PHP Push into an array - php

Question

I have a PHP loop that's getting data from my table and pushing it into an array.
$children = mysql_query("SELECT c.id, c.name, c.age, c.photoName, c.panelColor FROM children as c");
$temp = array();
while ($child = mysql_fetch_assoc($children)) {
// Get the child's reatings
$ratings = mysql_query('
SELECT r.behaviourID, t.points, t.typeName
FROM behaviourRatings as r
JOIN behaviourTypes as t
ON r.behaviourID = t.typeID
WHERE r.childID = ' . $child['id']);
// Loop over the ratings
$totalPoints = 0;
while ($childRatings = mysql_fetch_array($ratings)){
$totalPoints = ($totalPoints + $childRatings['points']);
}
// We can only max out at our set max
if(($totalPoints + $maxPoints) > $maxPoints) {
$total = $maxPoints;
} else if($totalPoints < 0){
$total = ($maxPoints + $totalPoints);
}else{
$total = ($maxPoints - $totalPoints);
}
// Set the child array
$temp[] = $child;
}
$response = array();
$response['timestamp'] = $currentmodif;
$response['children'] = $temp;
echo json_encode($response, JSON_PRETTY_PRINT);
I want to add another key/value to the array called points and assign its value as $total.
I tried doing $temp['points'] = $total but that put it outside of the array and not with the outer loops data.
This is the result of the function:
{
"timestamp": 1482918104,
"children": [
{
"id": "1",
"name": "Maya",
"age": "5",
"photoName": "maya.png",
"panelColor": ""
},
{
"id": "2",
"name": "Brynlee",
"age": "3",
"photoName": "brynlee.png",
"panelColor": "green"
}
]
}
I want to show the points for each of those children but I am unsure how to add it to that part of the array.

Answer 1

You should add it to the $child variable, just before adding that variable to the $temp array:
$child['points'] = $total;
$temp[] = $child;

Answer 2

Also you can reduce requests to database by getting all child's ratings in one query.
Something like this:
$children = mysql_query("SELECT c.id, c.name, c.age, c.photoName, c.panelColor FROM children as c");
$childrenIds = [];
while ($child = mysql_fetch_assoc($children)) {
$childrenIds[] = $child['id'];
}
if (!empty($childrenIds)) {
$ratings = mysql_query('
SELECT r.behaviourID, t.points, t.typeName
FROM behaviourRatings as r
JOIN behaviourTypes as t
ON r.behaviourID = t.typeID
WHERE r.childID IN (' . implode(',', $childrenIds) . ')');
}