I have timestamp column called time in one of my table called tbl_recordings. Its storing data like 2019-04-10 19:51:08. Now I am trying to get result filtered by date but its not working with below query.
$date = 2019-04-10
SELECT * FROM tbl_recordings WHERE time = $date;
here time is timestamp field in my table. Let me know if someone can help me for get out of it. Thanks
Assuming you $date value is a string you should compare the proper date converted values
SELECT * FROM tbl_recordings WHERE date(time) = str_to_date($date, '%Y-%m-%d') ;
Never use date() as it will execute date() on all rows, even those which do not match
Try something like this
... WHERE date >='2019-04-10' AND date <'2019-04-11'
Related
I have next problem:
My table date format was: LIKE 2017-01-08 18:50:25 (with time).
When i use sql query like
'SELECT date FROM table WHERE date = "2017-01-08"'
My row was empty, i need COUNT all row with same (today) date WITHOUT TIME.
Note, i will not change INSERT date time!
Use DATE() to get the date portion of the datetime field and compare it to today. Use COUNT() to get the number of records that match your query.
SELECT count(*) FROM table WHERE DATE(date) = CURDATE()
You can also replace CURDATE() with NOW(), CURRENT_DATE(), and CURRENT_DATE
You can also use it in the following way
'SELECT date FROM table WHERE date_format(date,'%Y-%m-%d') = "2017-01-08"'
the date_format is mysql function which return date according to your pattern the above pattern only return the Y-m-d from the datetime
I hope it will help you
plz change your statement equal operator to greater than
'SELECT date FROM table WHERE date > "2017-01-08"'
as by default if time portion is not present then it is putting 00:00...
Hi there please help me if you can. Here is my senario:
I have a MySQL database with a column that holds a date in the form of a varchar. The format of the date is the following 29/05/2014 (i.e. d/m/Y).
I'm trying to compare the value of this column with todays date and return any rows where the date is earlier than todays date.
I'm using a php variable to store todays as follows:
$date = date("d/m/Y");
Here is my SQL query:
SELECT * FROM patients WHERE last_seen < '$date'
What gets returned
So what is returned is very unusual (to me). All records where the last_seen "day" is less than todays "day". It seems to be overlooking the month and year. So in other words if I last_seen = "30/05/2014" and todays date is "29/05/2014" this record is still returned.
Does anyone have any ideas what I might be doing wrong here?
Thanks
You really, really shouldn't store dates in a varchar field - use date or datetime or timestamp data type.
That said, sometimes you don't have control over the database and you have to deal with somebody else's bad design decision. In this case, to compare dates, convert the varchar strings to dates and compare them that way. So, in your case, you can have something like this:
$date = date("d/m/Y");
and then
SELECT * FROM patients WHERE str_to_date('last_seen', '%d/%m/%Y') < str_to_date('$date', '%d/%m/%Y')
or simpler
SELECT * FROM patients WHERE date(last_seen) < current_date
This way you are actually comparing dates and not strings containing dates. Naturally, this assumes that all dates are stored in the same format.
EDIT: I just tested the last option - and, apparently, date('30/05/2014') returns NULL on my system (mysql 5.5 on linux), hence I suggest the best way is
SELECT * FROM patients WHERE str_to_date('last_seen', '%d/%m/%Y') < current_date
You need to store your date as DATE or DATETIME in your database.
Then you can use:
SELECT * FROM patients WHERE DATE(last_seen) < CURRENT_DATE
I have a UNIX timestamp in a table like 1321521158 and want to get the details from a table for the particular date, like:
$mydate="11/11/2011";
SELECT notes FROM table WHERE `addeddate`=$mydate
How do I get it?
you can use the mysql date function like:
WHERE date(addedate) = date(mydate)
or you can calculate the starting and ending timestamp for the given day you want to know and then do
WHERE addeddate >= mystarttimestamp AND addeddate <= myendtimestamp
try
WHERE $mydate = FROM_UNIXTIME('dateColumn')'%Y/%D/%M');
MySQL Date Time Functions
I am working with a table on which I can't change the structure.... Now there is a varchar column which contains a timestamp. Now I need to select the records whose timestamp translates to the current date, or a specified date.
Any help?
First off you shouldn't be storing date information in a mysql database with a VARCHAR field. Rather use DATETIME that is what it is for. I can only guess how you have stored your timestamp date in the database but I am going to assume it is the following format:
YYYY-mm-dd hh:mi:ss (ie '2011-04-15 09:23:55')
You now have to format your input which I am assuming is a time object or it is a string in the same format as the data in the database:
$yourdate = strftime("%Y-%m-%d", $input);
then construct your query
query = "select * from table where substring(datecol, 1, 10) = '$yourdate'";
execute this and you should be good
Based on the format that you're storing the date as a string, use the STR_TO_DATE function to parse out the date. Then you can use it as a part of the where clause to query desired data.
try this
select * from table where date(your_field)=CURDATE()
or specific date
select * from table where date(your_field)=DATE_FORMAT(2011-05-31 00:02:00, '%Y-%m-%d')
How to get date and time into one string ($moment) and if it works, can mysql do this:
SELECT * FROM table ORDER BY $moment ASC
?
Assuming you have a TIMESTAMP or a DATETIME column, then the date() function will give you a suitable value to use in a query:
$moment = date("Y-m-d H:i:s"); //current time
The query you put in your question doesn't seem to use it at all however. Using ORDER BY on a datetime/timestamp column does work though, so you'll get the result set in chronological order.