I have just started to learn about serialization and I have a question that I cannot seem to find a simple explanation to.
Say I had a table called week and inside week I had 3 columns with the third column containing a bunch of serialized meal IDs like so stored in my database:
INSERT INTO `week` (`week_id`, `meal_code`, `meal_id`) VALUES
(1, 'week12016', 'a:6:{i:0;i:1;i:1;i:2;i:2;i:3;i:3;i:4;i:4;i:5;i:5;i:6;}');
But later I want to append another meal_id to the existing string but not update any other column so it reads
(1, 'week12016','a:7:{i:0;i:1;i:1;i:2;i:2;i:3;i:3;i:4;i:4;i:5;i:5;i:6;i:6;i:7;}')
I have tried in a php file to store the following
$food=array("7");
$sfood=serialize($food);
Then trying to add the 7 to the existing meal_ids in the week table
mysqli_query($conn,"UPDATE week
SET meal_id ('$sfood')");
//if entry into the database is successful, confirm with a alert popup and refresh the home page
if(mysqli_affected_rows($conn) > 0){
//header("location: admin.php");
header("refresh:0; url=admin.php");
echo "<script type='text/javascript'>alert('Upload Successful!')</script>";
exit;
But when I check my database, nothing has changed.
What am I doing wrong, is it even possible to do what I am trying to achieve?
You have to read the column from your table row. Unserialize it into a PHP variable and then add a new occurance to it.
Then serialize the new array and store it back to your database
// SELECT from table
$s = 'a:7:{i:0;i:1;i:1;i:2;i:2;i:3;i:3;i:4;i:4;i:5;i:5;i:6;i:6;i:7;}';
$d = unserialize($s);
print_r($d);
$d[] = 99;
print_r($d);
$s2 = serialize($d);
echo $s2;
// UPDATE table row
RESULTS
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => 7
)
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 4
[4] => 5
[5] => 6
[6] => 7
[7] => 99
)
a:8:{i:0;i:1;i:1;i:2;i:2;i:3;i:3;i:4;i:4;i:5;i:5;i:6;i:6;i:7;i:7;i:99;}
Storing data like this is not recommended, as it makes this data impossible to process using queries
Related
Hi I need to select a rand value in the array removed and short the array i came out whit this small code but it keeps in an infinite loop but this is the weird look
<?php
$array=array("1","2","3","4","5","6","7","8","9","0");
$count=count($array);
for ($il=1;$il<=$count;$il++){
$array_value=array_rand($array, 1);
$array_value_key = array_search($array_value, $array);
$array_key_last=array_key_last($array);
for($if=0;$if<=$array_key_last;$if++){
if ($if==$array_value_key){
for($ia=$array_value_key;$ia<=$array_key_last;$ia++){
if ($ia<$array_key_last){
$ian=$ia+1;
$array[$ia]=$array[$ian];
}else{
unset($array[$ia]);
}
}
}
}
print_r($array);
}
?>
there the output can be different each time likes this but never ends
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 5
[4] => 6
[5] => 7
[6] => 8
[7] => 9
[8] => 0
)
Array
(
[0] => 2
[1] => 3
[2] => 5
[3] => 6
[4] => 7
[5] => 8
[6] => 9
[7] => 0
)
^C
and i have to break it but as you can see in the first loop work as expected removes the number 4 and in the second loop removes the number 1 but don't finish the third loop
I have reviewed many times and get in to the conclusion of the problem it is on the line
$array[$ia]=$array[$ian];
if i add a echo here get printing a number it self to the infinity why?
$array[$ia]=$array[$ian];
echo $array[$ia],"\n";
The Problem is not in one line. It takes a few commands to interact:
array_rand returns the key of the element not the value
array_search returns (bool)false if it doesn't find the value (because of 1 this can happen)
You use $array_value_key to start a for loop. Because of 2 it can be (bool)false.
When you increment a boolean, it does not change. I.e. your $ia++ does nothing.
That's why $ia<=$array_key_last will never turn false and your loop runs forever.
