PHP / MySQL Checking data between tables with long query - php

This is a more detailed question as my previous attempt wasn't clear enough. I'm new to MySQL and have no idea about the best way to do certain things. I'm building a voting application for images and am having trouble with some of the finer points of MySQL
My db
_votes
id
voter_id
image_id
_images
id
file_name
entrant_id
approved
_users
id
...
Basically I need to do the following:
tally up all votes that are approved
return the top 5 with the most votes
check if the user has voted on each of these 5 (return Boolean) from another table
I've tried variations of
SELECT i.id, i.file_name, i.total_votes
FROM _images i WHERE i.approved = 1
CASE WHEN (SELECT count(*) from _votes v WHERE v.image_id = i.id AND v.voter_id = ?) > 0 THEN '1' ELSE '0' END 'hasvoted'
ORDER BY i.total_votes DESC LIMIT ".($page*5).", 5
is that something I should try and do all in one query?
This query was working fine before I tried to add in the 'hasvoted' boolean:
SELECT id, file_name, total_votes FROM _images WHERE approved = 1 ORDER BY total_votes DESC LIMIT ".($page*5).", 5
At the moment I'm also storing the vote count in the _images table and I know this is wrong, but I have no idea about how to tally the votes by image_id and then order them.

Let me give this a shot to see if I understand your question:
SELECT i.*,(SELECT COUNT(*) FROM _votes WHERE i.id = image_id) AS total_votes, (SELECT count(*) from _votes where i.id = image_id and user_id = ?) as voted FROM _images AS i WHERE i.approved = 1

Related

Select random rows from one MYSQL table with join

Afternoon folks,
I have had a good dig around and can't find the answer, so a good time to ask!
I'd like to select random rows from one table and then join into this random rows from another table where the ID that I have is the same. It would also be great to only select where I have an entry in the second table. I have tried all manner of sub-queries but am getting a bit lost. An inner join as read will do it but again with the randomness of it all!! Grrr...
SELECT
tracks.track_id,
cuttings.square_cutting,
cuttings.cutting_2,
cuttings.cutting_3,
cuttings.blog_text
FROM tbl_tracks tracks,
(SELECT
square_cutting,
cutting_2,
cutting_3,
blog_text
FROM
tbl_cuttings
WHERE track_id = tracks.track_id <-- wont find it, obviously!!
ORDER BY RAND()
LIMIT 1) cuttings
WHERE tracks.active = '1' ORDER BY RAND()
Thanks in advance for any help.
So:
I'd like random tracks showing
track id -> with random cuttings, of which there can be many but I just want 1.
It would then be ideal to only show a result if there is a cutting associated with that track.
Hope that helps.
I'm now trying to go a step further with this and order this by a RAND() seed as I'm now having to add in pagination. Only problem is that its not giving me back the same random list due to a given seed. Any Ideas?
SELECT
tracks.track_id,
cuttings.square_cutting,
cuttings.cutting_2,
cuttings.cutting_3,
cuttings.blog_text
FROM tbl_tracks tracks
INNER JOIN
(SELECT track_id,
square_cutting,
cutting_2,
cutting_3,
blog_text
FROM
tbl_cuttings
ORDER BY RAND()) cuttings ON tracks.track_id = cuttings.track_id
WHERE tracks.active = '1'
ORDER BY RAND(1)
LIMIT 0,4;
you could use an inner join
SELECT
tracks.track_id,
cuttings.square_cutting,
cuttings.cutting_2,
cuttings.cutting_3,
cuttings.blog_text
FROM tbl_tracks tracks
INNER JOIN
(SELECT track_id,
square_cutting,
cutting_2,
cutting_3,
blog_text
FROM
tbl_cuttings
ORDER BY RAND()
LIMIT 1) cuttings on cuttings.track_id = tracks.track_id
WHERE tracks.active = '1'
ORDER BY RAND()

