I've searched everywhere for an answer to this, and I truly do hate asking what is probably a really simple question, but I am lost.
This is the code I'm using to display a pie cart ...
$s1 = array(
array('Carpets',235000),
array('Vinyl',35069),
array('LVT',36911),
array('Laminate',5243.97)
);
$pc = new C_PhpChartX(array($s1),'chart1');
$pc->set_grid(array('drawBorder'=>true,
'drawGridlines'=>false,
'background'=>'#ffffff',
'shadow'=>false));
$pc->set_axes_default(array());
$pc->set_series_default(array(
'renderer'=>'plugin::PieRenderer',
'rendererOptions'=>array('showDataLabels'=>true)));
$pc->set_legend(array('show'=>true,
'rendererOptions'=> array('numberRows'=> 1),
'location'=> 's'));
$pc->draw(400,400);
The chart works fine like this for testing purposes, but when I try and replace the data inside the data array with variables, no chart appears. I think it may be to do with the way the data in the array is being passed to the JavaScript, but I am not skilled enough to fix.
The data is in variables ... $cTotal, $vTotal, $lTotal & $laTotal
I have echoed these and can confirm they are just producing an integer.
I have tried ...
$s1 = array(
array('Carpets',$cTotal),
array('Vinyl',$vTotal),
array('LVT',$lTotal),
array('Laminate',$laTotal)
);
As well as using "" and "{}", but to no avail.
OK, so I figured it out. For some reason when I used ...
$cTotal= $dataLabel['carpet'];
It echoed 236987. But didn't work. However, had a last minute thought and physically forced it to be an integer with ..
$cTotal= (int)$dataLabel['carpet'];
... and it worked. I thought PHP was clever enough to figure that out for itself!
Related
I'm pulling google map data into a php array from MySQL. I have used this code as a base:
https://github.com/rajkavinchetty/Google-Maps-API-with-PHP-MySQL/blob/master/index.php
It almost works perfectly. The lat/long data is pulled from the array and sets-up the markers.
...
$locations[]=array( 'name'=>$name, 'lat'=>$latitude, 'lng'=>$longitude, 'lnk'=>$link );
...
But I'm having problem with the Title/Content of the infowindow.
With the base example I'm using, the content is formatted as a link:
var locations = [
<?php for($i=0;$i<sizeof($locations);$i++){ $j=$i+1;?>
[
'AMC Service',
'<p><?php echo $locations[0]['name'];?></p>',
<?php echo $locations[$i]['lat'];?>,
<?php echo $locations[$i]['lng'];?>,
0
]<?php if($j!=sizeof($locations))echo ","; }?>
];
but the variable pulls only the first link and name from the array, it does not go through the loop. I have tried many different variables, such as
<?php echo $locations[$i]['name'];?>
but this gives an error.
I'm not an expert in either php arrays or loop or java, so I'm fumbling around for clues. I've looked through all of the related questions here for help, and also consulted the Google stack as well.
Any help would be appreciated.
UPDATE:
The first three replies were useful, thank you, but no there yet.
After the comment from Andy, and encouragement from Divyamohan that the original solution should have worked, I realised that there must be some json formatting problem, so I tried:
<?php echo json_encode($locations[$i]['name']);?>
This worked and now I'm able to have these loop through.
But still trying to get this to work as an href link. I tried to solve with backslashes as Hardik and David observed, but still this does not work. Half way there.
'<p><?=$locations[$i]["name"]?></p>'
Just Replace this in your code and it should work.
You need to change this line
'<p><?php echo $locations[0]['name'];?></p>'
to
'<p><?php echo $locations[0][\'name\'];?></p>'
You need to add backslash ( \ ) character to escape quote from string literals.
So finally I found the solution to the problem. Thanks to the comments from everyone that helped me to look at it another way.
In the end, the problem was not with the code. The problem was the data. This should have been obvious. In the links column I had URLs with slashes and text in the names column included apostrophes and foreign characters. These combined were throwing off the json errors. I cleaned all the data and the modified code works perfectly.
<p><?=$locations[$i]['name']?></p>
Many thanks again for the comments.
I've been working with PHPExcel over the last few days and so far it's been perfect for what I need. However, today I've been trying to use mergeCells for "colspan" functionality but when I do it causes unreadable content errors and MS Excel prompts me to repair the file.
