Generate HTML code with PHP automatically, after data pull in MySql - php

I have written a really simple php page that populate a database.
I now want to fetch this data in another php page and that is ok.
What I would like to achive is:
when I add another row into the database, I would like the html to create a new card, and not add the information in the same card.
I am not sure I understand how this can be achived.
Do I have to use php templates like smarty or anybody can point me how could I proceed?
This is how it look when I add second raw:
While what i want to achive should look like
Here is the HTML code I use with the PHP code:
<section class="tm-section-3 tm-section-mb" id="tm-section-3">
<div class="row">
<div class="col-md-6 tm-mb-sm-4 tm-2col-l">
<div class="image">
<img src="img/tm-img-1.jpg" class="img-fluid" />
</div>
<div class="tm-box-3">
<h2>
<?php if (mysqli_num_rows($result) > 0) {
?>
<table>
<?php
include_once '../scripts/connection.php';
$result = mysqli_query($link,"SELECT
domain,subdomain,topic,topictitle,topictext FROM newpage");
$i=0;
while($row = mysqli_fetch_array($result)) {
?>
<tr>
<td><?php echo $row["domain"]; ?></td>
</tr>
<tr>
<td><?php echo $row["subdomain"]; ?></td>
</tr>
<tr>
<td><?php echo $row["topic"]; ?></td>
</tr>
<tr>
<td><h4><?php echo $row["topictitle"]; ?></h4></td>
</tr>
<tr>
<td><h5><?php echo $row["topictext"]; ?></h5></td>
</tr>
<?php
$i++;
}
?>
</table>
<?php
}
else{
echo "No result found";
}
?>
</h2>
<p>
</p>
<div class="text-center">
Details
</div>
</div>
</div>
</div>
</section>
This is how i send the code to the db:
<?php
include("connection.php");
$domain = mysqli_real_escape_string($link, $_POST['domain']);
$subdomain = mysqli_real_escape_string($link, $_POST['subdomain']);
$topic = mysqli_real_escape_string($link, $_POST['topic']);
$topictitle = mysqli_real_escape_string($link, $_POST['topictitle']);
$topictext = mysqli_real_escape_string($link, $_POST['topictext']);
$sql = "INSERT INTO newpage (domain,subdomain,topic,topictitle,topictext) VALUES ('$domain','$subdomain','$topic','$topictitle','$topictext')";
$result = mysqli_query($link, $sql);
// if query fails stop script and echo error
if( $result === false)
{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
exit;
}
$sql = "INSERT INTO menu (item) VALUES ('$domain')";
$result = mysqli_query($link, $sql);
// if query fails stop script and echo error
if( $result === false)
{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
exit;
}
header("location:../scripts/add-new-page-script-end.php");
exit;
echo "You'll never see this";
?>
Here the code that works even the style is bad. But logically is correct:
<div class="col-md-6 tm-mb-sm-4 tm-2col-l">
<?php
include_once '../scripts/connection.php'; $result = mysqli_query($link,"SELECT domain,subdomain,topic,topictitle,topictext FROM newpage"); foreach($result as $row){
?>
<div class="image">
<img src="img/tm-img-1.jpg" class="img-fluid" />
</div>
<div class="tm-box-3">
<h1><?php echo $row['domain']; ?></h1>
<h2><?php echo $row['subdomain']; ?></h2>
<h3><span><?php echo $row['topic']; ?></span></h3>
<h4> <span><?php echo $row['topictitle']; ?></span></h4>
<p><?php echo $row['topictext']; ?></p>
<div class="text-center">
Details
</div>
</div>
<?php
}
?>
</div>

It currently looks like you have something like this:
<div class="card">
<img src="..." />
<?php
foreach($result as $row){
?>
<h1><?php echo $row['domain-name']; ?></h1>
<h2><?php echo $row['sub-domain-name']; ?></h2>
<span><?php echo $row['topic-text-title']; ?></span>
<p><?php echo $row['text-of-topic']; ?></p>
<?php
}
?>
<button>Details</button>
</div>
If you instead put the foreach loop outside of the card div then it will make a new card for each result, something like this:
<?php
foreach($result as $row){
?>
<div class="card">
<img src="..." />
<h1><?php echo $row['domain-name']; ?></h1>
<h2><?php echo $row['sub-domain-name']; ?></h2>
<span><?php echo $row['topic-text-title']; ?></span>
<p><?php echo $row['text-of-topic']; ?></p>
<button>Details</button>
</div>
<?php
}
?>

Assuming that your are not using any framework.
In raw php context you could do something like this:
<div>
<?php foreach($arr as $item): ?>
<div>
<img src="...">
<h1><?php echo $item->domain_name; ?></h1>
<h2><?php echo $item->subdomain_name; ?></h2>
<h3><?php echo $item->topic; ?></h3>
<h4><?php echo $item->topic_text_title; ?></h4>
<h5><?php echo $item->text_pf_topic; ?></h5>
</div>
<?php endforeach; ?>
</div>

