array[] = $row; // add the row in to the results (data) array
}