Running the following MySQL Query and am getting this error:
database error Unknown column 'qd.ItemListID' in 'on clause'
SELECT
IFNULL(hqp.IsActive, qd.ItemName) AS Item_Name, DATE_FORMAT(IFNULL(hqp.SalesDate, qd.SalesDate), '%m-%d-%Y') AS effectDate, IFNULL(hqp.NoBid, qd.NoBid) AS noBid, IFNULL(hqp.VendorName, qd.VendorName) AS vendor, IFNULL(hqp.Source, qd.Source) AS source, IFNULL(hqp.Type, qd.Type) AS type, IFNULL(hqp.Cost, qd.PurchaseCost) AS cost, IFNULL(hqp.Price, qd.SalesPrice) AS price, IFNULL(hqp.ConditionCode, '') AS conditionCode, qi.UnitOfMeasureSetRef_FullName AS uom
FROM wp_quantum_data AS qd, wp_hunter_quote_parts AS hqp
LEFT JOIN wp_quickbook_items AS qi ON (qi.ListID = IFNULL(qd.ItemListID, hqp.Item_ListID))
WHERE qd.IsActive = 1 || hqp.IsActive = 1
GROUP BY Item_Name
ORDER BY Item_Name ASC
The column exists in the wp_quantum_data table so I can't explain why this error is occurring. I've tried renaming the column in phpmyadmin by typing the column name in and saving the column structure, but it is still saying that the column doesn't exist.
The problem is that you're mixing the archaic implicit JOIN syntax with LEFT JOIN. The LEFT JOIN only combines with the table immediately before it, which is wp_hunter_quote_parts; you can't refer to columns in wp_quantum_data in the ON clause.
You should get out of the habit of using implicit joins, and use explicit JOIN clauses for everything.
You also seem to have your joins in the wrong order. Since the row can be missing in wp_hunter_quote_parts, that's the table you should LEFT JOIN with.
SELECT
IFNULL(hqp.IsActive, qd.ItemName) AS Item_Name, DATE_FORMAT(IFNULL(hqp.SalesDate, qd.SalesDate), '%m-%d-%Y') AS effectDate, IFNULL(hqp.NoBid, qd.NoBid) AS noBid, IFNULL(hqp.VendorName, qd.VendorName) AS vendor, IFNULL(hqp.Source, qd.Source) AS source, IFNULL(hqp.Type, qd.Type) AS type, IFNULL(hqp.Cost, qd.PurchaseCost) AS cost, IFNULL(hqp.Price, qd.SalesPrice) AS price, IFNULL(hqp.ConditionCode, '') AS conditionCode, qi.UnitOfMeasureSetRef_FullName AS uom
FROM wp_quantum_data AS qd
LEFT JOIN wp_quickbook_items AS qi ON qi.ListID = qd.ItemListID
LEFT JOIN wp_hunter_quote_parts AS hqp ON qi.ListID = hqp.ItemListID AND hqp.IsActive = 1
WHERE qd.IsActive = 1
GROUP BY Item_Name
ORDER BY Item_Name ASC
Related
I was able to join 3 tables and count the data set, bet getting the columns on specific table it only see the 3rd table column..
SELECT *
FROM `InvoiceItemTable` a
JOIN `InvoiceTable` b
ON (b.id = a.invoice)
JOIN `products` c
ON (a.product = c.id)
WHERE b.status='1' AND c.store = '2'
//$invoices = $inginger->fetch(PDO::FETCH_ASSOC))
echo $invoices['a.price'];
This price return error : Undefined index: a.price in...
there is "price" in the first table(InvoiceItemTable).
echo $invoices['invoice'];
There is invoice in first table(InvoiceItemTable) and it returns it works
I dont want to use $invoices['price'] because there is 'price' colum in the third table too and that is what it returns, I want to get the price in the first table. $invoices['price.InvoiceItemTable'] returns undefined index
php wont recognize $invoices['a.price']; you have to use $invoices['price'];
if you have same fieldname in multiple tables you have to create an alias
SELECT a.price as a_price, b.price as b_price, c.price as c_price
and then you can use $invoices['a_price']
In general, it's much better to explicitly define your columns. In doing so you can add a specific name to the the column you're interested in (or conversely change the name of the one you're not to remove ambiguity)
For examples sake, I'm just showing the columns you've described but it would look something like.
