for($i=0;$i<$directoriesCount;$i++)
{
$fileName=$Config['path']['basePath']."language/".$directories[$i]."/"."commontest.conf";
$file = fopen($fileName,"a");
$data = "testcontent";
fwrite($file,"\n");
fwrite($file,$data);
fclose($file);
}
the $directories variable will have array values:
en_lang
fr_lang
it_lang, etc.,
in the every directory we should find the commongtest.conf file to write the content.
In my test file its writes only the first values of array for ex 1. en_lang folder file only get fwrite other files not affected.
You have an extra double quote here:
."/".commontest.conf"
should be:
."/.commontest.conf"
A foreach statement might work better here for you:
foreach($directories as $directory){
$fileName=$Config['path']['basePath']."language/".$directory."/.commontest.conf";
$file = fopen($fileName,"a");
$data = "testcontent"."\n";
fwrite($file,$data);
fclose($file);
}
This code is working for me.
I think using file_put_contents would be even better.
foreach($directories as $directory){
$fileName=$Config['path']['basePath']."language/".$directory."/.commontest.conf";
$data = "testcontent"."\n";
file_put_contents($fileName,$data);
}
Related
I am trying to replace some hyperlinks in a csv file, like this one:
[https://assets.suredone.com/683987/media-pics/6164307j-gabriel-61643-proguard-steel-shock-absorber-for-select-chevrolet-gmc-models.jpg. Here is my code:][1]. Here is my code:
<?php
$in_file = 'gabriel-images-urls.csv';
$out_file = 'results.csv';
$fd = fopen($in_file, "r");
$new_array= array();
$toBoot= array();
while ($data = fgetcsv($fd)) {
echo '<pre>';
if (strpos($data[2],'media-pics') !== false) {
$data[2]=str_replace('media-pics','media-photos',$data[2]);
fputcsv($fd, $data);
// echo $output;
}
}
?>
The new link for example must look like this:[1]https://assets.suredone.com/683987/media-photos/6164307j-gabriel-61643-proguard-steel-shock-absorber-for-select-chevrolet-gmc-models.jpg. The goal is he "media-pics" substring to be replaced with "media-photos". At this point nothing happens in the file. I think this is because the file is open only for reading but I am not sure.
Can you not simply do a string replacement on the whole file rather than attempting to load and process each line of the file using fgetcsv?
<?php
$srcfile='gabriel-images-urls.csv';
$outfile='results.csv';
$csvdata=file_get_contents( $srcfile );
$moddata=str_replace('media-pics','media-photos',$csvdata);
file_put_contents( $outfile, $moddata );
?>
I'm trying to make my PHP script open more than 1 text document and to read them.
My current script is as follows:
<?php
//$searchthis = "ignore this";
$matches = array();
$FileW = fopen('result.txt', 'w');
$handle = #fopen("textfile1.txt", "r");
ini_set('memory_limit', '-1');
if ($handle)
{
while (!feof($handle))
{
$buffer = fgets($handle);
if(stripos($buffer, $_POST["search"]) !== FALSE)
$matches[] = $buffer;
}
fwrite($FileW, print_r($matches, TRUE));
fclose($handle);
}
?>
I'm trying to fopen like a bunch of files, maybe like 8 of them or less.
How would I open, and read all these files?
Any help is GREATLY appreciated!
Program defensively, check the return's from functions to ensure you are not making incorrect assumptions about your code.
There is a function in PHP to read the file and buffer it:
enter link description here
I don't know why you would want to open a lot of files, it surely will use a lot of memory, anyway, you could use the file_get_contents function with a foreach:
$files = array("textfile1.txt", "textfile2.txt", "textfile3.txt");
$data = "";
foreach ($files as $file) {
$data .= #file_get_contents($file);
}
echo $data;
There is a function in php called file which reads entire file into an array.
<?php
// "file" function creates array with each line being 1 value to an array
$fileOne = file('fileOne.txt');
$fileTwo = file('fileTwo.txt');
// Print an array or do all array magic with $fileOne and $fileTwo
foreach($fileOne as $fo) {
echo $fo;
}
foreach($fileTwo as $ft) {
$echo $ft;
}
?>
Read more about : file function ion php
I have a directory which contains several text files. What I'm trying to do is to randomly select one of the files and then display it. Here's what i got so far, but i still haven't managed to get it working. Any idea's? Thanks.
<?php
function random_pic($dir = 'wp-content\files')
{
$files = opendir($dir . '/*.txt');
$file = array_rand($files);
return $files[$file];
}
while(!feof($file)) {
echo fgets($file) . "<br />";
}
fclose($file);
?>
scandir will put all elements in the directory into an array. Then use array_rand to choose a random element from the array.
