modelsearch not working in yii2 - php

I have some problems in making modelsearch in yii2.
Here's is my table's relation
I want to display Jurusan from table aitambah to ais3 and I want to display NamaMahasiswa from table ai to ais3. I made table s3penghubung so that table aitambah can be related to ais3. I was able to display them. But, when I try to type "71501" in "NRP" field, the searching not working properly. it is refreshing the page. there is no any change to the rows displayed. so, what should I do to fix that?
here is my modelsearch codes:
<?php
namespace app\models;
use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\Ais3;
/**
* Ais3Search represents the model behind the search form about `app\models\Ais3`.
*/
class Ais3Search extends Ais3
{
/**
* #inheritdoc
*/
public function rules()
{
return [
[['id', 'kode'], 'integer'],
[['NRP', 'namaMahasiswaText', 'ProgramStudi', 'TanggalMasuk', 'TanggalKeluar'], 'safe'],
];
}
public $NamaMahasiswa;
public $namaMahasiswaText;
/**
* #inheritdoc
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
/**
* Creates data provider instance with search query applied
*
* #param array $params
*
* #return ActiveDataProvider
*/
public function search($params)
{
$query = Ais3::find();
$query->joinWith('ai');
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
// grid filtering conditions
$query->andFilterWhere([
'id' => $this->id,
'kode' => $this->kode,
]);
$query->andFilterWhere(['like', 'ais3.NRP', $this->NRP])
->andFilterWhere(['like', 'ai.NamaMahasiswa', $this->namaMahasiswaText])
->andFilterWhere(['like', 'ais3.ProgramStudi', $this->ProgramStudi])
->andFilterWhere(['like', 'ai.TanggalMasuk', $this->TanggalMasuk])
->andFilterWhere(['like', 'ais3.TanggalKeluar', $this->TanggalKeluar]);
return $dataProvider;
}
}
here is mygridview codes
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
//'id',
'NRP',
'namaMahasiswaText',
'ProgramStudi',
//'TanggalMasuk',
[
'attribute' => 'TanggalMasuk',
'value' => function($data) {
return $data->ai->TanggalMasuk;
},],
'TanggalKeluar',
//YANG DITAMBAH
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.JURUSAN',
'label' => 'Jurusan',
],
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.NAMKANTOR',
'label' => 'Nama Kantor',
],
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.ANGKATAN',
'label' => 'Angkatan',
],
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.TELP',
'label' => 'Nomor HP/Telp',
],
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.PEKERJAAN',
'label' => 'Pekejaan',
],
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.EMAIL',
'label' => 'Email',
],
[
'attribute'=>'NRP',
'value'=>'s3penghubung.aitambah.KODEPROP',
'label' => 'KodeProp',
],
// 'kode',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
I thought there must be something wrong in my query filter
$query->andFilterWhere(['like', 'ais3.NRP', $this->NRP])
->andFilterWhere(['like', 'ai.NamaMahasiswa', $this->namaMahasiswaText])
->andFilterWhere(['like', 'ais3.ProgramStudi', $this->ProgramStudi])
->andFilterWhere(['like', 'ai.TanggalMasuk', $this->TanggalMasuk])
->andFilterWhere(['like', 'ais3.TanggalKeluar', $this->TanggalKeluar]);
but I dont know how to fix those codes. Could you please help me to solve this? Thankyou
The right answer is here:
here's gridview in index
and here's in modelsearch
thankyou ck_anjuk for solving my problem.