I have a grid of img squares that can be dragged into any order using the sortable library. Each img is a visual representation of a result from a mySQL db query that selects any image that shares an 'imageparent' identifier. The order they're presented in the grid is taken from the 'imageorder' column in the database and starts at 0 and works in sequence up to the nth number of images returned.
The purpose of dragging the img grid is to be able to change the 'imageorder' index. On completion of the drag, the sortable library POSTS an 'imageorder' var by ajax to service.php and is received correctly. So rather than the original 0,1,2,3,4,5,6,7 order of the original, it sends a string like 2,1,0,3,4,5,7,6. Not too hard to grasp. After I switch the order the orderList var sent to service.php is always correct, but the array I end up sending to the db and setting as my session var becomes a little garbled in order after the second or third drag and I'm not quite sure why.
Code Examples and Comments
$_SESSION['selectedCsImages'] Array structure:
[0] => Array
(
[imagename] => "Title"
[imageorder] => 0
[imageid] => 43
)
[1] => Array
(
[imagename] => "Title"
[imageorder] => 1
[imageid] => 21
)
[2] => Array
(
[imagename] => "Title"
[imageorder] => 2
[imageid] => 3
)
etc...
Services.php extract:
if (session_status() == PHP_SESSION_NONE) {
session_start();
}
// Turn the orderList posted into an array
$removeChars = array('"','[',']');
$orderList = str_replace($removeChars, "", $_POST['order']); // POST received fine.
$listArray = explode(",",$orderList);
// Retrieve the session array
$sorting = $_SESSION['selectedCsImages'];
/* My logic is that I compare the $sorting array to $listArray and reorder $sorting by 'imageorder' to match $listarray */
usort($sorting, function($a, $b) use ($listArray) {
return array_search($a['imageorder'], $listArray) - array_search($b['imageorder'], $listArray);
});
/* I now have a $sorting array that (sometimes, hence the problem) matches the order that the images had just been dragged into by the user. Typically, as I mentioned above, it's correct after the first drag, but not always after the second or third where it creates a new order that I can't see a pattern or logic in. */
/* Had there not been errors with the usort function, I (would) have a $sorting array in the order I want but with imageorder values referring to pre-sorting. I iterate through the array and set each key to 0, 1, 2, etc. so that I have an array in the correct order and with each imageorder correctly stating its place.*/
$i = 0;
foreach ($sorting as $key => $value) {
$sorting[$key]['imageorder'] = $i;
$i++;
}
/* The information is attempted to be sent to the db and, on success I update the session var */
// Database code (runs succesfully and updates the db as per the image orders found in the $sorting array)
$_SESSION['selectedCsImages'] = $sorting;
Debugging:
From debugging, it appears that something happens with the usort function when I call this page from ajax for the second or third time. Everything after this follows through fine and processes the correct or incorrect order as per expectations. The orderList var posted by sortable is correct each time. I'd provide a sample of the $sorted var after usort each time but it's as simple to describe it as the above array example in an order I didn't specify after dragging and I can't see a pattern in the seemingly random order it outputs.
From researching, I had thought that it was an issue with session vars being retained until the page is refreshed but it appears that the ajax call to services.php should refresh the $_SESSION['selectedCsImages'] var. I had also read that, perhaps, I was unknowingly using referenced array values and - as I source from a session var to a new array and, ultimately, save back to this session var from this array - I may have created some messy referencing feedback. However, I tried using $sorted = (array)clone(object)$_SESSION['selectedCsImages']; before attempting usort and the results didn't change.
PHP error logs are showing nothing.
Updates:
Per the suggestion of #Ayaou, I've checked the output of $listArray and am getting some unexpected results. I'd wrongly assumed that as the posted $orderList was correct, that the exploded array would not be a culprit.
