I wanting to be able to join two tables togeather.
How ever because I my forum table has column "name" and my forum_categories column "name"
I am not able to display both names.
On my select() if I use like $this->db->select('f.name, fc.name', false); it only displays name from forum_categories
array(1) { [0]=> array(1) { ["name"]=> string(17) "News & Discussion" } }
Question how can I get both names to show from both columns and
tables.
Note: I only want to be able to use $result['name'] in my foreach loop.
So the out put I would like it to be
General
News & Discussion
Lounge
I have looked at
CodeIgniter ActiveRecord field names in JOIN statement
codeigniter - select from 2 tables with same column name
Model
public function get_forums() {
$this->db->select('f.name, fc.name', false);
$this->db->from('forum as f');
// tried $this->db->join('forum_categories as fc', 'fc.forum_id = f.forum_id');
$this->db->join('forum_categories as fc', 'fc.forum_categories_id = f.forum_id');
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->result_array();
} else {
return false;
}
}
Controller
<?php
class Forums extends MY_Controller {
public function __construct() {
parent::__construct();
}
public function index() {
$data['label'] = '';
$data['forums'] = array();
$results = $this->get_forums();
var_dump($results);
if (isset($results)) {
foreach ($results as $result) {
$data['forums'][] = array(
'name' => $result['name'], // Only want to use single variable.
);
}
}
$data['header'] = Modules::run('admin/common/header/index');
$data['footer'] = Modules::run('admin/common/footer/index');
$this->load->view('template/forum/list_forum_view', $data);
}
public function get_forums() {
$this->db->select('f.name, fc.name', false);
$this->db->from('forum as f');
$this->db->join('forum_categories as fc', 'fc.forum_categories_id = f.forum_id');
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->result_array();
} else {
return false;
}
}
}
update
works fine with code below but would rather just use one lot of join()
public function get_forums() {
$this->db->select("*");
$this->db->from('forum');
$query = $this->db->get();
foreach ($query->result_array() as $f) {
$data[] = array(
'name' => $f['name']
);
$this->db->select("*");
$this->db->from('forum_categories');
$query = $this->db->get();
foreach ($query->result_array() as $fc) {
$data[] = array(
'name' => $fc['name']
);
}
}
return $data;
}
Try This , It Will Work .
public function get_forums() {
$this->db->select('f.name as forum_name, fc.name as forum_categories_name', false);
$this->db->from('forum f');
// tried $this->db->join('forum_categories fc', 'fc.forum_id = f.forum_id');
$this->db->join('forum_categories fc', 'fc.forum_categories_id = f.forum_id');
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->result_array();
} else {
return false;
}
}
From what i see in your updated question. What you need is UNION and not JOIN. You can use get_compiled_select() to build both query before concat with UNION.
public function get_forums() {
$forum = $this->db->select('name')->get_compiled_select('forum');
$forum_categories = $this->db->select('name')->get_compiled_select('forum_categories');
$query = $this->db->query($forum.' UNION '.$forum_categories);
if ($query->num_rows() > 0) {
return $query->result_array();
} else {
return false;
}
}
Simply use
AS
keyword, because when you try to print it, that AS keyword give you optional name for your column.
Here i have two table which have same column name "name" so i have changed those with AS keyword.
Ex:
$this->db->select('tbl_category.id_category,tbl_category.name AS cat_name,
tbl_subject.id_subject,tbl_subject.name AS sub_name');
In result
Array ( [0] => Array ( [id_category] => 9 [cat_name] => OL [id_subject] => 13 [sub_name] => Science )
So it is simple solution from the SQL language
Related
I have this php function in codeigniter where it fetches the data from my database:
function fetch_data()
{
$data = $this->projectionchart_model->make_query();
$array = array();
foreach($data as $row)
{
$array[] = $row;
}
$output = array(
'current' => intval($_POST["current"]),
'rowCount' => 10,
'total' => intval($this->projectionchart_model->count_all_data()),
'rows' => $array
);
echo json_encode($output);
}
I want to use the number_format function to some of columns and right now it's building everything in an array. How could I remove the array and list the data individually as variables so I can apply a function to some of them and then output them?