Related

Page Goes Blank With Function On Php

I have the following function.php:
function getPublishedPosts() {
// use global $conn object in function
global $conn;
$sql = "SELECT * FROM posts WHERE published=true";
$result = mysqli_query($conn, $sql);
// fetch all posts as an associative array called $posts
$posts = mysqli_fetch_all($result, MYSQLI_ASSOC);
$final_posts = array();
foreach ($posts as $post) {
$post['topic'] = getPostTopic($post['id']);
array_push($final_posts, $post);
}
return $final_posts;
}
and I am calling it to the other page with this:
<!-- THIS LOOP -->
<?php $posts = **getPublishedPosts();** ?>
<div class="content">
<h2 class="content-title">Recent Articles</h2>
<hr>
<!-- more content still to come here ... -->
<!-- Add this ... -->
<?php $posts = getPublishedPosts(); ?>
<?php foreach ($posts as $post): ?>
<div class="post" style="margin-left: 0px;">
<img src="<?php echo BASE_URL . '/static/images/' . $post['image']; ?>" class="post_image" alt="">
<!-- Added this if statement... -->
<?php if (isset($post['topic']['name'])): ?>
<a
href="<?php echo BASE_URL . 'filtered_posts.php?topic=' . $post['topic']['id'] ?>"
class="btn category">
<?php echo $post['topic']['name'] ?>
</a>
<?php endif ?>
<a href="single_post.php?post-slug=<?php echo $post['slug']; ?>">
<div class="post_info">
<h3><?php echo $post['title'] ?></h3>
<div class="info">
<span><?php echo date("F j, Y ", strtotime($post["created_at"])); ?></span>
<span class="read_more">Read more...</span>
</div>
</div>
</a>
</div>
<?php endforeach ?>
</div>
However, when it is on the server, the page goes blank.
I finally solved it, it was just a server extension and version problem regarding the incompatibility of my function.

Div-container around product-cards in php

I'm really new to php and now I got stucked on what I thought was something really easy. Byt I can't see wheres my problem is.
I'm trying to create a webshop page that displays all my products.
To the problem!
Here is my code so far. It displays all products as expected but it closes the main and product-container before all product-cards except from the first one. How to wrap all product-cards in the same div?
$pdo = connect();
$limit = 20;
$offset = 0;
$stmt = get_all_products($pdo, $limit, $offset);
$stmt->execute();
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
?>
<main>
<section class="product-container">
<?php
foreach($rows as $row) {
?>
<div class="product-card">
<img class="product-image" src="<?php echo $row['Img'];?>" >
<h2 class="title"><?php echo $row['ProductName']; ?></h2>
<span class="price"><?php echo $row['Price'];?></span><span>:-</span>
</div>
</section>
</main>
<?php
}?>
You should move the closing main and section tag after the foreach loop is closed.
<main>
<section class="product-container">
<?php
foreach($rows as $row) {
?>
<div class="product-card">
<img class="product-image" src="<?php echo $row['Img'];?>" >
<h2 class="title"><?php echo $row['ProductName']; ?></h2>
<span class="price"><?php echo $row['Price'];?></span><span>:-</span>
</div>
<?php }?> <!-- Close the foreach loop here -->
</section>
</main>