Related

Unknown Property – yii\base\UnknownPropertyException

I got the error in the title when trying to display a relational field in the gridview.
I have the problem with statuscode.statusname.
What do I miss?
Thanks in advance!
My Projectsearch model:
<?php namespace frontend\models;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use frontend\models\Project;
class ProjectSearch extends Project
{
/**
* {#inheritdoc}
*/
public function rules()
{
return [
[['id', 'client_id', 'status_id'], 'integer'],
[['number', 'name'], 'safe'],
[['client.name'], 'safe'],
[['statuscode.statusname'], 'safe'],
];
}
/**
* {#inheritdoc}
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
public function attributes()
{
// add related fields to searchable attributes
return array_merge(parent::attributes(), ['client.name']);
return array_merge(parent::attributes(), ['statuscode.statusname']);
}
/**
* Creates data provider instance with search query applied
*
* #param array $params
*
* #return ActiveDataProvider
*/
public function search($params)
{
$query = Project::find();
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->sort->attributes['client.name'] = [
'asc' => ['client.name' => SORT_ASC],
'desc' => ['client.name' => SORT_DESC],
];
$dataProvider->sort->attributes['statuscode.statusname'] = [
'asc' => ['statuscode.statusname' => SORT_ASC],
'desc' => ['statuscode.statusname' => SORT_DESC],
];
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->joinWith(['client' => function($query) {
$query->from(['client' => 'clients']); }]);
$query->joinWith(['statuscode' => function($query) { $query->from(['statuscode' => 'statuses']); }]);
// grid filtering conditions
$query->andFilterWhere(['like', 'project.number', $this->number])
->andFilterWhere(['like', 'project.name', $this->name])
->andFilterWhere(['LIKE', 'client.name', $this->getAttribute('client.name')])
->andFilterWhere(['LIKE', 'statuscode.statusname', $this->getAttribute('statuscode.statusname')]);
return $dataProvider;
}
}
My view:
<?php
use yii\helpers\Html;
use yii\grid\GridView;
use yii\widgets\Pjax;
$this->title = 'Projects';
$this->params['breadcrumbs'][] = $this->title;
?>
<div class="project-index">
<h1><?= Html::encode($this->title) ?></h1>
<?php Pjax::begin(); ?>
<?php // echo $this->render('_search', ['model' => $searchModel]); ?>
<p><?= Html::a('Create Project', ['create'], ['class' => 'btn btn-success']) ?></p>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'number',
'client.name',
'name',
[
'attribute' => 'statuscode.statusname',
'label' => 'Projectstatus',
],
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
<?php Pjax::end(); ?>
</div>
Nevermind, i got it! :)
return array_merge(parent::attributes(), ['client.name', 'statuscode.statusname']);
instead of:
return array_merge(parent::attributes(), ['client.name']);
return array_merge(parent::attributes(), ['statuscode.statusname']);
LOL

how to join table in grid view in yii2

i want to join my company table name to employee id. here my code in
employee model
public function attributeLabels()
{
return [
'id' => 'ID',
//'company_id' => 'Company ID',
'emp_name' => 'Emp Name',
'emp_email' => 'Emp Email',
'emp_salery' => 'Emp Salery',
];
}
public function getCompany()
{
return $this->hasOne(Company::className(),['id' => 'company_id']);
}
in index file i use this code
<?php PJax::begin();?>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
//['class' => 'yii\grid\SerialColumn'],
//'id',
[
'attribute' => 'company_id',
'value' => 'company.name',
],
'emp_name',
'emp_email:email',
'emp_salery',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
<?php PJax::end();?></div>
in employee search table i use this code
public function search($params)
{
$query = Employee::find();
$query->joinWith(['company']);
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
$query->where('0=1');
return $dataProvider;
}
// grid filtering conditions
$query->andFilterWhere([
'id' => $this->id,
]);
$query->andFilterWhere(['like', 'company_id', $this->company_id])
->andFilterWhere(['like', 'emp_name', $this->emp_name])
->andFilterWhere(['like', 'emp_email', $this->emp_email])
->andFilterWhere(['like', 'emp_salery', $this->emp_salery])
->andFilterWhere(['like', 'Company.name', $this->company_id])
->andFilterWhere(['like', 'company.name', $this->company])
;
return $dataProvider;
}
http://localhost/test/web/employee/
is shows in company field (not set)
pls help me
you can do this in two difference way : 1 . If you want use active record you must set property in first model you want to select it and join table with that like:
public $pin;
then when you get data you can access to pin in second table
the second way is you use asArray() that return all off data in both table
$model = News::find()->leftJoin('comment', 'news.id = comment.news_id')->asArray()->all();
then you can use it in your gridview
You should add a getter eg:getCompanyname()n your base model
......
public function attributeLabels()
{
return [
'id' => 'ID',
//'company_id' => 'Company ID',
'emp_name' => 'Emp Name',
'emp_email' => 'Emp Email',
'emp_salery' => 'Emp Salery',
'companyName' => 'Company Name')
];
}
public function getCompany()
{
return $this->hasOne(Company::className(),['id' => 'company_id']);
}
You should add a getter for company name
/*
Getter for company name
*/
public function getCommpanyName() {
return $this->company->name;
}
and in your gridview you should use the new get name (companyName)
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
'companyName',
'emp_name',
'emp_email:email',
'emp_salery',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
see this for more complete samples
http://www.yiiframework.com/wiki/621/filter-sort-by-calculated-related-fields-in-gridview-yii-2-0/

