i want to join two tables but i can't do it as i want to sum column and get the result between two dates
first table named : vip_allotment_details
allotment_id qty
2 3
2 5
1 2
1 4
the second table name : vip_allotment
id date_from date_to
1 2017-10-1 2017-10-5
2 2017-10-6 2017-10-10
what i want from the query to get me this result
id qty date_from date_to
1 6 2017-10-1 2017-10-5
2 8 2017-10-6 2017-10-10
i will explain the result :
first allotment_id field is linked with id field in second table , the result i want that we can make sum of qty by the two fields (id , allotment_id ) between the date_from and date_to
and here is my try :
$query1 = "
SELECT SUM(qyt) as total
FROM vip_allotment_details
where allotment_id IN ( SELECT id from vip_allotment where date_from >= '$date_1' AND date_to <= '$date_2')
";
In my query the result gets all the sum of qty field with no filter ..
I hope I have explained my problem well .
thanks/.
I'm not try yet, but maybe you can try like this:
SELECT a.id AS id, SUM(qyt) AS qty, date_from, date_to
FROM vip_allotment AS a
LEFT JOIN vip_allotment_details AS b on b.allotment_id = a.id
WHERE a.date_from >= '{thedatestart}' AND a.date_to <= '{thedateend}'
GROUP BY a.id
ORDER BY a.id ASC;
You need to use JOIN. I see you are using IN keyword, which won't work. There can be many ways to solve your problem. One of them is,
select allotment_id, qty, date_from, date_to
from
(select allotment_id, SUM(qty) as qty
from vip_allotment_details group by allotment_id
) at
INNER JOIN
vip_allotment va
ON va.id= at.allotment_id;
I think the following should do what you ask.
SELECT
va.id,
SUM(vad.qyt) AS total,
va.date_from,
va.date_to
FROM vip_allotment_details AS vad
LEFT JOIN vip_allotment AS va ON va.id = vad.allotment_id
GROUP BY vad.allotment_id
Try below.i think you will get your desired result.
select va.id, temp.qty , va.date_from,va.date_to from vip_allotment as va
inner join (select sum(qty) as qty , allotment_id from vip_allotment_details group by `allotment_id`) as temp
ON temp.allotment_id=va.id
where va.date_from >= '$date_1' AND va.date_to <= '$date_2';
If you want more then one result form an aggregate function (SUM, COUNT, AVG, ...) you'll need to use a GROUP BY. Your query isn't that hard, this should do the trick:
SELECT va.id, va.date_from, va.date_to, SUM(vad.qyt) AS qyt
FROM vip_allotment AS va
LEFT JOIN vip_allotment_details AS vad ON vad.allotment_id = va.id
GROUP BY va.id
And as you can see here, this produces the expected result: http://sqlfiddle.com/#!9/707a8/2
If you now want to start adding extra filters (like filter by date), you can just do so by adding a WHERE to the query. Something like this:
...
LEFT JOIN ...
WHERE va.date_from >= "2017-10-06" and va.date_to <= "2018-10-06"
GROUP BY ...
http://sqlfiddle.com/#!9/707a8/6
On a side note, I noticed you are not binding your params in the php part of your code . Do note that this can pose serious security issues, especially if these dates come directly from the user input. I would suggest looking in to PDO to do the actual querying in PHP.
Try this..change your table name and run the query..hopefully it should give the result as your requirement..if not let me know...
select a.id
, sum(b.qty)
, a.date_from
, a.date_to
from table1 a
, table2 b
where a.id = b.allotment_id
group
by b.allotment_id
Related
I have this table :
id idm date_play
1 5 2017-08-23 12:12:12
2 5 2017-08-23 12:12:12
3 6 2017-08-23 12:14:13
I want to identify if user has more then one insert in the same second. In the case describe I want to get the user id that is 5.
I tried like this :
SELECT `idm`, MAX(`s`) `conseq` FROM
(
SELECT
#s := IF(#u = `idm` AND (UNIX_TIMESTAMP(`date_play`) - #pt) BETWEEN 1 AND 100000, #s + 1, 0) s,
#u := `idm` `idm`,
#pt := UNIX_TIMESTAMP(`date_play`) pt
FROM table
WHERE date_play >= '2017-08-23 00:00:00'
AND date_play <= '2017-08-23 23:59:59'
ORDER BY `date_play`
) AS t
GROUP BY `idm`
Can you help me please ? Thx in advance and sorry for my english.
