How to get an array instead of json object? - php

Question

<?php
$link = mysql_connect('localhost', 'root', 'admin')
or die('There was a problem connecting to the database.');
mysql_select_db('hospitalmaster');
$hnum = (int)$_POST["hnum"];
$sql = "SELECT d.doctorid, d.doctorname
from hospitalmaster.doctor_master d
inner join pharmacymaster.pharbill e
where e.hnum = '$hnum'
and e.presid = d.d_empno
group by e.presid";
$result = mysql_query($sql);
$response = array();
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
$response = $row;
}
echo json_encode(array("Doctor"=>$response));
} else {
echo ("no DATA");
}
?>
i have the api shown above, but this api is returning me as json objects not an json array? i would like to know how to get dotorid an doctorname as a array, since i have many doctor names and id, i want each doctor and their corresponding id as an idividual array, right now they are returning as individual objects. Since this is my first time writing an api, i dont know how to modify the code.

Answer 1

You are over writing the array each time round the loop.
while ($row = mysql_fetch_assoc($result)) {
$response[] = $row;
//change ^^
}
You should use either mysqli_ or PDO. Here is a suggestion for mysqli_
<?php
$link = mysqli_connect('localhost', 'root', 'admin','hospitalmaster')
or die('There was a problem connecting to the database.');
$sql = "SELECT d.doctorid, d.doctorname
from hospitalmaster.doctor_master d
inner join pharmacymaster.pharbill e
where e.hnum = ?
and e.presid = d.d_empno
group by e.presid";
$stmt = $link->prepare($sql);
$stmt->bind_param('i', (int)$_POST["hnum"]);
$stmt->execute();
if ($stmt->num_rows() > 0) {
$result = $stmt->get_result();
$response = array();
while ($row = $result->fetch_assoc()) {
$response[] = $row;
}
echo json_encode(array("Doctor"=>$response));
} else {
echo ("no DATA");
}
?>