Convert JSON from MySQL to PHP - php

Question

So i have this JSON in my MySQL Database
{
"11011001": {
"id": 11011001,
"name": "Test",
"price": 4,
"inCart": 7
}
}
Now i want to work with this data in PHP.
I got the JSON by doing this in PHP:
$sql = "SELECT article FROM test WHERE id = '$id'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
$row = $result->fetch_assoc();
$aricle = $row["article"];
} else {
echo "Something went wrong";
}
After that i did this which resulted in getting a JSON Array:
$tarray = json_decode($article, TRUE);
What can i do now to get the values from the JSON?
For example i want the value of the price in a variable called $price.

Answer 1

$price = $tarray[11011001]['price'];
Or you can loop through the results if you have many articles
$tarray = json_decode($json,true);
foreach ($tarray as $index => $item)
{
$price[] = $item['price'];
}
var_dump($price);

Answer 2

Assuming you might have a collection of items, you can map the ids to prices with array_column.
<?php
$json =<<<JSON
{
"11011001": {
"id": 11011001,
"name": "Test",
"price": 4,
"inCart": 7
}
}
JSON;
$items = json_decode($json, TRUE);
$ids_prices = array_column($items, 'price', 'id');
var_export($ids_prices);
Output:
array (
11011001 => 4,
)
Only one item, but you don't know the key up front?
if(count($items) === 1) {
$item = array_pop($items);
$price = $item['price'];
}
echo $price;
Output:
4

Answer 3

First you have a sql injection, you must create a prepared query if you have data from users.
$sql = "SELECT article FROM test WHERE id = :id";
$query = $con->prepare($sql);
$query->bindValue(":id", $id);
$query->execute();
$result = $query->fetch();
if ($result) {
// $article will be stdClass if json correct
$article = json_decode($result['article']);
$price = $article->price;
// or $article = json_decode($result['article'], true);
// $price = $article['price'];
}
Just an example