I know, the headline is not very specific, but I dont't know how to title it.
I want to create a list from 1 to 10. All those numbers should be clickable and open a sublist. Again with the numbers from 1-10. Like this:
1
2
1
2
3
and so on...
Here is some code, I've got:
<?php
$num = $_GET['zahl'];
$zahlen = array();
while($num != 0){
$part = $num % 10;
array_push($zahlen, $part);
$num = floor($num/10);
}
foreach ($zahlen as $key => $value) {
$runs = $value + 1;
for ($i=1; $i < $runs ; $i++) {
if ($i == 1) {
echo $ulon . "\n";
}
echo $lion . "\n";
echo $a . "ordner.php?zahl=" . $i . $amiddle . $i . $aoff . "\n";
echo $lioff . "\n";
}
for ($i=1; $i < 11 ; $i++) {
if ($i == 1) {
echo $ulon;
}
echo $lion . "\n";
echo $a . "ordner.php?zahl=" . $zahlen[0] . $i . $amiddle . $i . $aoff;
echo $lioff . "\n";
}
echo $uloff;
echo "\n" . "</body>";
?>
What you wish to achieve should be fairly straigtforward with Javascript rather than PHP - the following uses PHP only to generate the initial list and subsequent sub-lists are generated using javascript.
<?php
echo "<ul id='infinite-menu'>";
for( $i=1; $i < 11; $i++ ){
echo "<li>$i</li>";
}
echo "</ul>";
?>
<script>
var children=10;
function newnodes(e){
if( e.target.childNodes.length==1 ){
var ul=document.createElement('ul');
e.target.appendChild(ul);
for( i=1; i < children+1; i++ ){
var li=document.createElement('li');
li.innerHTML=i;
ul.appendChild( li );
}
}
}
var col=document.querySelectorAll('ul#infinite-menu li');
if( col )for( n in col )if( col[n].nodeType==1){
col[n].addEventListener('click',newnodes,false);
}
</script>
This is my solution based on php. Thanks for your comments!
<body>
<?php
$open = isset($_GET["open"]) ? $_GET["open"] : "";
$openArr = explode(",",$open);
function liste($openArr, $link) {
$firstValue = array_shift($openArr);
echo "<ul>";
for ($i = 0; $i < 10; $i++) {
echo "<li>";
echo "<a href='rekursion.php?open=".$link.$i."'>$i</a>";
if (isset($firstValue) && $firstValue == $i) {
liste($openArr, $link.$i.",");
}
echo "</li>";
}
echo "</ul>";
}
liste($openArr,"");
?>
</body>
Related
I want to print number from 1 to 12 in matrix form and expected output is:
1 5 9
2 6 10
3 7 11
4 8 12
code:
<?php
for ($i=1; $i<=12; $i++)
{
for($j=1;$j<=$i;$j++)
{
echo $i." ";
}
echo "<br/>";
}
?>
I have got wrong output. So, How can I get expected output as I mention above? Please help me.
Thank You
Some "magic" code):
foreach (range(1,4) as $num) {
echo implode(' ', range($num,12,4)) . '<br />';
}
Version with for:
for ($i = 1; $i <= 4; $i++) {
for ($j = $i; $j <= 12; $j +=4) {
echo $j . ' ';
}
echo '<br />';
}
$z=0;
for ($x = 1; $x <= 4; $x++)
{
echo " $x ";
$z=$x;
for ($y = 1; $y <= 2; $y++)
{
$z=$z+4;
echo " $z ";
}
echo "\n";
}
$maxRow = 4;
$maxColumn = 3;
for ($row = 1; $row <= $maxRow; $row++)
{
for ($column = 1; $column <= $maxColumn; $column++) {
$number = $row + 4*($column-1);
echo $number." ";
}
echo "<br/>";
}
should work
foreach (range(1, 4) as $res) {
echo implode(' ', range($res, 12, 4));
echo "<br>";
}
I want to print star pattern like :
below is my code. but it doesn't work for me. How can i fix this problem.