$dir = "/path/to/pictures/";
$dirarray = scandir( $dir );
unset($dirarray [0]);
unset($dirarray [1]);
$content = file_get_contents( $dir . $dirarray[array_rand($dirarray )] );
echo $content;
The unset commands are to remove . and .. from the array.
This would for example result in echoing picturename.jpg.
You have wrong slash in your directory.
$dir = 'wp-content\files'
should be
$dir = 'wp-content/files'
It should be forward slash not back slash. Also check permission of the directory that you are accessing.
Try this:-
Use glob function to get all files in a directory, and then take a random element from that array and return it. Then read the file and echo its content.
function get_random_file($dir = 'folder_name')
{
$files = glob($dir . '/*.txt');
$file = array_rand($files);
return $files[$file];
}
$fh = fopen($myFile, 'r');
$theData = fread($fh, filesize($myFile));
fclose($fh);
echo $theData;
use function name with parameters in while loop condition and check function returning a file name or not. Check the following link for detail http://php.net/manual/en/function.readdir.php
I am very new to php, and i have search and put together this script to convert text to csv and write the out put on the file.
$File = "/var/apache2/htdocs/loginS/host.txt";
$Handle = fopen($File,"r");
$Content = fread ($Handle,filesize ($File));
fclose($File);
fclose($Handle);
$Content = explode("\t", $Content);
foreach($Content as $Value) {
//echo $Value."|"; // till this line working
fwrite($save, $Value);
fclose($save);
}
the problem is when I try to write on the file. I got only one line.what is my error.
You are calling fclose() on the file in your loop that is writing records. fclose() closes the file handle so it is no longer valid and cannot be written to.
Move fclose($save); after the } that ends the foreach() with your content.
Also, you could simplify things a bit by calling $Content = file_get_contents($File); since that is what you are doing in effect with fread(). Also, since $File is just a string variable, calling fclose() on it is unnecessary and doesn't do anything. You were correctly closing it by calling fclose() on $Handle. But using file_get_contents() will eliminate the need for both. The only file you would need is the one you were writing to.
Here is an example using the file() function which reads each line of a file into an array.
$file = '/var/apache2/htdocs/loginS/host.txt';
$content = file($file);
$save = fopen('./out.csv', 'w+');
foreach($content as $line) {
$line = rtrim($line, "\r\n"); // remove the newline from $line
$parts = explode("\t", $line);
$lineCsv = implode('|', $parts); // or ',' ?
fwrite($save, $lineCsv . "\n"); // write output to file
}
fclose($save);
I have test.txt file, like this,
AA=1
BB=2
CC=3
Now I wanna find "BB=" and replace it as BB=5, like this,
AA=1
BB=5
CC=3
How do I do this?
Thanks.
<?php
$file = "data.txt";
$fp = fopen($file, "r");
while(!feof($fp)) {
$data = fgets($fp, 1024);
// You have the data in $data, you can write replace logic
Replace Logic function
$data will store the final value
// Write back the data to the same file
$Handle = fopen($File, 'w');
fwrite($Handle, $data);
echo "$data <br>";
}
fclose($fp);
?>
The above peace of code will give you data from the file and helps you to write the data back to the file.
Assuming that your file is structured like an INI file (i.e. key=value), you could use parse_ini_file and do something like this:
<?php
$filename = 'file.txt';
// Parse the file assuming it's structured as an INI file.
// http://php.net/manual/en/function.parse-ini-file.php
$data = parse_ini_file($filename);
// Array of values to replace.
$replace_with = array(
'BB' => 5
);
// Open the file for writing.
$fh = fopen($filename, 'w');
// Loop through the data.
foreach ( $data as $key => $value )
{
// If a value exists that should replace the current one, use it.
if ( ! empty($replace_with[$key]) )
$value = $replace_with[$key];
// Write to the file.
fwrite($fh, "{$key}={$value}" . PHP_EOL);
}
// Close the file handle.
fclose($fh);
The simplest way (if you are talking about a small file as above), would be something like:
// Read the file in as an array of lines
$fileData = file('test.txt');
$newArray = array();
foreach($fileData as $line) {
// find the line that starts with BB= and change it to BB=5
if (substr($line, 0, 3) == 'BB=')) {
$line = 'BB=5';
}
$newArray[] = $line;
}
// Overwrite test.txt
$fp = fopen('test.txt', 'w');
fwrite($fp, implode("\n",$newArray));
fclose($fp);
(something like that)
You can use Pear package for find & replace text in a file .
For more information read
http://www.codediesel.com/php/search-replace-in-files-using-php/