PHP conditional statetment from form [duplicate] - php

Question

This question already has answers here:
The 3 different equals
(5 answers)
Closed 6 years ago.
How do I make the statement below work. I have a form that post the values to my function.php. Is it possible for me to include the .html files on the function.php as a content rather than heading to the locations? I am new student learning the hard way.
<?php
if ($_POST['city'] = 'london'){
header('Location: london.html');
}
if ($_POST['city'] = 'manchester'){
header('Location: manchester.html');
}
if ($_POST['city'] = 'conventry'){
header('Location: coventry.php');
}
exit;
?>

Answer 1

You have to use == in if statement, not =.
Try this,
<?php
if ($_POST['city'] == 'london'){
header('Location: london.html');
}
if ($_POST['city'] == 'manchester'){
header('Location: manchester.html');
}
if ($_POST['city'] == 'conventry'){
header('Location: coventry.php');
}
exit;
?>
Check the below link for more info.
https://www.tutorialspoint.com/php/php_decision_making.htm

Answer 2

If you are just using the value in the location as a straight swap of destination - you don't need any ifs at all - just put the variable in the location:
<?php
$city = $_POST['city'];
header('Location:' . $city . '.html');
exit;
?>
//$city = london;
//header('Location:london.html');
If you have different file extensions - eg the .html and .php that you show here - then you can use a switch statement to reduce the if statements:
<?php
$city = $_POST['city'];
switch ($city) {
case "london":
header('Location: london.html');
break;
case "manchester":
header('Location: manchester.html');
break;
case "coventry":
header('Location: coventry.php');
break;
default:
echo "Your destination did not match any of our available cities";
}
exit;
?>