Get two adjacent images in a while loop PHP - php

Question

I have a html code , when i convert into php some issues happended . Actually i need a foreach or while loop for the below div.
But all images are different (never mind the names of images, it can be any name).
<div class='img'>
<img src='img/1.jpg'>
<img src='img/2.jpg'>
</div>
<div class='img'>
<img src='img/3.jpg'>
<img src='img/4.jpg'>
</div>
//....more divs like this
Here my try
$stmt=$db->query("Select * from photo");
foreach ($stmt as $row)
{
?>
<div class='img'>
<img src='img/<?php echo $row['image']; ?>'>
<img src='img/<?php echo $row['image']; ?>'> // how to get this image diffent from above images
</div>
<?php }
Any experts?

Answer 1

Try that:
<?php
$pdo = new PDO('mysql:host=localhost;dbname=test', 'root', '');
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sth = $pdo->prepare("SELECT * FROM photo");
$sth->execute();
$data = $sth->fetchAll(PDO::FETCH_ASSOC);
?>
<?php $i = 0; ?>
<?php $response = array(); ?>
<?php foreach ($data as $dataIndex => $dataValue): ?>
<?php if ($i == 1): ?>
<?php $response[] = '<img src="img' . $dataValue["image"] . '"/>'; ?>
<?php $response[] = "</div>"; ?>
<?php $i = 0; ?>
<?php else: ?>
<?php $response[] = "<div class='img'>"; ?>
<?php $response[] = '<img src="img' . $dataValue["image"] . '"/>'; ?>
<?php $i++; ?>
<?php endif; ?>
<?php endforeach; ?>
<?php if(count($data)%2): ?>
<?php $response[] = "</div>"; ?>
<?php endif; ?>
<?php echo implode("", $response); ?>
output:
<div class="img">
<img src="img1">
<img src="img2">
</div>
<div class="img">
<img src="img3">
<img src="img4">
</div>
<div class="img">
<img src="img5">
<img src="img6">
</div>

Answer 2

Assuming $stmt is an array, you can do this.
<?php
$count = 0
while(sizeof($stmt) > $count) {
?>
<img src="<?php $stmt[$count]['image']?>"/>
<?php
$count++;
?>
<img src="<?php $stmt[$count]['image']?>"/>
<?php $count++; ?>
}
?>