How to echo nested JSON object in php - php

Question

I'm trying to figure out how to echo the address1 out of the JSON below. I've tried this - echo "$arr->location[1]->address1<br>";, but it returns this error
Catchable fatal error: Object of class stdClass could not be converted to string in /home/benrud/public_html/student/webdesign/2016/02_benrud/tinker/data/index.php on line 202.
echo $arr; returns the JSON below.
{
"photos": [
"https://s3-media2.fl.yelpcdn.com/bphoto/37El1q8mqM_1tKtQugncZQ/o.jpg",
"https://s3-media1.fl.yelpcdn.com/bphoto/GLsNPPz5do-_NJktIQvz6w/o.jpg",
"https://s3-media3.fl.yelpcdn.com/bphoto/Z4rdHERgb10MZgDXnct5lA/o.jpg"
],
"coordinates": {
"latitude": 33.0479031276,
"longitude": -117.256002333
},
"image_url": "https://s3-media1.fl.yelpcdn.com/bphoto/37El1q8mqM_1tKtQugncZQ/o.jpg",
"is_claimed": false,
"id": "oscars-mexican-seafood-encinitas-2",
"review_count": 48,
"rating": 4.5,
"hours": [
{
"hours_type": "REGULAR",
"is_open_now": true,
"open": [
{
"is_overnight": false,
"end": "2100",
"day": 0,
"start": "0800"
},
{
"is_overnight": false,
"end": "2100",
"day": 1,
"start": "0800"
},
{
"is_overnight": false,
"end": "2100",
"day": 2,
"start": "0800"
},
{
"is_overnight": false,
"end": "2100",
"day": 3,
"start": "0800"
},
{
"is_overnight": false,
"end": "2200",
"day": 4,
"start": "0800"
},
{
"is_overnight": false,
"end": "2200",
"day": 5,
"start": "0800"
},
{
"is_overnight": false,
"end": "2100",
"day": 6,
"start": "0800"
}
]
}
],
"display_phone": "[phone]",
"categories": [
{
"alias": "seafood",
"title": "Seafood"
},
{
"alias": "mexican",
"title": "Mexican"
}
],
"price": "$",
"phone": "[phone]",
"name": "Oscars Mexican Seafood",
"location": {
"zip_code": "92024",
"address3": null,
"address1": "115 N El Camino Real",
"country": "US",
"city": "Encinitas",
"state": "CA",
"cross_streets": "Via Molena & Encinitas Blvd",
"display_address": [
"115 N El Camino Real",
"Encinitas, CA 92024"
],
"address2": ""
},
"transactions": [],
"url": "https://www.yelp.com/biz/oscars-mexican-seafood-encinitas-2?adjust_creative=YqqOIA_bNY3Qb_A1TRMMUg&utm_campaign=yelp_api_v3&utm_medium=api_v3_business_lookup&utm_source=YqqOIA_bNY3Qb_A1TRMMUg",
"is_closed": false
}

Answer 1

Location isn't an array, so I'd imagine just $arr->location->address1.

Answer 2

$arr = json_decode($json, true);
the true parameter makes sure it's an array and not an object

Answer 3

You must first decode then call the key so:
// Decode the JSON STRING
$arr = json_decode($arr, true);
/*
* first argument is the JSON STRING,
* Second sets the flag that the string is a dictionary
* (associative array)
*/
Now it is time to call the element. I put it in a conditional so to prevent errors
if (array_key_exists('address1', $arr['location'])) {
echo $arr['location']['address1'];
}
else {
echo "Array element Not Found. Here is what I have:\n\r";
print_r($arr);
}
This Should return your element's value OR Dump the parsed PHP Array for review so you can edit the if statement to get the correct location.