I am trying to create a "setup script" for my website. I would like to create the database, adding tables and some content at the same time. So far this is how I did it, but it seems kind off messy using multiple queries:
<?php
$servername = "localhost";
$username = "root";
$password = "password";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// Create database
$sql = "CREATE DATABASE MYDB";
if ($conn->query($sql) === TRUE) {
echo "1. Database created successfully <br/>";
$conn->select_db("MYDB");
$sql_members = "CREATE TABLE MEMBERS (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
USERNAME VARCHAR(30) NOT NULL,
EMAIL VARCHAR(40) NOT NULL,
DISCOUNT VARCHAR(5),
PASSW CHAR(128),
ROLE VARCHAR(9)
)";
if ($conn->query($sql_members) === TRUE) {
echo "2. Table MEMBERS created successfully <br/>";
} else {
echo "Error creating table: " . $conn->error;
}
$sql_content = "CREATE TABLE CONTENT (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
TITLE VARCHAR(30) NOT NULL,
TEXT VARCHAR(30) NOT NULL
)";
if ($conn->query($sql_content) === TRUE) {
echo "3. Table CONTENT created successfully <br/>";
} else {
echo "Error creating table: " . $conn->error;
}
} else {
echo "Error creating database: " . $conn->error;
}
$conn->close();
?>
Is there a better way?
Thanks!
== UPDATE ==
I have tried to export the database and use the resulted .sql file as my setup query, but something is wrong, I get:
Error creating tables: You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'INSERT INTO CONTACTS (ID, NAME, PHONE,
EMAIL, ADDRESS, CITY, `COUN' at line 12
CREATE TABLE IF NOT EXISTS `CONTACTS` (
`ID` int(11) NOT NULL AUTO_INCREMENT,
`NAME` varchar(25) COLLATE utf8_romanian_ci NOT NULL,
`PHONE` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
`EMAIL` varchar(35) COLLATE utf8_romanian_ci NOT NULL,
`ADDRESS` text COLLATE utf8_romanian_ci NOT NULL,
`CITY` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
`COUNTRY` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
PRIMARY KEY (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_romanian_ci AUTO_INCREMENT=2 ;
INSERT INTO `CONTACTS` (`ID`, `NAME`, `PHONE`, `EMAIL`, `ADDRESS`, `CITY`, `COUNTRY`) VALUES
(1, 'Peter Brown', '0742062307', 'office#shop.com', 'Avenue 13.', 'Santaclaus', 'Austria');
== SOLUTUION ==
I needed "multi_query()" for executing my multiple queries.
You can try this too :p
$errors = [];
$table1 = "CREATE TABLE MEMBERS (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
USERNAME VARCHAR(30) NOT NULL,
EMAIL VARCHAR(40) NOT NULL,
DISCOUNT VARCHAR(5),
PASSW CHAR(128),
ROLE VARCHAR(9)
)";
$table2 = "CREATE TABLE CONTENT (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
TITLE VARCHAR(30) NOT NULL,
TEXT VARCHAR(30) NOT NULL
)";
$tables = [$table1, $table2];
foreach($tables as $k => $sql){
$query = #$conn->query($sql);
if(!$query)
$errors[] = "Table $k : Creation failed ($conn->error)";
else
$errors[] = "Table $k : Creation done";
}
foreach($errors as $msg) {
echo "$msg <br>";
}
You could export the whole database including all tables using the command line or using PhPMyAdmin. Then query the content of the file in php to create the database.
you can create a file and put all your sql queries in it..