Assuming your dates are accurate down to the second level, you can do this with a single aggregation:
select idm
from t
group by idm
having count(*) > count(distinct date_play);
If date_play has fractional seconds, then you would need to remove those (say by converting to a string).
If you want the play dates where there are duplicates:
select idm, date_play
from t
group by idm, date_play
having count(*) >= 2;
Or, for just the idms, you could use select distinct with group by:
select distinct idm
from t
group by idm, date_play
having count(*) >= 2;
(I only mention this because this is the only type of problem that I know of where using select distinct with group by makes sense.)
If you want all the rows that are duplicated, I would go for exists instead:
select t.*
from t
where exists (select 1
from t t2
where t2.idm = t.idm and t2.date_play = t.date_play and
t2.id <> t.id
);
This should have reasonable performance with an index on (idm, date_play, id).
If your table is called mytable, the following should work:
SELECT t.`idm`
FROM mytable t INNER JOIN mytable t2
ON t.`idm`=t2.`idm` AND t.`date_play`=t2.`date_play` AND t.`id`!=t2.`id`
GROUP BY t.`idm`
Basically we join the table with itself, pairing records that have the same idm and date_play, but not the same id. This will have the effect of matching up any two records with the same user and datetime. We then group results by user so you don't get the same user id listed multiple times.
Edit:
Gordon Linoff and tadman's suggestions led me to this probably much more efficient query (credit to them)
SELECT t.`idm`
FROM mytable t
GROUP BY t.`date_play`
HAVING COUNT(t.`id`)>1
Two tables, with a left join. For ease table 1 and table 2.
Table 1 contains a list of people and their current status, table 2 is all of their "invites". All im trying to do as part of the join is show in a list all the current "people" and then the LATEST invite status (from table 2) so return a single row from table 2.
I have everything working... but its duplicating for example if a person has had multiple invites it will put them twice on the list. I just want to limit it to
$sql = "SELECT table1.fieldname as table1fielname table2.fieldname [more fields]
FROM xxx
LEFT JOIN xxx on table1.sharedid=table2.sharedid
WHERE XXX LIMIT 1 ";`
Obvioulsy the limit 1 doesnt do what its supposed to. I have tried adding additional select statements in brackets but being honest it just breaks everything and im not an expert at all.
I'm not an expert too but I'll try. Have you tried to use DISTINCT?
For exemple:
SELECT DISTINCT column_name1,column_name2
FROM table_name; [...]
It normally delete double matches.
Here are the links:
http://www.w3schools.com/sql/sql_distinct.asp
https://www.techonthenet.com/oracle/distinct.php
Give example data. And use good table and column names. For example:
(this returns all rows that satisfy the join):
WITH people(ppl_id,ppl_name,status) AS (
SELECT 1,'Arthur','active'
UNION ALL SELECT 2,'Tricia','active'
), invites(ppl_id,inv_id,inv_date) AS (
SELECT 1,1, DATE '2017-01-01'
UNION ALL SELECT 1,2, DATE '2017-01-07'
UNION ALL SELECT 1,3, DATE '2017-01-08'
UNION ALL SELECT 2,1, DATE '2017-01-01'
UNION ALL SELECT 2,2, DATE '2017-01-08'
)
SELECT
*
FROM people
JOIN invites USING(ppl_id)
ORDER BY 1
;
ppl_id|ppl_name|status|inv_id|inv_date
1|Arthur |active| 1|2017-01-01
1|Arthur |active| 3|2017-01-08
1|Arthur |active| 2|2017-01-07
2|Tricia |active| 2|2017-01-08
2|Tricia |active| 1|2017-01-01
But we want only 'Arthur' with '2017-01-08' and 'Tricia' with '2017-01-08'.
