Counting # of rows in table which contain file_name - php

I am trying to make a page which displays products added to a database.
I need to use 'foreach' to automatically display all products.
Im stuck with one part where I need to display the number of downloads of each product. The only way to do this is to count the number of rows which contain the file name of the product in the downloads table.
This is what I use so far, but its not working:
SELECT * FROM products, file_product, files, downloads WHERE products.id = file_product.product_id AND file_product.file_id = files.id AND files.file_name = downloads.file_name
These are my tables: [products, file_product, files, downloads]

It sounds to me like you're doing this the hard way. I might suggest you look at mysql's grouping functions, specifically GROUP BY. You won't have to loop over the query at all, just the results.
Something like
SELECT `file_name`, COUNT(*) AS `count` FROM `files` GROUP BY `file_name`;
The results should look something like this:
---------------------------
| file_name | count|
--------------------------|
| background-2.png | 2 |
| foo.png | 1 |
---------------------------
You can JOIN that with your file_product table if you need to limit it to only files for the current product, as what I wrote will give you all files for all products.
Example:
SELECT
f.`file_name`,
COUNT(*) AS `count`
FROM `files` f
JOIN `file_product` fp
ON fp.`file_id` = f.`id`
JOIN `product` p
ON fp.`product_id` = ?
JOIN `downloads` d
ON d.`file_name` = f.`file_name`
GROUP BY `file_name`;
? is where you put the product id for the current product.

You have to write :
SELECT `file_name'`, COUNT(*) AS `count` FROM table GROUP BY `count` ORDER BY `count` DESC;
Then, this command returns how many rows per table for each file_name group by descroissant order.
In order to implement whith PHP :
<?php
// connect to MySQL
$db = mysql_connect('localhost', 'login', 'password');
// select database
mysql_select_db('database_name',$db);
// SQL query
$sql = 'SELECT `file_name`, COUNT(*) AS `count` FROM table GROUP BY `count` ORDER BY `count` DESC;';
$req = mysql_query($sql) or die('Error SQL !<br>'.$sql.'<br>'.mysql_error());
// close mysql
mysql_close();
?>
I can't test it, so it's maybe false :/

Related

MySQL, SELECT with COUNT, but GROUP BY if sort

I have two tables like these:
Table "users":
user_id | source
----------------
1 | 2
2 | 2
3 | 3
4 | 0
Table "sources":
source_id | name
----------------
1 | "one"
2 | "two"
3 | "three"
4 | "four"
Now I need to SELECT (*) FROM source and additionally COUNT "users" that have this source, BUT if there is an additional filter(requests by PHP mysqli), then additionally sort "sources" table by its users count.
What is the best way to do so, and is it possible to do in one statement?
--------------Added editing----------
The first part(SELECT with count from another table) I'm doing this way:
SELECT
id, name
(select count(*) from users where source = sources.id) as sourceUsersCount
FROM sources
And now, how to order this list by users count in each source?
Please check the below query if this is what you need.
select s.*,a.c from sources s
left join
(select count(*) as c,source as src
from user u join sources s
on s.source_id = u.source group by u.source) a
on s.source_id = a.src;
Count the number of users:
SELECT sources.*, COUNT(users.user_id) FROM sources
LEFT JOIN users ON users.source_id = sources.source_id
GROUP BY sources.source_id;
I assume by filters you mean the WHERE clause:
SELECT sources.*, COUNT(users.user_id) FROM sources
LEFT JOIN users ON users.source_id = sources.source_id
WHERE sources.source_id = 2
GROUP BY sources.source_id;
And you can always attach an ORDER BY on the end for sorting:
SELECT sources.*, COUNT(users.user_id) FROM sources
LEFT JOIN users ON users.source_id = sources.source_id
GROUP BY sources.source_id
ORDER BY sources.source_id DESC;
Achieved it by doing so:
SELECT
sources.*,
count(users.source) as sourceUsersCount
FROM sources
LEFT JOIN users ON sources.id = users.source
//In case of additional filters
WHERE
id != 0 AND (name LIKE %?% OR id LIKE %?%)
//\\
GROUP BY sources.id
//In case of sorting by "users" count
ORDER BY sourceUsersCount ASC
//\\
Is it the best way, or maybe there are some faster variants?

Mysql query to retrieve single image from an array of images?

Table to store array of Images:
`products` and `products_photos`
`products` includes only `id` field
`products_photos` includes `product_id` and `filename`
Table values:
products
--------
id-6
id-7
products_photos
---------------
6 - filename1
6 - filename2
7 - filename3
In these two table id 6 includes 2 images but i need to fetch only one image from that. How to write a query for that in mysql or laravel.
If you want to get the latest (last added) image of the product then you can do the following way
NOTE : Instead of *, use the precise columns so that your query performs faster.
SELECT * FROM products_photos WHERE product_id = 6 ORDER BY products_photos.id DESC LIMIT 1;
If you want to get the first (old added) image of the product then you can do the following way
SELECT * FROM products_photos WHERE product_id = 6 ORDER BY products_photos.id ASC LIMIT 1;
Updated : Query to get the list of all the records group
SELECT MAX(id) as id, photo_name FROM products_photos GROUP BY photo_name
In case if you have more than one columns and want to get the latest record for that too then go for this
Eg. Considering that your having description column and want to get the MAX (latest) content than use MAX, if you need oldest use MIN
SELECT MAX(id) as id, photo_name, MAX(description) as description FROM products_photos GROUP BY photo_name
You can give limit to your query to get single result
SELECT * FROM products_photos WHERE product_id = 6 ORDER BY id LIMIT 1;
Which will give single image only for id = 6 product
For retrieve all data use group by
SELECT * FROM GemSellerPortal.products pr
LEFT JOIN GemSellerPortal.products_photos ph
ON ph.product_id = pr.id
GROUP BY pr.id