for($i=1; $i<=5; $i++){
for($j=5; $j>$i; $j--){
echo " ";
}
echo "*";
for($j=1; $j<($i-1)*2; $j++){
echo " ";
}
if($i==1)echo "<br>";
else echo "*<br>";
}
for($i=4; $i>=1; $i--){
for($j=5; $j>$i; $j--){
echo " ";
}
echo "*";
for($j=1; $j<($i-1)*2; $j++){
echo " ";
}
if($i==1)echo "<br>";
else echo "*<br>";
}
?>
You should put all text that should keep form and not whitespace trimmed in between a <pre/> tag
<pre><?php
for($i=1; $i<=5; $i++){
for($j=5; $j>$i; $j--){
echo " ";
}
echo "*";
for($j=1; $j<($i-1)*2; $j++){
echo " ";
}
if($i==1)echo "<br>";
else echo "*<br>";
}
for($i=4; $i>=1; $i--){
for($j=5; $j>$i; $j--){
echo " ";
}
echo "*";
for($j=1; $j<($i-1)*2; $j++){
echo " ";
}
if($i==1)echo "<br>";
else echo "*<br>";
} ?></pre>
Note: if your target is console and PHP-CLI, don't put the <pre/> tag, omit the end of PHP tag (?>) and replace all <br/> tags with \n.
Thanks to all of you guys. I add <pre> tag before code and also change <br> tag with \n and now it is work. Thanks again. Have a nice day guys..
Try this...
function printPattern($n)
{
$k = 0;
// Print upper triangle
for ($i = 1; $i <= $n; $i++)
{
// Print spaces
for ($j = 1; $j <= $n - $i; $j++)
{
echo " ";
}
// Print #
while ($k != (2 * $i - 1))
{
if ($k == 0 or $k == 2 * $i - 2)
echo "*";
else
echo " ";
$k++;
}
$k = 0;
// move to next row
echo "\n";
}
$n--;
// Print lower triangle
for ($i = $n; $i >= 1; $i--)
{
// Print spaces
for ($j = 0; $j <= $n - $i; $j++)
{
echo " ";
}
// Print #
$k = 0;
while ($k != (2 * $i - 1))
{
if ($k == 0 or $k == 2 * $i - 2)
echo "*";
else
echo " ";
$k++;
}
echo "\n";
}
}
// Driver Code
$n = 6;
printPattern($n);
// This Code is contributed by mits
?>
I want to display 3 uls:
$one = '<ul>';
$j = 0;
while($j<3){
$one .= '<li data-src="' . $myarray[0][$j] . '"></li>';
$j++;
}
echo $one;
echo '</ul>';
$two = '<ul>';
$j = 0;
while($j<3){
$two .= '<li data-src="' . $myarray[1][$j] . '"></li>';
$j++;
}
echo $two;
echo '</ul>';
$whatever = '<ul>';
$j = 0;
while($j<3){
$whatever .= '<li data-src="' . $myarray[2][$j] . '"></li>';
$j++;
}
echo $whatever;
echo '</ul>';
How can I combine the above in shorter way?
Think about what you want to display first. Here you will have 3 lists, each of your 3 list containing a single sub-list. So you need to loop through your $myarray (which is a 2D array) :
<?php $j = 0; ?>
<?php foreach( $myarray as $row ): ?>
<ul>
<li data-src="<?php echo $row[$j] ?>"></li>
</ul>
<?php endforeach ?>
foreach will go through your first dimension, so you only deal with the next dimension, which make you $row becoming a one-dimension array instead of 2 which is lighter to deal with.
This solution is templating-oriented, which suit well when you need to separate your logic from your graphic.