With any database that supports ANSI 99, you could try with a temporary table containing the newest invitation date per "people id", and join that temporary table with the invitations table. We call that table newest_invite_date, and, apparently, it does what we expect it to do:
WITH people(ppl_id,ppl_name,status) AS (
SELECT 1,'Arthur','active'
UNION ALL SELECT 2,'Tricia','active'
), invites(ppl_id,inv_id,inv_date) AS (
SELECT 1,1, DATE '2017-01-01'
UNION ALL SELECT 1,2, DATE '2017-01-07'
UNION ALL SELECT 1,3, DATE '2017-01-08'
UNION ALL SELECT 2,1, DATE '2017-01-01'
UNION ALL SELECT 2,2, DATE '2017-01-08'
), newest_invite_date(ppl_id,inv_date) AS (
SELECT ppl_id,MAX(inv_date)
FROM invites
GROUP BY ppl_id
)
SELECT
people.ppl_id
, people.ppl_name
, people.status
, newest_invite_date.inv_date
FROM people
JOIN newest_invite_date USING(ppl_id)
ORDER BY 1
;
ppl_id|ppl_name|status|inv_date
1|Arthur |active|2017-01-08
2|Tricia |active|2017-01-08
Is this what you were looking for?
Happy playing ...
Marco the Sane
I want to do the following. I have a table in the database, I am working on a table called asistencia and this table has 3 columns
id_asistencia as a int AUTOINCREMENT
nro_matricula as an int which I took it from another table called
alumnos
fecha as a date
This is a sketch of the database
id_asistencia | nro_matricula | fecha
1 | 0001| 2015-01-10
2 | 0002| 2015-01-10
3 | 0002| 2015-02-10 (another date )
The thing is I have to do a percentage
select all id_1 records in my nro_matricula column and see how many times its repeated in my rows and do a percentage respect all the dates in my database
EG : id_1 came to class day(whatever day) and he/she did not came to class the next day so id_1 has 50% assistance
Expected result
nro_matricula | percentage
0001| 50
0002| 100
The question is how can I make this query. If can be done in PHP its even better but i feel that this can be done in SQL
PS : The Database wasn't created by me
And excuse my English is not the better and i expect it to be understandable for you to help me
You can use sql statement like this:
select (
sum (if nro_matricula = '001' ,1,0 )
/ count(*)
from asistencia
--where nro_matricula = '001'
Maybe just simply:
select al.nro_matricula,
100 * count(distinct al.fecha) / (select count(distinct al1.fecha) from alumnos al1) as percentage
from alumnos al
group by al.nro_matricula
I did found the answer to my question. Thank you all for helping me out
SELECT
asistencia.nro_matricula as matricula,
COUNT( DISTINCT asistencia.fecha)* 100 /
COUNT( DISTINCT asistencia.nro_matricula) / (SELECT COUNT(DISTINCT asistencia.fecha)
FROM asistencia
ORDER BY COUNT(*) DESC
LIMIT 1 )
as porcentaje_asistencia
FROM asistencia
JOIN alumno
WHERE asistencia.nro_matricula = alumno.nro_matricula AND alumno.id_curso = 'basica6a'
Tried this in Oracle. Should work in MySQL too.
SELECT aa.NRO_MATRICULA , days_present/total_count* 100 FROM
(SELECT DISTINCT NRO_MATRICULA,
COUNT(*) as days_present FROM ASISTENCIA GROUP BY NRO_MATRICULA ) AA
,
(SELECT COUNT(*) as total_count FROM (SELECT DISTINCT(FECHA) FROM ASISTENCIA GROUP BY FECHA)) BB
Ouptut
nro_matricula percentage
0001 50
0002 100
The query (SELECT COUNT(*) FROM (SELECT DISTINCT(FECHA) FROM ASISTENCIA AA GROUP BY FECHA)) will give count of distinct date (2 in your case). Then we are getting distinct nro_matricula group by nro_matricula to get its count which will give the days it was present. Then divide both values from above steps to get percentage.
I have one table with a list of number of sales per month against product code and another with a list of months that can extend before or after the months that had a sale in. I need to results to show 0 sales if there were no sales in the month and for the cumulative to add this up. I have tried using case and if and getting it to put 0 if sales.sales was null but this did not work and I still just had blanks.
