Right now I could list each application/(Internal Team Names) name in table. Now I want to find out passed (%) from each table for each application and print on html page. Each "aw..." table has all application/(Internal Team Names) names and respective result also.
<html>
<?php
$Show= htmlspecialchars($_GET["Show"]);
$team= htmlspecialchars($_GET["team"]);
$tablename = htmlspecialchars($_GET["tablename"]);
$servername="localhost";
$username="root";
$password="";
?>
<?php
// Create connection with mySQL
$conn = mysqli_connect($servername, $username, $password);
// Check connection
if (!$conn) {
die("Connection failed:" . mysqli_connect_error());
}
//echo "Connected to mysql successfully";
//select a database to work with
mysqli_query( $conn , "USE plm_dashboard" );
Echo "<Body bgcolor="."white".">" ;
//echo $Show;
Echo "<br>";
Echo "<br>";
Echo "Applied Filters Are <br> ";
//echo "Team = $team "; echo "TableName= $tablename ";
$Local_team= "Reports";
if ($Show == "failed"){
$Result_status = "passed";
} else {
// in this case the value of the $Result_status is 'all'
$Result_status = "";
}
echo "Result = $Show <br>";
//$result =mysqli_query($conn ,"SELECT * FROM aw34_0605_tc1122 where Application="."'".$team."'");
$result = mysqli_query($conn ,"SELECT * FROM teamnames");
$result1 =mysqli_query($conn ,"SELECT * FROM aw34_0530_tc1015 (Select count(id) from aw34_0530_tc1015 where result ='passed' and application='ace')/(Select count(id) from aw34_0530_tc1015 where application='ace')*100");
//$result =mysqli_query($conn ,"SELECT * FROM ". $tablename );
//********** determine number of rows result set **********/
// $row_cnt = $result->num_rows;
//mysqli_query()
//echo "Showing $row_cnt Results ";
//echo "<table border="."1".">
echo "<table border="."1"."align="."right".">
<tr>
<th>ID</th>
<th>Internal Team Names</th>
<th width="."10px"." >Passed % for aw34_0530_tc1015</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['ID'] . "</td>";
echo "<td>" . $row['TeamInternalNames'] . "</td>";
echo "<td>" . $row['TeamName'] . "</td>";
// if ($row['Result'] == "passed") {
// echo "<td style="."background-color:#33FF38".">P</td>";
// } else {
// echo "<td style="."background-color:#FF334C".">F</td>";
// }
echo "</tr>";
}
echo "</table>";
ECHO "BYE";
mysqli_close($conn);
Echo "<Body>";
?>
</html>
Related
I know this involves a loop. I've done a number of searches but can't quite figure it out.
I'm using the following code to output the data with 3 items per row. What I'd really like to figure out how to do is to have them go ascending by column instead of by row, but dynamically depending on the number of records in the query, instead of defining the number of rows in the column.
<?php
define('DB_SERVER', "xxx");
define('DB_USER', "xxx");
define('DB_PASSWORD', "xxx");
define('DB_TABLE', "xxx");
$row_count = 0;
// The procedural way
$mysqli = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_TABLE);
$mysqli->set_charset("utf8");
$mysqli->query("SET NAMES 'utf8'");
if (mysqli_connect_errno($mysqli)) {
trigger_error('Database connection failed: ' . mysqli_connect_error(), E_USER_ERROR);
}
$query = "
SELECT lvm.luchtvaartmaatschappij, COUNT(*) AS CountLVMPhotos
FROM tbl_photos p
LEFT JOIN tbl_luchtvaartmaatschappij lvm
ON p.img_lvm = lvm.IATACode
WHERE p.img_creator IN ('Daniël E. Cronk','Daniel E. Cronk')
GROUP BY lvm.luchtvaartmaatschappij
ORDER BY lvm.luchtvaartmaatschappij ASC ";
$result = mysqli_query($mysqli, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($mysqli), E_USER_ERROR);
echo "
<table id='fotosBij' class='tablesorter-dropbox table-responsive ui-table-reflow'>";
echo "<tbody>";
if($result) {
while($row = mysqli_fetch_assoc($result)) {
$items_in_row = 3 ;
$index = 0 ;
echo '<tr >';
while($row = mysqli_fetch_assoc($result)){
$index++ ;
echo "<td width='250px' valign='top'>" . $row['luchtvaartmaatschappij'] . "</td>";
echo "<td width='50px' valign='top'>" . $row['CountLVMPhotos'] . "</td>";
echo "<td width='80px'> </td>";
if ($index%$items_in_row == 0){
echo "</tr>";
}
}
echo "</tbody>";
echo "</table>";
}
}
mysqli_close($mysqli);
?>
If I understand what you want correctly, this will do it:
if($result) {
$row1html = "<tr>";
$row2html = "<tr>";
while($row = mysqli_fetch_assoc($result)) {
$row1html .= "<td width='250px' valign='top'>".