Here's the output of print_r($listArray) after completing the following order swaps of 16 img elements: 1st with 2nd, 2nd last with last,6th with 7th:
1st and 2nd:
(
[0] => 1
[1] => 0
[2] => 2
[3] => 3
[4] => 4
[5] => 5
[6] => 6
[7] => 7
[8] => 8
[9] => 9
[10] => 10
[11] => 11
[12] => 12
[13] => 13
[14] => 14
[15] => 15
)
last and 2nd last:
(
[0] => 1
[1] => 0
[2] => 2
[3] => 3
[4] => 4
[5] => 5
[6] => 6
[7] => 7
[8] => 8
[9] => 9
[10] => 10
[11] => 11
[12] => 12
[13] => 13
[14] => 15
[15] => 14
)
6th with 7th:
(
[0] => 1
[1] => 0
[2] => 2
[3] => 3
[4] => 4
[5] => 6
[6] => 5
[7] => 7
[8] => 8
[9] => 9
[10] => 10
[11] => 11
[12] => 12
[13] => 13
[14] => 15
[15] => 14
)
I was progressing with the idea that $listArray would show a sequential 0,1,2,3,etc. each time with only the two swapped items showing order changes. As it's not, I'll look back again at $orderList and check if my sortable library is updating the orders it's obtaining correctly from the updated session var. Older order swaps are being retained somewhere along the chain where they shouldn't.
The solution is on your sortable form (on the front end), so instead of sending the imageorder on your 'order' post data, send the imageid index.
Then change your sort callback like this
//Use imageid index instead of imageorder
usort($sorting, function($a, $b) use ($listArray) {
return array_search($a['imageid'], $listArray) - array_search($b['imageid'], $listArray);
});
on my ratings table for my software i have 4 fields.
id autoincrement
rvid vendor id
ratedate date of rating
rating the actual numeric rating
I have done alot with it over the last few months but this time im stumped and i cant get a clear picture in my head of the best way to do this. What i am trying to do is find out if the vendor has had 3 low 'consecutive' ratings. If their last three ratings have been < 3 then i want to flag them.
I have been playing with this for a few hours now so i thought i would ask (not for the answer) but for some path direction just to push me forward, im stuck in thought going in circles here.
I have tried GROUP BY and several ORDER BY but those attempts did not go well and so i am wondering if this is not a mysql answer but a php answer. In other words maybe i just need to take what i have so far and just move to the php side of things via usort and the like and do it that way.
Here is what i have so far i did select id as well at first thinking that was the best way to get the last consective but then i had a small breakthrough that if they have had 3 in a row the id does not matter, so i took it out of the query.
$sql = "SELECT `rvid`, `rating` FROM `vendor_ratings_archive` WHERE `rating` <= '3' ORDER BY `rvid` DESC";
which give me this
Array
(
[0] => Array
(
[rvid] => 7
[rating] => 2
)
[1] => Array
(
[rvid] => 5
[rating] => 1
)
[2] => Array
(
[rvid] => 5
[rating] => 0
)
[3] => Array
(
[rvid] => 5
[rating] => 3
)
)
this is just just samples i tossed in the fields, and there are only 4 rows here where as in live it will be tons of rows. But basically this tells me that these are the vendors that have low ratings in the table. And that is where i get stumpted. I can only do one sort in the query so that is why i am thinking that i need to take this and move to the php side to finish it off.
I think i need to sort the elements by rvid with php first i think, and then see if three elements in a row are the same vender (rvid).
Hope that makes sense. My brain hurts lol...
update - here is all of the table data using *
Array
(
[0] => Array
(
[id] => 7
[rvid] => 7
[ratedate] => 2016-05-01
[rating] => 2
)
[1] => Array
(
[id] => 8
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 1
)
[2] => Array
(
[id] => 6
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 0
)
[3] => Array
(
[id] => 5
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 3
)
)
Here's one way you can begin approaching this - completely in SQL:
Get the last rating for the vendor. ORDER BY date DESC, limit 1.
Get the second to last rating for the vendor. ORDER BY date DESC, limit 1, OFFSET 1.
Then write a query that does a LEFT join of the first two tables. You will have a dataset that has three columns:
vendor id
last rating
second to last rating
Then you can write an expression that says "if column1 is <3 and column2 < 3, then this new column is true"
You should be able to extend this to three columns relatively easily.