The code I'm using is:
$first = PHPExcel_Cell::stringFromColumnIndex($xCount).$yCount;
$second = PHPExcel_Cell::stringFromColumnIndex( $xCount + 2).$yCount;
$cell_merge = $first.":".$second;
$this->excelDoc->getActiveSheet()->mergeCells( $cell_merge );
I've output the result of $first, $second and $cell_merge to ensure I'm going about it the right way and the content is correct. Furthermore, when I try a static merge of cells (by entering mergeCells('A1:C1'); it works perfectly.
Would it be possible that trying to write to a merged cell would cause problems?
EDIT: just a note: I also tried to cast the variable as string just in case like this:
$this->excelDoc->getActiveSheet()->mergeCells( (string)$cell_merge );
... but no luck.
Just for future reference. The problem here existed between the keyboard and chair.
I was attempting to change the colspan during a loop and in this loop I had a call to mergeCells with 'A0:C0'.
When passing row "0" I wasn't getting any errors, just a bad excel sheet. Something to bear in mind.
Using PHP, I'm trying to grab data from the Goodreads API, which returns XML. I've been having a hell of a time trying to figure out how to pull data out of it.
At some point in the adventure, someone suggested I do a json decode( json encode ($blah)) of the whole thing and use JSON instead of XML.
That brings me to my current situation. Everything works as it should, up to the point where I'm pulling data out of the returned array. I probably should have spent more time reading and learning about arrays, but after more than two days of doing every Google search I could think of, I came here.
Here's the entirety of what gets returned by Goodreads:
a:2:{s:7:"Request";a:3:{s:14:"authentication";s:4:"true";s:3:"key";a:0:{}s:6:"method";a:0:{}}s:6:"search";a:7:{s:5:"query";a:0:{}s:13:"results-start";s:1:"1";s:11:"results-end";s:1:"1";s:13:"total-results";s:1:"1";s:6:"source";s:9:"Goodreads";s:18:"query-time-seconds";s:4:"0.06";s:7:"results";a:1:{s:4:"work";a:9:{s:11:"books_count";s:1:"7";s:2:"id";s:7:"5024045";s:24:"original_publication_day";s:2:"16";s:26:"original_publication_month";s:1:"9";s:25:"original_publication_year";s:4:"2008";s:13:"ratings_count";s:3:"227";s:18:"text_reviews_count";s:2:"53";s:14:"average_rating";s:4:"4.33";s:9:"best_book";a:5:{s:2:"id";s:7:"4958245";s:5:"title";s:37:"7 Habits of Happy Kids [With Earbuds]";s:6:"author";a:2:{s:2:"id";s:5:"38343";s:4:"name";s:10:"Sean Covey";}s:9:"image_url";s:56:"http://photo.goodreads.com/books/1343744353m/4958245.jpg";s:15:"small_image_url";s:56:"http://photo.goodreads.com/books/1343744353s/4958245.jpg";}}}}}
What I want from this array is the "id" variable appears under "best_book". For that, I'm using these lines of code:
$goodreads_results = json_decode(json_encode((array) simplexml_load_string($goodreads_data_a)), 1);
$goodreads_id = $goodreads_results->search->results->work->best_book->id;
I should point out that the array I posted (that began "a:2:{s:7") is what's contained in $goodreads_results after the above two lines of code. So I know everything UP TO that point works as it should.
For whatever reason, I'm not getting the ID. The $goodreads_id variable is empty.
Can somebody help me figure out why? Even though I know it's likely something basic, I'm lost, and everything is starting to look the same to me.
