I have 3 models
User
Channel
Reply
model relations
user have belongsToMany('App\Channel');
channel have hasMany('App\Reply', 'channel_id', 'id')->oldest();
let's say i have 2 channels
- channel-1
- channel-2
channel-2 has latest replies than channel-1
now, i want to order the user's channel by its channel's current reply.
just like some chat application.
how can i order the user's channel just like this?
channel-2
channel-1
i already tried some codes. but nothing happen
// User Model
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved')
->with(['replies'])
->orderBy('replies.created_at'); // error
}
// also
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved')
->with(['replies' => function($qry) {
$qry->latest();
}]);
}
// but i did not get the expected result
EDIT
also, i tried this. yes i did get the expected result but it would not load all channel if there's no reply.
public function channels()
{
return $this->belongsToMany('App\Channel')
->withPivot('is_approved')
->join('replies', 'replies.channel_id', '=', 'channels.id')
->groupBy('replies.channel_id')
->orderBy('replies.created_at', 'ASC');
}
EDIT:
According to my knowledge, eager load with method run 2nd query. That's why you can't achieve what you want with eager loading with method.
I think use join method in combination with relationship method is the solution. The following solution is fully tested and work well.
// In User Model
public function channels()
{
return $this->belongsToMany('App\Channel', 'channel_user')
->withPivot('is_approved');
}
public function sortedChannels($orderBy)
{
return $this->channels()
->join('replies', 'replies.channel_id', '=', 'channel.id')
->orderBy('replies.created_at', $orderBy)
->get();
}
Then you can call $user->sortedChannels('desc') to get the list of channels order by replies created_at attribute.
For condition like channels (which may or may not have replies), just use leftJoin method.
public function sortedChannels($orderBy)
{
return $this->channels()
->leftJoin('replies', 'channel.id', '=', 'replies.channel_id')
->orderBy('replies.created_at', $orderBy)
->get();
}
Edit:
If you want to add groupBy method to the query, you have to pay special attention to your orderBy clause. Because in Sql nature, Group By clause run first before Order By clause. See detail this problem at this stackoverflow question.
So if you add groupBy method, you have to use orderByRaw method and should be implemented like the following.
return $this->channels()
->leftJoin('replies', 'channels.id', '=', 'replies.channel_id')
->groupBy(['channels.id'])
->orderByRaw('max(replies.created_at) desc')
->get();
Inside your channel class you need to create this hasOne relation (you channel hasMany replies, but it hasOne latest reply):
public function latestReply()
{
return $this->hasOne(\App\Reply)->latest();
}
You can now get all channels ordered by latest reply like this:
Channel::with('latestReply')->get()->sortByDesc('latestReply.created_at');
To get all channels from the user ordered by latest reply you would need that method:
public function getChannelsOrderdByLatestReply()
{
return $this->channels()->with('latestReply')->get()->sortByDesc('latestReply.created_at');
}
where channels() is given by:
public function channels()
{
return $this->belongsToMany('App\Channel');
}
Firstly, you don't have to specify the name of the pivot table if you follow Laravel's naming convention so your code looks a bit cleaner:
public function channels()
{
return $this->belongsToMany('App\Channel') ...
Secondly, you'd have to call join explicitly to achieve the result in one query:
public function channels()
{
return $this->belongsToMany(Channel::class) // a bit more clean
->withPivot('is_approved')
->leftJoin('replies', 'replies.channel_id', '=', 'channels.id') // channels.id
->groupBy('replies.channel_id')
->orderBy('replies.created_at', 'desc');
}
If you have a hasOne() relationship, you can sort all the records by doing:
$results = Channel::with('reply')
->join('replies', 'channels.replay_id', '=', 'replies.id')
->orderBy('replies.created_at', 'desc')
->paginate(10);
This sorts all the channels records by the newest replies (assuming you have only one reply per channel.) This is not your case, but someone may be looking for something like this (as I was.)
Related
sorry for the title of this question but I am not sure how to ask it...
I am working on a project where I have two Models Trains and Cars, to this model I have a belonging Route.
I want to make a query and check if the routeable_type is App\Car than with the selected routeable_id to get the data from the Car. And if the routeable_type is Train then with the ID to get the data from the Tran.