Like so:
for ($i = 0; $i < 3; $i++) {
echo '<ul>';
for ($j = 0; $j < 3; $j++) {
echo '<li data-src="' . $myarray[$i][$j] . '"></li>';
}
echo '</ul>';
}
$html = "";
for($i=0;$i<=2;$i++) {
$html .= '<ul>';
$j = 0;
while($j<3){
$html .= '<li data-src="' . $myarray[$i][$j] . '"></li>';
$j++;
}
$html .= '</ul>';
}
echo $html;
Something like this springs to mind:
$i = 0;
$j = 0;
while($i < 3) {
echo '<ul>';
while ($j < 3) {
echo '<li data-src="' . $myarray[$i][$j] . '"></li>';
$j++;
}
echo '</ul>';
$i++;
$j = 0;
}
Since you have two loops (which you could also replace with for-loops), you can nest them to only type your html once.
This way you also don't need to store the html in strings. You can echo them right away.
If I understand correctly, you have the same code repeating three times. You can simply replace it with a nested for / while loop:
$i= 0;
while ($i < 3) {
echo '<ul>';
$j = 0;
while ($j < 3) {
echo '<li data-src="' . $myarray[$i][$j] . '"></li>';
$j++;
}
echo '</ul>';
$i++;
}
I want to iterate an array of data using foreach loop.
However, I want the first 4 results to display two items per row.Thereafter I want the rest of the data to display I item per row
i found a possible solution here
$data = range(1, 30);
for($count = 0; $count < count($data);)
{
echo "<tr>\n";
for($i = 0; $count < count($data) && $i < 2; $count++, $i++) {
echo "\t<td>$data[$count]</td>\n";
}
for(; $i < 2; $i++) {
echo "\t<td>-</td>\n";
}
echo "</tr>\n";
}
how the problem with this code is that it displays all the data in rows of two.i however only want the first 4 results to display that way.
You can do something like this:
$data = range(1, 30);
for($count = 0; $count < count($data); ++$count){
if($count < 4){
if($count % 2 == 0){
echo "<tr><td>" . $data[$count] . "</td>";
}else{
echo "<td>" . $data[$count] . "</td></tr>";
}
}else{
echo "<tr><td>" . $data[$count] . "</td></tr>";
}
}
Here's the demo
You're using the already incremented $i variable twice.
$i is never < 2
Add this instead
for($j = 0; $j < 2; $j++) {
echo "\t<td>-</td>\n";
}
Test here
Try with -
$data = range(1, 30);
for($count = 0; $count < count($data); $count++)
{
echo "<tr>";
if($count < 2) {
for($i = 1; $i <= 2; $i++) {
echo "<td>" . $data[$count] . "</td>";
if($i == 1) {
echo "</tr><tr>";
}
}
} else {
echo "<td>" . $data[$count] . "</td>";
}
echo "</tr>";
}
What about something like this?
echo '<table border=1>';
$data = range(1, 30);
for($count = 0; $count < count($data); $count++){
echo "<tr>\n";
if($count < 4) {
echo "\t<td>$data[$count]</td>\n";
$count++;
echo "\t<td>$data[$count]</td>\n";
} else {
echo "\t<td colspan=2>$data[$count]</td>\n";
}
echo "</tr>\n";
}
echo '</table>';
Draw a staircase of height N like this:
#
##
###
####
#####
######
Staircase of height 6, note the last line should have zero spaces.
My solution does not work correctly
function draw($size)
{
for ($i = 1; $i <=$size ; $i++)
{
$spaces = $size-$i;
while ($spaces)
{
echo " ";
$spaces--;
}
$stairs = 0;
while ($stairs < $i)
{
echo "#";
$stairs++;
}
echo "<br/>";
}
}
draw(6);
//output
#
##
###
####
#####
######
It is not printing the spaces, I tried \n, PHP.EOL still it didn't work. Any suggestions?
Although other solutions are all good , here is my code as well.
