Unknown Property – yii\base\UnknownPropertyException - php

Question

I got the error in the title when trying to display a relational field in the gridview.
I have the problem with statuscode.statusname.
What do I miss?
Thanks in advance!
My Projectsearch model:
<?php namespace frontend\models;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use frontend\models\Project;
class ProjectSearch extends Project
{
/**
* {#inheritdoc}
*/
public function rules()
{
return [
[['id', 'client_id', 'status_id'], 'integer'],
[['number', 'name'], 'safe'],
[['client.name'], 'safe'],
[['statuscode.statusname'], 'safe'],
];
}
/**
* {#inheritdoc}
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
public function attributes()
{
// add related fields to searchable attributes
return array_merge(parent::attributes(), ['client.name']);
return array_merge(parent::attributes(), ['statuscode.statusname']);
}
/**
* Creates data provider instance with search query applied
*
* #param array $params
*
* #return ActiveDataProvider
*/
public function search($params)
{
$query = Project::find();
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->sort->attributes['client.name'] = [
'asc' => ['client.name' => SORT_ASC],
'desc' => ['client.name' => SORT_DESC],
];
$dataProvider->sort->attributes['statuscode.statusname'] = [
'asc' => ['statuscode.statusname' => SORT_ASC],
'desc' => ['statuscode.statusname' => SORT_DESC],
];
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->joinWith(['client' => function($query) {
$query->from(['client' => 'clients']); }]);
$query->joinWith(['statuscode' => function($query) { $query->from(['statuscode' => 'statuses']); }]);
// grid filtering conditions
$query->andFilterWhere(['like', 'project.number', $this->number])
->andFilterWhere(['like', 'project.name', $this->name])
->andFilterWhere(['LIKE', 'client.name', $this->getAttribute('client.name')])
->andFilterWhere(['LIKE', 'statuscode.statusname', $this->getAttribute('statuscode.statusname')]);
return $dataProvider;
}
}
My view:
<?php
use yii\helpers\Html;
use yii\grid\GridView;
use yii\widgets\Pjax;
$this->title = 'Projects';
$this->params['breadcrumbs'][] = $this->title;
?>
<div class="project-index">
<h1><?= Html::encode($this->title) ?></h1>
<?php Pjax::begin(); ?>
<?php // echo $this->render('_search', ['model' => $searchModel]); ?>
<p><?= Html::a('Create Project', ['create'], ['class' => 'btn btn-success']) ?></p>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'number',
'client.name',
'name',
[
'attribute' => 'statuscode.statusname',
'label' => 'Projectstatus',
],
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
<?php Pjax::end(); ?>
</div>

Answer 1

Nevermind, i got it! :)
return array_merge(parent::attributes(), ['client.name', 'statuscode.statusname']);
instead of:
return array_merge(parent::attributes(), ['client.name']);
return array_merge(parent::attributes(), ['statuscode.statusname']);
LOL