Here is what a came up with to solve this riddle. I think explaining it on here helped as well as Alex also helped as he keyed my brain on using the date. I first started looking at using if statment inside of the query and actually that got my brain out of the box and then it hit me what to do.
It is not perfect and certainly could use some trimming to reduce the code, but i understand it and it seems to work, so that is par for me on this course.
the query...
$sql = "SELECT `rvid`, `ratedate`,`rating` FROM `vendor_ratings_archive` WHERE `rating` <= '3' ORDER BY `ratedate`, `rvid` DESC";
which gives me this
Array
(
[0] => Array
(
[rvid] => 7
[ratedate] => 2016-05-01
[rating] => 2
)
[1] => Array
(
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 1
)
[2] => Array
(
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 0
)
[3] => Array
(
[rvid] => 5
[ratedate] => 2016-05-01
[rating] => 3
)
)
notice how vendor (rvid) 5 is grouped together which is an added plus.
next a simple foreach to load a new array
foreach($results as $yield)
{
$rvidarray[] = $yield['rvid'];
}//close foreach
which gives me this
Array
(
[0] => 7
[1] => 5
[2] => 5
[3] => 5
)
then we count the array values to group dups
$rvidcounter = array_count_values($rvidarray);
which results in this
Array(
[7] => 1
[5] => 3
)
so now vender 7 as 1 low score and vendor 5 has 3 low scores and since they were already sorted by date i know that its consecutive. Well it sounds good anyway lol ")
then we create our final array with another foreach
foreach($rvidcounter as $key => $value)
{
//anything 3 or over is your watchlist
if($value > 2)
{
$watchlist[] = $key; //rvid number stored
}
}//close foreach
which gives me this
Array
(
[0] => 5
)
this was all done in a service function. So the final deal is everyone in this array has over 3 consecutive low ratings and then i just use a returned array back in my normal php process file and grab the name of each vender by id and pass that to the html and print out the list.
done...
please feel free to improve on this if you like. I may or may not use it because the above code makes sense to me. Something more complicated may not make sense to me 6 mos from now lol But it would be interesting to see what someone comes up with to shorten the process a bit.
Thanks so much and Happy Coding !!!!!
Dave :)
You could do it in SQL like that:
SET #rvid = -1;
SELECT DISTINCT rvid FROM
(
SELECT
rvid,
#neg := rating<3, /* 0 or 1 for addition in next line */
#count := IF(#rvid <> rvid , #neg, #count+#neg) AS `count`, /* set or add */
#rvid := rvid /* remember last row */
FROM
testdb.venrate
ORDER BY
rvid, datetime desc
) subq
WHERE count>=3
;
You set a variable to a non existing id. In each chronologically sorted row you check if rating is too low, that results in 1 (too low) or 0 (ok). If rvid is not equal to the last rvid, it means a new vender section is beginning. On begin of section set the value 0 or 1, else add this value. Finally store the current row's rvid for comparison in next row process.
The code above is looking for 3 consecutive low ratings (low means a value less than 3) over all the time.
A small modification checks if all the latest 3 ratings has been equal to or less than 3:
SET #rvid = -1;
SELECT DISTINCT
rvid
FROM
(
SELECT
rvid,
#high_found := rating>3 OR (#rvid = rvid AND #high_found) unflag,
#count := IF(#rvid <> rvid , 1, #count+1) AS `count`,
#rvid := rvid /* remember last row */
FROM
testdb.venrate
ORDER BY
rvid, datetime desc
) subq
WHERE count=3 AND NOT unflag
;
The user can search for something using select and checkbox forms. The data is sent in GET variables.
I'm collected all the possible values in variables and putting it into an array:
$term_taxomony_ids_array = array($term_taxonomy_id_m, $term_taxonomy_id_l, $term_taxonomy_id_t_1, $term_taxonomy_id_t_2, $term_taxonomy_id_t_3, $term_taxonomy_id_t_4, $term_taxonomy_id_t_5, $term_taxonomy_id_t_6, $term_taxonomy_id_t_7, $term_taxonomy_id_t_8);
print_r($term_taxomony_ids_array); would then give
eg:
Array (
[0] => 12
[1] => 14
[2] =>
[3] =>
[4] => 9
[5] =>
[6] => 2
[7] =>
[8] =>
[9] =>
)
How would I make this array simpler but leaving out the empty results altogether (as suggested in a comment)?
