Turning a query result to an associative array - php

Question

In my php I am running a simple query which returns a resultset(0 or many) from the database I have.
Currently on the fronted the rersult looks like this :
name: Smoothie description: Banana Smothie name: Phad Thai description: Noodles with shrimps name: Noodles description: Noodles with noodles.
The string can also look like this, aka name: Smoothie description: Banana Smothie or with more entries, like in the example above.
What I am aiming to have is an associative array from my result, which I can turn into json string and pass it to the frontend.
Unfortunately what i tried so far didn't work.
This is my php :
<?php
include_once 'db/dbconnect.php';
$input = json_decode(stripcslashes($_POST['data']));
for ($i=0; $i < count($input); $i++) {
$stmt=$con->prepare("SELECT recipes.recipeName, recipes.recipeDescription FROM ingredients, recipes, recipesingredients WHERE recipes.recipeId = recipesingredients.recipeIdFK AND recipesingredients.ingredientIdFK = ingredients.IngredientId AND ingredients.ingredientName = ?");
$stmt->bind_param("s", $input[$i]);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($db_recipe_name, $db_recipe_description);
while ($stmt->fetch()) {
echo "name: ".$db_recipe_name." description: ".$db_recipe_description." ";
}
}
?>
Can someone help me make the result from the query to an associative array with the current code i have?

Answer 1

Just add each one to an array. Also, use modern JOIN syntax:
<?php
include_once 'db/dbconnect.php';
$input = json_decode(stripcslashes($_POST['data']));
for ($i=0; $i < count($input); $i++) {
$stmt=$con->prepare("SELECT recipes.recipeName,
recipes.recipeDescription
FROM ingredients i
JOIN recipesingredients ri
ON ri.ingredientIdFK = i.IngredientId
JOIN recipes r
ON r.recipeId = ri.recipeIdFK
WHERE i.ingredientName = ?");
$stmt->bind_param("s", $input[$i]);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($db_recipe_name, $db_recipe_description);
$rslt = array();
$rowno = 0;
while ($stmt->fetch()) {
$rslt[$rowno] = array('name' => $db_recipe_name, 'description' => $db_recipe_description);
$rowno++;
echo "name: ".$db_recipe_name." description: ".$db_recipe_description." ";
}
$jsonRslt = json_encode($rslt);
echo "<p>JSON Results:<pre>".$jsonRslt."</pre></p>\n";
$stmt->close();
}

Answer 2

You can use fetch_assoc method and save it into an array. Like
// In the beginning of your code initialize an ampty array
$result = array();
// Have your query here.
while($row = $stmt->fetch_assoc()) {
$result[] = $row;
}
$stmt->close();
echo json_encode($result);

Answer 3

Just call fetchAll(PDO::FETCH_ASSOC) on $stmt. It returns a associative array of all results. No need to use a while loop.
http://php.net/manual/en/pdostatement.fetchall.php#refsect1-pdostatement.fetchall-examples
include_once 'db/dbconnect.php';
$input = json_decode(stripcslashes($_POST['data']));
$stmt = $con->prepare("SELECT recipes.recipeName, recipes.recipeDescription FROM ingredients, recipes, recipesingredients WHERE recipes.recipeId = recipesingredients.recipeIdFK AND recipesingredients.ingredientIdFK = ingredients.IngredientId AND ingredients.ingredientName = ?");
for ($i=0; $i < count($input); $i++) {
$stmt->bind_param("s", $input[$i]);
$stmt->execute();
$result = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo json_encode($result);
}