CREATE TABLE MEMBERS (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
USERNAME VARCHAR(30) NOT NULL,
EMAIL VARCHAR(40) NOT NULL,
DISCOUNT VARCHAR(5),
PASSW CHAR(128),
ROLE VARCHAR(9)
);
CREATE TABLE CONTENT (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
TITLE VARCHAR(30) NOT NULL,
TEXT VARCHAR(30) NOT NULL
);
then in your php code:
$query = file_get_contents ('queries.sql');
if ($conn->query($query) === TRUE) {
echo "all tables created successfully <br/>";
} else {
echo "Error creating tables: " . $conn->error;
}
Related
No answers were found at google and stackoverflow
The code is as follows
<?php
pdo_query("CREATE TABLE IF NOT EXISTS `ims_cyl_vip_video` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`uniacid` int(5) NOT NULL,
`title` varchar(255) NOT NULL,
`uid` varchar(25) NOT NULL,
`openid` varchar(255) NOT NULL,
`time` varchar(15) NOT NULL,
`video_url` text NOT NULL,
`share` int(3) NOT NULL,
`yvideo_url` text NOT NULL,
`type` VARCHAR(25) NOT NULL,
`index` int(2) NOT NULL,
`video_id` int(11) NOT NULL,
UNIQUE KEY `id` (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=1 ;
CREATE TABLE IF NOT EXISTS `ims_cyl_vip_video_member` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`uniacid` int(10) NOT NULL,
`openid` varchar(255) NOT NULL,
`uid` varchar(25) NOT NULL,
`nickname` varchar(255) NOT NULL,
`avatar` varchar(1000) NOT NULL,
`end_time` varchar(15) NOT NULL,
`is_pay` int(2) NOT NULL,
I think you are trying to create a table with PHP. Here is the simple code example from which you can create the tables: Replace the sample query with your SQL query.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// sql to create table
$sql = "CREATE TABLE MyGuests (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
firstname VARCHAR(30) NOT NULL,
lastname VARCHAR(30) NOT NULL,
email VARCHAR(50),
reg_date TIMESTAMP
)";
if ($conn->query($sql) === TRUE) {
echo "Table MyGuests created successfully";
} else {
echo "Error creating table: " . $conn->error;
}
$conn->close();
?>
I have below code I am trying to run..Connection is successfully created but still mysqli_query does not create a table.What I am missing...
here is the script I am executing...
error_reporting(E_ALL);
ini_set('display_errors', '1');
$con=mysqli_connect("localhost","xxxxxx","xxxxx","xxx");
if (mysqli_connect_errno()) {
echo mysqli_connect_error();
exit();
} else {
echo "Successful database connection";
}
$tbl_users = "CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(255) NOT NULL,
lastname VARCHAR(255) NOT NULL,
email VARCHAR(255) NOT NULL,
password VARCHAR(255) NOT NULL,
gender ENUM('m','f') NULL,
state VARCHAR(255) NULL,
country VARCHAR(255) NULL,
userlevel ENUM('admin','user') NOT NULL DEFAULT 'user',
ip VARCHAR(255) NOT NULL,
signup DATETIME NOT NULL,
lastlogin DATETIME NOT NULL,
activated ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (email)
)";
$query = mysqli_query($con, $tbl_users);
if ($query === TRUE) {
echo "<h3>user table created OK :) </h3>";
} else {
echo "<h3>user table NOT created :( </h3>";
}
You need to change your Primary key to the auto_increment column, remove it from email, you can set this (email) to unique if it should be
CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL // >>> PRIMARY KEY //<<< AUTO_INCREMENT,
firstname VARCHAR(255) NOT NULL,
[Err] 1075 - Incorrect table definition; there can be only one auto column and it must be defined as a key
PRIMARY KEY (email) is the issue. Make id your primary key.
I am having trouble with my create a table .php script, It creates all tables in the database except one which is 'useroptions'. I am new to php but still understand it to an extent, feedback and help would be greatly appreciated.
