I'm currently struggling with my code. I want to delete certain row from my table, but I can't figure out what's wrong.
This is my .php for delete function:
<?php
$connect = mysqli_connect("localhost", "root", "", "produktai") or die (mysql_error());
mysqli_select_db($connect,'dazai');
if (isset($_GET['recordID']))
{
$id = $_GET['recordID'];
$query = "DELETE FROM dazai WHERE id = '$id'";
header("refresh:0; url=Dazai.php");
}
else
{
echo "Not Delete";
}
?>
That's my main .php:
<?php
session_start();
if(!isset($_SESSION['uid']))
{
header("Location:signup.php");
}
$connect = mysqli_connect("localhost", "root", "", "produktai");
$query = "SELECT * FROM dazai ORDER BY id ASC";
$result = mysqli_query($connect, $query);
if(mysqli_num_rows($result) > 0)
{
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row['id'];?></td>
<td><?php echo $row['pavad'];?></td>
<td><?php echo $row['Gamintojas'];?></td>
<td><?php echo $row['Spalva'];?></td>
<td><?php echo $row['Kiekis'];?></td>
<td><?php echo $row['Blizgumas'];?></td>
<td><?php echo $row['Kaina'];?>€</td>
<td><?php echo $row['Kategorija'];?></td>
<td><?php echo $row['sandely'];?></td>
<td>X
</tr>
<?php
}
}
?>
You probably don't want this...
mysqli_select_db($connect,'dazai');
as it is changing the database you are connected to.
$query = "DELETE FROM dazai WHERE id = '$id'";
$result = mysqli_query($connect, $query);
You miss to run the query and connect to bd in your delete.php file
Try this:
$connect = mysqli_connect("localhost", "root", "", "produktai");
if (isset($_GET['recordID'])) {
$id = $_GET['recordID'];
$query = "DELETE FROM dazai WHERE id = $id";
mysqli_query($connect, $query);
header ("refresh:0; url=Dazai.php");
}
else {
echo "Not Delete";
}
?>
Related
I inserted the data in the table very well and it's showing in phpMyadmin but when i try to display data from the database only one single item is displayed. I need help.
Code and screenshoots below
<?php
$sql = "SELECT * FROM nw";
$result = mysqli_query($conn, $sql);
if($result == TRUE){
$count = mysqli_num_rows($result);
if($count > 0){
while($row = mysqli_fetch_assoc($result)){
$incidentId = $row['id'];
$icTypeName = $row['inctype_name'];
$addedBy = $row['added_by'];
$addedOn = $row['added_on'];
}
?>
<tr class="tableData">
<td><?php echo $incidentId;?></td>
<td><?php echo $icTypeName;?></td>
<td><?php echo $addedBy;?></td>
<td><?php echo $addedOn;?></td>
<td><i class="uil uil-edit icon editIcon"></i></td>
</tr>
<?php
} else {
$_SESSION['noData'] = 'No incidents to show!';
}
} else {
die('Failed to Connect!');
}
?>
Images below
I expect to get all the data in the database tables displayed with the "SELECT * FROM nw"
Simply move the } that ends the while loop to after the code that is using the variables. You are currently consuming all the resultset before outputting anything, so you will only see the last rows data.
<?php
$sql = "SELECT * FROM nw";
$result = mysqli_query($conn, $sql);
if($result == TRUE){
$count = mysqli_num_rows($result);
if($count > 0){
while($row = mysqli_fetch_assoc($result)){
$incidentId = $row['id'];
$icTypeName = $row['inctype_name'];
$addedBy = $row['added_by'];
$addedOn = $row['added_on'];
//} REMOVED
?>
<tr class="tableData">
<td><?php echo $incidentId;?></td>
<td><?php echo $icTypeName;?></td>
<td><?php echo $addedBy;?></td>
<td><?php echo $addedOn;?></td>
<td><i class="uil uil-edit icon editIcon"></i></td>
</tr>
<?php
} // END OF WHILE LOOP
} else {
$_SESSION['noData'] = 'No incidents to show!';
}
} else {
die('Failed to Connect!');
}
?>
I'm writing a forum, and my PHP code shows all the records for the selected column on a simple row.