Sorting data from MySQL by SUM with Grouping By - not working properly

I have a problem with mysql - i'm kind new to it, byt looking to improve my skills :)
Have a code like this:
if($where > 0) $query = mysql_query("SELECT img.*, user.user as owner_name, cat.name as cat_name FROM tentego_img AS img LEFT JOIN tablicacms_users AS user ON user.id = img.owner LEFT JOIN tentego_img_cat AS cat ON cat.id = img.cat WHERE img.`is_waiting` LIKE ".$where.$cat." INNER JOIN tentego_img_vote ON tentego_img.id = tentego_img_vote.object_id GROUP BY tentego_img_vote.object_id ORDER BY SUM ( (CASE WHEN tentego_img_vote.vote = '0' THEN '-1' ELSE '1' END) ) DESC LIMIT ".$page.",".$objPerPage);
I need to make sorting by number of votes, sorted descending.
Still it makes results sorted by it own way.
In table I have rows:
ID - vote id for table purpose
object_id- id of object joined with another table to show results.
User ID - user id
Vote - where values are 0 for dislike and 1 for like (so -1 for 0, and +1 for 1)
So, as I understand i need to sum up all records for each of unique object_id, then sort by sum of vote values of each.
This code worked before my script provider decide to upgrade it, so right now i dont know how to fix it :(

retrive second highest point from table with no unique column

i have one table named users. In this table i have one column named credits(not unique).
Now i want the second highest user accroding to the users credits. If the credits field is unique thenmy below query is working fine
SELECT * FROM users ORDER BY credits DESC LIMIT 1 , 1
But , if the users credit is not unique then its create problem for retrive me data
suppose,
mack has 200 credits
jack has 200 credits
rock has 150 credits
when i has this types of record then,in output of this query i want the rock record not jack
can anyone help me to find out the correct value ?
thanks in advance
SELECT a.*
FROM users a
INNER JOIN
(
SELECT DISTINCT credits
FROM users
ORDER BY credits desc
LIMIT 1,1
) b ON a.credits = b.credits
SQLFiddle Demo
Hope this helps (first get second highest credits then find the users having those that credit andselect one from the top`. This will retrieve one user having second highest credit):
SELECT * FROM users
WHERE credits = (SELECT distinct credits FROM users
ORDER BY credits DESC LIMIT 1,1)
LIMIT 1;
EDIT: If you also want to select within users having same score then use the appropriate filter/sorting condition e.g. to select rock between rock and jenni, you could have another ordering base on name(assuming name is the column having names)
SELECT * FROM users
WHERE credits = (SELECT distinct credits FROM users
ORDER BY credits DESC LIMIT 1,1)
ORDER name desc
LIMIT 1;
To get both rock and jenni, just remove the limit from the end and update the inner limit e.g:
SELECT * FROM users
WHERE credits = (SELECT distinct credits FROM users
ORDER BY credits DESC LIMIT 1, 1);
try this
Select * FROM users
Where Credits < (Select Max(Credits) From Users)
ORDER BY credits DESC LIMIT 1;

