How to update or add value to JSON [duplicate] - php

Question

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Is there a JSON api based CMS that is hosted locally? [closed]
(1 answer)
Update JSON value if exists otherwise add it in PHP
(2 answers)
Closed 3 years ago.
I am running an app from AndroidHive which has feed.json which the app loads the content below from.
http://api.androidhive.info/feed/feed.json and this is the post url http://www.androidhive.info/2014/06/android-facebook-like-custom-listview-feed-using-volley/
{
"feed": [{
"id": 1,
"name": "National Geographic Channel",
"image": "A URL",
"status": "Science and etc"
And Cosmos is all about making science an experience.
","
profilePic ": "
A URL ","
timeStamp ": "
1403375851930 ","
url ": null
}]
}
the above is the default content am wondering how to i add more to this content from or using a php script. I would love to know how to do it because I noticed that most application source code created in www_androidhive_info uses .json to load content which is an alternative to webview

Answer 1

You can use json_decode() function to convert JSON string to object, add your variable, and then conver the object back to JSON
$obj = json_decode($json, true);
$obj->feed[0]->url = "google.com"
:

Answer 2

Load the JSON
Decode the JSON
Add your content
Encode to JSON
Send it to your app
Code:
<?php
function failure($reason) {
header('HTTP/1.1 500 Internal Server Error');
echo json_encode(['failure' => $reason]);
exit;
}
// 1. Load the JSON
$content = file_get_contents('http://api.androidhive.info/feed/feed.json');
if (!$content) {
return failure('Failed to load upstream JSON');
}
// 2. Decode the JSON
$decodedContent = json_decode($content, true);
if ($decodedContent === false) {
return failure('Failed to parse upstream JSON');
} elseif (empty($decodedContent)) {
return failure('Upstream JSON empty');
}
// 3. Add your content
$decodedContent['feed'][] = [
"id": 12,
"name": "An example name",
"image": "https://example.com/test_image.jpg",
"status": "Hello!",
"profilePic": "https://example.com/test_profile_pic.jpg",
"timeStamp" => time(),
"url" => "https://example.com"
];
// 4. Encode to JSON
$responseContent = json_encode($decodedContent);
// 5. Send it to your app
echo $responseContent;

Answer 3

Decode the JSON and make new function for changes then encode back.
<?php
$JsonVar = file_get_contents('http://api.androidhive.info/feed/feed.json');
$myjson = json_decode($JsonVar,true);
function Changes() {
$myjson->feed[2]->name = "FeedID2";
$myjson->feed[2]->id = "2";
$myjson->feed[2]->image = "link to image.png";
$myjson->feed[2]->status = "I am here.";
$myjson->feed[2]->profilePic = "link to image.png";
$myjson->feed[2]->timeStamp = time();
$myjson->feed[2]->url = 'http://url.com';
}
json_encode(Changes());
?>