Extracting dates from date range - php

Question

Part of my answer was answered by dynamic:
How to extract every Monday and every fortnightly Monday from a range of two dates in PHP?
I've added a foreach loop to print all the mondays in this example:
$start = strtotime('2016-09-05');
$end = strtotime('2016-09-30');
$mondays=array();
$tuesdays=array();
while( $start <= $end ) {
if ( date('N',$start)==1 )
$mondays[]=$start;
$start += 86400;
}
foreach ($mondays as $item) {
print date("D. Y-m-d", ($item));
print ("<br>");
}
and i get these results:
enter image description here
But how do i add an else/if statements to display the tuesdays for example
if the date begins with $start = strtotime('2016-09-06');
I want it to show:
enter image description here
Thanks.

Answer 1

In this code, we first find the DayOfWeek, and then find all dof in range:
// Data
$StartDate = strtotime('2016-09-06');
$EndDate = strtotime('2016-09-30');
$DayOfWeek = date("l", $StartDate); // Determine day of week
$LoopDate = $StartDate;
// Find all DayOfWeek's Between Start and End
$Result = [$StartDate];
while (true) {
$NextDayOfWeek = strtotime("next " . $DayOfWeek, $LoopDate);
if ($NextDayOfWeek > $EndDate) {
break;
}
$Result[] = $LoopDate = $NextDayOfWeek;
}
// Print Result
/**
| 2016-09-06
| 2016-09-13
| 2016-09-20
| 2016-09-27
*/
foreach( $Result as $Row ) {
echo date("Y-m-d", $Row) . '<br/>';
}

Answer 2

In keeping with your current approach:
$start = strtotime('2016-09-05');
$end = strtotime('2016-09-30');
while($start <= $end) {
if(date("D", $start) == "Mon"){
$mondays[] = $start;
}
elseif(date("D", $start) == "Tue"){
$tuesdays[] = $start;
}
$start += 86400;
}
foreach ($mondays as $item){
echo date("D. Y-m-d", $item);
echo "<br>";
}
echo "<br>";
foreach ($tuesdays as $item){
echo date("D. Y-m-d", $item);
echo "<br>";
}