Trying to make json file from this php but its not working what im missing
// Initialize variable for database credentials
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'users';
$dblink = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
if ($dblink->connect_errno) {
printf("Failed to connect to database");
exit();
}
//Fetch 3 rows from actor table
$result = $dblink->query("SELECT * FROM profile");
//Initialize array variable
$dbdata = array();
//Fetch into associative array
while ( $row = $result->fetch_assoc()) {
$dbdata[]=$row;
}
//Print array in JSON format
echo json_encode($dbdata);
Related
I am writing a PHP script which
connects to the database
fetches all orders in an array. ($result)
I want to go through the array and fetch all say "userName"
The trouble is, with my code below, I am able to only get the first character of each "userName" in the array.I want an array with all "userName"s.
<?php
$dbhost = 'localhost';
$dbuser = 'user';
$dbpass = 'password';
$dbname = 'dbname';
//Create database connection
$dblink = new mysqli($dbhost, $dbuser, $dbpass, $dbname);
$sql = "select * from ordertest";
$retval = mysqli_query($dblink, $sql) or die(mysqli_error($dblink));
$result = mysqli_fetch_array($retval, MYSQLI_ASSOC);
if (mysqli_num_rows($retval) > 0) {
$arr = json_decode($result, true);
foreach ($result as $key => $value) {
echo $value["userName"];
}
} else {
echo $sql;
}
The solution should be next:
<?php
$sql = "select * from ordertest";
// retrieve query result from DB
$retval = mysqli_query($dblink, $sql) or die(mysqli_error($dblink));
// if result not empty
if (mysqli_num_rows($retval) > 0) {
// retrieve single row from $retval
while ($result = mysqli_fetch_array($retval, MYSQLI_ASSOC)) {
echo $result["userName"];
echo "\n";
}
} else {
echo $sql;
}
Look example here: PHPize.online
I am trying to connect my html page with MySQL database to show data from one specific table to my page, but I always get an error actually it just goes to die part of an SQL code. I am really new to PHP programming so please can someone help me, what am I doing wrong?
Here is my code:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>AJDE</title>
</head>
<?php
$servername = "localhost";
$username = "******";
$password = "*****";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$query = "select * from PERCENTILE";
$result = mysqli_query($conn,$query);
if(!$result) {
die ("Umro!");
}
/* close connection */
$mysqli->close();
?>
<body>
</body>
</html>
Thank you!
Do you want to show the table as a HTML table or just an array?
The following is what I did to display my table as a HTML table:
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '*****';
$dbname = 'dbname';
$selectedTable = 'whateverTableYouWant';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if (!$conn){
die('cannot connect to mysql');
}
$query = "SELECT * FROM $selectedTable";
if ($result = mysqli_query($conn , $query)) {
echo("<div class = 'data_wrapper'>");
// Display Header of the table
$fieldcount=mysqli_num_fields($result); //value = number of columns
$row = mysqli_fetch_assoc($result); //Fetch a result row as an associative array:
//array to string conversion
echo("<table id='example' class='table table-striped table-bordered' cellspacing='0' width='100%'>");
echo("<thead> <tr>");
foreach($row as $item){
echo "<th>" .$item. "</th>";
}
echo("</tr> </thead>");
//Footer
echo("<tfoot> <tr>");
foreach($row as $item){
echo "<th>" .$item. "</th>";
}
echo("</tr> </tfoot>");
//Display Data within the table
echo("<tbody>");
while ($row = mysqli_fetch_assoc($result)){
echo "<tr>";
foreach ($row as $item){
echo "<td contenteditable = 'true'>" . $item . "</td>"; //Change contenteditable later
//Editable data should be constricted, int = numbers only, string = words, date = date
}
echo "</tr>";
}
echo("<tbody>");
echo "</table>";
echo("</div>");
}
The following is just displaying as an array:
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '*****';
$dbname = 'dbname';
$selectedTable = 'whateverTableYouWant';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname);
if (!$conn){
die('cannot connect to mysql');
}
$query = "SELECT * FROM $selectedTable";
if ($result = mysqli_query($conn , $query)) {
while ($row = mysqli_fetch_array($result)){
print_r($row);
}
}
Please change the connection string like mentioned below.
<?php
$con = mysqli_connect("localhost","username","password","dbname");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
Please let me know if you've any queries.
I Think you need to select a database where you will run the query:
Try with this code:
<?php
$username = "your_name";
$password = "your_password";
$hostname = "localhost";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
echo "Connected to MySQL<br>";
//select a database to work with (so replace the database name examples)
$selected = mysql_select_db("examples",$dbhandle)
or die("Could not select examples");
//execute the SQL query and return records
$result = mysql_query("SELECT * FROM PERCENTILE");
//fetch the data from the database and display results
//replace id,name,year with the columns you have on your table PERCENTILE and you want to show
while ($row = mysql_fetch_array($result)) {
echo "ID:".$row{'id'}." Name:".$row{'name'}."Year: ". $row{'year'}."<br>";
}
//close the connection
mysql_close($dbhandle);
?>
Hope it helps,
Vince.
