Cannot get URL from Database to link - php

Question

I am doing a project and would be eternally grateful for help in getting my URl's to link. I have tried looking around to no avail. I have a database (4columns). The last one (link1) should link to videos with the specified URL.When the table comes up the URL's are not clickable (is there a way to simplify this say "click me"?). Here is my code. I've also attached an image of the table. This is really busting my brains, thanks.
<?php
$con = mysqli_connect("localhost","feedb933_charles","pass100","feedb933_test");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM videos";
$result = mysqli_query($con, $sql);
echo "<table>";
echo "<tr>
<th>topic1</th>
<th>subject1</th>
<th>link1</th>
</tr>";
while( $row = mysqli_fetch_array( $result)) {
$topic1 = $row["topic1"];
$subject1 = $row["subject1"];
$link1 = $row["link1"];
echo "<tr>
<td>$topic1</td>
<td>$subject1</td>
<td>$link1</td>
</tr>";
}
echo "</table>";
mysqli_close($con);
?>
Table output

Answer 1

Try this:
<?php
$sql = "SELECT * FROM `videos`";
$result = mysqli_query($con, $sql);
?>
<table>
<?php
while($row = mysqli_fetch_assoc( $result)) {
?>
<tr>
<td><?php echo $row['topic1'];?></td>
<td><?Php echo $row['subject1'];?></td>
<td><a href="<?php echo $row['link1']; ?>" target="_blank">Click me</td>
</tr>
<?php } ?>
<table>
Or you can also use do while loop:
do{
echo '<tr>';
echo '<td>'.$row['topic1'].'</td>';
echo '<td>'.$row['subject1'].'</td>';
echo '<td><a href="'.$row['link1'].'" target="_blank">Click me</td>';
echo '</tr>';
} while($row = mysqli_fetch_assoc( $result);
I added the target attribute to open the link in a new window.

Answer 2

I looked at your code and i found a couple errors.
change $con = mysqli_connect("localhost","feedb933_charles","pass100","feedb933_test"); to $con = new mysqli("localhost", "feedb933_charles", "pass100", "feedb933_test");
Then change if (mysqli_connect_errno()) to if (mysqli_connect_error()) {
Then change
$sql = "SELECT * FROM videos";
to
$sql = "SELECT topic1, subject1, link1 FROM videos";
or if you want to select one row
$differentvalue = ""; // value to run
$sql = "SELECT topic1, subject1, link1 FROM videos WHERE difvalue = ?";
difvalue is the value different frm the rest so the php code knows what to grab.
Using stmt means no sql injection
Add:
$stmt = $con->stmt_init();
if (!$stmt->prepare($sql))
{
print "Failed to prepare statement\n";
}
else
{
}
Then in side if (something) { } else { IN HERE }
(if you have WHERE diffvalue) Add:
$stmt->bind_param("s", $differentvalue); // $stmt->bind_param("s", $differentvalue); if text, $stmt->bind_param("i", $differentvalue); if integer
Then
Add:
$stmt->execute();
$list = $stmt->fetchAll();
then outside the if (something) { code } else { code }
Add:
echo "<table><tr><th>topic1</th><th>subject1</th><th>link1</th></tr><tr>";
foreach ($list as $row => $new) {
$html = '<td>' . $new['topic1'] . '</td>';
$html .= '<td>' . $new['subject1'] . '</td>';
$html .= '<td>' . $new['link1'] . '</td>';
echo $html;
}
echo "</tr></table>";
If you are still having problems goto the links listed
http://php.net/manual/en/pdostatement.fetchall.php
http://php.net/manual/en/mysqli-stmt.get-result.php
http://php.net/manual/en/mysqli-result.fetch-all.php
Hope this helps

Answer 3

<?php
$con=mysqli_connect("localhost","feedb933_charles","pass100","feedb933_test");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "SELECT * FROM videos";
$result = mysqli_query($con, $sql);
echo "<table>";
echo "<tr>
<th>topic1</th>
<th>subject1</th>
<th>link1</th>
</tr>";
while( $row = mysqli_fetch_array( $result)) {
$topic1 = $row["topic1"];
$subject1 = $row["subject1"];
$link1 = $row["link1"];
echo "<tr>
<td>$topic1</td>
<td>$subject1</td>
<td>$link1</td>
*//this href will give u the link as u asked. //be sure you store proper url. In case of exact video name saved in column thn can make the url for your web output. //ex:<a href="http://example.com/'.$link.'.extension">*
</tr>";
}
echo "</table>";
mysqli_close($con);
?>