How to increase date using php based on condition? - php

Question

Well, I have following code : It's return next all date base on given date until do-while loop end.
$paid = 2600;
$monthly = 700;
$x=0;
do {
$monthly;
$date = date('2016'.'-'.'05'.'-d');
$time = strtotime($date);
$bill_month = date("Y-m-d", strtotime("+$x month", $time));
echo "$bill_month => $monthly <br/>";
$paid -= $monthly;
if ($paid < $monthly) {
$monthly = $paid;
}
$x++;
} while ($paid > 0);
It's return following result :
2016-05-12 => 700
2016-06-12 => 700
2016-07-12 => 700
2016-08-12 => 500
And I have another array which is bellow :
$date_array = array("2016-05-12", "2016-07-12");
Now I want to show following date using above do-while loop :
2016-06-12
2016-08-12
2016-09-12
2016-10-12
I mean :
You know above do while loop return all next date until end the loop. for example : next 4 months from given date.
But I want to show next 4 months which is not exist in $date_array. That's mean these 4 months :
2016-06-12
2016-08-12
2016-09-12
2016-10-12

Answer 1

Simply check if generated is not in $date_array, if it is get next month:
$found = false;
while (!$found) {
$date = date('2016'.'-'.'05'.'-d');
$time = strtotime($date);
$bill_month = date("Y-m-d", strtotime("+$x month", $time));
$found = !in_array($bill_month,$date_array);
++$x;
}
echo "$bill_month => $monthly <br/>";
and remove ++$x at and of while loop
cleaner if
$bill_month = date("Y-m-d",strtotime(($x++) . " month"),$time));
Full example:
<?php
/**
*/
$paid = 2600;
$monthly = 700;
$date_array = array("2016-05-12", "2016-07-12");
$x=0;
do {
$found = false;
while (!$found) {
$date = date('2016'.'-'.'05'.'-d');
$time = strtotime($date);
$bill_month = date("Y-m-d", strtotime( ($x++)." month", $time));
$found = !in_array($bill_month,$date_array);
}
echo "$bill_month => $monthly <br/>\n";
$paid -= $monthly;
if ($paid < $monthly) {
$monthly = $paid;
}
} while ($paid > 0);