I am learning as i go and been picking up snippets of code as i go and been working on this for the past few days and now i have thrown the towel in to seek help.
I am trying to calculate the sum of 2 columns in my database using PDO.
here is my code
<?php
$host = "localhost";
$db_name = "dbname";
$username = "root";
$password = "root";
try {
$con = new PDO("mysql:host={$host};dbname={$db_name}", $username, $password);
}
// show error
catch(PDOException $exception){
echo "Connection error: " . $exception->getMessage();
}
$query = "SELECT SUM (fill_up) AS TotalFill,
SUM (mileage_covered) AS Totalmiles
FROM fuel_cost";
$row = $query->fetch(PDO::FETCH_ASSOC);
$total_fill = $row['TotalFill'];
$total_miles = $row['Totalmiles'];
$myanswer = $total_fill/$total_miles;
//display the answer
echo $myanswer
?>
I have also checked my database table and both columns are varchar(32)
the error I am getting is Call to a member function fetch() on a non-object
I have searched into this but not sure what's the issue with the above code
Thank You in advance
Try this code :-
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "dbname";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT SUM (fill_up) AS TotalFill,
SUM (mileage_covered) AS Totalmiles
FROM fuel_cost";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while ($row = $result->fetch_assoc()) {
$total_fill = $row['TotalFill'];
$total_miles = $row['Totalmiles'];
$myanswer = $total_fill / $total_miles;
//display the answer
echo $myanswer;
die;
}
} else {
echo "0 results";
}
$conn->close();
?>
I am trying to print all the rows in my database say 'student'. I am trying with many of codes with while loops and even examples from w3school. But, it's not working. Here's a simple code of php
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(!$conn) {
die('Could not connect to MySql'.mysql_error());
}
mysql_select_db("StudDatabase") or die(mysql_error());
$sql = "SELECT * FROM Student";
mysql_query($sql);
mysql_close($conn);
?>
I am working in wamp server 2.2
Your code don't print the result of the query.
Try to add this code:
$results = mysql_query($sql) or die(mysql_error());
while($row = mysql_fetch_assoc($results)){
foreach($row as $cname => $cvalue){
print "$cname: $cvalue\t";
}
print "\r\n";
}
But you should consider using PDO, mylsql is deprecated : http://php.net/manual/en/pdo.connections.php
$database = new PDO('mysql:host=localhost;dbname=test', $user, $pass);
foreach($database->query('SELECT * FROM `Student`') as $row) {
print_r($row);
}
I'm using PHP code to upload or insert data from MDB file to MySQL database.I want my table value get inserted into MySQL database. But data does not inserted into MySQL database.This code shows me no error.Here is my code. please help I have tried every solution on net.
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$dbname = 'payroll_system';
//mysql
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');
mysql_select_db($dbname);
$sql = "SELECT * FROM attendance";
$result = mysql_query($sql);
//mdb
$conn2 = new COM("ADODB.Connection") or die("Cannot start ADO");
$conn2->Open("DRIVER={Microsoft Access Driver (*.mdb)}; DBQ=C:\\xampp\\htdocs\\payroll\\eTimeTrackLite1.mdb");
$rs = $conn2->Execute("SELECT * FROM AttendanceLogs");
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
$column1=$row["AttendanceLogId"];$column2=$row["AttendanceDate"];$column3=$row["EmployeeId"];$column4=$row["InTime"];
$column6=$row["OutTime"];$column8=$row["Duration"];
echo "hello";
echo $column1;echo $column2;echo $column3;echo $column4;
$rs->MoveFirst();
while (!$rs->EOF)
{
$attendance_id = $rs->Fields("AttendanceLogId");
$attendance_date = $rs->Fields("AttendanceDate");
$emp_id = $rs->Fields("EmployeeId");
$in_time = $rs->Fields("InTime");
$out_time = $rs->Fields("OutTime");
$duration = $rs->Fields("Duration");
mysql_query("UPDATE attendance SET AttendanceLogId = '$attendance_id', AttendanceDate='$attendance_date', EmployeeId='$emp_id',InTime='$in_time',OutTime='$out_time',Duration='$duration' '"); ?>
<?php
$rs->MoveNext();
}
}
?>
</table> <?php
mysql_free_result($result);
$rs->Close();
$conn2->Close();
$rs = null;
$conn2 = null;
?>
you need to INSERT each records data instead of UPDATE. Re-write the following line:
mysql_query("UPDATE attendance SET AttendanceLogId = '$attendance_id', AttendanceDate='$attendance_date', EmployeeId='$emp_id',InTime='$in_time',OutTime='$out_time',Duration='$duration' '");