Thank you
Edit: explaining in more detail
This function fetch_data() calls the make_query() function stored in the projectionchart_model file which contains the following:
function make_query()
{
if(isset($_POST["rowCount"]))
{
$this->records_per_page = $_POST["rowCount"];
}
else
{
$this->records_per_page = 10;
}
if(isset($_POST["current"]))
{
$this->current_page_number = $_POST["current"];
}
$this->start_from = ($this->current_page_number - 1) * $this->records_per_page;
$this->db->select("*");
$this->db->from("projection_chart");
if(!empty($_POST["searchPhrase"]))
{
$this->db->like('ae', $_POST["searchPhrase"]);
$this->db->or_like('client', $_POST["searchPhrase"]);
$this->db->or_like('product', $_POST["searchPhrase"]);
$this->db->or_like('week_of', $_POST["searchPhrase"]);
$this->db->or_like('month', $_POST["searchPhrase"]);
$this->db->or_like('type', $_POST["searchPhrase"]);
}
if(isset($_POST["sort"]) && is_array($_POST["sort"]))
{
foreach($_POST["sort"] as $key => $value)
{
$this->db->order_by($key, $value);
}
}
else
{
$this->db->order_by('id', 'DESC');
}
if($this->records_per_page != -1)
{
$this->db->limit($this->records_per_page, $this->start_from);
}
$query = $this->db->get();
return $query->result_array();
}
So the output currently is this:
I want to format the Planned Spend, Cleared and Total Commission with the number_format php function but right now it's all in an array.
How could I accomplish this?
I have a question
Let say we have this 2 tables in our database
first table : category_lists
second table: data_category
so if list_data_id is equal to 1 meaning that it has 2 data if you look at data_category table which is 6 and 7
Now what I want is to query from category_list table so that 6 and 7 will echo Car Wreckers and Cash For Cars.
This is what my code looks like:
below is my controller:
public function index($listing_name)
{
$this->load->view('layouts/head_layout_seo');
$this->load->view('layouts/head_layout');
$data['main_view'] = 'listings/main_view';
$data['listing_data'] = $this->Listing_model->get_detail_listing($listing_name);
$list_id = $data['listing_data']->list_data_id; // this is what I get list_data_id is equal to 1
$data['category_ads'] = $this->Ads_model->get_ads($list_id); // this is what you need to look
$this->load->view('layouts/main', $data);
$this->load->view('layouts/footer_layout');
}
below is my model:
public function get_ads($list_id)
{
$this->db->where('list_data_id', $list_id);
$query = $this->db->get('data_category');
$query = $query->result();
//return $query;
if (count($query) > 0) {
for ($i=0; $i < count($query); $i++) {
foreach ($query as $value) {
$this->db->where('category_lists_id', $value->category_lists_id);
$querys = $this->db->get('category_lists');
//print_r($query);
return $querys->result();
}
}
}
}
below is my view:
foreach ($category_ads as $value) {
<p><?php echo $value->categories; ?></p> }
with the code above I get only 1 data which is Car Wreckers as you can see from the table, it supposes to show 2 data Car Wreckers and Cash For Cars
Can anyone help me with this?
Thank You
Try this, in your model so no need to call DB two times and no need to loop
public function get_ads($list_id)
{
$this->db->select('cl.category_lists_id,cl.categories');
$this->db->from('category_lists cl');
$this->db->join('data_category dc','cl.category_lists_id = dc.category_lists_id');
$this->db->where('dc.list_data_id',$list_id);
$query = $this->db->get();
if($query->num_rows() > 0){
return $query->result();
}else{
return array();
}
}
i want to make pagination on ci from other web reference, but average of them use only 1 table
does anyone know how to input more than 1 table on this condition
public function data($number,$offset){
return $query = $this->db->get('client',$number,$offset)->result();
}
i have try to input like this
public function data($number,$offset){
return $query = $this->db->get('client,advertisement,size',$number,$offset)->result();
}
but the result is not my expected
the NAMA is looping, the IKLAN too but the SIZE is not
i take the refences from here
I use this:
public function fetch_countries($limit, $start) {
$this->db->limit($limit, $start);
$this->db->join('client', 'advertisement.id_client= client.id_client','inner');
$this->db->join('size', 'advertisement.id_size= size.id_size','inner');
$query = $this->db->get("advertisement");
if ($query->num_rows() > 0) {
foreach ($query->result() as $row) {
$data[] = $row;
}
return $data;
}
return false;
}
I have two tables sport_tbl, match_tbl. In sport_tbl, i defined sport_name such as cricket. In match_tbl, I have match_name,match_date,sport_id.
