in PHP, I want to change this string:
",,,3,4,,,5,6,,7,8,"
into this:
"3,4,5,6,7,8"
I've managed to strip commas at the beginning and end of the string, but this only accomplish 50% of my need:
<?php
$hello = ",,,3,4,5,6,,7,8,";
echo rtrim(ltrim($hello,","),",");
result:
"3,4,,,5,6,,7,8"
Any solution?
Do this little trick:
$hello = ",,,3,4,,,5,6,,7,8,";
$hello = implode(",",array_filter(explode(',',$hello)));
If your string is more complicated (i.e. it's a CSV which may potentially have fields wrapped in " " to escape commas you can do this:
$hello = ",,,3,4,,,5,6,,\"I,have,commas\",,7,8,";
$fields = array_filter(str_getcsv($hello));
$hello = str_putcsv($fields);
Where str_putcsv is defined in https://gist.github.com/johanmeiring/2894568 as
if (!function_exists('str_putcsv')) {
function str_putcsv($input, $delimiter = ',', $enclosure = '"') {
$fp = fopen('php://temp', 'r+b');
fputcsv($fp, $input, $delimiter, $enclosure);
rewind($fp);
$data = rtrim(stream_get_contents($fp), "\n");
fclose($fp);
return $data;
}
}
You can use trim() and Regx to achieve this, please have a look on the below code, it may help you
$from = ",,,,,,3,4,,,5,6,,7,8,,,";
echo $from;
echo "<pre>";
$to = preg_replace('/,+/', ',', trim($from,","));
echo $to;
implode(",", array_filter(explode(",", ",,,3,4,,,5,6,,7,8,"))
That's a little bit to read, but essentially explode the string on a comma, call array_filter on the result of that, then implode it back together.
Related
I'm a newbie in PHP ,andnow I'm struck on this problem . I have a string like this :
$string = "qwe,asd,zxc,rty,fgh,vbn";
Now I want when user click to "qwe" it will remove "qwe," in $string
Ex:$string = "asd,zxc,rty,fgh,vbn";
Or remove "fhg,"
Ex:$string = "asd,zxc,rty,vbn";
I try to user str_replace but it just remove the string and still have a comma before the string like this:
$string = ",asd,zxc,rty,fgh,vbn";
Anyone can help? Thanks for reading
Try this out:
$break=explode(",",$string);
$new_array=array();
foreach($break as $newData)
{
if($newData!='qwe')
{
$new_array[]=$newData;
}
}
$newWord=implode(",",$new_array);
echo $newWord;
In order to achieve your objective, array is your best friend.
$string = "qwe,asd,zxc,rty,fgh,vbn";
$ExplodedString = explode( "," , $string ); //Explode them separated by comma
$itemToRemove = "asd";
foreach($ExplodedString as $key => $value){ //loop along the array
if( $itemToRemove == $value ){ //check if item to be removed exists in the array
unset($ExplodedString[$key]); //unset or remove is found
}
}
$NewLook = array_values($ExplodedString); //Re-index the array key
print_r($NewLook); //print the array content
$NewLookCombined = implode( "," , $NewLook);
print_r($NewLookCombined); //print the array content after combined back
here the solution
$string = "qwe,asd,zxc,rty,fgh,vbn";
$clickword = "vbn";
$exp = explode(",", $string);
$imp = implode(" ", $exp);
if(stripos($imp, $clickword) !== false) {
$var = str_replace($clickword," ", $imp);
}
$str = preg_replace('/\s\s+/',' ', $var);
$newexp = explode(" ", trim($str));
$newimp = implode(",", $newexp);
echo $newimp;
You could try preg_replace http://uk3.php.net/manual/en/function.preg-replace.php if you have the module set up. It will allow you to optionally replace trailing or leading commas easily:
preg_replace("/,*$providedString,*/i", '', "qwe,asd,zxc,rty,fgh,vbn");
How can i remove duplicate commas used in string.
String = ",a,b,c,,,d,,"
I tried rtrim and itrim functions and removed the unwanted commas from beginning and ending .How can i remove duplicate commas ?
Try this:
$str = preg_replace('/,{2,}/', ',', trim($str, ','));
The trim will remove starting and trailing commas, while the preg_replace will remove duplicate ones.
See it in action!
Also, as #Spudley suggested, the regex /,{2,}/ could be replaced with /,,+/ and it would work too.
EDIT:
If there are spaces between commas, you may try adding the following line after the one above:
$str = implode(',', array_map('trim', explode(',', $str)))
i think you can just explode your string and then create a new one getting only relevant data
$string = ",a,b,c,,,d,,";
$str = explode(",", $string);
$string_new = '';
foreach($str as $data)
{
if(!empty($data))
{
$string_new .= $data. ',';
}
}
echo substr_replace($string_new, '', -1);
This will output
a,b,c,d
Live Demo
EDITED
If you are having problems with blank spaces you can try use this code
$string = ",a,b,c, ,,d,,";
$str = explode(",", str_replace(' ', '', $string));
$string_new = '';
foreach($str as $data)
{
if(!empty($data))
{
$string_new .= $data. ',';
}
}
echo substr_replace($string_new, '', -1);
This should solve spaces issue
Probably not very fast, but a simple method may be:
$str = "a,b,c,,,d";
$str2 = "";
while($str <> $str2) {
$str2 = $str;
$str = str_replace(',,', ',', $str);
}
<?php
$str = ",a,b,c,,,d,,"
echo $str=str_replace(',,','',$str);
?>
Output:
,a,b,c,d
<?php
$str = ",a,b,c,,,d,,"
echo $str=trim(str_replace(',,','',$str),',');
?>
Output:
a,b,c,d
I have a string of HTML with tags inside saved in the database e.g:
<p>Hello {$name}, welcome to {$shop_name}....</p>
I want to replace all of the tags with real data, now at the moment I loop through all available data and replace if it exists.