SELECT a.price as price, c.price as product_price
FROM `InvoiceItemTable` a
JOIN `InvoiceTable` b ON (b.id = a.invoice)
JOIN `products` c ON (a.product = c.id)
WHERE b.status='1' AND c.store = '2';
Doing naming such as this is more work, but insulates your code from changes and more explicitly shows the reader what is being returned.
I am running this query, and I am getting ** #1241 - Operand should contain 1 column(s)** error:
SELECT `forumCategories`.`id`, `forumCategories`.`name`, `forumCategories`.`order`, `forumCategories`.`description`, `forumCategories`.`date_created`, COUNT(forumPosts.forumCategory_id) as postCount,
(SELECT `forumPosts`.*, `forumChildPosts`.`id`, `forumChildPosts`.`forumPost_id`, COUNT(forumChildPosts.forumPost_id) as childCount FROM `forumChildPosts` LEFT JOIN `forumPosts` ON `forumPosts`.`id` = `forumChildPosts`.`forumPost_id` GROUP BY `forumPosts`.`id`) AS childCount
FROM `forumCategories`
LEFT JOIN `forumPosts` ON `forumCategories`.`id` = `forumPosts`.`forumCategory_id`
GROUP BY `forumCategories`.`id`
ORDER BY `forumCategories`.`order` DESC
I have 3 tables:
forumCategories
forumPosts | forumPosts.forumCategory_id = forumCategories.id
forumChildPosts | forumChildPosts.forumPosts_id = forumPosts.id
I want to count all posts for the forum category, and them I want to count all the child posts that belongs to that forum category. How can I do this?
You can't select several items with a subselect and then give them one name. Now you're getting everything from forumPosts, something from forumChildPosts etc and trying to put that into a single column, childCount. This is not allowed.
It might be enough to remove all other result columns from that select and only leave the count?
I couldn't try it, is that makes sense ? But you can't get nested results from mysql due to its limitation, MYSQL is a Matrix table.
SELECT `forumCategories`.`id`,
`forumCategories`.`name`,
`forumCategories`.`order`,
`forumCategories`.`description`,
`forumCategories`.`date_created`,
COUNT(forumPosts.forumCategory_id) AS postCount,
(SELECT COUNT(forumChildPosts.forumPost_id) AS childCount FROM `forumChildPosts` LEFT JOIN `forumPosts` ON `forumPosts`.`id` = `forumChildPosts`.`forumPost_id` GROUP BY `forumPosts`.`id`) AS childCount
FROM `forumCategories`
LEFT JOIN `forumPosts` ON `forumCategories`.`id` = `forumPosts`.`forumCategory_id`
GROUP BY `forumCategories`.`id`
ORDER BY `forumCategories`.`order` DESC
I have three tables named issue_details, nature_payments, and rci_records. Now I have this query which joins this three tables.
SELECT issue_details.issue_date AS Date,
issue_details.check_no AS Check_No,
payees.payee_name AS Name_payee,
nature_payments.nature_payment AS Nature_of_Payment,
issue_details.issue_amount AS Checks_issued,
issue_details.nca_balance AS Nca_balance
FROM
issue_details
INNER JOIN
nature_payments ON
issue_details.nature_id = nature_payments.nature_id
INNER JOIN
payees ON
issue_details.payee_id = payees.payee_id
ORDER BY Date Asc, Check_no ASC
On my column in Nca_balance, this is a computed differences of every issuances of check. But you may not know what really the process of how I got the difference but to make it simple, let's say that I have another query
that dynamically get also the difference of this nca_balance column. Here is the query:
SELECT r.*,
(#tot := #tot - issue_amount) as bank_balance
FROM (SELECT #tot := SUM(nca_amount) as nca_total FROM nca
WHERE account_type = 'DBP-TRUST' AND
year(issue_date) = year('2015-01-11') AND
month(issue_date) = month('2015-01-11')
)
vars CROSS JOIN issue_details r
WHERE r.account_type = 'DBP-TRUST' AND
r.issue_date = '2015-01-11'
ORDER BY r.issue_date, r.check_no
I know it you may not get my point but I just want to replace the first query of the line
issue_details.nca_balance AS Nca_balance
with my own computation on my second query.