create table summary as (SELECT
q1.productid As productid,
q1.date AS Month_View,
q1.sales AS Monthly_Units_Sold,
(#runtot_sales := #runtot_sales + q1.sales) AS Cumulative_Sales
FROM
(SELECT
sales.productid,
dates.date,
if(sales.date is null,0,sales.sales) as sales
from
dates
left join sales on dates.date = sales.date
where
sales.productid = '$input1'
group by dates.date
ORDER BY date) AS q1);
";
Try COALESCE() function to return the first non-NULL value of a list Also see demo here
CREATE TABLE summary AS
(SELECT
q1.productid AS productid,
q1.date AS Month_View,
q1.sales AS Monthly_Units_Sold,
(
#runtot_sales := #runtot_sales + q1.sales
) AS Cumulative_Sales
FROM
(SELECT
sales.productid,
dates.date,
COALESCE(sales.sales, 0) AS sales
FROM
dates
LEFT JOIN sales
ON dates.date = sales.date
WHERE sales.productid = '$input1'
GROUP BY dates.date
ORDER BY DATE) AS q1) ;
MySQL COALESCE() function
You are misusing GROUP BY and therefore getting indeterminate results. See this: http://dev.mysql.com/doc/refman/5.5/en/group-by-extensions.html
If you're aggregating your items by product and date you probably want something like this.
SELECT sales.productid,
dates.date,
SUM(sales.sales) as sales
FROM dates
LEFT JOIN sales ON dates.date = sales.date
WHERE sales.productid = '$input1'
GROUP BY sales.productid, dates.date
ORDER BY /* i'm not sure what you're trying to do with the running total */
Note that SUM(sales.sales) handles the NULL values from your LEFT JOIN correctly. If the date doesn't join a sales row then sales.sales will be NULL.
If you're trying to do a month-by-month summary you need more logic than you have. See this writeup: http://www.plumislandmedia.net/mysql/sql-reporting-time-intervals/
i've got a big Problem and i was trying the whole day and did not find any Solution. Hope you can help me?
I have two tables:
The first one named "orders":
orders_id | orders_date | .....
1 xxxxxxxxxx
2 xxxxxxxxxx
3 xxxxxxxxxx
The second is "orders_history":
orders_id | order_status_id | date_added
1 1 2009-10-01
1 2 2010-01-01
2 1 2010-02-01
3 1 2010-02-01
So now i want to have all orders where order_status_id = '1'
I have tried with MAX, HAVING, GROUP BY, ... Subselects also, but i haven't found any solution. I know it's not very hard, but i'm finished...
Is it something like:
SELECT orders.*, orders_history.* FROM orders, orders_history WHERE orders_history.order_status_id <= '1'
But then i also get Order with order_id 1
Hope you can help. Thank you!
Sascha
To further clarify, the poster's 'orders_history' table keeps track of the state of all orders over time. The goal is a query that will find all orders that currently have an order status of 1. Order ID# 1 currently has a status of 2, so it should not be included in the results.
Assumably, order status goes up over time and never goes down, so that the order status and date_added will constantly increase.
This should do it for you:
SELECT *
FROM orders
, orders_history
WHERE orders.orders_id = orders_history.orders_id
AND orders.orders_id IN (
SELECT orders_id
FROM orders_history
GROUP BY orders_id
HAVING MAX(order_status_id) = 1
)
I'm not surprised you had trouble getting this to work - it's a very tricky type of query where you must 'GROUP BY' and find the MAX and also all the other corresponding values in the same row. This is a common request, and it often surprises people that it's actually quite difficult to express this in SQL. Here's one way to do it in MySQL:
SELECT T2.orders_id FROM (
SELECT orders_id, MAX(date_added) AS date_added
FROM orders_history
GROUP BY orders_id
) AS T1
JOIN orders_history T2
ON T1.orders_id = T2.orders_id AND T1.date_added = T2.date_added
GROUP BY T2.orders_id, T2.date_added
HAVING MAX(order_status_id) = 1
Here I am assuming that:
orders_id, date_added is not unique.
orders_id, date_added, order_status_id is unique.
If not the second assumption is not true, add DISTINCT after the first SELECT.
Here are the results I get for your test data:
2
3
You can join this to your orders table if you want to fetch extra information about each order.
Edited after discussion in comments (changed the where clause):
SELECT orders.*, orders_history.*
FROM orders INNER JOIN orders_history
ON orders.orders_id = orders_history.orders_id
WHERE orders.orders_id IN
(SELECT orders_id FROM orders_history
GROUP BY orders_id
HAVING MAX(order_status_id) = 1)
select o.*, oh.*
from orders o
inner join orders_history oh on oh.orders_id = o.orders_id
where oh_orders_status = 1
should do the trick. It's a while since I touched mysql though, so I don't know if your orders_status should be in quotes - I'd guess not if it is an int...