I am using Laravel 5.4,
How to sort twice with two columns?
For example:
ArticleController.php
public function index()
{
$articles = Auth::user()->articles->sortByDesc('updated_at')->sortByDesc('status');
return view('index', compact('articles'));
}
I use sortByDesc() twice,but the result does not follow the rules,what should I do?
update:
User.php
public function articles()
{
return $this->hasMany('App\Article');
}
You shouldn't sort on collection but you should get sorted results from database like this:
$articles = Auth::user()->articles()
->orderBy('updated_at', 'DESC')
->orderBy('status','DESC')
->get();
To explain a bit more - in your code you got all results from database (in random order) and then tried to sort all the results.
In code I presented you sort results in database so you can easily sort on mutliple columns.
Notice difference in my code - instead of ->articles I used ->articles() and added ->get() at the end to get results.
Related
I got two tables. Both have a relationship to each other. I´m trying to query both to get the matching results. This results get checked if they also have an column which matches with a parameter value.
I´m trying it with a scope and it work. I only need one column from the second table and I´m trying to use it as column in my first table when I got my result.
So the code works and I got an result but I´m trying to filter to select only one column from the second table.
My code look like that.
My controller:
public function test()
{
$UID='LQuupgYvnuVzbEoguY4TF8bnHUU2';
$event=Events::withState($UID)->get();
echo $event;
}
My model scope function:
public function scopeWithState($query,$UID){
return $query->with(['EventLiked' => function($query) use($UID) {
$query
->where('EventLiked.UID', $UID)
;
}]);
}
My hasMany relationship function:
public function EventLiked()
{
return $this->hasMany(EventLiked::class,'EID','ID')->select('State','UID','EID');
}
I would go for specifying columns inside closure.
New scope:
public function scopeWithState($query,$UID){
return $query->with(['EventLiked' => function($query) use($UID) {
$query
->where('EventLiked.UID', $UID)
->select('State');
}]);
}
Calling scope:
$event=Events::withState($UID)->get();
You're not getting expected results because Laravel splits it into 2 queries:
First, for selecting events.
Then it plucks EID
Second, when it looks for EventLiked where matching ID's is found (from second step) and loads as relationships.
So you want to change select statement only in 2nd query. Not in a first one
I have got three tables in laravel like so:
Users, posts, and comments
I'm trying to come up with a query that fetches me all the user's posts, plus the date of last comment with each post.
Approach i've taken that's not working perfectly is:
$posts = User::find($userId)->posts()->with('latestComment')->get();
In my Post model I have:
public function latestComment()
{
return $this->hasOne(Comment::class)->latest();
}
In my findings, i haven't been to see a way to get the date from the lastComment load.
Any pointers welcome,
Thanks
Just discovered one needs to add the foreign key to the select method like so:
return $this->hasOne(Comment::class)->latest()->select('field','foreign_key');
You should use eager loading constraint. Code from the other answers will first load all comments, which you don't want.
$posts = Post::where('user_id', $userId)
->with(['comments' => function($q) {
$q->taletst()->take(1);
}])
->get();
You can use the existing relationship and get the latest comment.
public function comments() {
return $this->hasMany(Comment::class);
}
public function latestComment() {
return $this->comments()->last();
}
I have 3 models
User
Channel
Reply
model relations
user have belongsToMany('App\Channel');
channel have hasMany('App\Reply', 'channel_id', 'id')->oldest();
let's say i have 2 channels
- channel-1
- channel-2
channel-2 has latest replies than channel-1
now, i want to order the user's channel by its channel's current reply.
just like some chat application.
how can i order the user's channel just like this?
channel-2
channel-1
i already tried some codes. but nothing happen
// User Model
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved')
->with(['replies'])
->orderBy('replies.created_at'); // error
}
// also
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved')
->with(['replies' => function($qry) {
$qry->latest();
}]);
}
// but i did not get the expected result
EDIT
also, i tried this. yes i did get the expected result but it would not load all channel if there's no reply.
public function channels()
{
return $this->belongsToMany('App\Channel')
->withPivot('is_approved')
->join('replies', 'replies.channel_id', '=', 'channels.id')
->groupBy('replies.channel_id')
->orderBy('replies.created_at', 'ASC');
}
EDIT:
According to my knowledge, eager load with method run 2nd query. That's why you can't achieve what you want with eager loading with method.
I think use join method in combination with relationship method is the solution. The following solution is fully tested and work well.
// In User Model
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved');
}
public function sortedChannels($orderBy)
{
return $this->channels()
->join('replies', 'replies.channel_id', '=', 'channel.id')
->orderBy('replies.created_at', $orderBy)
->get();
}
Then you can call $user->sortedChannels('desc') to get the list of channels order by replies created_at attribute.
For condition like channels (which may or may not have replies), just use leftJoin method.
public function sortedChannels($orderBy)
{
return $this->channels()
->leftJoin('replies', 'channel.id', '=', 'replies.channel_id')
->orderBy('replies.created_at', $orderBy)
->get();
}
Edit:
If you want to add groupBy method to the query, you have to pay special attention to your orderBy clause. Because in Sql nature, Group By clause run first before Order By clause. See detail this problem at this stackoverflow question.