So my models go like this:
Train:
class Train extends Model
{
public function routes()
{
return $this->morphMany('App\Route', 'routeable');
}
}
Car:
class Car extends Model
{
public function routes()
{
return $this->morphMany('App\Route', 'routeable');
}
}
Route:
class Route extends Model
{
public function routeable()
{
return $this->morphTo();
}
}
And the query I have at the moment is:
$data = Route::leftjoin('cars', 'cars.id', '=', 'routes.routeable_id')
->leftjoin('trains', 'trains.id', '=', 'routes.routeable_id')
->select('routes.id', 'cars.model AS carmodel', 'trains.model AS trainmodel', 'routeable_type', 'routes.created_at');
With this query if I have the same ID in cars and trains I get the data from both and all messes up. How do I check if routeable_type is Car ... do this, if routeable_type is Train .. do that?
Will something like this be possible in a 1 single query:
$data = Route::select('routes.id', 'routeable_type', 'routes.created_at');
if(routeable_type == 'Car'){
$data = $data->leftjoin('cars', 'cars.id', '=', 'routes.routeable_id')->select('routes.id', 'cars.model AS carmodel', 'routeable_type', 'routes.created_at');
}else{
$data = $data->leftjoin('trains', 'trains.id', '=', 'routes.routeable_id')->select('routes.id', 'trains.model AS trainmodel', 'routeable_type', 'routes.created_at');
}
Maybe this is what you are looking for?
DB::table('routes')
->leftJoin('cars', function ($join) {
$join->on('cars.id', '=', 'routes.routeable_id')
->where('routes.routeable_type', 'App\Car');
})
->leftJoin('trains', function ($join) {
$join->on('trains.id', '=', 'routes.routeable_id')
->where('routes.routeable_type', 'App\Train');
})
->select('routes.id', 'cars.model AS car_model', 'trains.model AS train_model', 'routes.routeable_type', 'routes.created_at');
->get();
I think you may want to follow the morphedByMany design.
https://laravel.com/docs/5.7/eloquent-relationships#many-to-many-polymorphic-relations
This was also a neat visual for the different relation types.
https://hackernoon.com/eloquent-relationships-cheat-sheet-5155498c209
I was faced with a similar issue though I failed to follow the correct design initially and was forced to query the many possible relations then wrote custom logic after to collect the relation types and ids then do another query and assign them back through iteration. It was ugly but worked... very similar to how Eloquent does things normally.
i don't have enough repo, so i can't comment. that's why i am putting as an answer.
You should use 2 different queries, for each model.
This will be better, code wise as well as performance wise. also if both models have similar fields you should merge them to 1 table and add a 'type' column.
and put non-similar fields in a 'meta' column.
( in my opinion )
I have many to many connect with between user - cityarea.
I have also area which connect cityarea (One cityarea can connect only one area).
I have this database structure:
users
id
username
password
cityareas
id
name
area_id
cityarea_user
id
cityarea_id
user_id
areas
id
name
Next I have Models
User
public function cityareas()
{
return $this->belongsToMany('App\Cityarea');
}
Cityarea
public function area()
{
return $this->belongsTo('App\Area');
}
public function users()
{
return $this->belongsToMany('\App\User');
}
Area
public function cityareas()
{
return $this->hasMany('App\Cityarea');
}
QUESTION:
How I can get all users where areas.name = "South" with Eloquent ?
Thanks!!
By using whereHas, you can do:
$users = User::whereHas('cityareas.area', function ($query) {
$query->where('name', 'South');
})->get();
Jeune Guerrier solution is perfect, but you can use with() method of eloquent If you also need cityarea collection along with users collection.
$users = User::with('cityareas')->whereHas('cityareas.area', function ($query) {
$query->where('name', 'South');
})->get();
This is exactly what the belongs to many relationships is built for.
You simply have to do, Cityarea::where('name', 'South')->first()->users;
If you want to do something further with the query, e.g. sort by users created at, you can do
Cityarea::where('name', 'South')->first()->users()->orderBy('creaated_at', desc')->get();
Note that if there is no such Cityarea with name 'South', the ->first() query above will return null and therefore will fail to fetch the users.
A more performant way to do it programmatically is to use the whereHas approach as discussed in the comments below.
I have got three tables in laravel like so:
Users, posts, and comments
I'm trying to come up with a query that fetches me all the user's posts, plus the date of last comment with each post.
Approach i've taken that's not working perfectly is:
$posts = User::find($userId)->posts()->with('latestComment')->get();
In my Post model I have:
public function latestComment()
{
return $this->hasOne(Comment::class)->latest();
}
In my findings, i haven't been to see a way to get the date from the lastComment load.
