PHP Array to string conversion - php

Question

So I made a query which returns many restaurants and I put them in a variable $row:
<?php if(count($Result_restaurants)>0)
{
foreach($Result_restaurants as $row)
{ ?>
<div id="ForEveryRestaurant">
<?php
$Rest_Name = $row['name'];
//$Rest_Name = $row;
$stmt = $db->prepare("SELECT Restaurant.idRestaurant FROM Restaurant WHERE Restaurant.name = \"$Rest_Name\"");
$stmt->execute();
$idRestaurant = $stmt->fetch();
$avg = 0;
$rateSum = 0;
$strcard = "SELECT rating FROM Review WHERE Review.idRestaurant = $idRestaurant";
$stmtcard = $db->prepare($strcard);
$stmtcard->execute();
$result = $stmtcard->fetchAll();
if (count($result) === 0)
{
return 0;
}
foreach( $result as $coments)
{
$rateSum += $coments['rating'];
}
$avg = $rateSum / count($result);
$avg = round($avg, 1);
When I try to run my code, it prints Array to string conversion.
The problem appears in this line:
$strcard = "SELECT rating FROM Review WHERE Review.idRestaurant = $idRestaurant";
I searched about the error and I understand but I tried many resolutions and didn't solved the problem.
can someone help please?

Answer 1

You should do like the following
$stmt->execute();
$stmt->bind_result($idRestaurant);
$stmt->fetch();
Try For PDO:
$result = $stmt->fetch(PDO::FETCH_ASSOC);
$idRestaurant = $result['idRestaurant'];

Answer 2

The problem is in this statement
$idRestaurant = $stmt->fetch();
Have you tried $idRestaurant = $stmt->fetch()[0];?
You can actually check what's coming into $idResturant by checking it via var_dump
var_dump($idResturant)

Answer 3

Check this:
$idRestaurant = $stmt->fetch();
// Its an array and you cannot use an array directly with WHERE clause in a query. Convert it to normal variable and use it.
$strcard = "SELECT rating FROM Review WHERE Review.idRestaurant = $idRestaurant";
// here you are using the array in WHERE clause
To do this:
$rating = isset($stmt->fetch()[0]) ? $stmt->fetch()[0]: null;