<?php
include_once("php_includes/db_connect.php");
$tbl_users = "CREATE TABLE IF NOT EXISTS users (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(100) NOT NULL,
lastname VARCHAR(100) NOT NULL,
email VARCHAR(255) NOT NULL,
password VARCHAR(255) NOT NULL,
gender ENUM('m','f') NOT NULL,
avatar VARCHAR(255) NULL,
ip VARCHAR(255) NOT NULL,
signup DATETIME NOT NULL,
lastlogin DATETIME NOT NULL,
notescheck DATETIME NOT NULL,
activated ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (id),
UNIQUE KEY email (email)
)";
$query = mysqli_query($db_connect, $tbl_users);
if ($query === TRUE) {
echo "<h3>user table created OK :) </h3>";
} else {
echo "<h3>user table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_useroptions = "CREATE TABLE IF NOT EXISTS useroptions (
id INT(11) NOT NULL,
question VARCHAR(255) NULL,
answer VARCHAR(255) NULL,
PRIMARY KEY (id),
UNIQUE KEY email (email)
)";
$query = mysqli_query($db_connect, $tbl_useroptions);
if ($query === TRUE) {
echo "<h3>useroptions table created OK :) </h3>";
} else {
echo "<h3>useroptions table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_friends = "CREATE TABLE IF NOT EXISTS friends (
id INT(11) NOT NULL AUTO_INCREMENT,
user1 VARCHAR(100) NOT NULL,
user2 VARCHAR(100) NOT NULL,
datemade DATETIME NOT NULL,
accepted ENUM('0','1') NOT NULL DEFAULT '0',
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_friends);
if ($query === TRUE) {
echo "<h3>friends table created OK :) </h3>";
} else {
echo "<h3>friends table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_blockedusers = "CREATE TABLE IF NOT EXISTS blockedusers (
id INT(11) NOT NULL AUTO_INCREMENT,
blocker VARCHAR(100) NOT NULL,
blockee VARCHAR(100) NOT NULL,
blockdate DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_blockedusers);
if ($query === TRUE) {
echo "<h3>blockedusers table created OK :) </h3>";
} else {
echo "<h3>blockedusers table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_status = "CREATE TABLE IF NOT EXISTS status (
id INT(11) NOT NULL AUTO_INCREMENT,
osid INT(11) NOT NULL,
account_name VARCHAR(100) NOT NULL,
author VARCHAR(100) NOT NULL,
data TEXT NOT NULL,
postdate DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_status);
if ($query === TRUE) {
echo "<h3>status table created OK :) </h3>";
} else {
echo "<h3>status table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_photos = "CREATE TABLE IF NOT EXISTS photos (
id INT(11) NOT NULL AUTO_INCREMENT,
user VARCHAR(100) NOT NULL,
gallery VARCHAR(16) NOT NULL,
filename VARCHAR(255) NOT NULL,
description VARCHAR(255) NULL,
uploaddate DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_photos);
if ($query === TRUE) {
echo "<h3>photos table created OK :) </h3>";
} else {
echo "<h3>photos table NOT created :( </h3>";
}
////////////////////////////////////
$tbl_notifications = "CREATE TABLE IF NOT EXISTS notifications (
id INT(11) NOT NULL AUTO_INCREMENT,
firstname VARCHAR(100) NOT NULL,
initiator VARCHAR(100) NOT NULL,
app VARCHAR(255) NOT NULL,
note VARCHAR(255) NOT NULL,
did_read ENUM('0','1') NOT NULL DEFAULT '0',
date_time DATETIME NOT NULL,
PRIMARY KEY (id)
)";
$query = mysqli_query($db_connect, $tbl_notifications);
if ($query === TRUE) {
echo "<h3>notifications table created OK :) </h3>";
} else {
echo "<h3>notifications table NOT created :( </h3>";
}
?>
Also I'm getting this error when I click on database ?
Error
SQL query:
SELECT tracking_active
FROM `phpmyadmin`.`pma_tracking`
WHERE db_name = 'circle'
AND table_name = 'blockedusers'
ORDER BY version DESC
MySQL said:
1146 - Table 'phpmyadmin.pma_tracking' doesn't exist
Your useroptions create table statement has an invalid unique key ref: UNIQUE KEY email (email). There is no column email on useroptions. Remove it and it will likely run clean.
As for the query issue, not really sure what you're trying to do.
I am trying to populate a database with tables (am new to this) The message I get back upon execution of .php is:
Table "users" successfully created
Table "tempRes" successfully created
Table "empRec" successfully created
However the second and third tables are not appearing in the database in phpMyAdmin. SHOW TABLES & SHOW TABLE STATUS only shows "user" table.
Does anyone know why this is happening? How can I rectify?
