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How do you join on the same table, twice, in mysql?
(3 answers)
Closed 12 months ago.
I have table info with 3 rows: id,monter1,monter2. Monter1 and monter2 are id's from table monterzy (id, name, surname) that i want to join with. The problem is i cant make a proper query to pick up these values then in php. Currently i have:
SELECT i.id
, m.name
, m.surname
FROM info i
JOIN monterzy m
ON i.monter1 = m.id;
I want to expand it to also get monter2 and corresponding name and surname. I have searched on google, there were examples with AS but i have no idea how to do it. Thanks!
You need to join the same table twice with different alias names
SELECT info.id,
m1.name as m1_name, m1.surname as m1_surname,
m2.name as m2_name, m2.surname as m2_surname
FROM info
INNER JOIN monterzy m1 ON info.monter1 = m1.id
INNER JOIN monterzy m2 ON info.monter2 = m2.id
You just need to alias the tables. That is, with each join of the same table give it a different alias (name) so that the rest of the query knows which one is which. Something like this:
SELECT
info.id,
m1.name,
m1.surname,
m2.name,
m2.surname
FROM
info
INNER JOIN monterzy AS m1 ON info.monter1 = m1.id
INNER JOIN monterzy AS m2 ON info.monter2 = m2.id
Notice how each join has an AS someAlias to give the joined table a new name just for the purposes of this query. And how the rest of the query references that alias instead of the table name.
You need to use table aliases for this :
SELECT info.id, m1.name as name1, m1.surname as surname1, m2.name as name2, m2.surname as surname2
FROM info
INNER JOIN monterzy m1 ON info.monter1 = m1.id
INNER JOIN monterzy m2 ON info.monter2 = m2.id;
You can use left join
SELECT
info.id,
m1.name,
m1.surname,
m2.name,
m2.surname
FROM
info
INNER JOIN monterzy AS m1 ON info.monter1 = m1.id
LEFT JOIN monterzy AS m2 ON info.monter2 = m2.id
Related
I have created an INNER JOIN query as shown below and was wondering how I can make it work? I need for the HomeTeam and AwayTeam to equal TeamID in the query. Any help would be much appreciated. Thanks
$result = mysqli_query($con,"SELECT results.*,team.TeamName
FROM results
INNER JOIN team ON team.TeamID = results.HomeTeam
INNER JOIN team on team.TeamID = results.AwayTeam");
You need to use aliases for the table that you are including twice. Otherwise mysql cannot distinguish between the two.
To be able to process the results easily, you can do the same with the names you are selecting.
Something like:
SELECT
results.*,
t1.TeamName AS TeamNameHome,
t2.TeamName AS TeamNameAway
FROM results
INNER JOIN team t1
ON t1.TeamID = results.HomeTeam
INNER JOIN team t2
ON t2.TeamID = results.AwayTeam
I am using php and I have to get the data from multiple tables with common id, but the problem is that in few tables that common id contains multiple records,using inner join gives me separate rows of data e.g.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"2"}
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId":"3"}
extraId is the multiple record for the dish_id:52.
I need result like this.
{"dish_id":"52","quantity":"1","STATUS":"pending","franchise_id":"5","order_type":"PickUp","extraId"[{"id":"2"},{"id":"3"]}}
My query is:
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status'";
please help.
Use group by and group_concat. Something like this:
Select d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type,
group_concat(e.extra_id) as extraids
from order_main m INNER JOIN
order_detail d
ON m.id = d.order_id INNER JOIN
order_extras e
ON m.id = e.order_id INNER JOIN
order_addons a
ON m.id = a.order_id
where m.franchise_id = '$storeId' and d.STATUS <> '$order_status'
group by d.dish_id, d.quantity, d.STATUS, m.franchise_id, m.order_type;
Your desired results do not include these columns:
e.extra_title
a.addon_id
a.addon_size
I would also suggest that you remove the join to order_addons.
Notice that table aliases make the query easier to write and to read.