I need to find the 'places' in the database who match all the criteria that was selected.
My database table is set up so I have two columns.
1. Object_id 2. term_taxonomy_id.
The term_taxonomy_id are the values in the array.
eg my table looks like this
Object id term_taxonomy_id
2 12
2 3
3 12
3 14
3 9
3 2
4 5
5 9
So only object_id '3' matches all the terms in the array - 12, 14, 9, 2
How would I run a query to find this result?
I'm using a mysql database, phpmyadmin and my site is built on wordpress.
Thanks
Basically:
SELECT objectID, COUNT(term_taxonomy_id) AS cnt
FROM yourtable
WHERE term_taxonomy_id IN (2, 9, 14, 12)
GROUP BY objectID
HAVING cnt = 4
find all the objectIDs that have one or more matching taxonomy IDs, but then return only the object IDs that have FOUR matching taxonomy IDs.
Use IN, Combined with COUNT() and having/GROUP.
$array = array_filter(array_unique($array));
$count = count($array);
$sql = "SELECT id, COUNT(*) FROM table WHERE field IN (" . implode(',', $array) . ") GROUP BY id HAVING COUNT(*) = " . $count;
The SQL might be a bit off (you might have to re-order having and group).
I am trying to build a website that will display the text in multiple languages.
I have a table 'text' with all the languages. If the text does not exist in the chosen language it has to display the default language.
query SELECT * FROM text WHERE TextId = 10
results in
Id TextId LanguageId Text
10 10 1 first name
13 10 2 名前
If I r_print this result I get something like this
Array ( [0] => Array ( [0] => 10 [Id] => 10 [1] => 10 [TextId] => 10 [2] => 1 [LanguageId] => 1 [3] => first name [Text] => first name )
[1] => Array ( [0] => 13 [Id] => 13 [1] => 10 [TextId] => 10 [2] => 2 [LanguageId] => 2 [3] => 名前 [Text] => 名前 ) )
How can I check that LanguageId 2 exist in this array ?
the problem is that it is possible that TextId 2 and Id 2 can also exist in this array.
Is this possible to do with in_array()?
Here is a function that can check if LanguageId equals a special value .
function isLanguageIdExists($yourArray , $LanguageId){
$exists=false;
foreach($yourArray as $array){
if(isset($array['LanguageId'])&& $array['LanguageId'] == $LanguageId){
$exists=true;break;
}
}
return $exists;
}
$exist = isLanguageIdExists($yourArray , 2);//return true or false
You can check by isset the key and match the value in php.
$dataArray = array(
0 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1),1 => array(0 => 10 ,'Id' => 10, 1 => 10, 'TextId' => 10, 2 => 1, 'LanguageId' => 1)
);
foreach($dataArray as $value) {
if(isset($value['LanguageId']) && $value['LanguageId'] == 2) {
echo 'language ID 2 is available';
}
}
Working Demo
After giving this some more thought I came up with a maybe not so elegant solution.
Instead of getting an array back I modified the SQL Query to give one row back with the default language (English) and a user selected language (Japanese).
It uses two left joins. This shows that I received (some) training in SQL but am really not at ease with multidimensional arrays.
Query
def_text = text in default language
usr_text = text in user chosen language
$table01 = "text";
$query="SELECT $table01.TextId,
text_def.Text as def_text,
text_usr.Text as usr_text
FROM $table01
LEFT JOIN $table01 as text_def ON $table01.TextId = text_def.TextId AND text_def.LanguageId = $_SESSION[default_language]
LEFT JOIN $table01 as text_usr ON $table01.TextId = text_usr.TextId AND text_usr.LanguageId = $_SESSION[language]
WHERE $table01.TextId=$mess;";
after getting back the results it is easy to check with isset() or empty() to see if the text is available in the user selected language