display first set of result in row - php

Question

I want to iterate an array of data using foreach loop.
However, I want the first 4 results to display two items per row.Thereafter I want the rest of the data to display I item per row
i found a possible solution here
$data = range(1, 30);
for($count = 0; $count < count($data);)
{
echo "<tr>\n";
for($i = 0; $count < count($data) && $i < 2; $count++, $i++) {
echo "\t<td>$data[$count]</td>\n";
}
for(; $i < 2; $i++) {
echo "\t<td>-</td>\n";
}
echo "</tr>\n";
}
how the problem with this code is that it displays all the data in rows of two.i however only want the first 4 results to display that way.

Answer 1

You can do something like this:
$data = range(1, 30);
for($count = 0; $count < count($data); ++$count){
if($count < 4){
if($count % 2 == 0){
echo "<tr><td>" . $data[$count] . "</td>";
}else{
echo "<td>" . $data[$count] . "</td></tr>";
}
}else{
echo "<tr><td>" . $data[$count] . "</td></tr>";
}
}
Here's the demo

Answer 2

You're using the already incremented $i variable twice.
$i is never < 2
Add this instead
for($j = 0; $j < 2; $j++) {
echo "\t<td>-</td>\n";
}
Test here

Answer 3

Try with -
$data = range(1, 30);
for($count = 0; $count < count($data); $count++)
{
echo "<tr>";
if($count < 2) {
for($i = 1; $i <= 2; $i++) {
echo "<td>" . $data[$count] . "</td>";
if($i == 1) {
echo "</tr><tr>";
}
}
} else {
echo "<td>" . $data[$count] . "</td>";
}
echo "</tr>";
}

Answer 4

What about something like this?
echo '<table border=1>';
$data = range(1, 30);
for($count = 0; $count < count($data); $count++){
echo "<tr>\n";
if($count < 4) {
echo "\t<td>$data[$count]</td>\n";
$count++;
echo "\t<td>$data[$count]</td>\n";
} else {
echo "\t<td colspan=2>$data[$count]</td>\n";
}
echo "</tr>\n";
}
echo '</table>';