I have next problem:
My table date format was: LIKE 2017-01-08 18:50:25 (with time).
When i use sql query like
'SELECT date FROM table WHERE date = "2017-01-08"'
My row was empty, i need COUNT all row with same (today) date WITHOUT TIME.
Note, i will not change INSERT date time!
Use DATE() to get the date portion of the datetime field and compare it to today. Use COUNT() to get the number of records that match your query.
SELECT count(*) FROM table WHERE DATE(date) = CURDATE()
You can also replace CURDATE() with NOW(), CURRENT_DATE(), and CURRENT_DATE
You can also use it in the following way
'SELECT date FROM table WHERE date_format(date,'%Y-%m-%d') = "2017-01-08"'
the date_format is mysql function which return date according to your pattern the above pattern only return the Y-m-d from the datetime
I hope it will help you
plz change your statement equal operator to greater than
'SELECT date FROM table WHERE date > "2017-01-08"'
as by default if time portion is not present then it is putting 00:00...
Related
I have timestamp column called time in one of my table called tbl_recordings. Its storing data like 2019-04-10 19:51:08. Now I am trying to get result filtered by date but its not working with below query.
$date = 2019-04-10
SELECT * FROM tbl_recordings WHERE time = $date;
here time is timestamp field in my table. Let me know if someone can help me for get out of it. Thanks
Assuming you $date value is a string you should compare the proper date converted values
SELECT * FROM tbl_recordings WHERE date(time) = str_to_date($date, '%Y-%m-%d') ;
Never use date() as it will execute date() on all rows, even those which do not match
Try something like this
... WHERE date >='2019-04-10' AND date <'2019-04-11'
Hello I am working with Word Press and I want to fetch records according to the the
date.MySQL database has a table wp_evr_event with end_date column which has
a number of dates in end_date column according to each record like:
1. 2017-1-4
2. 2017-1-6
3. 2017-10-10
I want to fetch those record which has End date greater than to the current
date.I used Query
SELECT * FROM `wp_evr_event` WHERE `end_date`>'2017-1-31'
But I get number of records which has the less date to the current date.
How to resolved this problem.
You need to use DATE() of mysql like below:-
SELECT * FROM `wp_evr_event` WHERE DATE(`end_date`)>'2017-1-31'
Note:- I think that end_date field is of datetime type , so that's why your code is not working
You need to use str_to_date MySQL function to convert string into date. Here's the documentation.
Your query will look like this:
SELECT * FROM wp_evr_event
WHERE str_to_date(date, '%Y-%m-%d') > '2017-1-31';
Here's the SQL Fiddle.
In mySQL I have a timestamp column named when
2015-01-07 16:43:21
My question is how using PHP/mySQL
For now I can show the results based on month number like
... where month(`when`) = '1' ...
but what if I want to show the rows of a particular date for example 2015-01-05 ?
I will pass the preferable date through a variable into the sql query.
Just wrap the date() function around your date string which is already in the YYYY-MM-DD format, and also around your timestamp field in the where clause:
select * from table where date(`when`) = date('2015-01-05');
From the documentation for date():
Extracts the date part of the date or datetime expression expr.
Here's how to convert the date via MySQL:
SELECT
DATE_FORMAT(`when`, '%Y-%m-%d') AS my_date
FROM
my_table
WHERE
MONTH(`when`) = 1;
Take a look at the MySQL documentation here for other formats: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_date-format
In my sql query I output dates in chronological order.
The dates in my database are stored in d-M-Y format.
What I want to do is sort the results by dates equal to or greater than today to be output first.
In my query I have this sort in my query
...From $db ORDER BY STR_TO_DATE(sortdate, '%d-%M-%Y') ASC
Can anyone tell me if I can do a comparison on todays date as each record is output from the db?
This will give me todays date
$todaysdate = date("d-M-Y", time());
but can anyone tell me if I can build that into my query?
Thanks in advance.
check mysql DATEDIFF in combination with CURRENT_DATE ==>
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_current-date
My guess is that you saved the date in a VARCHAR column. Please don't do that, you make it very complicated for yourself when you want to do stuff (like this) with the date. I'd suggest that you convert the column to a DATE field and then just use:
SELECT * FROM my_table WHERE my_date_field >= CURDATE()
And if you want to output the date in the d-m-Y format, you can use DATE_FORMAT()
You really should be storing the dates in a dateTime format. That will make it much easier to do all sorts of orders, comparisons and plenty of other things. You could for example, then use the mysql now() function to only get the results you need?
...From $db where sortDate>=now() ORDER BYsortdate ASC
Assuming sortdate is datetime field, in order to display dates equal to or greater than today first,could use UNION.
SELECT * FROM my_table WHERE sortdate>= CURDATE()
UNION
SELECT * FROM my_table WHERE sortdate< CURDATE()
You can use WHERE sortdate >= $todaysdate
Just put this condition in where like date_column >= curdate()/$todaysdate
thanks
I am trying to select all records in a table which have a date between the current date and 1 month ahead.
The date is stored like this DD-MM-YYYY
And the query I have tried:
SELECT * from tablename WHERE renewalDate BETWEEN DATE_FORMAT(CURDATE(),GET_FORMAT(DATE,'EUR')) AND DATE_ADD(DATE_FORMAT(CURDATE(),GET_FORMAT(DATE,'EUR')), INTERVAL 1 MONTH)
But this does not return the correct results.
Is the date stored in an actual date or datetime field? If it's in a char/varchar field, you won't be able to use the BETWEEN syntax, as mysql will just treat them as fixed strings.