SQL Left Join Return Latest Row - php

Two tables, with a left join. For ease table 1 and table 2.
Table 1 contains a list of people and their current status, table 2 is all of their "invites". All im trying to do as part of the join is show in a list all the current "people" and then the LATEST invite status (from table 2) so return a single row from table 2.
I have everything working... but its duplicating for example if a person has had multiple invites it will put them twice on the list. I just want to limit it to
$sql = "SELECT table1.fieldname as table1fielname table2.fieldname [more fields]
FROM xxx
LEFT JOIN xxx on table1.sharedid=table2.sharedid
WHERE XXX LIMIT 1 ";`
Obvioulsy the limit 1 doesnt do what its supposed to. I have tried adding additional select statements in brackets but being honest it just breaks everything and im not an expert at all.

I'm not an expert too but I'll try. Have you tried to use DISTINCT?
For exemple:
SELECT DISTINCT column_name1,column_name2
FROM table_name; [...]
It normally delete double matches.
Here are the links:
http://www.w3schools.com/sql/sql_distinct.asp
https://www.techonthenet.com/oracle/distinct.php

Give example data. And use good table and column names. For example:
(this returns all rows that satisfy the join):
WITH people(ppl_id,ppl_name,status) AS (
SELECT 1,'Arthur','active'
UNION ALL SELECT 2,'Tricia','active'
), invites(ppl_id,inv_id,inv_date) AS (
SELECT 1,1, DATE '2017-01-01'
UNION ALL SELECT 1,2, DATE '2017-01-07'
UNION ALL SELECT 1,3, DATE '2017-01-08'
UNION ALL SELECT 2,1, DATE '2017-01-01'
UNION ALL SELECT 2,2, DATE '2017-01-08'
)
SELECT
*
FROM people
JOIN invites USING(ppl_id)
ORDER BY 1
;
ppl_id|ppl_name|status|inv_id|inv_date
1|Arthur |active| 1|2017-01-01
1|Arthur |active| 3|2017-01-08
1|Arthur |active| 2|2017-01-07
2|Tricia |active| 2|2017-01-08
2|Tricia |active| 1|2017-01-01
But we want only 'Arthur' with '2017-01-08' and 'Tricia' with '2017-01-08'.
With any database that supports ANSI 99, you could try with a temporary table containing the newest invitation date per "people id", and join that temporary table with the invitations table. We call that table newest_invite_date, and, apparently, it does what we expect it to do:
WITH people(ppl_id,ppl_name,status) AS (
SELECT 1,'Arthur','active'
UNION ALL SELECT 2,'Tricia','active'
), invites(ppl_id,inv_id,inv_date) AS (
SELECT 1,1, DATE '2017-01-01'
UNION ALL SELECT 1,2, DATE '2017-01-07'
UNION ALL SELECT 1,3, DATE '2017-01-08'
UNION ALL SELECT 2,1, DATE '2017-01-01'
UNION ALL SELECT 2,2, DATE '2017-01-08'
), newest_invite_date(ppl_id,inv_date) AS (
SELECT ppl_id,MAX(inv_date)
FROM invites
GROUP BY ppl_id
)
SELECT
people.ppl_id
, people.ppl_name
, people.status
, newest_invite_date.inv_date
FROM people
JOIN newest_invite_date USING(ppl_id)
ORDER BY 1
;
ppl_id|ppl_name|status|inv_date
1|Arthur |active|2017-01-08
2|Tricia |active|2017-01-08
Is this what you were looking for?
Happy playing ...
Marco the Sane

Related

How to choose oldest row from the table of similar rows?