$row['luchtvaartmaatschappij'] ."</td>";
$row2html .= "<td width='50px' valign='top'>".
$row['CountLVMPhotos'] . "</td>";
}
$row1html = "</tr>";
$row2html = "</tr>";
echo $row1html . $row2html;
}
There might be more elegant ways but this should work.
If you have a lot of data, that table is gonna get pretty wide though, so hopefully you have a design for that.
I am trying to use the results of a database and display them in an HTML table. I've searched around but can't find a specific answer for my situation as I am new to PHP and I had to copy this code from another source because I was unable to get it to work on my own. Please help.
<?php $server = "127.0.0.1";
$user = "admin";
$pass = "password";
$dbname = "hysteryalelogs";
// Create connection in mysqli
$connection = new mysqli($server, $user, $pass, $dbname);
//Check connection in mysqli
if($connection->connect_error){
die("Error on connection:" .$connection->connect_error);
}
//Display the informaion
$sql = "SELECT * FROM logs";
$res = $connection->query($sql);
if($res->num_rows > 0){
while($row = $res->fetch_assoc()){
echo "Sales Number: ". $row["Sales_Number"]. "<br/>";
echo "Quantity: ". $row["Quantity"]. "<br/>";
echo "Due Date: ". $row["Due_Date"]. "<br/>";
echo "Burnished Housing: ". $row["Burnished"]. "<br/>";
echo "Greased Bearings: ". $row["Grease"]. "<br/>";
echo "Air Cleaned: ". $row["Air"]. "<br/>";
echo "SS Screw: ". $row["Screw"]. "<br/>";
echo "Test Date: ". $row["Test_Date"]. "<br/>";
echo "Pass: ". $row["Pass"]. "<br/>";
echo "Fail: ". $row["Fail"]. "<br/>";
echo "Tester: ". $row["Tester"]. "<br/>";
echo "Final Check: ". $row["Final_Check"]. "<br/>";
echo "Green Dot: ". $row["Green_Dot"]. "<br/>";
echo "Green Dot Check: ". $row["Green_Dot_Check"]. "<br/>";
echo "Ship Date: ". $row["Ship_Date"]. "<br/>";
echo "Serial Number: ". $row["Serial_Number"]. "<br><br><hr><br/>";
}
} else {
echo "No Record Found!";
}
$connection->close();
?>
(clarification) The code works. I Just don't know how to format the table for it to display inside.
Hi :) Hope this helps :)
<?php
$server = "127.0.0.1";
$user = "admin";
$pass = "password";
$dbname = "hysteryalelogs";
// Create connection in mysqli
$connection = new mysqli($server, $user, $pass, $dbname);
//Check connection in mysqli
if($connection->connect_error){
die("Error on connection:" .$connection->connect_error);
}
//Display the informaion
$sql = "SELECT * FROM logs";
$res = $connection->query($sql);
if($res->num_rows > 0){
echo "<table border='3px' cellpadding='5px' cellspacing='5px' align='center' bgcolor='skyblue' ";
echo "<tr>";
echo "<td><center><strong>Sales Number</strong></center></td>";
echo "<td><center><strong>Quantity</strong></center></td>";
echo "<td><center><strong>Due Date</strong></center></td>";
echo "<td><center><strong>Burnished Housing</strong></center></td>";
echo "<td><center><strong>Greased Bearings</strong></center></td>";
echo "<td><center><strong>Air Cleaned</strong></center></td>";
echo "<td><center><strong>SS Screw</strong></center></td>";
echo "<td><center><strong>Test Date</strong></center></td>";
echo "<td><center><strong>Pass</strong></center></td>";
echo "<td><center><strong>Fail</strong></center></td>";
echo "<td><center><strong>Tester</strong></center></td>";
echo "<td><center><strong>Final Check</strong></center></td>";
echo "<td><center><strong>Green Dot</strong></center></td>";
echo "<td><center><strong>Green Dot Check</strong></center></td>";
echo "<td><center><strong>Ship Date</strong></center></td>";
echo "<td><center><strong>Serial Number</strong></center></td>";
echo "</tr>";
while($row = $res->fetch_assoc()){
echo "<tr>";
echo "<td>"."<center>"."<i>".$row["Sales_Number"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Quantity"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Due_Date"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Burnished"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Grease"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Air"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Screw"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Test_Date"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Pass"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Fail"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Tester"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Final_Check"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Green_Dot"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Green_Dot_Check"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Ship_Date"]."</i>"."</center>"."</td>";
echo "<td>"."<center>"."<i>".$row["Serial_Number"]."</i>"."</center>"."</td>";
echo "</tr>";
}
echo "</table>";
} else {
echo "No Record Found!";
}
$connection->close();
?>
I am trying to display my query results on page. However, whenever I run the code although the query is correct it does not display anything.