SQL Table Structure for news site

I want to make a fast table structure for news site with php and mysql. My database structure is ID, title, content, cat_ids (; separedet IDs of categories - ;5;10;15;20;), active, publish_date.
I want to make a fast query to select news from this table. Something like that:
SELECT id
FROM news
WHERE cat_ids LIKE '%;15;%'
AND active = 1
AND publish_date < NOW()
ORDER by publish_date DESC
LIMIT 0, 10
But if my table is 2-3GB the query is very slow. I need some ideas to make structure and make the select faster.
Instead of using cat_ids column, try creating a news_cats table with news_id and cat_id, and using this query:
SELECT id
FROM news JOIN news_cats ON news_id = id
WHERE cat_id = 15
AND active = 1
AND publish_date < NOW()
ORDER by publish_date DESC
LIMIT 0, 10
Some suggestions as below:
1) Create index on "active" field
2) Create index on "publish_date" field
3) Create separate table for category and news relation and remove "cat_ids" field from news table
New table might look like below:
news_category_ids
news_id
category_id
It can have multiple rows for each news_id, if news item falls in 3 categories, it will have 3 rows
Then use SQL like below:
SELECT news.id
FROM news INNER JOIN news_category_ids ON news.id = news_category_ids.news_id
WHERE 1
AND news.active = 1
AND news_category_ids.cat_id = 15
AND news.publish_date < NOW()
ORDER by news.publish_date DESC
LIMIT 0, 10

SQL position of row(ranking system) WITHOUT same rank for two records

so I'm trying to create a ranking system for my website, however as a lot of the records have same number of points, they all have same rank, is there a way to avoid this?
currently have
$conn = $db->query("SELECT COUNT( * ) +1 AS 'position' FROM tv WHERE points > ( SELECT points FROM tv WHERE id ={$data['id']} )");
$d = $db->fetch_array($conn);
echo $d['position'];
And DB structure
`id` int(11) NOT NULL,
`name` varchar(150) NOT NULL,
`points` int(11) NOT NULL,
Edited below,
What I'm doing right now is getting records by lets say
SELECT * FROM tv WHERE type = 1
Now I run a while loop, and I need to make myself a function that will get the rank, but it would make sure that the ranks aren't duplicate
How would I go about making a ranking system that doesn't have same ranking for two records? lets say if the points count is the same, it would order them by ID and get their position? or something like that? Thank you!
If you are using MS SQL Server 2008R2, you can use the RANK function.
http://msdn.microsoft.com/en-us/library/ms176102.aspx
If you are using MySQL, you can look at one of the below options:
http://thinkdiff.net/mysql/how-to-get-rank-using-mysql-query/
http://www.fromdual.ch/ranking-mysql-results
select #rnk:=#rnk+1 as rnk,id,name,points
from table,(select #rnk:=0) as r order by points desc,id
You want to use ORDER BY. Applying on multiple columns is as simple as comma delimiting them: ORDER BY points, id DESC will sort by points and if the points are the same, it will sort by id.
Here's your SELECT query:
SELECT * FROM tv WHERE points > ( SELECT points FROM tv WHERE id ={$data['id']} ) ORDER BY points, id DESC
Documentation to support this: http://dev.mysql.com/doc/refman/5.0/en/sorting-rows.html
Many Database vendors have added special functions to their products to do this, but you can also do it with straight SQL:
Select *, 1 +
(Select Count(*) From myTable
Where ColName < t.ColName) Rank
From MyTable t
or to avoid giving records with the same value of colName the same rank, (This requires a key)
Select *, 1 +
(Select Count(Distinct KeyCol)
From myTable
Where ColName < t.ColName or
(ColName = t.ColName And KeyCol < t.KeyCol)) Rank
From MyTable t

PHP / MySQL Checking data between tables with long query

This is a more detailed question as my previous attempt wasn't clear enough. I'm new to MySQL and have no idea about the best way to do certain things. I'm building a voting application for images and am having trouble with some of the finer points of MySQL
My db
_votes
id
voter_id
image_id
_images
id
file_name
entrant_id
approved
_users
id
...
Basically I need to do the following:
tally up all votes that are approved
return the top 5 with the most votes
check if the user has voted on each of these 5 (return Boolean) from another table
I've tried variations of
SELECT i.id, i.file_name, i.total_votes
FROM _images i WHERE i.approved = 1
CASE WHEN (SELECT count(*) from _votes v WHERE v.image_id = i.id AND v.voter_id = ?) > 0 THEN '1' ELSE '0' END 'hasvoted'
ORDER BY i.total_votes DESC LIMIT ".($page*5).", 5
is that something I should try and do all in one query?
This query was working fine before I tried to add in the 'hasvoted' boolean:
SELECT id, file_name, total_votes FROM _images WHERE approved = 1 ORDER BY total_votes DESC LIMIT ".($page*5).", 5
At the moment I'm also storing the vote count in the _images table and I know this is wrong, but I have no idea about how to tally the votes by image_id and then order them.
Let me give this a shot to see if I understand your question:
SELECT i.*,(SELECT COUNT(*) FROM _votes WHERE i.id = image_id) AS total_votes, (SELECT count(*) from _votes where i.id = image_id and user_id = ?) as voted FROM _images AS i WHERE i.approved = 1

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