Please help me combine those two query into a single query. Thanks
Before asking this question, I already search a lot of entries on Google and StockOverflow. Nothing can fulfil my question.
There are two tables - group_sale_bonuses and members. I want to check is already there records with product_id "1" in the group_sale_bonuses.
If not, I want to insert all records from members table into group_sale_bonuses with product_id "1".
My overall requirement is as follow:
IF ((Select count(id) from group_sale_bonuses where product_id = 1) = 0) THEN
INSERT INTO group_sale_bonuses (member_id, product_id, quantity_counter, credit)
SELECT id, 1, 0, 0 FROM members
END IF
But this sql causes the errors.
I know there are solutions about Insert Ignore, Where Not Exists.
But these conditions checking are based on per each record. I have thousands of records in members table. I want to make condition checking just one time like in my above sql example.
By the way, I will use this Sql in Php web application.
You could just set the code in a WHERE clause instead of the IF.
INSERT INTO group_sale_bonuses(
member_id,
product_id,
quantity_counter,
credit)
SELECT
id, 1, 0, 0 FROM members
WHERE(
SELECT
count(id) FROM group_sale_bonuses
WHERE product_id = 1
) = 0;
This should do it for all product_id's
SELECT m.product_id, m.member_id FROM members AS m
LEFT JOIN group_sale_bonuses AS gsb ON gsb.product_id = m.product_id
WHERE gsb.product_id IS NULL ;
You can filter it to a specific product_id by adding to the where clause
SELECT m.product_id, m.member_id FROM members AS m
LEFT JOIN group_sale_bonuses AS gsb ON gsb.product_id = m.product_id
WHERE gsb.product_id IS NULL AND m.product_id = 1;
Take a look at this SQLfiddle: http://sqlfiddle.com/#!2/8482c/2
I would like to seek some help in my query...i want to do is if specific atic and oaic is empty in the table...the interview_sum or other_sum to that specific atic oaic should be empty too....can anyone know how to do that?
picture of current output:
current query: my query still gives numbers to other_sum or interview_sum even its empty.
SELECT DISTINCT
IF(t.inttotal=NULL,0,(SELECT SUM(t2.inttotal)
FROM app_interview2 AS t2
WHERE t2.atic = t.atic AND t2.inttotal>0)/7)
AS interview_sum,
IF(o.ototal=NULL,0,(SELECT SUM(o2.ototal)
FROM other_app2 AS o2
WHERE o2.oaic = o.oaic AND o2.ototal>0)/7)
AS other_sum,
atid,
atic,
atname,
region,
town,
uniq_id,
position,
salary_grade,
salary
FROM app_interview2 AS t, other_app2 AS o
GROUP BY t.atname HAVING COUNT(DISTINCT t.atic)
I made a few assumptions:
You probably have a table that app_interview2.atic and other_app2.oaic are the foreign keys of, but since you did not share it, I derived a table in the FROM clause.
This assumes atname is always the same for atid.
You are also dividing by 7 - which I assume is to get the average, so I used the AVG function.
Solution---
SELECT t1.id AS atid
,interview.atname AS atname
,COALESCE(interview.interviewsum, 0) AS interviewsum
,COALESCE(interview.interviewavg,0) AS interviewavg
,COALESCE(other.othersum, 0) AS othersum
,COALESCE(other.otheravg) AS otheravg
FROM (SELECT DISTINCT atid AS id
FROM app_interview2
UNION
SELECT DISTINCT oaic
FROM other_app2) AS t1
LEFT JOIN (SELECT atid, atname, SUM(inttotal) AS interviewsum, AVG(inttotal) AS interviewavg
FROM app_interview2
GROUP BY atid, atname) as interview
ON interview.atid = t1.id
LEFT JOIN (SELECT oaic, SUM(ototal) AS othersum, AVG(ototal) AS otheravg
FROM other_app2
GROUP BY oaic) AS other
ON other.oaic = t1.id;
--
If this gives the results your were hoping for, I would replace the t1 derived table in the FROM clause with the table whose primary key I described above AND probably has those columns (e.g., region, town, etc) that I did not include