Can anyone help? Would be muchly appreciated
<?php
session_start();
require_once("../config1.php");
if(isset($_POST["DailySales"])) {
$linkid = mysqli_connect(DB_DATA_SOURCE, DB_USERNAME, DB_PASSWORD, DB_DATABASE) or die("Could not connect:" . connect_error());
$sql = "SELECT Retdatetime AS date , sum(rentalrate + overduecharge) AS mny
FROM frs_FilmRental
WHERE shopid='2'
Order BY retdatetime DESC ";
$result = mysqli_query($linkid, $sql);
if (!$result)) {
printf("Errormessage: %s\n", mysqli_error($linkid));
}
echo "<table border = '1' align='center'>";
echo "<th> Shop ID 2</th></tr>";
while ($row = mysqli_fetch_assoc($result)) {
echo "<h2><center>Shop ID 2 daily sales : </center></h2>";
echo "<tr><td>";
echo $row['mny'];
echo "</td><td>";
echo $row ['date'];
echo "</td></tr>";
}
}
?>
replace
echo $row ['date'];
by
echo $row ['Retdatetime'];
To understand query errors you should use mysqli_error() in your code. If there are no errors for executed query, then you can run while loop for it.
<?php
session_start();
require_once("../config1.php");
if(isset($_POST["DailySales"])) {
$linkid = mysqli_connect(DB_DATA_SOURCE, DB_USERNAME, DB_PASSWORD, DB_DATABASE) or die("Could not connect:" . connect_error());
$sql = "SELECT Retdatetime , sum(rentalrate + overduecharge) AS mny
FROM frs_FilmRental
WHERE shopid='2'
Order BY retdatetime DESC ";
$result = mysqli_query($linkid, $sql);
if (!$result)) {
printf("Errormessage: %s\n", mysqli_error($linkid));
} else {
echo "<table border = '1' align='center'>";
echo "<tr><th> Shop ID 2</th></tr>";
while ($row = mysqli_fetch_assoc($result)) {
echo "<h2><center>Shop ID 2 daily sales : </center></h2>";
echo "<tr><td>";
echo $row['mny'];
echo "</td><td>";
echo $row ['date'];
echo "</td></tr>";
}
echo "</table>";
}
}
?>
fixes given in comments also applied
Please copy/paste the error, given by mysqli_error()
I want every different record of database to be display on each table rows, but I'm unable to retrieve different record for each row and column. Please give me suggestion where I can paste than while block so it will give different result for each row and column.
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$rec_limit = 10;
$scriptname=$_SERVER['PHP_SELF'];
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('online_shopping'); // include your code to connect to DB.
