Hi I have a hyperlink from a page:
<h3>hitest</h3>
the route:
Route::get('hitest', function(){ return 'hitest message';});
There is an error:
No query results for model [App\User2].
hyper link is from a page with this url
/userpage/1
the 1 is a model object.
Shouldn't the hyperlink route to /hitest ?
Please see my other post: Strange behavior with routing and hypertext.
I'm new at web development. Is there configurations for routing? The app is hosted (not local).
As bytesarelife already mentioned, you can use the url()-function, like so:
{{ url('your/url/') }}
A better way in terms of maintainability would be to give your routes names, so you would not have to replace every url in every template once you want to change it. You can do so, by adding the name in your routes:
Route::get('hitest', function(){ return 'hitest message';})->name('getHittest');
And then you can use the route function in your view:
{{ route('getHittest') }}
Related
After reading the documentation, I still only have a vague idea of what Named Routes are in Laravel.
Could you help me understand?
Route::get('user/profile', function () {
//
})->name('profile');
Route::get('user/profile', 'UserProfileController#show')->name('profile');
It says:
Once you have assigned a name to a given route, you may use the route's name when generating URLs or redirects via the global route function
I don't understand what the second part of the sentence means, about generating URLs or redirects.
What would be a generated URL in the case of profile from the above example? How would I use it?
The best resource is right here : https://laravel.com/docs/5.8/routing#named-routes
One of the common use case is in your views. Say your post request goes to a particular route, basically without named routes you can simply go like this to store a task
action="/task"
but say for example you need to update the route to /task/store , you will need to update it everywhere you use the route.
But consider you used a named route
Route::post('/task', 'TaskController#store')->name('task.store');
With named routes you can use the route like this in your view:
action="{{route('task.store')}}"
Now if you choose to update your route, you only need to make the change in the routes file and update it to whatever you need.
Route::post('/task/now/go/here', 'TaskController#store')->name('task.store');
If you need to pass arguments to your routes, you pass it as arguments to route helper like this:
route('task.edit', 1), // in resource specific example it will output /task/1/edit
All of the view examples are given you use blade templating.
After adding a name to a route, you can use the route() helper to create urls.
This can now be used in your application.
For instance, in your blade templates this may look like:
{{ route('profile') }}
This will use the application url and the route path to create a url.
this is how it looks it:
named route sample name('store');:
Route::get('/store-record','YourController#function')->name('store');
store is the named route here. to call it use route('store')
defining another type of route. this is not named route:
Route::get('/store-record','YourController#function')
you can access this route using {{ url('/store-record') }}
hope this helps
I have never understood how to create proper URLs. Every time I end up with trying to figure out if I should do ?var=value or &var=value and then if ?var=value already exists then I end up with ?var=value&var=value.
P.S. I am working with Laravel. (So maybe there is a built-in function?)
For example:
I have pagination and my URL could look like this
www.example.com OR
www.example.com?name=John
Then my pagination link is href="?page=2" and I end up with
www.example.com?name=John?page=2
Then I want to navigate to the next page with href="?page=3" and I end up with this. Because it keeps on adding.
www.example.com?name=John?page=2?page=3
What a mess.... is there a function for PHP or Laravel that would create proper URLS? (knowing when to use ? or & and not add existing values all the time but replace them if they exist already.
If you're using Laravel I think you should use some helper functions:
route('user.profile', ['id' => 1]);
It will create url by route name and parameters, It will look like:
http://sitename/user/profile?id=1
And you can find some useful helper functions here
There should be one and only ? in URL's which separates URI and parameters, rest of the key-value pairs are separated by &, and if you need to pass & or ? as a parameter, then you need to encode them.
you could pass an array to http_build_query and it will build the url for you
and in laravel there are url helper functions you can use them with ease.
Laravel come with a route helper which allow you to generage url quickly by passing the name with which you register your route.