Code:
<td bgcolor="#FAB1CA">
<?php
$link = mysqli_connect("xxxx", "xxx", "xxxx", "xxxxxx");
if ($link === false) {
die("ERROR: Could not connect. " . mysqli_connect_error());
}
if (isset($_SESSION['logged'])) {
$sql = "Select ID from forum_question ORDER by id DESC";
$result = mysqli_query($link, $sql);
while ($row = mysqli_fetch_assoc($result)) {
$show = $row['ID'];
print_r($show);
}
}
mysqli_close($link);
?>
</td>
<td bgcolor="#FAB1CA">
<?php
$link = mysqli_connect("xxxx", "xxx", "xxxx", "xxxxxx");
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
if(isset($_SESSION['logged'])){
$sql= "Select ID from forum_question ORDER by id DESC";
$result = mysqli_query($link, $sql);
while($row = mysqli_fetch_assoc($result)){
$show = $row['ID'];
print_r($show);
echo"<br />";
}
}
mysqli_close($link);
?>
</td>
please echo a "br"-tag. hope your problem will be fixed.
I am doing a project and would be eternally grateful for help in getting my URl's to link. I have tried looking around to no avail. I have a database (4columns). The last one (link1) should link to videos with the specified URL.When the table comes up the URL's are not clickable (is there a way to simplify this say "click me"?). Here is my code. I've also attached an image of the table. This is really busting my brains, thanks.
<?php
$con = mysqli_connect("localhost","feedb933_charles","pass100","feedb933_test");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM videos";
$result = mysqli_query($con, $sql);
echo "<table>";
echo "<tr>
<th>topic1</th>
<th>subject1</th>
<th>link1</th>
</tr>";
while( $row = mysqli_fetch_array( $result)) {
$topic1 = $row["topic1"];
$subject1 = $row["subject1"];
$link1 = $row["link1"];
echo "<tr>
<td>$topic1</td>
<td>$subject1</td>
<td>$link1</td>
</tr>";
}
echo "</table>";
mysqli_close($con);
?>
Table output
Try this:
<?php
$sql = "SELECT * FROM `videos`";
$result = mysqli_query($con, $sql);
?>
<table>
<?php
while($row = mysqli_fetch_assoc( $result)) {
?>
<tr>
<td><?php echo $row['topic1'];?></td>
<td><?Php echo $row['subject1'];?></td>
<td><a href="<?php echo $row['link1']; ?>" target="_blank">Click me</td>
</tr>
<?php } ?>
<table>
Or you can also use do while loop:
do{
echo '<tr>';
echo '<td>'.$row['topic1'].'</td>';
echo '<td>'.$row['subject1'].'</td>';
echo '<td><a href="'.$row['link1'].'" target="_blank">Click me</td>';
echo '</tr>';
} while($row = mysqli_fetch_assoc( $result);
I added the target attribute to open the link in a new window.
I looked at your code and i found a couple errors.
change $con = mysqli_connect("localhost","feedb933_charles","pass100","feedb933_test"); to $con = new mysqli("localhost", "feedb933_charles", "pass100", "feedb933_test");
Then change if (mysqli_connect_errno()) to if (mysqli_connect_error()) {
Then change
$sql = "SELECT * FROM videos";
to
$sql = "SELECT topic1, subject1, link1 FROM videos";
or if you want to select one row
$differentvalue = ""; // value to run
$sql = "SELECT topic1, subject1, link1 FROM videos WHERE difvalue = ?";
difvalue is the value different frm the rest so the php code knows what to grab.
Using stmt means no sql injection
Add:
$stmt = $con->stmt_init();
if (!$stmt->prepare($sql))
{
print "Failed to prepare statement\n";
}
else
{
}
Then in side if (something) { } else { IN HERE }
(if you have WHERE diffvalue) Add:
$stmt->bind_param("s", $differentvalue); // $stmt->bind_param("s", $differentvalue); if text, $stmt->bind_param("i", $differentvalue); if integer
Then
Add:
$stmt->execute();
$list = $stmt->fetchAll();
then outside the if (something) { code } else { code }
Add:
echo "<table><tr><th>topic1</th><th>subject1</th><th>link1</th></tr><tr>";
foreach ($list as $row => $new) {
$html = '<td>' . $new['topic1'] . '</td>';
$html .= '<td>' . $new['subject1'] . '</td>';
$html .= '<td>' . $new['link1'] . '</td>';
echo $html;
}
echo "</tr></table>";
If you are still having problems goto the links listed
http://php.net/manual/en/pdostatement.fetchall.php
http://php.net/manual/en/mysqli-stmt.get-result.php
http://php.net/manual/en/mysqli-result.fetch-all.php
Hope this helps
<?php
$con=mysqli_connect("localhost","feedb933_charles","pass100","feedb933_test");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM videos";
$result = mysqli_query($con, $sql);
echo "<table>";
echo "<tr>
<th>topic1</th>
<th>subject1</th>
<th>link1</th>
</tr>";
while( $row = mysqli_fetch_array( $result)) {
$topic1 = $row["topic1"];
$subject1 = $row["subject1"];
$link1 = $row["link1"];
echo "<tr>
<td>$topic1</td>
<td>$subject1</td>
<td>$link1</td>
*//this href will give u the link as u asked. //be sure you store proper url. In case of exact video name saved in column thn can make the url for your web output. //ex:<a href="http://example.com/'.$link.'.extension">*
</tr>";
}
echo "</table>";
mysqli_close($con);
?>
I am trying to remove a string from DB by a Href in a form. Why does this not work for me? The query is right, nothing happens.