Any pointers welcome,
Thanks
Just discovered one needs to add the foreign key to the select method like so:
return $this->hasOne(Comment::class)->latest()->select('field','foreign_key');
You should use eager loading constraint. Code from the other answers will first load all comments, which you don't want.
$posts = Post::where('user_id', $userId)
->with(['comments' => function($q) {
$q->taletst()->take(1);
}])
->get();
You can use the existing relationship and get the latest comment.
public function comments() {
return $this->hasMany(Comment::class);
}
public function latestComment() {
return $this->comments()->last();
}
I would like to display the posts of everyone the current user follows, ordered by date desc.
I have a many to many relationship supplying all the people the user is following.
$users = User::find(Auth::user()->id)->follow()->get();
I have a one to many relationship displaying the posts for any user.
$updates = App\User::find(?????)->updates()->orderBy('created_at', 'desc')->get();
The question mark's shows where the followers ID's need to be placed.
I can put the above query inside the for each loop but that obviously works its way through each follower rather than all posts in date order.
I suspect I may need to set a new relationship and work from the beginning. Can anyone advise.
User Model
public function updates()
{
return $this->hasMany('App\update');
}
/**
* User following relationship
*/
// Get all users we are following
public function follow()
{
return $this->belongsToMany('App\User', 'user_follows', 'user_id', 'follow_id')->withTimestamps()->withPivot('id');;;
}
// This function allows us to get a list of users following us
public function followers()
{
return $this->belongsToMany('App\User', 'user_follows', 'follow_id', 'user_id')->withTimestamps();;
}
}
Update Model
public function user_update()
{
return $this->belongsTo('App\User');
}
Thank you.
Since you want the posts, it is probably going to be easier starting a query on the Post model, and then filter the posts based on their relationships.
Assuming your Post model has an author relationship to the User that created the post, and the User has a follower relationship to all the Users that are following it, you could do:
$userId = Auth::user()->id;
$posts = \App\Post::whereHas('author.follower', function ($q) use ($userId) {
return $q->where('id', $userId);
})
->latest() // built in helper method for orderBy('created_at', 'desc')
->get();
Now, $posts will be a collection of your Post models that were authored by a user that is being followed by your authenticated user.
I have 3 models
User
Pick
Schedule
I'm trying to do something like the following
$picksWhereGameStarted = User::find($user->id)
->picks()
->where('week', $currentWeek)
->first()
->schedule()
->where('gameTime', '<', Carbon::now())
->get();
This code only returns one array inside a collection. I want it to return more than 1 array if there is more than 1 result.
Can I substitute ->first() with something else that will allow me to to return more than 1 results.
If not how can I set up my models relationship to allow this to work.
My models are currently set up as follow.
User model
public function picks()
{
return $this->hasMany('App\Pick');
}
Schedule model
public function picks()
{
return $this->hasMany('App\Pick');
}
Pick model
public function user()
{
return $this->belongsTo('App\User');
}
public function schedule()
{
return $this->belongsTo('App\Schedule');
}
Since you already have a User model (you used it inside you find method as $user->id), you can just load its Pick relationship and load those Picks' Schedule as follows:
EDIT:
Assuming you have a schedules table and your picks table has a schedule_id column. Try this.
$user->load(['picks' => function ($q) use ($currentWeek) {
$q->join('schedules', 'picks.schedule_id', '=', 'schedules.id')
->where('schedules.gameTime', '<', Carbon::now()) // or Carbon::now()->format('Y-m-d'). See what works.
->where('picks.week', $currentWeek);
}])->load('picks.schedule');
EDIT: The code above should return the user's picks which have a schedules.gameTime < Carbon::now()
Try it and do a dump of the $user object to see the loaded relationships. That's the Eloquent way you want.
Tip: you may want to do $user->toArray() before you dump $user to see the data better.
EDIT:
The loaded picks will be in a form of Collections so you'll have to access it using a loop. Try the following:
foreach ($user->picks as $pick) {
echo $pick->schedule->gameTime;
}
If you only want the first pick from the user you can do: $user->picks->first()->schedule->gameTime
I think a foreach loop may be what you're looking for:
$picks = User::find($user->id)->picks()->where('week', $currentWeek);
foreach ($picks as $pick){
$pickWhereGameStarted = $pick->schedule()->where('gameTime', '<', Carbon::now())->get();
}
Try this and see if it's working for you