yii2 grid filtering is not working

my grid view filter is not filtering categories, I have given category_id to nesserray places but yet it is not filtering my posts according to their category_id, please help me.
here are my source codes:
post-->index.php
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'title',
[
'attribute'=>'category_id',
'value'=>function($model) {
return $model->category->name;
},
'filter'=>$category
],
[
'attribute'=>'user_id',
'value'=>function($model) {
return $model->user->fullname;
},
'filter'=>$user,
'label'=>'user'
],
'category.name',
'user.fullname',
// 'user_id',
// 'description',
// 'content:html',
'count_view',
'status',
'created_at',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
and here is model/postSearch.php
<?php
namespace app\models\search;
use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\post;
/**
* PostSearch represents the model behind the search form about `app\models\post`.
*/
class PostSearch extends post
{
/**
* #inheritdoc
*/
public function rules()
{
return [
[['id', 'user_id','category_id', 'count_view'], 'integer'],
[['title', 'description', 'content', 'status', 'created_at'], 'safe'],
];
}
/**
* #inheritdoc
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
/**
* Creates data provider instance with search query applied
*
* #param array $params
*
* #return ActiveDataProvider
*/
public function search($params)
{
$query = post::find();
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
// grid filtering conditions
$query->andFilterWhere([
'id' => $this->id,
'category_id' => $this->category_id,
'user_id' => $this->user_id,
'count_view' => $this->count_view,
'created_at' => $this->created_at,
]);
$query->andFilterWhere(['like', 'title', $this->title])
->andFilterWhere(['like', 'description', $this->description])
->andFilterWhere(['like', 'content', $this->content])
->andFilterWhere(['like', 'status', $this->status]);
return $dataProvider;
}
}
it worked, I had to removle jQuery files

YII2 - How to Display Defferent Value of Two Relation on Same Table

I have a football match function. But always display same team on home or away.
Here's my code,
Model [Match] :
use app\models\Team;
...
public function getTeam()
{
return $this->hasOne(Team::className(), ['id' => 'home', 'id' => 'away']);
}
...
Team model is list of all team
Match table only keep id of Team on Home Field and Away Field
Model [MatchSearch] :
....
public $team_home;
public $team_away;
public function rules()
{
return [
[['home', 'away'], 'integer'],
[['team_home', 'team_away'], 'safe'],
];
}
...
public function search($params)
{
$query = Match::find()->joinWith(['team']);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->sort->attributes['team_home'] = [
'asc' => ['team.team' => SORT_ASC],
'desc' => ['team.team' => SORT_DESC],
];
$dataProvider->sort->attributes['team_away'] = [
'asc' => ['team.team' => SORT_ASC],
'desc' => ['team.team' => SORT_DESC],
];
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere([
'home' => $this->home,
'away' => $this->away,
]);
$query->andFilterWhere(['like', 'team.team', $this->team_home])
->andFilterWhere(['like', 'team.team', $this->team_away]);
return $dataProvider;
}
Views [Index] :
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
[
'attribute' => 'home',
'value' => function($data) {
return $data->team->team;
},
],
[
'attribute' => 'away',
'value' => function($data) {
return $data->team->team;
},
],
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
<?php Pjax::end(); ?>
But the result always show the Away team both Home or Away :
Home :
Team Away
Away :
Team Away
How to fix this?
You can use inner join
$query = Match::find()
->innerJoin('team_tname as home', '`team_taame`.`id` = `match_table_name`.`home`')
->innerJoin('team_taname as away', '`team_name`.`id` = `match_table_name`.`away`');
the you should refer to the column name using the proper table alias

Yii2 column in GridView is not displaying (not set)