select 3 rows from mysql table, then get each row's specific column

Select 3 rows from table1
Get a specific column data out of each row.
Then use that each column data obtained , to make a query again to get data from table2.
Store the data obtained in step 4 into a variable for each row.
Then put them in json array (table 1 , 3 rows + table 2's data(each of them).
I am building a rank table, it displays top 3 users with their rank name.
For example:
User1 has 2000 points , user 2 has 4000points , user 3 has 10k points , so the top 3 user is :
user 3 > user 2 > user 1
So , i want the php to go to 'users' table and get the top 3 members using this:
$query = mysql_query("SELECT * FROM users ORDER BY pts DESC LIMIT 3");
$rows = array();
while($r = mysql_fetch_assoc($query)) {
$rows[] = $r;
}
Table structure for 'user':
1.username(varchar)
2.pts(int)
After the rows are put into an array , how can i get 'points' for each of the row in that array.
Then go to 'rank' table to get their ranknames.
Table structure for 'rank':
1.rank(varchar)
2.pts(int)
Inside rank table there is 'pts' to let php choose compare which rank the user is at based on the points from each row of the array.
Normally i would use this if its only for 1 user , but for multiple users , im not sure:
$result = mysql_query("SELECT * FROM rank WHERE pts <= '$upts' ORDER BY pts DESC LIMIT 1")
or die(mysql_error());
Then after getting the rank for the top 3 users , php will now add the ranks to each of the user(row) in that array(of course , add it to the rank owner, not just simply place it in).
Then JSON encode it out.
How can i do this?
I am not sure if this is what you want. That is combine the two query into one query. Please take a look at http://sqlfiddle.com/#!2/ad419/8
SELECT user.username,user.pts,rank.rank
FROM user LEFT JOIN rank
ON user.pts <=rank.pts group by user.id
UPDATED:
For extracting top 3, could do as below;
SELECT user.username,user.pts,rank.rank
FROM user LEFT JOIN rank
ON user.pts <=rank.pts
GROUP BY user.id
ORDER BY pts DESC LIMIT 3
If i understand correctly, you need to get values from Rank and Users tables. In order to do that in just one query You need to add FK (Foreign Key) to the Rank table that points to a specific user in the Users table.
So you need to add userId to the Rank table and then you can run:
SELECT r.rank, u.points from users u,rank r where u.userId = r.userId
This is roughly what you need.
Not quite the answer to your exact question, but this might be of use to you: How to get rank using mysql query. And may even mean that you don't require a rank table. If this doesn't help, I'll check back later.
Use this query
$query = "SELECT
u.pts,
r.rank
FROM users as u
left join ranks as r
on r.pts = u .pts
ORDER BY pts DESC
LIMIT 3";
This will bring what you required without putting into an array
$rec = mysql_query($query);
$results = arrau();
while($row = mysql_fetch_row($rec)){
$results[] = $row;
}
echo json_encode($results);
It looks like what you're trying to do is retrieve the rank with the highest point requirement that the user actual meets, which isn't quite what everyone else is giving here. Fortunately it is easily possible to do this in a single query with a nice little trick:
SELECT
user.username,
SUBSTRING_INDEX(GROUP_CONCAT(rank.rank ORDER BY pts DESC),",",1) AS `rank`
FROM user
LEFT JOIN rank ON user.pts >= rank.pts
GROUP BY user.id
ORDER BY pts DESC
LIMIT 3
Basically what the second bit is doing is generating a list of all the ranks the user has achieved, ordering them by descending order of points and then selecting the first one.
If any of your rank names have commas in then there's another little tweak we need to add on, but I wouldn't have thought they would so I've left it out to keep things simple.

SQL: Forum Order by behaviour (in Codeigniter)

Here's the situation:
In my database i have a table with threads, and a table with replies. Both have a Timestamp field.
Now i am developing a forum and wish to order threads in the following manner:
If the thread has replies, then: ORDER BY tblReply.Timestamp DESC
Else, the thread has no replies: ORDER BY tblThread.Timestamp DESC
I do not know how to combine these 2 in one statement.
My query as it is now:
SELECT `PK_ThreadID`, `Title`, `tblUsers`.`Username`, `tblThread`.`Date`, count(tblReply.FK_ThreadID) AS number_replies FROM (`tblThread`)
JOIN `tblUsers` ON `tblUsers`.`PK_UserID` = `tblThread`.`FK_UserID`
LEFT JOIN `tblReply` ON `tblReply`.`FK_ThreadID` = `tblThread`.`PK_ThreadID`
WHERE `isExpertQuestion` = 0 AND `isPublic` = 1
GROUP BY `PK_ThreadID`
ORDER BY max(tblReply.Date)` desc
//Here it only orders by reply date, so threads with no replies appear at the bottom
How do i achieve the ordering i want in this query?
Like this probably:
SELECT `PK_ThreadID`, `Title`,
`tblUsers`.`Username`,
`tblThread`.`Date`,
count(tblReply.FK_ThreadID) AS number_replies
FROM (`tblThread`)
JOIN `tblUsers` ON `tblUsers`.`PK_UserID` = `tblThread`.`FK_UserID`
LEFT JOIN `tblReply` ON `tblReply`.`FK_ThreadID` = `tblThread`.`PK_ThreadID`
WHERE `isExpertQuestion` = 0 AND `isPublic` = 1
GROUP BY `PK_ThreadID`
ORDER BY
CASE WHEN COUNT(tblReply.FK_ThreadID) > 0 THEN tblReply.Timestamp
WHEN COUNT(tblReply.FK_ThreadID) = 0 OR tblReply.FK_ThreadID IS NULL
THEN tblThread.Timestamp
END DESC

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