I have a table. Table has structure of id, name, color, product_id.
And the table has multiple rows with the same product_id.
With SQL query from PHP file - I would like to choose only one, the oldest, row. (The first one that was added to the current table).
What query should I use or approach?
Thank you!
Just making up a bit of mockup data ... Note the notes I put in. And I trust it's a newer version of MySQL, as the older ones did not support ROW_NUMBER() OVER() .
Here goes:
WITH
-- input ... you *need* a timestamp to identify the oldest ---
indata(id, name, color, product_id,ts) AS (
SELECT 1,'Arthur','blue' ,42,TIMESTAMP'2021-01-31 17:45:00'
UNION ALL SELECT 1,'Arthur','blue' ,42,TIMESTAMP'2021-01-31 17:50:00'
UNION ALL SELECT 1,'Arthur','blue' ,42,TIMESTAMP'2021-01-31 17:55:00'
UNION ALL SELECT 1,'Arthur','blue' ,42,TIMESTAMP'2021-01-31 18:00:00'
UNION ALL SELECT 2,'Ford' ,'red' ,42,TIMESTAMP'2021-01-31 17:45:00'
UNION ALL SELECT 2,'Ford' ,'blue', 42,TIMESTAMP'2021-01-31 17:50:00'
UNION ALL SELECT 2,'Ford' ,'green',42,TIMESTAMP'2021-01-31 17:55:00'
UNION ALL SELECT 2,'Ford' ,'cyan' ,42,TIMESTAMP'2021-01-31 18:00:00'
)
,
-- select all, plus a rank, on which you will filter outside ..
with_rank AS (
SELECT
*
, ROW_NUMBER() OVER(PARTITION BY id ORDER BY ts) AS rnk
FROM indata
)
SELECT
id
, name
, color
, product_id
, ts
FROM with_rank
WHERE rnk = 1
id|name |color|product_id|ts
1|Arthur|blue |42 |2021-01-31 17:45:00
2|Ford |red |42 |2021-01-31 17:45:00
One method is a correlated subquery:
select t.*
from t
where t.id = (select min(t2.id)
from t t2
where t2.product_id = t.product_id
);
This assumes that id is incrementing with each insertion. If not, you have no way of knowing what the "oldest" row is. SQL tables represent unordered sets, so there is no "oldest" row unless a column contains that information.
SELECT * FROM TableName WHERE product_id = ProductID ORDER BY product_id LIMIT 1;

get monthwise row count from datewise data in mysql

I have two tables:
table 1.a
id--entry_date-amount
============================
2---2016-04-14--$400
3---2016-04-14--$400
4----2017-07-14--$200
5---2017-07-14--$500
6---2017-05-14--$600
7----2017-06-18--$100
table 2.b
id--entry_date
===========================
2---2016-04-14--$230
3---2016-04-14--$230
4----2017-07-14--$567
5---2017-07-14--$600
6---2017-05-14--$560
7----2017-06-18--$90
8---2016-04-14--$100
from the two tables how can i get count with montwise
my desired result:
month_name--total(count form table a)--total(count form table b)--amount(table a)--amount(table b)
========================================================
April,16-----------2-------------------3---$800-$500
May,17-----------1-------------------1 --$600--$700
June,17-----------2-------------------2--$100--$800
July,17-----------2-------------------2---$700-$400
this is the demo data.
I want to show data from two tables in a single query month wise.
How can i do this?
I tried:
SELECT MONTHNAME(r.entry_date),r.a_total FROM(
SELECT
IFNULL((SELECT COUNT(tr.id) AS amount FROM a AS tr WHERE MONTH(tr.entry_date)=MONTH(t.entry_date)),0) AS a_total
,t.entry_date
FROM(SELECT tr.id,tr.entry_date
FROM a AS tr
WHERE DATE(tr.entry_date) BETWEEN '2017-07-01' AND '2018-06-30') t
GROUP BY MONTH(t.entry_date)) r
But takes 58 seconds for simple query. How can i make this in a simple query?
You can get the counts and sum from each table individually, then use UNION to combine the two result sets into one result set. Something like this :
SELECT Month_name,
SUM(aCount) AS aCount,
SUM(bCount) AS bCount,
SUM(aAmount) AS aAmount,
SUM(bAmount) AS bAmount
FROM
(
SELECT
MONTHNAME(a.entry_date) AS Month_name,
COUNT(a.id) AS aCount,
0 AS bCount,
SUM(a.amount) AS aAmount,
0 AS bAmount
FROM a
GROUP BY MONTHNAME(a.entry_date)
UNION ALL
SELECT
MONTHNAME(b.entry_date) AS Month_name,
0 AS aCount,
COUNT(b.id) AS bCount,
0 AS aAmount,
SUM(b.amount) AS bAmount
FROM b
GROUP BY MONTHNAME(b.entry_date)
) AS t
GROUP BY Month_Name;
live demo
user9131497 has a good design for the big picture. However, I would suggest stuff like this for handling the dates:
SELECT DATE_FORMAT(entry_date, "%M,%y") AS 'Month',
COUNT(*) AS 'aCount'
FROM a
GROUP BY LEFT(entry_date, 7) -- eg, "2017-03"
Try that to see what I mean.
Note that this will work beyond a year. Or did you need January values from all years to be combined?? -- That's what your solution and user9131497's will do. Mine keeps them separate.