Try:
<?php
$goodreads_data_a = 'a:2:{s:7:"Request";a:3:{s:14:"authentication";s:4:"true";s:3:"key";a:0:{}s:6:"method";a:0:{}}s:6:"search";a:7:{s:5:"query";a:0:{}s:13:"results-start";s:1:"1";s:11:"results-end";s:1:"1";s:13:"total-results";s:1:"1";s:6:"source";s:9:"Goodreads";s:18:"query-time-seconds";s:4:"0.06";s:7:"results";a:1:{s:4:"work";a:9:{s:11:"books_count";s:1:"7";s:2:"id";s:7:"5024045";s:24:"original_publication_day";s:2:"16";s:26:"original_publication_month";s:1:"9";s:25:"original_publication_year";s:4:"2008";s:13:"ratings_count";s:3:"227";s:18:"text_reviews_count";s:2:"53";s:14:"average_rating";s:4:"4.33";s:9:"best_book";a:5:{s:2:"id";s:7:"4958245";s:5:"title";s:37:"7 Habits of Happy Kids [With Earbuds]";s:6:"author";a:2:{s:2:"id";s:5:"38343";s:4:"name";s:10:"Sean Covey";}s:9:"image_url";s:56:"http://photo.goodreads.com/books/1343744353m/4958245.jpg";s:15:"small_image_url";s:56:"http://photo.goodreads.com/books/1343744353s/4958245.jpg";}}}}}
';
$goodreads_results = unserialize($goodreads_data_a);
echo $goodreads_id = $goodreads_results['search']['results']['work']['best_book']['id'];
?>
The problem i'm facing right now is im getting a URL, like so:
www.example.com/example.php?url=www.google.com
now the problem is, if theres a get in my url, like so:
www.example.com/example.php?url=www.google.com?id=1
it doesn't actually cause a problem yet, but if theres two GET vars in the my URL, it doesn't know where the "and" goes, the first get or the second one, and basically just chooses the first, ex:
www.example.com/example.php?url=www.google.com?id=1&username=me
is there a workaround? I could recode a lot of things to have it as one get variable, but it'll involve a lot of work and I wish i could have a solution!
thanks!
Heres my code:
$facebookapi=new facebook(array('appId'=>'*******','secret'=>'********','fileUpload'=>'false'));
$url='http://******.com/questions/view.php?id=884&username=robot';
$facebookapi->api('/me/******app:answer?question=' . urlencode($url),'POST');
You need urlencode to encode the url parameter.
$url = 'www.google.com?id=1';
echo 'www.example.com/example.php?url='.urlencode($url).'&username=me';
Edit:
After seeing your posted code, it seems that you should use the third parameter for params.
$url='http://******.com/questions/view.php?id=884&username=robot';
$facebookapi->api('/me/******app:answer', 'POST', array('question' => $url));
Well the function urlencode is perfect for this.
Once the url is encoded,
The first get variable will turn from this
www.google.com?id=1&username=me
to this
www.google.com%3Fid%3D1&6username=me
Your website will then appear as [www.example.com/example.php?url=www.google.com%3Fid%3D1%26username%3Dme]
Once PHP receives that variable you can decode it
$url = urldecode($_GET['url']);
Note: some versions of PHP do it automatically.
I'm having this problem that's driving me nuts.
I've got a MySQL database in which there is a table that contains a text field. I am querying the table in PHP and trying to put the content of the text field for each row into a var.
I am doing something like this:
for ($i=0;$i<$nbrows;$i++){
$id = $data[$i]['ID'];
$description = $data[$i]['DESCRIPTION'];
$mystring .= '<div>'.$id.': '.$description.'</div>';
}
DESCRIPTION is my text field.
I'll pass on the details. The $data array is built from mysql_fetch_array($result). I also tried using objects instead, as I use mysql_fetch_object for all my other routines, but there is no change.
Anyway, the problem is this: if I do "echo $description;" then it works. I am getting my text field data as expected. The problem is that I don't want to output it directly, but add it to a concatenated string, and that is not working. What happens in that case is it seems to be taking $description for some kind of array or object. To make the above example work, I have the replace the string with:
$mystring .= '<div>'.$id.': '.$description[0].'</div>';
So in the concatenated string code, if I treat $description as an array, it works, but obviously I am getting only one letter. (it doesn't actually seem to be an array because I can't implode it).
I tried a million things but I just can't make this work unless I use echo, but that is not what I am trying to do.
There is no issue with fields that aren't text.
Thanks for any ideas!
There is nothing visually wrong with the code you pasted, maybe if you could also add the fetching function as well, we might be able to help you further.
Maybe you could post a var_dump of your $data array?
Have you tried $mystring .= "<div> $id : $description </div>";
Ack, well, you know, hours spent on this and then it becomes obvious after I decide to post for help. This is just because of text encoding/escaping and nothing else. I just didn't see well enough where the problem was actually happening.
Thanks for taking the time to read and respond!