I have two variables (first is of type date and second is of type time):
$ref_date = '2016-12-22';
$ref_time = '09:00';
I need to sum these two and find the date difference from now - summed_variable.
Any suggestions?
Using the PHP DateTime object you can do this quite easily
$ref_date = '2016-12-22';
$ref_time = '09:00';
$ref = new DateTime($ref_date . ' ' . $ref_time);
$now = new DateTime();
$diff = $now->diff($ref);
echo $diff->format('%R%a days %H Hours %i Minutes');
And the result would be
+14 days 22 Hours 30 Minutes
Related
$order_created = date('d.m.Y H:i:s',$items[0]->created2);
$order_deadline = date('d.m.Y H:i:s',$items[0]->created);
$order_created = new DateTime($order_created);
$order_deadline = new DateTime($order_deadline);
$interval = $order_created->diff($order_deadline);
echo $interval->format('%d days %H hours %i minutes')?>;"
Now I want to reduce 30% from the $interval i.e. the date-time being displayed at the end.
For e.g. if the deadline is 10th july after 30% reduction it should display as 7th July along with time.
I would get the difference between the two dates as a timestamp, and then subtract the 30% to create a new DateTime that can then be compared to the order_created.
Example
$order_created = new DateTime("29-07-2016");
$order_deadline = new DateTime("30-07-2016");
//Get the difference in seconds between the two DateTimes
$diff = $order_created->getTimestamp() - $order_deadline->getTimestamp();
//Subtract 30%
$diff = $diff * 0.70;
//Create the new deadline (# is used to initialize a DateTime with a Timestamp)
$new_deadline = new DateTime('#' . ($order_deadline->getTimeStamp() - $diff));
$result = $order_created->diff($new_deadline);
I have this timestamp from the database 1496592689
the problem is I don't know how to get the remaining days, hours and minutes
but I have this code bellow
this is my variable from where the timestamp stored $db_user_timestamp
and now I have this current time now $timenow = time();
I tried to calculate it with
$remainingtime = $db_user_timestamp - $timenow;
But I don't know how to put it in the days, hours and minutes.
Thanks in advance for helping me :)
Always use DateTime
$create_time = "1496592689";
$current_time = time();
$dtCurrent = DateTime::createFromFormat('U', $current_time);
$dtCreate = DateTime::createFromFormat('U', $create_time);
$diff = $dtCurrent->diff($dtCreate);
$interval = $diff->format("%y years %m months %d days %h hours %i minutes %s seconds");
$interval = preg_replace('/(^0| 0) (years|months|days|hours|minutes|seconds)/', '', $interval);
echo $interval;
result
6 months 30 days 5 hours 52 minutes
If your PHP version is 5.3 or latest, you should check
http://php.net/manual/en/class.dateinterval.php
and
http://php.net/manual/en/datetime.diff.php
$datetime1 = new DateTime(date('Y-m-d H:i:s', $db_user_timestamp));
$datetime2 = new DateTime(date('Y-m-d H:i:s'));
$interval = $datetime1->diff($datetime2);
echo $interval->format('%y years %m months %d days %h hours %m minutes %s seconds');
<?php
$db_user_timestamp = 1496592689;
$difference = $db_user_timestamp - time();
echo "Day : ".$day = date('d',$difference);
echo "<br>Hour : ".$hour = date('H',$difference);
echo "<br>Minute : ".$minute = date('i',$difference);
?>
Using date('M/d/Y H:i:s', $theTimestamp); will give you date in day, month, year, hour, minute, seconds in the order you want (change 'M/d/Y H:i:s' to your string depending on http://php.net/manual/en/function.date.php)
I want to calculate the time difference from now (lets say 18:30:00) till this evening at 20pm.
$today = date('Y-m-d', time());
$remain = strtotime($today. " 00:00:00 + 20 hours") - time();
$remain = date('H:i:s', $remain);
I get a result which is one hour larger (02:30:00) than the actual result (01:30:00). I tried setting time zones but it's always the same result.
Using the DateTime object, you can do this easily:
$d1 = new DateTime('2015-04-23 18:30');
$d2 = new DateTime('2015-04-23 20:00');
$interval = $d2->diff($d1);
echo $interval->format('%H:%i hours');
This question already has answers here:
How to calculate the difference between two dates using PHP?