combine two tables and sum mysql

i want to join two tables but i can't do it as i want to sum column and get the result between two dates
first table named : vip_allotment_details
allotment_id qty
2 3
2 5
1 2
1 4
the second table name : vip_allotment
id date_from date_to
1 2017-10-1 2017-10-5
2 2017-10-6 2017-10-10
what i want from the query to get me this result
id qty date_from date_to
1 6 2017-10-1 2017-10-5
2 8 2017-10-6 2017-10-10
i will explain the result :
first allotment_id field is linked with id field in second table , the result i want that we can make sum of qty by the two fields (id , allotment_id ) between the date_from and date_to
and here is my try :
$query1 = "
SELECT SUM(qyt) as total
FROM vip_allotment_details
where allotment_id IN ( SELECT id from vip_allotment where date_from >= '$date_1' AND date_to <= '$date_2')
";
In my query the result gets all the sum of qty field with no filter ..
I hope I have explained my problem well .
thanks/.
I'm not try yet, but maybe you can try like this:
SELECT a.id AS id, SUM(qyt) AS qty, date_from, date_to
FROM vip_allotment AS a
LEFT JOIN vip_allotment_details AS b on b.allotment_id = a.id
WHERE a.date_from >= '{thedatestart}' AND a.date_to <= '{thedateend}'
GROUP BY a.id
ORDER BY a.id ASC;
You need to use JOIN. I see you are using IN keyword, which won't work. There can be many ways to solve your problem. One of them is,
select allotment_id, qty, date_from, date_to
from
(select allotment_id, SUM(qty) as qty
from vip_allotment_details group by allotment_id
) at
INNER JOIN
vip_allotment va
ON va.id= at.allotment_id;
I think the following should do what you ask.
SELECT
va.id,
SUM(vad.qyt) AS total,
va.date_from,
va.date_to
FROM vip_allotment_details AS vad
LEFT JOIN vip_allotment AS va ON va.id = vad.allotment_id
GROUP BY vad.allotment_id
Try below.i think you will get your desired result.
select va.id, temp.qty , va.date_from,va.date_to from vip_allotment as va
inner join (select sum(qty) as qty , allotment_id from vip_allotment_details group by `allotment_id`) as temp
ON temp.allotment_id=va.id
where va.date_from >= '$date_1' AND va.date_to <= '$date_2';
If you want more then one result form an aggregate function (SUM, COUNT, AVG, ...) you'll need to use a GROUP BY. Your query isn't that hard, this should do the trick:
SELECT va.id, va.date_from, va.date_to, SUM(vad.qyt) AS qyt
FROM vip_allotment AS va
LEFT JOIN vip_allotment_details AS vad ON vad.allotment_id = va.id
GROUP BY va.id
And as you can see here, this produces the expected result: http://sqlfiddle.com/#!9/707a8/2
If you now want to start adding extra filters (like filter by date), you can just do so by adding a WHERE to the query. Something like this:
...
LEFT JOIN ...
WHERE va.date_from >= "2017-10-06" and va.date_to <= "2018-10-06"
GROUP BY ...
http://sqlfiddle.com/#!9/707a8/6
On a side note, I noticed you are not binding your params in the php part of your code . Do note that this can pose serious security issues, especially if these dates come directly from the user input. I would suggest looking in to PDO to do the actual querying in PHP.
Try this..change your table name and run the query..hopefully it should give the result as your requirement..if not let me know...
select a.id
, sum(b.qty)
, a.date_from
, a.date_to
from table1 a
, table2 b
where a.id = b.allotment_id
group
by b.allotment_id

