I copied this from W3Schools and when I try to run it it gives me the a error. I am really new to MySQL so I am trying to fix this but I don't know how.
ERROR:
Warning: mysqli::mysqli(): (HY000/1045): Access denied for user
'username'#'localhost' (using password: YES) in
C:\xampp\htdocs\Informatica\test.php on line 10 Connection failed:
Access denied for user 'username'#'localhost' (using password: YES)
<html>
<body>
<?php
$servername = "localhost";
$username = "username";
$password = "password";
// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
</body>
</html>
your username or password is incorrect if you are very new and just starting with the local server try
$username = "root";
$password = "";
as your username and password
W3schools don't know your localhost details, do the following
$servername = "localhost";
$username = "root"; //put your username here
$password = ""; // your password here
Leave password empty and put "root" in username, that's the default xampp setting.
you have to add correct information provided by your hosting provider here :
$servername = "localhost";
$username = "username";
$password = "password";
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$conn = mysqli_connect($dbhost, $dbuser, $dbpass);
//Connection to mysql check
if(! $conn ) {
die('Could not connect: ' . mysql_error());
}
mysqli_select_db($conn,'databaseName');
?>
Related
I have a MySQL database and I am trying to figure out how to access it with a php file. I keep getting an error, so I was wondering if that was because my hostname is incorrect. If so, could anyone help me identify exactly what it is? The database is hosted on this website: https://christopherliao2002.000webhostapp.com/.
Below is my HTML code.
<?php
//Step1
$db = mysqli_connect('localhost','***********','password','******')
or die('Error connecting to MySQL server.');
?>
<html>
<head>
</head>
<body>
<h1>PHP connect to MySQL</h1>
<?php
//Variables
$servername = "localhost";
$username = "*****";
$password = "****";
$dbname = "******";
//Connection to database
$conn = new mysqli($servername, $username, $password, $dbname);
//Test connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
</body>
</html>
Try this format
$servername = "localhost"; // This is fixed for 000webhost.
$username = "id***_name";
$password = "****";
$dbname = "id***_name";
Try this without the try / catch:
//Variables
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database_name";
//Connection to database
$conn = new mysqli($servername, $username, $password, $dbname);
//Test connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());}
Reference: https://www.w3schools.com/php/php_mysql_connect.asp
Here the problem is with your hostname. Normally the hostname will be 'localhost' and in 000webhost the hostname is something like mysql#.000webhost.com and '#' needs to be replaced with the number for that you need to check your hosting providers members area.
And please don't post your username and password publicly
$db = mysqli_connect('mysql#.000webhost.com','xxxxx','password','xxxxxx')
or die('Error connecting to MySQL server.');
?>
I am new to php/sql and i have a login system which runs on my local host using xammp and it all works fine. I now want to upload it to my website but the code no longer works... I have created a sql db on my hosting service and tried to change the code.
the code that is used on the local host is
<?php
$dbServername = "localhost";
$dbUsername = "root";
$dbPassword = "";
$dbName = "loginsystem";
$conn = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName);
and this is the code that i have got from my hosting.
<?php
$host_name = 'db682827654.db.1and1.com';
$database = 'db682827654';
$user_name = 'dbo682827654';
$password = '<Enter your password here.>';
$conn = mysql_connect($host_name, $user_name, $password, $database);
if (mysql_errno()) {
die('<p>Failed to connect to MySQL: '.mysql_error().'</p>');
} else {
echo '<p>Connection to MySQL server successfully established.</p >';
}
?>
however this brings up an errror message. I have changed the password to the password for my database but its still not connecting.
This is the error message.
Failed to connect to MySQL: Access denied for user 'dbo706265806'#'217.160.62.78' (using password: YES)
Any help would be greatly appreciated
use mysqli_connect (not mysql_connect) like localhost:
<?php
$dbServername = "db682827654.db.1and1.com";
$dbUsername = "dbo682827654";
$dbPassword = "<Enter your password here.=)>";
$dbName = "db682827654";
$conn = mysqli_connect($dbServername, $dbUsername, $dbPassword, $dbName);
?>
On your computer you are using mysqli_connect, but on the server you are trying to use mysql_connect. Just use the same file from your computer and simply change $dbServername, $dbUsername, $dbPassword and $dbName to match those that your hosting provided.