I am trying to combine 3 tables in the my ActiveRecord Search().
I have this table
employees
id
first_name
projects
id
name
project_assignment
id
employee_id
project_id
date_added
date_removed
I am using GridView to display all the employees in my database.
Now, I wanted to display project where the employee is being assigned. So having said this, obviously we need these 3 tables to connect.
In my Employees.php Model, i have this code:
public function getproject_assignment()
{
return $this->hasMany(ProjectAssignment::className(), ['employee_id' => 'id']);
}
In my ProjectAssignment.php model
/**
* #return \yii\db\ActiveQuery
*/
public function getEmployee()
{
return $this->hasOne(Employees::className(), ['id' => 'employee_id']);
}
/**
* #return \yii\db\ActiveQuery
*/
public function getProject()
{
return $this->hasOne(Projects::className(), ['id' => 'project_id']);
}
In my EmployeeSearch.php
class EmployeesSearch extends Employees
{
public $project_name;
public function rules()
{
return [
[['id', 'employment_status_id'], 'integer'],
[['project_name','string_id', 'first_name', 'last_name', 'middle_name', 'gender', 'birth_date', 'civil_status', 'phone', 'address', 'zip', 'email', 'position', 'start_date', 'tin', 'philhealth', 'sss', 'hdmf', 'photo_location'], 'safe'],
];
}
public function search($params)
{
$query = Employees::find();
$query->addSelect(['projects.name as project_name','employees.*']);
$query->leftJoin('project_assignment','project_assignment.employee_id = employees.id');
$query->leftJoin('projects','projects.id = project_assignment.project_id');
$query->andWhere([
'project_assignment.date_removed' => NULL
]);
$dataProvider = new ActiveDataProvider([
'query' => $query,
'pagination' => array('pageSize' => 20),
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->andFilterWhere([
'id' => $this->id,
]);
$query->andWhere([
'employees.deleted_at' => NULL
// 'projects.deleted_at' => NULL
]);
$query->andFilterWhere(['like', 'string_id', $this->string_id])
->andFilterWhere(['like', 'first_name', $this->first_name])
->andFilterWhere(['like', 'last_name', $this->last_name])
->andFilterWhere(['like', 'middle_name', $this->middle_name])
->andFilterWhere(['like', 'gender', $this->gender])
->andFilterWhere(['like', 'civil_status', $this->civil_status])
->andFilterWhere(['like', 'phone', $this->phone])
->andFilterWhere(['like', 'address', $this->address])
->andFilterWhere(['like', 'zip', $this->zip])
->andFilterWhere(['like', 'email', $this->email])
->andFilterWhere(['like', 'position', $this->position])
->andFilterWhere(['like', 'tin', $this->tin])
->andFilterWhere(['like', 'philhealth', $this->philhealth])
->andFilterWhere(['like', 'sss', $this->sss])
->andFilterWhere(['like', 'hdmf', $this->hdmf])
->andFilterWhere(['like', 'photo_location', $this->photo_location]);
return $dataProvider;
}
In my index.php (view file)
$gridColumns = [
[
'attribute' => 'Project',
'value' => 'projects', //the value means that this is the value of the column
//the zip here is the get parameter
'filter' => Html::activeDropDownList($searchModel, 'project_name', ArrayHelper::map(\app\models\Projects::find()->asArray()->all(), 'id', 'name'),['class'=>'form-control','prompt' => 'Select Project']),
],
'first_name',
'middle_name',
'last_name',
// 'position',
[
'attribute' => 'position',
'value' => 'position',
'filter' => Html::activeDropDownList($searchModel, 'position', ArrayHelper::map(Employees::find()->groupBy('position')->asArray()->all(), 'position', 'position'),['class'=>'form-control','prompt' => 'Select Position']),
],
['class' => 'yii\grid\ActionColumn',
'template' => '{update} {delete}'],
];
<?php echo
GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => $gridColumns,
'export' => [
'fontAwesome' => true,
]
]);
?>
The problem here is the Project column is not displaying anything.
Here's a screenshot:
When I checked on Yii Debuger, this sql query has been ran:
SELECT `projects`.`name` AS `project_name`, `employees`.* FROM `employees` LEFT JOIN `project_assignment` ON project_assignment.employee_id = employees.id LEFT JOIN `projects` ON projects.id = project_assignment.project_id WHERE (`project_assignment`.`date_removed` IS NULL) AND (`employees`.`deleted_at` IS NULL) LIMIT 20
This query is correct and what I was expecting. The only problem is that the Project column is not displaying as the screenshot that i showed you above.
I am not sure how to make this work. Been scratching my head for a couple of hours already.
Any help please. Thank You!
'value' => 'projects', //the value means that this is the value of the column
Actually the value here can be string or closure. If it is a string then it means that a string representing the attribute name to be displayed in this column as documentation says. Try to use closure. In your case it will be like this:
'value' => function ($model, $key, $index, $column){
return $model->project->name;
}
for kartik\grid\GridView;
'class' => 'kartik\grid\EditableColumn',
'attribute'=>'myAttribute',
'header' => 'myHeader',
'editableOptions' => [
'inputType' => \kartik\editable\Editable::INPUT_TEXT,
'valueIfNull' => '-',
/**
* #var string the value to be displayed. If not set, this will default to the attribute value. If the attribute
* value is null, then this will display the value as set in [[valueIfNull]].
*/
public $displayValue;

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