How to JSON with duplicate 'id' values? - php

Question

I am receiving data from another site with json API.
how can I get the data of the objects with the same id number.
I try as follows but it turns blank..
there are 10 objects with the same id number
how can i get them.
The typeid number is the same but the specialvalue value is different.
{"id":4620041,"active":true,"typeid":56,"specialvalue":"0.5","fields":{"magic":{"active":true,"type":"magic","value":"1.05"},"xmagic":{"active":true,"type":"xmagic","value":"7.5"}}}
{"id":4620045,"active":true,"typeid":56,"specialvalue":"1.5","fields":{"magic":{"active":true,"type":"magic","value":"3.05"},"xmagic":{"active":true,"type":"xmagic","value":"3.5"}}}
if($test->typeid =="56")
{
if (specialvalue == "0.5") {
$alta = $test->fields->magic->value;
$uste = $test->fields->xmagic->value;
}
}
echo $alta - $uste ;
Thank you in advance for your help
https://i.hizliresim.com/Pl0LL7.jpg

Answer 1

Few observations :
Provided JSON is not a valid JSON.
It should be an array of objects to filter the specific data as per the requirement.
Solution :
let jsonObj = [{
"id": 5246752,
"active": true,
"typeid": 56,
"specialvalue": "0.5",
"fields": {
"magic": {
"active": true,
"type": "magic",
"value": "1.06"
},
"xmagic": {
"active": true,
"type": "xmagic",
"value": "7.0"
}
}
}, {
"id": 5246753,
"active": true,
"typeid": 56,
"specialvalue": "1.5",
"fields": {
"magic": {
"active": true,
"type": "magic",
"value": "1.35"
},
"xmagic": {
"active": true,
"type": "xmagic",
"value": "3.0"
}
}
}, {
"id": 5246754,
"active": true,
"typeid": 56,
"specialvalue": "2.5",
"fields": {
"magic": {
"active": true,
"type": "magic",
"value": "2.0"
},
"xmagic": {
"active": true,
"type": "xmagic",
"value": "1.7"
}
}
}, {
"id": 5246755,
"active": true,
"typeid": 56,
"specialvalue": "3.5",
"fields": {
"magic": {
"active": true,
"type": "magic",
"value": "3.45"
},
"xmagic": {
"active": true,
"type": "xmagic",
"value": "1.25"
}
}
}, {
"id": 5246756,
"active": true,
"typeid": 56,
"specialvalue": "4.5",
"fields": {
"magic": {
"active": true,
"type": "magic",
"value": "6.25"
},
"xmagic": {
"active": true,
"type": "xmagic",
"value": "1.08"
}
}
}, {
"id": 5246757,
"active": true,
"typeid": 56,
"specialvalue": "5.5",
"fields": {
"magic": {
"active": true,
"type": "magic",
"value": "9.5"
},
"xmagic": {
"active": true,
"type": "xmagic",
"value": "1.02"
}
}
}];
let filteredData = jsonObj.filter(item => item.typeid===56 && item.specialvalue==="0.5");
console.log(filteredData);

Answer 2

Use .filter
var filteredData = data.filter(
(el) => {
return el.typeid===56 && el.specialvalue==="0.5";
}
);
This will return only those elements with el.typeid===56 && specialvalue==="0.5"