I want to show match_date of every sport_name (ex. i am showing match_date list for cricket sport and i want to show every date has match_name list).
I want to show one distinct match_date.
Image
my controller code:-
$url = 'cricket' // for example first sport_name
$data['getSportMatch'] = $this->user_model->getSportMatch($url);
my model code:-
public function getSportMatch($sport)
{
$query = $this->db->get_where('match_tbl',array('sport_name' => $sport));
if($query->num_rows > 0)
{
foreach($query->result() as $item){
$data[] = $item;
}
return $data;
}
}
my code in view:-
<div><?php foreach($getSport as $item): ?><h4><?= $item->sport_name; ?></h4><div><?= foreach($getSportMatch as $item): ?>
match_date)) ?>here i want to show list match_name of every match_date
My table structure images
1) sport_tbl
2) match_tbl
3) another match_tbl
you can solve this in model easily. if i did not understand wrong . you need 2 function in model.
1. will get sport names
2. will get matches of given sport name
//model functions
function get_sports(){
$data = array();
$sports = $this->db->select('sport_name')->from('sport_tbl')->get()->result();
if($sports)
{
foreach($sports as $sport){
$data[$sport->sport_name] = $this->get_matches($sport->sport_name);
}
return $data;
}
}
function get_matches($sport_name){
$matches = $this->db->select('*')->from('match_tbl')->where('sport_name',$sport_name)->get()->result();
return $matches;
}
so in view data will be something like this
$data => array(
'cricket'=> array(0 => array(
'match_id' => 11,
'sport_id' = 2 .....
)))
Try this coding ...
public function getSportMatch($sport)
{
$query = $this->db->query("SELECT * FROM sport_tbl as st INNER JOIN match_tbl as mt ON st.sport_id = mt.sport_id WHERE st.sport_name ='".$sport."'");
if($query->num_rows > 0)
{
$query_result = $query->result_array();
$final_result = array();
foreach($query_result as $result ) {
$date = $result['match_date'];
$final_result[$date][] = $result;
}
return $final_result;
}
}
View Coding :-
if(isset($final_result)) {
foreach($final_result as $result) {
echo $result['match_date']; // First display match date
if(isset($result['match_date'])) {
foreach($result['match_date'] as $match) {
echo $match['match_name']; // Second listout the match name
}
}
}
}
Am working on a student portal, below is the code i used for students position but, every user keeps getting 1st position. Every student seems to have 1st position, when they check their results from the front view. Cant seem to figure out where the problem is from in the code
function get_position($student, $class, $session, $term){
$this->db->select('*');
$this->db->from('result');
$this->db->where(array( 'class_id'=>$class, 'Session'=>$session, 'Term'=>$term));
$this->db->order_by('Total', 'asc');
$other_results = $this->db->get()->result_array();
$this->db->select("*");
$this->db->from('result');
$this->db->where(array('class_id'=> $class, 'Session'=>$session, 'Term'=>$term, 'StudentID'=>$student ));
$student_result = $this->db->get()->result_array();
$student_total = $this->get_student_total($student_result);
$position =1;
foreach($other_results as $res){
if($student_total < $res['Total']){
$position++;
}
}
return $position;
}
function get_student_total($result){
$total = 0;
foreach($result as $res){
$total+= $res['Total'];
}
return $total;
}
}
?>
I am assuming that the result table may have many records for a given studentID. Several test scores (Totals) for each student during the term right?
This should do the trick
public function get_position($student, $class, $session, $term)
{
//I like to use db method chaining.
$ranking = $this->db->select('StudentID')
->select_sum('Total', 'sumScore')
->from('result')
->where(array('class_id' => $class, 'Session' => $session, 'Term' => $term))
->group_by('StudentID')
->order_by('sumScore', 'desc')
->get()->result_array();
//The code above retrieves results from a query statement that looks like this:
//SELECT `StudentID`, SUM(`Total`) as sumScore
//FROM `result` where `class_id` = $class and `Session` = $session and `Term` = $term
//GROUP BY `StudentID`
//order by `sumScore` desc
$position = 1;
foreach($ranking as $rank)
{
if($rank['StudentID'] !== $student)
{
++$position;
}
else
{
return $position;
}
}
return NULL; //to indicate studentID was not found
}