I am trying to connect to MySQL on the server but gives following error. User is created and granted all privileges.
It's working on local machine but not after deploying to a server.
Also mysql_connect function works but new mysqli() gives access denied as mentioned below.
Also Tried adding port.
Warning: mysqli::mysqli(): (HY000/1045): Access denied for user ''usernam'#'localhost' (using password: YES) in /home/domainname/public_html/autopublish/test.php on line 8
Connection failed: Access denied for user ''username'#'localhost' (using password: YES)
<?php
$servername = "localhost";
$username = "'xxxxx";
$password = "xxxxx";
$dbname = "xxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password); **//line 8**
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
} else {
echo "no connection";
}
$sql = "SELECT * FROM pages";
$result = $conn->query($sql);
$data = array();
$arr = array();
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
}
} else {
echo "No Token";
}
print_r(json_encode($data));
$conn->close();
?>
Either the user does not have the required rights for the database or the password is wrong.
Otherwise remove the user and use the following statement to create:
1.CREATE USER 'user'#'localhost' IDENTIFIED BY '123456789';
2.
3.GRANT ALL PRIVILEGES ON project.* TO 'user'#'localhost' WITH GRANT OPTION;
or try this:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "dbname";
//Create
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $dbname);
echo "Yaaay";
I am developing a login/register system for a website but when i'm trying to connect to the database it gives this error:
Warning: mysqli_connect(): (HY000/1045): Access denied for user 'root'#'localhost' (using password: YES) in C:\xampp\htdocs\register.php on line 17
I'm using a external config file wich is been imported.
My config file:
// Connection details
$servername = "127.0.0.1";
$username = "root";
$password = "password";
$dbname = "database";
My connection code:
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
I found one solution that worked to connect but then my config file was useless.
No config but only this:
// Create connection
$conn = mysqli_connect('127.0.0.1', 'root', 'password', 'database');
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
If someone nows a solution where i can keep using my config file please post it here.
Thanks in advance.
Well, if the connection works with this values:
$conn = mysqli_connect('127.0.0.1', 'root', 'password', 'database');
But not with this values:
$servername = "127.0.0.1";
$username = "root";
$password = "";
$dbname = "cloud";
Why don't you just set the "working" values into your config file. So it would look like this:
$servername = "127.0.0.1";
$username = "root";
$password = "password";
$dbname = "database";
Another solution which is described here includes the creation of a new user, so you don't connect via root, but the new created user.
I made some projects with using mysql and there was no problem. Today my friend show me how to create user in mysql by :
Create database cc;
use cc
CREATE USER 'testing'#'localhost' IDENTIFIED BY 'pass';
GRANT ALL ON cc.* TO 'testing'#'localhost';
Now I tried to use my project but I got following error :
Connection failed: Access denied for user ''#'localhost' to database 'login'
I deleted previously created user :
drop user 'testing'#'localhost';
I managed to delete that user, I checked user with :
select User from mysql.user;
testing account was gone but now I have 3 root accounts, I didn't understand why. Since I deleted that "testing" account, I tried my project again and I got the same error. Why I can't use default 'root' account anymore?
EDIT :
Error part of php code :
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "login";
// Error is in following line
$conn = mysqli_connect ( $servername, $username, $password, $dbname );
I also tried this :
GRANT ALL ON login.* TO 'root'#'localhost';
show grants;
Result is :
GRANT ALL PRIVILEGES ON *.* TO 'root'#'localhost' WITH GRANT OPTION
GRANT ALL PRIVILEGES ON login.* TO 'root'#'localhost'
It seems like 'root' has access to everything. Why am I getting error?
EDIT 2:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "login";
$username = $_POST['username'];
$pass = $_POST['password'];
// Create connection
$conn = mysqli_connect ( $servername, $username, $password, $dbname );
// Check connection
if (! $conn) {
die ( "Connection failed: " . mysqli_connect_error () );
}
Your over riding the previously set $username variable with the $_POST['username'] data which appears to be empty. So mysqli_connect attempts to connect to the database with a blank username.
To correct this, rename the $username variable to something else which doesn't conflict.
Example:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "login";
$username_post = $_POST['username'];
$pass = $_POST['password'];
// Create connection
$conn = mysqli_connect ( $servername, $username, $password, $dbname );
// Check connection
if (! $conn) {
die ( "Connection failed: " . mysqli_connect_error () );
}