Route::get('/', 'HomeController#index')->name('home.route')
Here you can see I pass home.route to the name method which is the name which I use for this route. And when I want to generate the URL for that route in my view I will juste do
{{ route('home.route') }}
If ny route take some parameters like this
Route::get('/person/{id}', 'HomeController#index')->name('home.route')
In view I will generate the url like this
{{ route('home.route', ['id' =>$id]) }}
Because you want juste to make pagination, Laravel comme with a buil in pagination. When you want to paginate something in your views, you must just call the paginate function on your model and laravel will handle all the route for that. For example I you have a Person Model you can do that like this in your controller
$persons = Person::paginate(25)
And in your views to generate pagination for that you will have to do
{{ $persons->links() }}
And that's all
Hi I'm coming for a very simple question (I think) but i didn't found the answer or a similar case.
I'm using symfony 3 and trying to build a second menu for my administration pannel.
However, I have a problem about how I have to declare the relative url in my "href", For my main menu i used to do like this
{{ url ( 'admin' ) }}
and it worked. The fact is that now I have subfolders and many levels in my url.
The url i try to reach is myapp/admin/gameadmin, this url work when I'm going on it but when i try to put it in 'href' I have an error message which says that the route is not working.
i declared it like that ->
{{ url(admin/gameadmin) }}
I tried with different character -> admin:gameadmin, admin\gameadmin ... etc and with path instead of url i don't know if it's not the good way to declare it or if I have a problem with my controllers.
In my bundle it's organised like that :
->Controllers(folder)
->admin(folder) (You can also find my main controllers on this level)
->admingamecontroller (Where the page I try to reach is routed)
I hope i gave you all the informations, thank you for your help and sorry for my english !
The url parameter is not the the url per se (ie: admin/gameadmin), this is the route name, defined in your routing.yaml file, or in your controller annotation.
If your action is something like this:
/**
* #Route("/admin/gameadmin", name="gameadmin")
*/
public function gameAdminAction()
{
...
}
Then, to generate the route, you have to do this:
{{ url('gameadmin') }}
By doing this, all the links on your website will be up to date if you change the gameadmin url, as long as you don't change the route name.
I suggest you to read this documentation on the Symfony website: https://symfony.com/doc/current/bundles/SensioFrameworkExtraBundle/annotations/routing.html
Edit: As pointed by user254319, if you're not using annotations, you'll have to edit your routing.yaml config file.
gameadmin:
path: /admin/gameadmin
controller: App\Controller\Admin\AdminGameController::gameadminAction
The route name is the yaml key: gameadmin.
Related Symfony documentation: https://symfony.com/doc/current/routing.html
I'm using Vue.js and Laravel to render a simple table listing products. From there I want to link to a product detail page like this:
#{{ product.id }}
Since the table is generated on client side base on a data object, I'm looking for the most elegant way to implement that while not bypassing any laravel methods like route() that allows me to link to a named route.
Do I really have to manually merge the result of the route-method with the Vue variable in Javascript?
In my mind is something like:
#{{ product.id }}
which I could probably parse/inject by Vue via data binding?
As Vue it's client side and laravel it's server side you can't accomplish that in that way.
But you can do something like this over the rendered route:
Create a vue method
goto_route: function (param1) {
route = '{{ route("yournamedroute", ["yourparameter" => "?anytagtoreplace?"]) }}'
location.href = route.replace('?anytagtoreplace?', param1)
}
Now in your action element
<div v-for="o in object">
<a v-on:click="goto_route(o.id_key)">press</a>
</div>
Basically you're replacing the... uhmm... let's name it "placehoder" in the rendered route with the required value.
hope it helps.
With Silex (the PHP micro framework), it's possible to give names to existing controllers, so that we can easily generate urls to them later. Example:
$app->get('/gallery', function () {...})
->bind('gallery');
// Later on, in a template
{{ path('gallery') }}
I think this is really useful and I can't live without it.
But is it possible to register a route to an external website ? Say I'd like to generate urls to a google search, kind of
{{ path('google', {'search':'symfony'}) }}
// Would render to http://google.com/search?q=symfony
I take any idea :) Thx for your help !
path() is a Twig Extension for routing. Routing is to route an incoming URL to a controller action.
You can, however, create your own twig extension if you want a helper to easily create those standard outgoing URLs.
Take a look at: http://symfony.com/doc/current/cookbook/templating/twig_extension.html
You could then create an extension that turns {{ google('search string') }} into a URL. Only the imagination is your boundary.