Get data if insert are in the same second

I have this table :
id idm date_play
1 5 2017-08-23 12:12:12
2 5 2017-08-23 12:12:12
3 6 2017-08-23 12:14:13
I want to identify if user has more then one insert in the same second. In the case describe I want to get the user id that is 5.
I tried like this :
SELECT `idm`, MAX(`s`) `conseq` FROM
(
SELECT
#s := IF(#u = `idm` AND (UNIX_TIMESTAMP(`date_play`) - #pt) BETWEEN 1 AND 100000, #s + 1, 0) s,
#u := `idm` `idm`,
#pt := UNIX_TIMESTAMP(`date_play`) pt
FROM table
WHERE date_play >= '2017-08-23 00:00:00'
AND date_play <= '2017-08-23 23:59:59'
ORDER BY `date_play`
) AS t
GROUP BY `idm`
Can you help me please ? Thx in advance and sorry for my english.
Assuming your dates are accurate down to the second level, you can do this with a single aggregation:
select idm
from t
group by idm
having count(*) > count(distinct date_play);
If date_play has fractional seconds, then you would need to remove those (say by converting to a string).
If you want the play dates where there are duplicates:
select idm, date_play
from t
group by idm, date_play
having count(*) >= 2;
Or, for just the idms, you could use select distinct with group by:
select distinct idm
from t
group by idm, date_play
having count(*) >= 2;
(I only mention this because this is the only type of problem that I know of where using select distinct with group by makes sense.)
If you want all the rows that are duplicated, I would go for exists instead:
select t.*
from t
where exists (select 1
from t t2
where t2.idm = t.idm and t2.date_play = t.date_play and
t2.id <> t.id
);
This should have reasonable performance with an index on (idm, date_play, id).
If your table is called mytable, the following should work:
SELECT t.`idm`
FROM mytable t INNER JOIN mytable t2
ON t.`idm`=t2.`idm` AND t.`date_play`=t2.`date_play` AND t.`id`!=t2.`id`
GROUP BY t.`idm`
Basically we join the table with itself, pairing records that have the same idm and date_play, but not the same id. This will have the effect of matching up any two records with the same user and datetime. We then group results by user so you don't get the same user id listed multiple times.
Edit:
Gordon Linoff and tadman's suggestions led me to this probably much more efficient query (credit to them)
SELECT t.`idm`
FROM mytable t
GROUP BY t.`date_play`
HAVING COUNT(t.`id`)>1

