I have a MySQL database and I am trying to figure out how to access it with a php file. I keep getting an error, so I was wondering if that was because my hostname is incorrect. If so, could anyone help me identify exactly what it is? The database is hosted on this website: https://christopherliao2002.000webhostapp.com/.
Below is my HTML code.
<?php
//Step1
$db = mysqli_connect('localhost','***********','password','******')
or die('Error connecting to MySQL server.');
?>
<html>
<head>
</head>
<body>
<h1>PHP connect to MySQL</h1>
<?php
//Variables
$servername = "localhost";
$username = "*****";
$password = "****";
$dbname = "******";
//Connection to database
$conn = new mysqli($servername, $username, $password, $dbname);
//Test connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
</body>
</html>
Try this format
$servername = "localhost"; // This is fixed for 000webhost.
$username = "id***_name";
$password = "****";
$dbname = "id***_name";
Try this without the try / catch:
//Variables
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database_name";
//Connection to database
$conn = new mysqli($servername, $username, $password, $dbname);
//Test connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());}
Reference: https://www.w3schools.com/php/php_mysql_connect.asp
Here the problem is with your hostname. Normally the hostname will be 'localhost' and in 000webhost the hostname is something like mysql#.000webhost.com and '#' needs to be replaced with the number for that you need to check your hosting providers members area.
And please don't post your username and password publicly
$db = mysqli_connect('mysql#.000webhost.com','xxxxx','password','xxxxxx')
or die('Error connecting to MySQL server.');
?>
Related
I am stuck after writing all the code, the Website just doesn't connect with mysql at all!
I think this code will help
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password,$dbname);
?>
write this code in html file and save it as .php
I hope it works
Create a database in phpmyadmin and then write down below code in a file and save it with .php extension
<?php
$db_username = "db_username"; // Your database login username
$db_password = "db_password"; // Your database login password
$db_name = "db_name"; // The name of the database you wish to use
$db_host = "db_host"; // The address of the database. Often this is localhost, but may be for example db.yoursite.com
$conn = new mysqli($db_host, $db_username, $db_password, $db_name);
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
set those 4 variable as per your db details. mysqli_connect_error() will give you error if the connection will not establish
I got following error when i run code:
Notice: Use of undefined constant newdb - assumed 'newdb' in C:\xampp\htdocs\cj\include\conn.php on line 9 No database selected
The following code for connecting i am using in conn.php file
,
<?php
$lusername = "root";
$lpassword = "";
$lhostname = "localhost";
// connection to the database
$dbhandle = ($GLOBALS["___mysqli_ston"] = mysqli_connect($lhostname, $lusername, $lpassword)) or die("Unable to connect to mysql");
mysqli_select_db($GLOBALS["___mysqli_ston"], newdb) or die("Unable to connect to mysql");
// echo "Connected to mysql<br>";
?>
how to fix it?
This is just something to consider: try using it without ["___mysqli_ston"]
Example
<?php
$servername = "localhost";
$username = "";
$password = "yourpass";
$dbname = "yourDBname";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Read special character sets
$conn->set_charset("utf8");
// Check connection
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
?>
Just an example of different easier approach all up to you.
For the converter
Example
<?php
$servername = "localhost" ;
$username = "root";
$pass = "";
$con = ($GLOBALS["___mysqli_ston"] = mysqli_connect($servername, $username, $pass)) or die("Problem occur in connection");
$db = ((bool)mysqli_query($con, "USE " . info));
?>
I am trying to connect to a remote rackspace DB
PHP:
<?php
$servername = "XX.XX.XX.XX";
$username = "username";
$password = "password";
$dbname = "table";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
?>
And I get
Warning: mysqli::mysqli(): (HY000/2002): Connection timed out
Try this
<?php
$servername = "XX.XX.XX.XX";
$username = "username";
$password = "password";
$dbname = "table";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();die();
}
?>
I am using my website database with php mysql_connect but my hosting provider is saying I need to use mysqli_connect.
When I edit connection file and update change method its not working with mysqli.
Currently using this code:
MSQL Method:
$con=mysql_connect("localhost","username","password");
mysql_select_db("databasename");
and for mysqli I am using this code but fail
MYSQLI Method:
$con = mysqli_connect("localhost","my_user","my_password","my_db");
Please help. Why is mysqli not working? Is my method wrong?
Try this:
Example (MySQLi Object-Oriented)
<?php
$servername = "localhost";
$username = "username";
$password = "password";
` $dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
Example (MySQLi Procedural)
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
?>
I am developing a login/register system for a website but when i'm trying to connect to the database it gives this error:
Warning: mysqli_connect(): (HY000/1045): Access denied for user 'root'#'localhost' (using password: YES) in C:\xampp\htdocs\register.php on line 17
I'm using a external config file wich is been imported.
My config file:
// Connection details
$servername = "127.0.0.1";
$username = "root";
$password = "password";
$dbname = "database";
My connection code:
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
I found one solution that worked to connect but then my config file was useless.
No config but only this:
// Create connection
$conn = mysqli_connect('127.0.0.1', 'root', 'password', 'database');
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
If someone nows a solution where i can keep using my config file please post it here.
Thanks in advance.
Well, if the connection works with this values:
$conn = mysqli_connect('127.0.0.1', 'root', 'password', 'database');
But not with this values:
$servername = "127.0.0.1";
$username = "root";
$password = "";
$dbname = "cloud";
Why don't you just set the "working" values into your config file. So it would look like this:
$servername = "127.0.0.1";
$username = "root";
$password = "password";
$dbname = "database";
Another solution which is described here includes the creation of a new user, so you don't connect via root, but the new created user.