(34 answers)
Closed 8 years ago.
I have two timestamps let us say
$end_date = 2014-09-09 15:03:10 and now date
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
I want to calculate number of days remaining .Suppose if that particular date crosses now date and it should display remaining days with -ve value.
I am using the following code
$remaining_days =strtotime($end_date) - strtotime($now) ;
$Result_days = floor($remaining_days /86400);
echo $remaining_days.' '.$Result_days.'<br/>'
Problem is that if the end date = today's date it is displaying -1 . I want to calculate based on time and display remaining days and hours.
Please help me to find out the solution.
Try this:
<?php
$end_date = "2014-10-09 15:03:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$diff = strtotime($now) - strtotime($end_date);
$fullDays = floor($diff/(60*60*24));
$fullHours = floor(($diff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($diff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Difference is $fullDays days, $fullHours hours and $fullMinutes minutes.";
Output:
Difference is -30 days, 0 hours and 39 minutes.
Demo:
http://3v4l.org/3auqe
Edit (using DATE OBJECT):
<?php
// Example 1
$end_date = "2014-09-11 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
+2 days, 3 hours, 0 minutes, 44 seconds
// Example 2
$end_date = "2014-09-08 20:35:10";
date_default_timezone_set('Asia/Calcutta');
$now = date('Y-m-d H:i:s');
$date1=date_create($now);
$date2=date_create($end_date);
$diff=date_diff($date1,$date2,FALSE);
echo $diff->format("%R%d days, %h hours, %m minutes, %s seconds").PHP_EOL;
//Output:
-0 days, 20 hours, 0 minutes, 16 seconds
Demo:
http://3v4l.org/dPSgX#vhhvm-320
you can use date_diff php method .you can see example here http://php.net/manual/en/function.date-diff.php
You may try like this:
<?php
$dateDiff = $date1 - $date2;
$fullDays = floor($dateDiff/(60*60*24));
$fullHours = floor(($dateDiff-($fullDays*60*60*24))/(60*60));
$fullMinutes = floor(($dateDiff-($fullDays*60*60*24)-($fullHours*60*60))/60);
echo "Differernce is $fullDays days, $fullHours hours and $fullMinutes minutes.";
?>
See the Source for more options
$date1 = new DateTime("2014-09-09");
$date2 = new DateTime("2014-09-12");
$interval = $date1->diff($date2);
echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";
The duplicate
I'm calculating the difference between 2 dates using DateTime() and it's working fine. The problem is that I want to have the days format be able to go above a full month so 30/31 or higher.
$now = new DateTime();
$future_date = new DateTime($contest->expires_at);
$interval = $future_date->diff($now);
$enddate = $interval->format("%m month, %d days, %h hours, %i minutes");
The current problem with this is that when I don't display the months, the days can only go up to 30/31 and anything over that will be carried over to make a new month resetting the days count with the leftover days.
I want to be able to display 42 days when the difference is 6 weeks with this kind of format:
$enddate = $interval->format("%d days, %h hours, %i minutes");
Is there a quick fix for this or do I need to manually convert the timestamp to seconds and use my own function with modulus operators for this?
You can try:
$enddate = $interval->format("%a days, %h hours, %i minutes");
See the DateInterval::format in the manual.
NOTE
Take care of the bug if you're working on windows.
This should solve your porblem:
$now = new DateTime();
$future_date = new DateTime();
// a period of 2 months
$addPeriod = new DateInterval('P2M');
// adding the period
$future_date->add($addPeriod);
// get the differnce
$interval = $future_date->diff($now);
echo($interval->days) . ' days';
For today: echo returns '61 days'
// EDIT
To avoid running into the dataInterval-Bug you can use:
$now = new DateTime();
$future_date = new DateTime();
// a period of 2 months
$addPeriod = new DateInterval('P2M');
// adding the period
$future_date->add($addPeriod);
// get the difference in second
$diffTimestamp = $future_date->getTimestamp() - $now->getTimestamp();
// convert to days
// 1 day = 86.400 seconds
$diffDays = $diffTimestamp/86400;
echo(floor($diffDays)) . ' days';
Update my php version since this is a bug in my old and it works perfectly now.
How to get aggregate days from PHP's DateTime::diff?