Identify JSON object from different table - php

Question

I am trying to get data from three different tables (MySQL) using php script in xcode.
I know how to fetch elements from one table but I don't know how I can extend this method to be able to get the data from two other tables using the same php script and NSURLSession in xcode.
My php script for one table (working):
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_DATABASE);
if (mysqli_connect_error()) {
die('Connect Error (' . mysqli_connect_errno(). ') ' . mysqli_connect_error());
}
$sql = "SELECT * FROM table1";
$test = $mysqli->query($sql);
$Nrows = $test->num_rows;
$resultArray = array();
if ($result = mysqli_query($mysqli, $sql)) {
while ($row = $result->fetch_assoc()) {
$resultArray[] = $row;
}
echo json_encode($resultArray);
}
else {
echo 'oups.';
}
Now the problem is that I would like to do the same with two others tables. I tried to incorporate my fetching method in a separate php file (say getElementFunction.php) and calling this method in the main file:
getElementFunction.php
<?php
function getElements()
{
$test = $mysqli->query($sql);
$Nrows = $test->num_rows;
$resultArray = array();
if ($result = mysqli_query($mysqli, $sql)) {
while ($row = $result->fetch_assoc()) {
$resultArray[] = $row;
}
echo json_encode($resultArray);
}
else {
echo 'oups.';
}
}
?>
main_file.php:
$mysqli = new mysqli(DB_HOST, DB_USERNAME, DB_PASSWORD, DB_DATABASE);
if (mysqli_connect_error()) {
die('Connect Error (' . mysqli_connect_errno(). ') ' . mysqli_connect_error());
}
include 'getElementFunction.php';
$sql = "SELECT * FROM table1";
getElements() // --> how can I flag the json object as being returned from table 1
$sql = "SELECT * FROM table2";
getElements() // --> how can I flag the json object as being returned from table 2
$sql = "SELECT * FROM table3";
getElements() // --> how can I flag the json object as being returned from table 3
But I don't know if it is correct and how I could "flag" the different json objects that will be returned in order to be used in my xcode script. I would like to run the fetching process in one loop with only one URL.
Just in case, my objective-C script where I need a way to specify from which table is the json object returned...
XCODE script with NSURLSession:
id jsonObject = [NSJSONSerialization JSONObjectWithData:_downloadedData options:NSJSONReadingAllowFragments error:&error];
if ([jsonObject isKindOfClass:[NSArray class]]) {
NSArray *deserializedArray = (NSArray *)jsonObject;
if (deserializedArray.count > 0) {
dispatch_async(dispatch_get_main_queue(), ^{
...
}
If someone could help me...
Thanks!

Answer 1

Not sure to clearly understand.. But you can try a foreach in getElements().
I mean :
function getElements(array $allSQL)
{
//Final array to json_encode
$finalResultsArray = array();
foreach($allSQL as $tableName => $sqlStatement) {
$arrayResults = array();
$test = $mysqli->query($sqlStatement);
$Nrows = $test->num_rows;
if ($result = mysqli_query($mysqli, $sqlStatement)) {
while ($row = $result->fetch_assoc()) {
$arrayResults[] = $row;
}
//echo json_encode($arrayResults);
$finalResultsArray[$tableName] = $arrayResults;
}
else {
echo 'oups.';
}
}
echo json_encode($finalResultsArray);
}
And this part :
$sql = "SELECT * FROM table1";
getElements() // --> how can I flag the json object as being returned from table 1
$sql = "SELECT * FROM table2";
getElements() // --> how can I flag the json object as being returned from table 2
$sql = "SELECT * FROM table3";
getElements() // --> how can I flag the json object as being returned from table 3
Become this :
$sql1 = "SELECT * FROM table1";
$sql2 = "SELECT * FROM table2";
$sql3 = "SELECT * FROM table3";
getElements(["table1"=> $sql1, "table2" => $sql2, "table3" => $sql3]);