$tbl_name="mobile_db"; //your table name
$start = 0;
$limit = 5;
$sql = "SELECT id,company,model,price,availability,image FROM $tbl_name LIMIT $start, $limit";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
$company=$row['company'];
$model=$row['model'];
$available=$row['availability'];
$price=$row['price'];
}
echo "<table border='2'>";
$j = 0;
for($j = 0; $j<5; $j++)
{
echo "<tr>";
for($i = 0; $i<3; $i++)
{
echo "<td>";
echo "<table border='2'>";
echo "<tr>";
echo "<td><img src='abc.jpg' height='250' width='250'/></td>";
echo "</tr>";
echo "<tr>";
echo "<td>";
echo "<table border='2'>";
echo "<tr>";
echo "<td><b>Brand : </b></td>";
echo '<td>'.$company.'</td>';
echo "</tr>";
echo "<tr>";
echo "<td><b>Model : </b></td>";
echo '<td>'.$model.'</td>';
echo "</tr>";
echo "<tr>";
echo "<td><b>Availability : </b></td>";
echo '<td>'.$available.'</td>';
echo "</tr>";
echo "<tr>";
echo "<td><b>Price : </b></td>";
echo '<td>'.$price.'</td>';
echo "</tr>";
echo "</table>";
echo "</td>";
echo "</tr>";
echo "</table>";
echo "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
You need to move the table rows inside the fetch loop or store the row in an array. I have simplified your tables to make the example clearer:
$result = mysql_query($sql);
if (!$result) {
/* Error */
}
echo '<table>';
while ($row = mysql_fetch_array($result)) {
echo '<tr><td><img src="', htmlspecialchars ($row['image']), '">';
echo '<tr><td><table>';
echo ' <tr><th>Brand<td>', htmlspecialchars ($row['company']);
echo ' <tr><th>Model<td>', htmlspecialchars ($row['model']);
echo ' <tr><th>Availability<td>', htmlspecialchars ($row['availability']);
echo ' <tr><th>Price<td>', htmlspecialchars ($row['price']);
echo ' </table>';
}
echo "</table>\n";
Some notes about the code:
Test the return value of mysql_query(). The query might fail.
Escape your output using htmlspecialchars().
You should use <th> elements for your headings and style those, instead of using inline <b> elements.
I added output of $row['image'] which might not do what you want.
And do not use the deprecated mysql extension. Use PDO or mysqli instead.
In your while loop you always rewrite the same variables, after loop you have only last record saved.
In the loop, you have to save records into array.
In your code you have nested tables, but in the first one, there is only one row and one table cell which contains another table. I use just nested table.
<?php
...
$result = mysql_query($sql);
$data = array();
while($row = mysql_fetch_array($result)) {
$data[] = $row;
}
if (count($data) > 0) {
echo '<table>';
foreach ($data as $row) {
echo '<tr>';
echo '<td>Brand: ' . $row['company'];
echo '<td>Model: ' . $row['model'];
echo '<td>Availability: ' . $row['availability'];
echo '<td>Price: ' . $row['price'];
}
echo '</table>';
} else {
echo 'no records';
}
?>
Not sure I fully understand what you are trying to accomplish but try this.
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$rec_limit = 10;
$scriptname=$_SERVER['PHP_SELF'];
$conn = mysql_connect($dbhost, $dbuser, $dbpass);
if(! $conn )
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('online_shopping'); // include your code to connect to DB.
$tbl_name="mobile_db"; //your table name
$start = 0;
$limit = 5;
$sql = "SELECT id,company,model,price,availability,image FROM $tbl_name LIMIT $start, $limit";
$result = mysql_query($sql);
echo "<table border='2'>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>".$row['company']."</td>";
echo "<td>".$row['model']."</td>";
echo "<td>".$row['availability']."</td>";
echo "<td>".$row['price']."</td>";
echo "</tr>";
}
echo "</table>";
?>
I have rows in MYSQL.
They are basically articles and rumours based on user input. In my query, i would like the table created to have the later results ranked higher. How would that Order By Query work?
$query = "SELECT * FROM rumours";
$query.= "ORDER BY"
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
while ($row = mysql_fetch_assoc($query)) {
$id = $row['id'];
$band = $row['band'];
$title = $row['Title'];
$description = $row['description'];
echo "<table border='1'>";
echo "<tr>";
echo "<td> $title </td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'> $description </td>";
echo "</tr>";
echo "</table>";
}
Few things regarding your snippet.
Use a column list and avoid selecting *
mysql_ functions are being deprecated. You should use either mysqli_ or PDO functions.
You can save yourself time by calling your columns directly, rather than reassigning them variables.
When you are asking for the older records to display first, what is the criteria for this? Does a higher id mean the record is newer? I've assumed this in my answer.
Here's an improved version of your code using mysqli_:
$link = mysqli_connect("localhost", "user", "pass", "db");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$q = "SELECT id, band, Title, description FROM rumours ORDER BY id DESC";
$result = mysqli_query($link, $q);
while($row = mysqli_fetch_array($result, MYSQLI_BOTH)) {
echo "<table border='1'>";
echo "<tr>";
echo "<td>" . $row[id] . "</td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'>" . $row[description] . "</td>";
echo "</tr>";
echo "</table>";
}
mysqli_free_result($result);