So if you add groupBy method, you have to use orderByRaw method and should be implemented like the following.
return $this->channels()
->leftJoin('replies', 'channels.id', '=', 'replies.channel_id')
->groupBy(['channels.id'])
->orderByRaw('max(replies.created_at) desc')
->get();
Inside your channel class you need to create this hasOne relation (you channel hasMany replies, but it hasOne latest reply):
public function latestReply()
{
return $this->hasOne(\App\Reply)->latest();
}
You can now get all channels ordered by latest reply like this:
Channel::with('latestReply')->get()->sortByDesc('latestReply.created_at');
To get all channels from the user ordered by latest reply you would need that method:
public function getChannelsOrderdByLatestReply()
{
return $this->channels()->with('latestReply')->get()->sortByDesc('latestReply.created_at');
}
where channels() is given by:
public function channels()
{
return $this->belongsToMany('App\Channel');
}
Firstly, you don't have to specify the name of the pivot table if you follow Laravel's naming convention so your code looks a bit cleaner:
public function channels()
{
return $this->belongsToMany('App\Channel') ...
Secondly, you'd have to call join explicitly to achieve the result in one query:
public function channels()
{
return $this->belongsToMany(Channel::class) // a bit more clean
->withPivot('is_approved')
->leftJoin('replies', 'replies.channel_id', '=', 'channels.id') // channels.id
->groupBy('replies.channel_id')
->orderBy('replies.created_at', 'desc');
}
If you have a hasOne() relationship, you can sort all the records by doing:
$results = Channel::with('reply')
->join('replies', 'channels.replay_id', '=', 'replies.id')
->orderBy('replies.created_at', 'desc')
->paginate(10);
This sorts all the channels records by the newest replies (assuming you have only one reply per channel.) This is not your case, but someone may be looking for something like this (as I was.)
I have 3 models
User
Pick
Schedule
I'm trying to do something like the following
$picksWhereGameStarted = User::find($user->id)
->picks()
->where('week', $currentWeek)
->first()
->schedule()
->where('gameTime', '<', Carbon::now())
->get();
This code only returns one array inside a collection. I want it to return more than 1 array if there is more than 1 result.
Can I substitute ->first() with something else that will allow me to to return more than 1 results.
If not how can I set up my models relationship to allow this to work.
My models are currently set up as follow.
User model
public function picks()
{
return $this->hasMany('App\Pick');
}
Schedule model
public function picks()
{
return $this->hasMany('App\Pick');
}
Pick model
public function user()
{
return $this->belongsTo('App\User');
}
public function schedule()
{
return $this->belongsTo('App\Schedule');
}
Since you already have a User model (you used it inside you find method as $user->id), you can just load its Pick relationship and load those Picks' Schedule as follows:
EDIT:
Assuming you have a schedules table and your picks table has a schedule_id column. Try this.
$user->load(['picks' => function ($q) use ($currentWeek) {
$q->join('schedules', 'picks.schedule_id', '=', 'schedules.id')
->where('schedules.gameTime', '<', Carbon::now()) // or Carbon::now()->format('Y-m-d'). See what works.
->where('picks.week', $currentWeek);
}])->load('picks.schedule');
EDIT: The code above should return the user's picks which have a schedules.gameTime < Carbon::now()
Try it and do a dump of the $user object to see the loaded relationships. That's the Eloquent way you want.
Tip: you may want to do $user->toArray() before you dump $user to see the data better.
EDIT:
The loaded picks will be in a form of Collections so you'll have to access it using a loop. Try the following:
foreach ($user->picks as $pick) {
echo $pick->schedule->gameTime;
}
If you only want the first pick from the user you can do: $user->picks->first()->schedule->gameTime
I think a foreach loop may be what you're looking for:
$picks = User::find($user->id)->picks()->where('week', $currentWeek);
foreach ($picks as $pick){
$pickWhereGameStarted = $pick->schedule()->where('gameTime', '<', Carbon::now())->get();
}
Try this and see if it's working for you
Hi I was able to get the values from two tables, now I want this two values to be subtracted. How can i do it here in laravel?
public function displayBalance()
{
$results= DB::table('accountspayable')
->selectRaw('sum(accountspayable.amount) as sum')
->where('accountspayable.regnum','=','15459')
->get();
$subjects= DB::table('pay')
->selectRaw('sum(pay.amount) as sum')
->join('accountspayable','pay.accountno','=','accountspayable.accountno')
->where('accountspayable.regnum','=','15459')
->get();
return View::make('users.Balance')->with(array('results'=>$results,'subjects'=>$subjects));
}
Try it this way:
public function displayBalance()
{
$results = DB::table('accountspayable')->
where('regnum'. '='. '15459')->
sum('amount');
$subjects = DB::table('pay')->
join('accountspayable','pay.accountno','=','accountspayable.accountno')->
where('accountspayable.regnum','=','15459')->
sum('pay.amount');
return View::make('users.Balance', compact('results', 'subjects'));
}
You were probably getting collections of 1 record having 1 attribute (sum). And that's the only thing you basically need. So you can use aggregate functions directly in your query builder to get the SUM values.
Also I used "compact" to assign the values you just retrieved to the view. This is not necessary but saves some code and is easier to read.