Showing fields from a query in php

I'm new in PHP and i'm having a trouble in showing the retrived data from a query. There area four area_name and many type_name, type_desc and type_price under that area_name
I wanted to display those data in a format like this:
area_name1
type_name1_1
type_desc1_1
type_price1_1
type_name1_2
type_desc1_2
type_price1_2
then
area_name2
type_name2_1
type_desc2_1
type_price2_1
type_name2_2
type_desc2_2
type_price2_2
But in my code, it is displayed like this:
area_name1
type_name1_1
type_desc1_1
type_price1_1
area_name1
type_name1_2
type_desc1_2
type_price1_2
then
area_name2
type_name2_1
type_desc2_1
type_price2_1
area_name2
type_name2_2
type_desc2_2
type_price2_2
Can anyone help me on how to show the area_name once then show the type_names under that specific area_name? any help/assistance will be greatly appreciated.
<?php
include 'config.php';
$query = "select a.area_name,t.type_no,t.type_name,t.type_desc,t.type_price,t.area_no, a.area_no from area as a INNER JOIN type as t where a.area_no=t.area_no";
$stmt= dbConnect()->prepare($query);
$stmt -> execute();
$text_num = $stmt -> rowCount();
?>
<div id="prices_content">
<div>
<?php if ($text_num>0) {?>
<?php while ($row=$stmt->fetch(PDO::FETCH_ASSOC)) {?>
<div id="content">
<br><br><br><center>
<b><h1><?php echo $row['area_name']; ?></h1></b><br>
<p><?php echo $row['type_name']; ?></p><br>
<p><?php echo $row['type_desc']; ?></p><br>
<p><?php echo $row['type_price']; ?></p></center><br>
</div>
<?php }?>
<?php }?>
</div>
</div>
In your while loop you're echoing $row['area_name'] every time. You need to declare a variable outside the loop to hold the area name and check it in each loop to see if it changed.
Like this:
$area_name = '';
<?php while ($row=$stmt->fetch(PDO::FETCH_ASSOC)) {?>
<div id="content">
<br><br><br><center>
<?php if($area_name != $row['area_name']){ ?>
<?php $area_name = $row['area_name']; ?>
<b><h1><?php echo $row['area_name']; ?></h1></b><br>
<?php } ?>
<p><?php echo $row['type_name']; ?></p><br>
<p><?php echo $row['type_desc']; ?></p><br>
<p><?php echo $row['type_price']; ?></p></center><br>
</div>
<?php } ?>
Try this Code,
<?php
include 'config.php';
$query = "select a.area_name,t.type_no,t.type_name,t.type_desc,t.type_price,t.area_no, a.area_no from area as a INNER JOIN type as t where a.area_no=t.area_no";
$stmt= dbConnect()->prepare($query);
$stmt -> execute();
$text_num = $stmt -> rowCount();
?>
<div id="prices_content">
<div>
<?php if ($text_num>0) {?>
<?php while ($row=$stmt->fetch(PDO::FETCH_ASSOC)) {?>
<div id="content">
<br><br><br><center>
<?if($area_name !== $row['area_name']){?>
<b><h1><?php echo $row['area_name']; ?></h1></b><br>
<?php }?>
<p><?php echo $row['type_name']; ?></p><br>
<p><?php echo $row['type_desc']; ?></p><br>
<p><?php echo $row['type_price']; ?></p></center><br>
</div>
<?php $area_name = $row['area_name'];}?>
<?php }?>
</div>
</div>
You are adding the area_name into the loop so it will be displayed
you should try this
<div id="prices_content">
<div>
<?php if ($text_num>0) {?>
<b><h1><?php echo $row['area_name']; ?></h1></b><br><!-- this outside of the loop-->
<?php while ($row=$stmt->fetch(PDO::FETCH_ASSOC)) {?>
<div id="content">
<br><br><br><center>
<p><?php echo $row['type_name']; ?></p><br>
<p><?php echo $row['type_desc']; ?></p><br>
<p><?php echo $row['type_price']; ?></p></center><br>
</div>
<?php }?>
<?php }?>
</div>

php form submitting info twice

I have a form that's supposed to enter a reply to a forum topic into the database and redirect the user back to the same topic. After much trial and error I have finally got the form to work, only it is putting two identical entries into the db every time. I cannot figure out why. I have looked up this same problem and most of the other people were not redirecting after the form submission or they were using AJAX or jquery or something. Here is my page info:
<?php
session_start();
include_once('includes/config.php');
include_once('classes/topic.php');
include_once('classes/post.php');
include('includes/header.php');
?>
<link rel="stylesheet" href="css/dd.css">
<?php
$topic = new Topic;
if (isset($_GET['id']))
{
$topic_id = $_GET['id'];
$data = $topic->fetch_data($topic_id);
if (isset($_POST['content']))
{
// someone posted a reply
$date = date('Y-m-d H:i:s');
$by = $_SESSION['user_id'];
$query = $pdo->prepare("INSERT INTO dd_posts (post_content, post_date, post_by, post_topic) VALUES (? ,? ,?, ?)");
$query->bindParam(1, $_POST['content']);
$query->bindParam(2, $date);
$query->bindParam(3, $by);
$query->bindParam(4, $_GET['id']);
$query->execute();
$result = $query->execute();
header("location:topic.php?id=".$_GET['id']);
exit;
}
?>
<div id ="wrapper">
<div class="drop-section">
<div id="menu">
<a class="item" href="drop_index.php">Dead Drop</a>
<a class="item" href="add_topic.php">New Post</a>
<a class="item" href="admin/add_cat.php">New Category</a>
<div id="userbar">
<?php
if( $user->is_logged_in() ) {
echo 'Hello ' . $_SESSION['user_name'] . '. How are you?';
} else {
echo '<a class="item" href="login.php">Sign in</a> or <a class="item" href="index.php">Create an account</a>';
}
?>
</div>
</div>
<table>
<tr class = "header-row">
<div id = "sans">
<?php echo $data['topic_subject']; ?>
- <small>started by <?php echo $data['user_name']; ?> </small><br />
<?php echo $data['topic_content']; ?>
</div>
</tr>
<?php
// retrieve all the replies to the original topic
$post = new Post;
$topic_id = $_GET['id'];
$posts = $post->fetch_all_posts_by_topic($topic_id);
?>
<tr>
<td class="first-column">
<?php foreach ($posts as $post) { ?>
<div class="drop-content-box">
<li><?php echo $post['post_content']; ?><br />
<div class = "forum-user-info">
<a href="player.php?id=<?php echo $post['user_id']; ?>">
<?php echo $post['user_name']; ?></a> - level:
<?php echo $post['user_level']; ?>
</div>
</li>
</div>
<?php } ?>
</td>
</tr>
</table>
<?php
if( $user->is_logged_in() )
{
?>
<div id = "header-section">Reply</div>
<?php if (isset($error)) { ?>
<small><?php echo $error; ?></small>
<?php } ?>
<form action="<?php echo "topic.php?id=".$_GET['id']?>" method="post" autocomplete="off">
<small><i>Do not post the actual answer to any level.</i></small><br />
<textarea rows="15" cols="50" name="content" placeholder="Give us your thoughts..."></textarea><br />
<input type="submit" value="Post" />
</form>
</div>
</div>
<?php
} else {
echo '<div id = "errors"><small>You must be signed in to reply.</div></small>';
}
}
include_once('includes/footer.php');
?>
You're executing the query twice.
$query->execute();
$result = $query->execute();