Here is my code:
<?php
// connect to the MySQL server
$conn = new mysqli('localhost', 'fiona', 'xxx', 'Org_db');
// check connection
if (mysqli_connect_errno()) {
exit('Connect failed: '. mysqli_connect_error());
}
// Performs the $sql query on the server to create the table users
$sql = "CREATE TABLE IF NOT EXISTS `users` (
`id` INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
`name` VARCHAR(25) NOT NULL,
`pass` VARCHAR(18) NOT NULL,
`email` VARCHAR(45),
`reg_date` TIMESTAMP
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8";
// performs query to check table successfully created or get error message
if ($conn->query($sql) === TRUE) {
echo '<br/>Table "users" successfully created<br/>';
}
else {
echo 'Error: '. $conn->error;
}
// Performs the $sql query on the server to create the table temporary reservations
"CREATE TABLE IF NOT EXISTS `tempRes` (
`tr_id` INT NOT NULL AUTO_INCREMENT,
`aaid` INT NOT NULL,
`cid` INT NOT NULL,
`date_res` DATE NOT NULL,
`rem` VARCHAR(5) NOT NULL,
primary key ( `tr_id` )) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8";
if ($conn->query($sql) === TRUE) {
echo 'Table "tempRes" successfully created<br/>';
}
else {
echo 'Error: '. $conn->error;
}
// Performs the $sql query on the server to create the table employee records
"CREATE TABLE IF NOT EXISTS `empRec` (
`eid` INT NOT NULL auto_increment,
`empPos` VARCHAR( 20 ) NOT NULL,
`tfn` INT NOT NULL,
`emp_DOB` DATE NOT NULL,
`eStart` DATE NOT NULL,
`super_co` VARCHAR( 30 ),
`s_mem_no` INT NOT NULL,
`icin` INT NOT NULL,
`epn` INT NOT NULL,
primary key ( emp_id )) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8";
if ($conn->query($sql) === TRUE) {
echo 'Table "empRec" successfully created<br/>';
}
else {
echo 'Error: '. $conn->error;
}
?>
Your not storing the second and third create statements in $sql variable. That's why isn't it?
Add $sql = infront of those two statements as well
I am trying to read from a database in MySQL and insert my data in another database in MySQL .
my first table is like this
CREATE TABLE IF NOT EXISTS `link` (
`_id` bigint(20) NOT NULL AUTO_INCREMENT,
`country` varchar(30) COLLATE utf8 DEFAULT NULL,
`time` varchar(20) COLLATE utf8 DEFAULT NULL,
`link` varchar(100) COLLATE utf8 DEFAULT NULL,
PRIMARY KEY (`_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=6149 ;
and the second table is
CREATE TABLE IF NOT EXISTS `country` (
`ID` int(11) NOT NULL AUTO_INCREMENT,
`Name` varchar(15) CHARACTER SET utf8 NOT NULL,
`Logo` varchar(50) CHARACTER SET utf8 DEFAULT NULL,
PRIMARY KEY (`ID`),
UNIQUE KEY `Name_3` (`Name`),
UNIQUE KEY `ID` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8457 ;
There are about 6114 rows in first table that I'm trying to insert to second using this code
<?php
$tmp = mysqli_connect(******, *****, ****, *****); // First table in here
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$main = mysqli_connect(*****, *****, ****, ******); //Second table in here
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$req = "SELECT country FROM link";
$result = mysqli_query($tmp, $req) or die( mysqli_error($tmp) );
echo "-> ".mysqli_num_rows($result)."<br>";
while ($row = mysqli_fetch_array($result)) {
$con = $row["country"];
$req = "INSERT IGNORE INTO country (Name) VALUES ('$con')";
mysqli_query($main, $req) or die( mysqli_error($main) ) ;
}
?>
problem is the php code works but for 6114 take a very long time which I can't afford .
what is causing the code to take this long to work ? is it the "INSERT IGNORE" ?
is there any way I can do this faster ?
Since the databases are on the same server, you can simply use INSERT ... SELECT (which avoids having to bring the data into PHP and loop over the results executing separate database commands for each of them, so will be considerably faster):
INSERT INTO db2.country (Name) SELECT country FROM db1.link
you can try a create an index on column "country" of table Link.