<?php
// Make a MySQL Connection
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("cms") or die(mysql_error());
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM pages")
or die(mysql_error());
echo "<table border='1'>";
while ($row = mysql_fetch_array($result)) {
echo "<li class='list-group-item'>";
echo $row['header'];
echo "<br/>";
echo $row['description'];
echo "<br/>";
echo "<form method='POST'><a href='delete.php?id=".$row['page_id']."'>Remove</a></form>";
echo "</li>";
}
echo "</table>";
?>
delete.php
<?php
$db = new mysqli('localhost', 'root', '', 'cms');
$id = mysqli_query($db, "SELECT page_id FROM pages");
if (isset($_POST['id'])) {
mysqli_query($db, "DELETE FROM pages WHERE id='".$_GET['id']."'");
}
?>
And it still won't work. Just sends me to a blank page with no query.
Change this :
echo "<form method='POST'><a href='delete.php?".$row['page_id']."'>Remove</a></form>";
to
echo "<form method='POST' action='delete.php'><input type='hidden' value=".$row['page_id']." name='id'/><input type='submit' value='Remove'/></form>";
And in delete.php
This :
if (isset($_GET['id'])) {
To
if (isset($_POST['id'])) {
This
mysqli_query($db, "DELETE FROM pages WHERE id='".$_GET['id']."'");
to
mysqli_query($db, "DELETE FROM pages WHERE id='".$_POST['id']."'");
I am using a for loop to construct a HTML table from the contents of a MySQL table select query. I have a link on the end of each row to copy that row into another table.
I'm unsure how to get the data from the table row for the MySQL insert query - I have marked the place where I'm struggling with XXX.
<?php
mysql_select_db("cardatabase");
$link = mysql_connect("localhost", "root", "password");
$query = "SELECT * from cars";
$result = mysql_query($query);
if($_GET['rent']) {
$rent = "INSERT INTO rentedcars VALUES('XXX','XXX','XXX','XXX','XXX','XXX','XXX','XXX','XXX','XXX')";
mysql_query($rent);
echo "<meta http-equiv='refresh' content='0;url=rent.php'/>";
}
echo "<table>";
echo "<tr><td>ID</td><td>Make</td><td>Model</td><td>Fuel Type</td><td>Transmission</td><td>Engine Size</td><td>Doors</td><td>Amount</td><td>Available</td><td>Date Added</td><td>Remove</td></tr>";
for ($i = 0; $i < mysql_num_rows($result); $i++) {
$row = mysql_fetch_object($result);
echo "<tr>
<td>$row->ID</td>
<td>$row->CARMAKE</td>
<td>$row->CARMODEL</td>
<td>$row->FUELTYPE</td>
<td>$row->TRANSMISSION</td>
<td>$row->ENGINESIZE</td>
<td>$row->DOORS</td>
<td>$row->AMOUNT</td>
<td>$row->AVAILABLE</td>
<td>$row->DATEADDED</td>
<td><a href='?rent=$row->ID'>Rent</a></td>
</tr>";
}
echo "</table>";
edit (updated code):
<?php
mysql_select_db ("cardatabase");
$link = mysql_connect ("localhost", "root", "password");
$query = "SELECT * from cars";
$result = mysql_query ($query);
if($_GET['rent']) {
$query_car = sprintf("SELECT * from cars WHERE ID=%s",$_GET['rent']);
$rslt = mysql_query($query_car);
$car = mysql_fetch_object ($rslt);
$rent = "INSERT INTO rentedcars VALUES('$car->ID','$car->CARMAKE','$car->CARMODEL','$car->FUELTYPE','$car->TRANSMISSION','$car->ENGINESIZE','$car->DOORS','$car->AMOUNT','$car->AVAILABLE','$car->DATEADDED')";
mysql_query($rent);