$max=5;
for ( $i =1 ; $i<=$max;$i++) {
for ( $space = 1; $space <= ($max-$i);$space++) {
echo " ";
}
for ( $hash = 1; $hash <= $i;$hash ++ ) {
echo "#";
}
echo "\n";
}
//PHP
$n = 6; // Number of rows.
for($i=1;$i<=$n;$i++){
echo str_repeat(' ', $n-$i) . str_repeat('#', $i);
echo '\n';
}
for(var i = 0; i < n; i++)
{
var s = "";
for(var j = 0; j < n; j++)
{
if(n - i - 2 < j)
{
s += "#";
}
else
{
s += " ";
}
}
console.log(s);
}
for ($i=0; $i<$n; $i++){
for ($j=0; $j<$n; $j++){
if($i+$j>$n-2){
echo "#";
} else {
echo " ";
}
if($j==$n-1 && $i+$j<$n*2-2){ //The second part is to dont break the last line
echo "\n";
}
}
}
Here's another solution:
$int = 7;
for($i = 1; $i<=$int; $i++){
printf('%1$s%2$s%3$s',str_repeat(" ",$int-$i),str_repeat("#",$i),"\n");
}
From official PHP documentation:
str_repeat
$n = 6;
for ($i = 0; $i < $n; $i++) {
$pad = 1;
for ($space = 0; $space < $n-$i-1; $space++) {
$pad++;
}
echo str_pad('#', $pad,' ',STR_PAD_LEFT);
for ($j = 0; $j < $i; $j++) {
echo '#';
}
echo '<br>';
}
Took me a while but finally I manage to do it following OFC (A. Sharma) Example.
<?php
$handle = fopen("php://stdin","r");
$n = intval(fgets($handle));
for ($rows = 0; $rows < $n; $rows++) {
for ($columns = 0; $columns < $n - $rows - 1; $columns++) {
echo " ";
}
for ($columns = 0; $columns < $rows + 1; $columns++) {
echo "#";
}
echo "\n";
}
?>
Use PHP functions range() and str_repeat() for an elegant solution:
function staircase($n){
foreach (range(1, $n) as $i)
print( str_repeat(' ',$n-$i).str_repeat('#',$i)."\n");
}
demo
Check if n is between 0 and 101 ( 0 < n <= 100)
Loop through each row
2.1 print spaces according to the last item position
2.2 print the items
Separate rows
The code below explains everything...
function staircase($n) {
// check if n is between 0 and 101 (0 < n <=100)
if( 0 < $n && $n > 100 ) {
} else {
// Loop through each row
for($i = 1; $i <= $n; $i++) {
// print spaces according to the last item position
$si = 1;
while( $si <= ($n - $i)){
print(" ");
$si++;
}
// print the items
for($j = 1; $j <= $i; $j++) {
print("#");
}
// separate rows
print("\n");
}
}
}
Output: For n = 6
#
##
###
####
#####
######
After playing around with the code and trying/failing couple of times I finally got it right. Notice how in order to print the space and new line I am using "\n". Previous "<br/>" and " " for space didn't work.
Break line will come out of the loop every row number. So if we have $n=4 then every 4 spaces after break line will be echoed.
I have made 2 loops to fill in all fields in the staircase.
The tricky part here is to have them right aligned. This is where if statement comes in place.
Reference link:
Hackerrank Challenge
// Complete the staircase function below.
function staircase($n) {
for($i=1; $i<=$n; $i++){
for($j=1; $j <= $n; $j++){
if( ($n - $i) < $j ){
echo "#";
}else{
echo " ";
}
}
echo "\n";
}
}
Try This
$n=6;
for($i=1;$i<=$n;$i++){
for($spaces=1;$spaces<=($n-$i);$spaces++){
echo " ";
}
for($staires=0;$staires<$i;$staires++){
echo "#";
}
echo "\n";
}
This worked for me
$n = 6;
function staircase($n) {
for($i=1; $i <= $n; $i++){
for($j=1; $j <= $n; $j++){
if($j > $n-$i){
echo "#";
}else{
echo " ";
}
}
echo "\n";
}
}
Use print(' '), if you want to go to next line put print(' ')."\n"
JavaScript:
Solution:
function StairCase(n){
let x = [];
for(let i = 0; i<n; i++){
while(x.length < n){
x.push(" ");
}
x.shift();
x.push("#");
console.log(x.join(''));
} } //StairCase(6)