Pick a row with a specific index in a foreach loop - php

Question

I want to output all image files of a specific productid. What is the right syntax to output the image path for row 1, row 2, row 3 etc? I can not find it.
$sql = "SELECT *
FROM images
WHERE productid = $productid";
$select = $db->prepare($sql);
$select->execute(array());
foreach($select as $index => $rs) {
if($rs['imagepath']){
if($index == 0){
echo $imagepath[0]; // <---What is the right sytax of this?
}
}
if($rs['imagepath']){
if($index == 1){
echo $imagepath[1]; // <---and this?
}
}
if($rs['imagepath']){
if($index == 3){
echo $imagepath[2]; // <---and this?
}
}

Answer 1

The whole point of a foreach loop is it goes once through each select as "index". so you shouldn't have to worry about making an if-statement for each possible row, just make the statement once, and it will happen on each and every iteration

Answer 2

$rows = [];
$sql = "SELECT *
FROM images
WHERE productid = productid";
$select = $db->prepare($sql);
$select->execute(array());
foreach($select as $index => $rs) {
$rows []= $rs;
}
echo $rows[0]['imagepath'];

Answer 3

aren't we missing the fetch function?
`
$select = $db->prepare($sql);
$select->execute(array());
$i = 0;
while($row = $select->fetch()) {
echo $i . ' '. $row['imagepath'] . '<br>';
$i++;
}
?>
`
--
addendum:
I now understand you only want one, or some, of the images to be shown.
Would it not be easier then, to only select that/those images?
SELECT imagepath
FROM images
WHERE productid = productid
AND someid = 3
or if no "someid" is present:
SELECT imagepath
FROM images
WHERE productid = productid
LIMIT 2,1
That would avoid the need to loop through may be 100 records to only use the 3th.