foreach($data as $key => $data){
$content = str_replace('{$'.$key.'}', $data, $content);
}
Is there a better way of doing this without looping through all of the $data? This is now growing to over 5000 rows.
I mean is it possible to extract all variables {$name}/{$shop_name} then do a replace on only the found?
You can do it with a single str_replace call.
$find = array();
$replace = array();
foreach($data as $key => $data) {
$find[] = "\{$" . $key . "}";
$replace[] = $data;
}
$content = str_replace($find, $replace, $content);
Unless there is a real performance issue, I wouldn't worry about it too much.
str_replace accepts arrays, you can build the array with array_keys, array_values and user array_map to add the {$}
$content = str_replace(
array_map(function($e) { return '{$' . $e . '}';}, array_keys($data)),
array_values($data),
$content);
Can just do
$content = preg_replace('/\{$(\w+)\}/e', '$data[\'$1\']', $content);
I am trying to trim a string in PHP so that I can only get certain text from the String.
I have an email stored to a String for instance some_name#somedomain.com .
How can I remove the text after the '#' so that I would only 'some_name'?
In PHP you can do :
$string = 'some_name#somedomain.com';
$res = explode('#', $string);
echo $res[0];
Or you can use regexp, string functions in php ... etc
You should know both ways to do this:
substr
$mail = "some_name#somedomain.com";
echo substr($mail, 0, strpos($mail, '#') );
explode
list($name, $domain) = explode('#', $mail);
echo $name;
If you don't need the $domain you can skip it:
list($name) = explode('#', $mail);
More about list.
Demo: http://ideone.com/lbvQF
$str = 'some_name#somedomain.com';
$strpos = strpos($str, "#");
echo $email = substr($str, 0,$strpos);
you can try this to get string before #
Try This
$str1 = "Hello World";
echo trim($str1,"World");
You could try split using regex and the # symbol. This will return two Strings which you can then use just to acquire the 'some_name'.
http://docs.oracle.com/javase/1.4.2/docs/api/java/lang/String.html
String s = "some_name#somedomain.com";
String name = s.substring(0,s.indexOf("#");
I have a csv file with this:
software
hardware
educational
games
languages
.
.
.
I need a new csv file with:
software;hardware;educational;games;languages;....
How can I do that?
I'm doing:
<?php
$one = file_get_contents('one.csv');
$patterns =" /\\n/";
$replacements = ";";
$newone = preg_replace($patterns, $replacements, $one);
echo $newone;
file_put_contents('newone.csv', $newone );
?>
This adds the semicolon at the end of the line but the line break is still there
Surprisingly none of you mentioned file() that returns what he needs:
$cont = file('somefile.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES);
file_put_contents('somefile.csv',implode(';',$cont));
2 lines of code without using slow regex
OR
if you need less code, here with 1 line of code, the way i like !
file_put_contents(
'somefile.csv',
implode(
';',
file('somefile.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES)
)
);
Here is how you can do this.
Edit : tested this, works correct.
<?php
$row = 1;
$readHandle = fopen("in.csv", "r"); // open the csv file
$writeHandle = fopen("out.csv","w");
$subArr = array();
while (($data = fgetcsv($readHandle, 1000, "\n")) !== FALSE) {
$myStr = $data[0]; // this stores the zeroth column of each CSV row
$subArr[] = $myStr; // subArr contains all your words
}
fputcsv($writeHandle,$subArr,";"); // it creates a CSV with single line seperated by ;
fclose($readHandle);
fclose($writeHandle);
?>
I guess you could get a preg_match_all() to get every alphanumeric word surrounded by quotes into an array.
Then you just loop on that array and display them adding a semicolon.
as a one off, I would run home to mama...
perl -p -i -e 's|(.*)\n|$1;|m' one.cvs
Your file may have carriage returns. Try this:
$newone = str_replace("\r\n", ';', $one);
To cover all possibilities:
<?php
$file = 'data.csv';
file_put_contents($file, '"software"
"hardware"
"educational"
"games"
"languages"
');
$input_lines = file($file);
$output_columns = array();
foreach($input_lines as $line){
$line = trim($line); // Remove trailing new line
$line = substr($line, 1); // Remove leading quote
$line = substr($line, 0, -1); // Remove trailing quote
$output_columns[] = $line;
}
echo implode(';', $output_columns);
Beware: this code assumes no errors in input file. Always add some validation.
I suggest doing it like this:
<?php
$one = file_get_contents('one.csv');
$patterns ="/\\r?\\n/";
$replacements = ";";
$newone = preg_replace($patterns, $replacements, $one);
echo $newone;
file_put_contents('newone.csv', $newone );
?