each query a different background-image

I build this in php:
<?php
$bg = array('block2.png', 'block3.png', 'block4.png', 'block5.png', 'block7.png' );
$i = rand(0, count($bg)-1);
$selectedBg = "$bg[$i]";
?>
<style type="text/css">
<!--
.block_small{
background-image: url(/tableaux/customer/images/<?php echo $selectedBg; ?>);
}
-->
</style>
<?php
$db = new DB();
$db->query("SELECT * FROM vestigingen ");
while($item = $db->next_record()){
?>
<div class="block_small">
<img src="<?php echo $item['afbeelding']; ?>" />
<h1><?php echo $item['plaats']; ?></h1>
<div class="content_blocks">
<p><?php echo $item['adres']; ?></p>
<p><?php echo $item['postcode']; ?></p>
<p><?php echo $item['telefoon']; ?></p>
<p><?php echo $item['mail']; ?></p>
</div>
<div class="arrow"><?php echo $item['link']; ?></div>
</div>
<?
}
?>
Content loads from a SQL database, I want every block to have a different background-image, now they are all the same.
I first tried to put the style in the while loop but that didn't work.
Idea's ?
If you want all the div containers to have a different background you cannot append the same class to all of them. The image in the class is chosen randomly, but afterwards the same image-background is given to all the div elements with the same class.
With only php you got two possibilities to set a different background for all of the images:
first solution:
write a loop and set the css for ids #small_block1-#small_blockx.
second solution:
set inline css for all the elements within the style tag in a loop. I will show this solution below.
<?php
$bg = array('block2.png', 'block3.png', 'block4.png', 'block5.png', 'block7.png' );
$db = new DB();
$db->query("SELECT * FROM vestigingen ");
$counter = 0;
while($item = $db->next_record()){
?>
<div class="block_small" style="background-image: url(/tableaux/customer/images/<?php echo $bg[$counter]; ?>);" >
<img src="<?php echo $item['afbeelding']; ?>" />
<h1><?php echo $item['plaats']; ?></h1>
<div class="content_blocks">
<p><?php echo $item['adres']; ?></p>
<p><?php echo $item['postcode']; ?></p>
<p><?php echo $item['telefoon']; ?></p>
<p><?php echo $item['mail']; ?></p>
</div>
<div class="arrow"><?php echo $item['link']; ?></div>
</div>
<?
$counter++;
}
?>
You are do it in wrong way, you are always update the style. Instead of this, add an inline style.
<?php
$bg = array('block2.png', 'block3.png', 'block4.png', 'block5.png', 'block7.png');
$db = new DB();
$db->query("SELECT * FROM vestigingen ");
while ($item = $db->next_record()) {
$selectedBg = $bg[array_rand($bg)];
?>
<div class="block_small" style="background-image: url('/tableaux/customer/images/<?php echo $selectedBg; ?>)';">
<img src="<?php echo $item['afbeelding']; ?>" />
<h1><?php echo $item['plaats']; ?></h1>
<div class="content_blocks">
<p><?php echo $item['adres']; ?></p>
<p><?php echo $item['postcode']; ?></p>
<p><?php echo $item['telefoon']; ?></p>
<p><?php echo $item['mail']; ?></p>
</div>
<div class="arrow"><?php echo $item['link']; ?></div>
</div>
<?php
}

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