Extract part of url in php - php

Question

I have a url: http://domain.tld/123456789abc.html
My goal is to create an embed code like this:
<iframe src="http://domain.tld/embed-123456789abc-620x360.html" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" width="620" height="360"></iframe>
But instead of gave me this:
<iframe src="http://domain.tld/embed-123456789abc.html-620x360.html" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" width="620" height="360"></iframe>
Notice the ".html" included above (123456789abc.html-620x360)?. How can create the code without the ".html" from the source url?
This is the code being used.
elseif (substr_count($link,"domain")){
$video_id = explode("/",$link);
if (isset($video_id[count($video_id)-1])){
$video_id = $video_id[count($video_id)-1];
$embed = '<IFRAME SRC="http://domain.tld/embed-'.$video_id.'-'.$width.'x'.$height.'.html" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" width="'.$width.'" height="'.$height.'"></iframe>';
}
Appreciate the help. Thank you.

Answer 1

You need to 'clean' $video_id because the ".html" should be contained into the array component you are retrieving.
So instead of
$video_id = $video_id[count($video_id)-1];
try something like this:
$video_id = str_replace('.html', '', $video_id[count($video_id)-1]);

Answer 2

It might be easier to use a regex to match the last part of your
original link, already excluding the .html:
elseif (substr_count($link,"domain")) {
$embed = preg_replace(
'#.+/([^/]+).html$#',
'<iframe src="http://domain.tld/embed-$1-'
. $width . 'x' . $height . '.html"'
. 'frameborder="0" marginwidth="0" marginheight="0" scrolling="no"'
. 'width="' . $width . '" height="' . $height . '"></iframe>',
$link
);
}