echo "<meta http-equiv='refresh' content='0;url=rent.php'/>";
}
echo "<table>";
echo "<tr>";
echo "<td>ID</td><td>Make</td><td>Model</td><td>Fuel Type</td><td>Transmission</td><td>Engine Size</td><td>Doors</td><td>Amount</td><td>Available</td><td>Date Added</td><td>Remove</td>";
echo "</tr>";
while ($row = mysql_fetch_object($result)) {
echo "<tr>
<td>$row->ID</td>
<td>$row->CARMAKE</td>
<td>$row->CARMODEL</td>
<td>$row->FUELTYPE</td>
<td>$row->TRANSMISSION</td>
<td>$row->ENGINESIZE</td>
<td>$row->DOORS</td>
<td>$row->AMOUNT</td>
<td>$row->AVAILABLE</td>
<td>$row->DATEADDED</td>
<td><a href='?rent=$row->ID'>Rent</a></td>
</tr>";
}
echo "</table>";
mysql_* is deprecated as of PHP 5.5.0, you should use something like PDO.
try {
$DBH = new PDO('mysql:dbname=cardatabase;host=localhost', 'root', 'password');
} catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$STH = $DBH->query("SELECT * FROM cars")->execute();
while ($row = $STH->fetch(PDO::FETCH_OBJ)) {
echo "<tr>
<td>$row->ID</td>
<td>$row->CARMAKE</td>
<td>$row->CARMODEL</td>
<td>$row->FUELTYPE</td>
<td>$row->TRANSMISSION</td>
<td>$row->ENGINESIZE</td>
<td>$row->DOORS</td>
<td>$row->AMOUNT</td>
<td>$row->AVAILABLE</td>
<td>$row->DATEADDED</td>
<td><a href='?rent=".$row->ID."'>Rent</a></td>
</tr>";
}
Edit: Just like #Skatox said!
I would do it like this:
<?php
$link = mysql_connect ("localhost", "root", "password");
mysql_select_db ("cardatabase");
$query = "SELECT * from cars";
$result = mysql_query ($query);
Get car information and store it
if($_GET['rent'])
{
$query_car = sprintf("SELECT * from cars WHERE ID=%s",$_GET['rent']); //Avoids sql injection
$rslt = mysql_query($query_car);
$car = mysql_fetch_object ($rslt)
Here you need to validate if there's no car
$rent = "INSERT INTO rentedcars VALUES('$car->ID','$car->CARMAKE','$car->CARMODEL','$car->FUELTYPE','$car->TRANSMISSION','$car->ENGINESIZE','$car->DOORS','$car->AMOUNT','$car->AVAILABLE','$car->DATEADDED')";
mysql_query($rent);
echo "<meta http-equiv='refresh' content='0;url=rent.php'/>";
}
Change it to while like #Vinoth Babu said:
while ($row = mysql_fetch_object ($result))
{
$row = mysql_fetch_object ($result);
echo "<tr>
<td>$row->ID</td>
<td>$row->CARMAKE</td>
<td>$row->CARMODEL</td>
<td>$row->FUELTYPE</td>
<td>$row->TRANSMISSION</td>
<td>$row->ENGINESIZE</td>
<td>$row->DOORS</td>
<td>$row->AMOUNT</td>
<td>$row->AVAILABLE</td>
<td>$row->DATEADDED</td>
<td><a href='?rent=$row->ID'>Rent</a></td>
</tr>";
}
print "</table>";
?>
I would recommend you to switch to MySQL PDO, it's safer and you'll get a better and secure code.
you are missing the column names in your insert query
$rent = "INSERT INTO rentedcars (id ,carmake, carmodel,fueltype,transmission, enginesize,doors,amount ,available, dateadded)
VALUES('xxx','xxx','".$carmodel."','XXX','XXX','XXX','XXX','XXX','XXX','XXX')";
^^^^^-------------i showed u exempel under
those XXX are values you get the from the inputs values
exemple
<input name= "car_model" id= "car_model" value="mercedes" >
then you get this value
if (isset($_POST['car_model'])){ $carmodel = $_POST['car_model']}
and then use this value $carmodel in your sql