I have a date field I'm pulling from WordPress, where the default format is:
16/12/2016
Been a while since I played with PHP, but I remember the way to format dates was: echo date_format($date,"[format syntax]");
But when I do
$date = myWPField;
echo date_format($date,"F d, y");
If doesn't display the date.
What am I missing. Has this changed?
Since your date is not an acceptable format in date_create like mm/dd/yy(yy) or mm-dd-yy(yy)
Use php DateTime::createFromFormat function instead this function can detect what format you
(PHP 5 >= 5.3.0, PHP 7)
DateTime::createFromFormat -- date_create_from_format — Parses a time string according to a specified format
$date = '16/12/2016';
$show_date = DateTime::createFromFormat('d/m/Y', $date)->format('F d, y');
Demo
when create data format form string use slash format, it's in the mm/dd/yy(yy) format. So in you code your first 16 is not allowed by default, you have to specify in what format to create from the string.
Note that when you create a new date object using a format with slashes and dashes (eg 02-02-2012 or 02/02/2012) it must be in the mm/dd/yy(yy) or mm-dd-yy(yy) format (rather than british format dd/mm/yy)! Months always before years (the american style) otherwise you'll get an incorrect date and may get an error like the one above (where PHP is crashing on trying to decode a 13th month).
Related
I have a php string from db it is 20/11/2017 I want to convert it milliseconds.
It's my code to doing that.
$the_date = "20/11/2017";
$mill_sec_date = strtotime($the_date);
var_dump($mill_sec_date);
But it does not print any thing rather than
bool(false);
What is the problem and how can i solve it ????
When using slashes to separate parts of the date, PHP recognizes the format as MM/DD/YYYY. Which makes your date invalid because there is no 20th month. If you want to use the format where day and month is swapped, you need to use hyphens, like DD-MM-YYYY.
$time = strtotime('10/16/2003');
$newformat = date('Y-m-d',$time);
print_r($newformat);
Use DateTime class to call function createFromFormat
$date = date_create_from_format('d/M/Y:H:i:s', $string);
$date->getTimestamp();
Most likely you got the date format wrong, see
here for a list of supported date and time formats:
This section describes all the different formats that the strtotime(), DateTime and date_create() parser understands.
You string is not accept by the strtotime, you can use createFromFormat set set the with the format type of the time string like below, you can also check the live demo. And you also can refer to this answer
var_dump(DateTime::createFromFormat('d/m/Y', "20/11/2017"));
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 5 years ago.
As ive echoed out the datetime value from my db, i am now trying to display this value to edit it in the datetime-local field within my form.
The datetime vaue from db is set to:
22/3/2017 10:00:00
however, after attempting to use the following code, im left with this:
1970-01-01T01:00:00
$dat = date("Y-m-d\TH:i:s", strtotime($_GET["dat"]));
How & why is this function not working correctly to display '22/3/2017 10:00' in the form field?
Use DateTime::createFromFormat:
$date = DateTime::createFromFormat('d/m/Y H:i:s', '22/3/2017 10:00:00');
$dat = $date->format('Y-m-d\TH:i:s');
echo $dat;
Your code is not working because strtotime makes assumption based on delimiters about actual format:
m/d/Y- American format
d.m.Y or d-m-Y - European
It's not working because strtotime() can translate only specific date format.
Check the manual. For a list of supported date format, look here.
Your date format looks not included in the supported ones to me.
Examples:
strtotime("03/22/2017 10:00:00"); // Works: returns 1490173200
strtotime("22/3/2017 10:00"); // Doesn't work: returns false
You have to either change the date format in your DB or format it to one of the supported formats to make it work.
I have a controller action in which I fetch the currrent date like following:
$fullDate=date("Y-m-d");
$date = strtotime($fullDate);
$viewModel->setVariable("currentDate",$date);
// Here I would like to pass the variable to the View and then compare it with another date ...
With the method above I'm getting this when I do var_dump($currentDate);
int(1463587200)
which is not what I was expecting... I need a date in format like this 2016-05-19 (year-month-day)... How can I do this the valid way???
This strtotime is converting your formatted date into a Unix time-stamp. just remove it.
$fullDate=date("Y-m-d");
$viewModel->setVariable("currentDate",$fullDate);
you'll be able to compare two dates in this format Y-m-d without converting to time-stamp.
I'm trying to format a date passed from a google plus Api thats like the guide says in RFC 3339 format:
PUBLISHED-> datetime-> The time at which this activity was initially published. Formatted as an RFC 3339 timestamp.
So by php documentation i found that:
DATE_RFC3339
Same as DATE_ATOM (since PHP 5.1.3)
And that both format are something like:
"Y-m-d\TH:i:sP"
Actually the output of the Google api is something like:
2014-01-22T10:36:00.222Z
When I'm trying to launch command like:
$date = DateTime::createFromFormat("Y-m-d\TH:i:sP", $activity['published']); //$activity['published'] contain the date
I have always FALSE as return.
In my opinion the problem is in the final part
.222Z
any suggestion will be appreciate before cutting it by some rudimental approach...
You don't need to use DateTime::createFromFormat() for standard inputs. Just use:
$date = new DateTime('2014-01-22T10:36:00.222Z');
var_dump($date);
But if you still insist to use createFromFormat(), then use correct format, with microseconds:
$date = DateTime::createFromFormat('Y-m-d\TH:i:s.uP', '2014-01-22T10:36:00.222Z');
var_dump($date);
There is a trick. A special constant DATE_RFC3339 was made to help, but it does not work if the last character is "Z" - which is perfectly fine for rfc3339 format. Actually JSON would specify format like that:
expected format YYYY-MM-DDThh:mm:ssZ or YYYY-MM-DDThh:mm:ss+hh:mm
But using this DATE_RFC3339 you can receive an Error message from PHP:
InvalidArgumentException: The timezone could not be found in the database
That is why we need to specify format manually:
With DateTime
$date = DateTime::createFromFormat ('Y-m-d\TH:i:s.u\Z', $time);
With Carbon:
\Carbon\Carbon::createFromFormat('Y-m-d\TH:i:s.u\Z', $time);
I'm facing an issue with managinging dates, some dates pass others dont. I want to produce an insertable date for mysql. there are two possible types of post dates
yyyy-mm-dd //should go without conversion
m/d/yyyy // should be converted
I'm using this
$date = $_REQUEST['date'];
$date_regex = '/(0[1-9]|1[012])[- \/.](0[1-9]|[12][0-9]|3[01])[- \/.](19|20)\d\d/';
if(preg_match($date_regex, $date)){
$date = DateTime::createFromFormat('m/d/Y',$date)->format('Y-m-d');}
problems
I realised this regex is failing for dates like
2/5/2013
but has been working for
12/12/2013
so I removed it BUT still
DateTime::createFromFormat('m/d/Y',$date)->format('Y-m-d');
is also failing for m/d/yyyy
This date thing has got my head spinning for the last 6 hours.
In this case, there is no need to use DateTime::createFromFormat because m/d/yyyy is one of the recognized date formats (see "American month, day and year"). Just convert it to a DateTime object and let the constructor handle the format and forget the regex:
$date = $_REQUEST['date'];
$datetime = new DateTime($date);
$datex = $datetime->format('Y-m-d');
The reason DateTime::createFromFormat('m/d/Y',$date) fails for dates like 2/5/2013 is because you are forcing it to be specifically 'm/d/Y' and that date does not fit that pattern. You can see a list of all date formats here. Specifically, m expects there to be a leading zero (like 02), so when you give it one without that, it won't recognize it. Same goes for d. In this case you would have to use n and j respectively. But, like I said, let the constructor do the hard work for you.