Need help in optimising query

I have two tables - incoming tours(id,name) and incoming_tours_cities(id_parrent, id_city)
id in first table is unique, and for each unique row from first table there is the list of id_city - s in second table(i.e. id_parrent in second table is equal to id from first table)
For example
incoming_tours
|--id--|------name-----|
|---1--|---first_tour--|
|---2--|--second_tour--|
|---3--|--thirth_tour--|
|---4--|--hourth_tour--|
incoming_tours_cities
|-id_parrent-|-id_city-|
|------1-----|---4-----|
|------1-----|---5-----|
|------1-----|---27----|
|------1-----|---74----|
|------2-----|---1-----|
|------2-----|---5-----|
........................
That means that first_tour has list of cities - ("4","5","27","74")
AND second_tour has list of cities - ("1","5")
Let's assume i have two values - 4 and 74:
Now, i need to get all rows from first table, where my both values are in the list of cities. i.e it must return only the first_tour (because 4 and 74 are in it's list of cities)
So, i wrote the following query
SELECT t.name
FROM `incoming_tours` t
JOIN `incoming_tours_cities` tc0 ON tc0.id_parrent = t.id
AND tc0.id_city = '4'
JOIN `incoming_tours_cities` tc1 ON tc1.id_parrent = t.id
AND tc1.id_city = '74'
And that works fine.
But i generate the query dynamically, and when the count of joins is big (about 15) the query slowing down.
i.e. when i try to run
SELECT t.name
FROM `incoming_tours` t
JOIN `incoming_tours_cities` tc0 ON tc0.id_parrent = t.id
AND tc0.id_city = '4'
JOIN `incoming_tours_cities` tc1 ON tc1.id_parrent = t.id
AND tc1.id_city = '74'
.........................................................
JOIN `incoming_tours_cities` tc15 ON tc15.id_parrent = t.id
AND tc15.id_city = 'some_value'
the query run's in 45s(despite on i set indexes in the tables)
What can i do, to optimaze it?
Thanks much
SELECT t.name
FROM incoming_tours t INNER JOIN
( SELECT id_parrent
FROM incoming_tours_cities
WHERE id IN (4, 74)
GROUP BY id_parrent
HAVING count(id_city) = 2) resultset
ON resultset.id_parrent = t.id
But you need to change number of total cities count.
SELECT name
FROM (
SELECT DISTINCT(incoming_tours.name) AS name,
COUNT(incoming_tours_cities.id_city) AS c
FROM incoming_tours
JOIN incoming_tours_cities
ON incoming_tours.id=incoming_tours_cities.id_parrent
WHERE incoming_tours_cities.id_city IN(4,74)
HAVING c=2
) t1;
You will have to change c=2 to whatever the count of id_city you are searching is, but since you generate the query dynamically, that shouldn't be a problem.
I'm pretty sure this works, but a lot less sure that it is optimal.
SELECT * FROM incoming_tours
WHERE
id IN (SELECT id_parrent FROM incoming_tours_cities WHERE id_city=4)
AND id IN (SELECT id_parrent FROM incoming_tours_cities WHERE id_city=74)
...
AND id IN (SELECT id_parrent FROM incoming_tours_cities WHERE id_city=some_value)
Just an hint.
If you use the IN operator in a WHERE clause, you can hope that the short-circuit of operator AND may remove unnecessary JOINs during the execution for the tours that do not respect the constraint.
Seems like an odd way to do that query, here
SELECT t.name FROM `incoming_tours` as t WHERE t.id IN (SELECT id_parrent FROM `incoming_tours_cities` as tc WHERE tc.id_city IN ('4','74'));
I think that does it, but not tested...
EDIT: Added table alias to sub-query
I've written this query using CTE's and it includes the test data in the query. You'll need to modify it so that it queries the real tables instead. Not sure how it performs on a large dataset...
Declare #numCities int = 2
;with incoming_tours(id, name) AS
(
select 1, 'first_tour' union all
select 2, 'second_tour' union all
select 3, 'third_tour' union all
select 4, 'fourth_tour'
)
, incoming_tours_cities(id_parent, id_city) AS
(
select 1, 4 union all
select 1, 5 union all
select 1, 27 union all
select 1, 74 union all
select 2, 1 union all
select 2, 5
)
, cityIds(id_city) AS
(
select 4
union all select 5
/* Add all city ids you need to check in this table */
)
, common_cities(id_city, tour_id, tour_name) AS
(
select c.id_city, it.id, it.name
from cityIds C, Incoming_tours_cities tc, incoming_tours it
where C.id_city = tc.id_city
and tc.id_parent = it.id
)
, tours_with_all_cities(id_city) As
(
select tour_id from common_cities
group by tour_id
having COUNT(id_city) = #numCities
)
select it.name from incoming_tours it, tours_with_all_cities tic
where it.id = tic.id_city

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