You can use group bywith dish_id
$orders = "Select DISTINCT order_detail.dish_id,order_detail.quantity,order_detail.STATUS,
order_main.franchise_id,order_main.order_type,
order_extras.extra_id,order_extras.extra_title,
order_addons.addon_id,order_addons.addon_size
from order_main
INNER JOIN order_detail ON order_main.id=order_detail.order_id
INNER JOIN order_extras ON order_main.id=order_extras.order_id
INNER JOIN order_addons ON order_main.id=order_addons.order_id
WHERE order_main.franchise_id='$storeId'
and
order_detail.STATUS!='$order_status' group by order_detail.dish_id";
I have three tables on MySQL:
users_data
id[PK]
name
users_permissions
userid[FK]
moduid[FK]
modules
id[PK]
name
I want to print the modules.name table for the user that has only an entry on the permissions table base on the moduid[FK].
Does anybody can help me with this? I just don't know how to do it...
select m.name
from users_data ud
inner join users_permissions p on ud.id = p.userid
inner join modules m on m.id = ud.moduid
I have the following query which works perfectly:
SELECT *
FROM contacts
WHERE id in (
SELECT DISTINCT contacts.id
FROM contacts
INNER JOIN contacts2tags
ON contacts.id = contacts2tags.contactid
WHERE tagid in(7,4)
)
Here contacts table contains id, first_name, last_name, ..and tags table contains id, name. contacts2tags table contains contactid and tagid which are same as contacts.id and tags.id respectively
Now, what I want is, to display only the contacts which have both a tagid 7 and a tagid 4.
I tried something like this:
SELECT *
FROM contacts
WHERE id IN
(
SELECT CT1.contactid
FROM
tags T1, contacts2tags CT1, tags T2, contacts2tags CT2
WHERE CT1.contactid = CT2.contactid
AND CT1.tagid = T1.id
AND CT2.tagid = T2.id
AND (T1.id = 7 AND T2.id = 4)
and it works too.
My problem is, I want to convert the above second query to one using inner joins.
I have an array of ids stored in $tmp in php
I want to use those ids and write the above query for them.
How do I do that? I am not comfortable with sql. Might be its a very simple thing to ask.
Thanks in advance
EDIT:
The answer below solved the problem. But the sql runs very slow for 10k records. Any suggestions to optimise it? Pasting the updated query as given in the answer.
SELECT c.id
FROM contacts c
inner join contacts2tags t on c.id = t.contactid
where t.tagid in (7,4)
group by c.id
having count(distinct t.tagid) = 2
This should work
SELECT c.id
FROM contacts c
inner join contacts2tags t on c.id = t.contactid
where t.tagid in (7,4)
group by c.id
having count(distinct t.tagid) = 2
I have a MYSQL query who have to list all post i want it to post. But it dont do it. It shows posts when i have more then one post in the table "meaOrder" with the same "ordCode". But when i have only on post in meaOrder, i don't show it. What can i do?
SELECT koden, wish, rnamn, bild, pris, cname, onsktext
FROM (
SELECT m.wishText as onsktext, m.meaOID as midn, m.ordcode as koden, w.wish as wish, r.meaName as rnamn, r.meaImg as bild,
r.meaPrice as pris, k.catName as cname from cats k, meals r, wishes w,
meaOrder m
join orders c on c.ordNR=4401
WHERE c.ordStatus=1 AND m.ordNR=c.ordNR AND m.meaID=r.meaID AND m.wishesID=w.id
AND r.catID=k.catID
) T
GROUP BY koden, rnamn, bild, pris, cname
ORDER BY midn DESC
TABLE orders
http://grab.by/m74E
TABLE meaOrder http://grab.by/m74Q
Try replacing the JOIN with RIGHT JOIN in this case. The difference is explained at JOIN Syntax page in MySQL docs . In short - JOIN returns row only if there are corresponding rows in both joined tables (inner join). LEFT JOIN / RIGHT JOIN return all rows from one of the tables and corresponding row if it exists from the other table (those are outer joins)
Do you need a subselect?
This seems to cover it:-
SELECT m.ordcode AS koden, w.wish AS wish, r.meaName AS rnamn, r.meaImg AS bild, r.meaPrice AS pris, k.catName AS cname, m.wishText AS onsktext
FROM cats k
INNER JOIN meals r ON r.catID = k.catID
INNER JOIN meaOrder m ON m.meaID = r.meaID
INNER JOIN wishes w ON m.wishesID = w.id
INNER JOIN orders c ON m.ordNR = c.ordNR
WHERE c.ordStatus = 1
AND c.ordNR = 4401
GROUP BY m.ordcode, r.meaName, r.meaImg, r.meaPrice, k.catName
ORDER BY midn DESC